CHEMISTRY COMMUNITY

Merzia Subhan 1L

you have to use delta G naught = -nFE for each step because you can't just add up the Es. when you get the final delta G, convert it back to E.

Merzia Subhan 1L

When solving for rate laws, would we have to use the pre equilibrium approach on the final? In section, I learned another way that made more sense to me so if we used that way, would we be penalized for it?

Merzia Subhan 1L

Since when writing rate laws, the coefficients of the equation are not the power in the rate law, like 3 I- is not [I-]^3, how would you determine the power of a concentration in a rate law? Is it impossible to determine just by looking at the chemical equation?

Merzia Subhan 1L

Since [C] is zero order, it is not listed in the rate law. rate=k[A][B]^2

Merzia Subhan 1L

If a chemist is sick, and you can't helium, and you can't curium, then you might as well barium.

Merzia Subhan 1L

Technically, alcohol is a solution.

Merzia Subhan 1L

Today I told a chemistry joke, no reaction.

Merzia Subhan 1L

Two chemists walk into a bar, First says "hello, I'll have H2O" Second says "I'll also have some water, and stop ordering like that, you sound like an idiot"

Merzia Subhan 1L

I think I lost an electron. In fact, I'm positive.

Merzia Subhan 1L

NaCl NaOH
RED ALERT! THE BASE IS UNDER A SALT!!

Merzia Subhan 1L

Did you know that you can cool yourself to -273.15˚C and still be 0 K?

Merzia Subhan 1L

Also I tried doing the first one over the third one and I also got 2 so it doesn't matter which one goes on top and which one is on the bottom. I just got decimals when I put the small one on top but the same answer - second order.

Merzia Subhan 1L

For [B], I used the first and third experiment since [B] is the only thing that changes then. So I write the third one over the first one: (\frac{3.02}{1.25})^{b} = \frac{50.8}{8.7} So, 3.02/1.25 = 2.416 Also, 50.8/8.7 = 5.839 I know that the order for [B] has to be a whole number so like 2 ...

Merzia Subhan 1L

I believe the pseudo reactions are always going to be second order but one reactant's concentration is so high so when the one with the lesser concentration runs out, the big one barely changes so you can pretend that it didn't change and that its just a first order reaction with the reactant with t...

Merzia Subhan 1L

So would I completely disregard the fast one?

Merzia Subhan 1L

I was wondering why the rate law is the way that it is: Step 1: NO + Br2 --> NOBr2 (slow) Step 2: NOBr2 + NO --> NOBr + NOBr (fast) Write the rate law for the formation of NOBr implied by this mechanism. The answer in the back of the book is rate=k[NO][Br2] I understand that NOBr2 cancels and the ov...

Merzia Subhan 1L

I'm sure that if they use a different unit in the problem like hours or minutes, you could leave the k in that unit instead of in seconds

Merzia Subhan 1L

Since it ends up being 1, I wouldn't include it. It makes the equation look cluttered

Merzia Subhan 1L

Not sure why I'm not getting the right answer The half-life for the second-order reaction of a substance A is 50.5 s when [A]0 = 0.84 mol*L^-1. Calculate the time needed for the concentration of A to decrease to (a) one-sixteenth....of its original value I used the the half life 2nd order reaction t...

Merzia Subhan 1L

I also have this question. In the solutions manual for the anode, they put O2(g) and H+(aq) on the same side of the equation and made H2O but I thought that they would be on opposite sides of each other in the chemical equation. Can anyone explain why this is?

Merzia Subhan 1L

yeah it's just the sign is switched

Merzia Subhan 1L

I think it's because HBr(g) is larger than HF(g) so less compact and would therefore have a higher entropy. This may be wrong so if anyone has a different explanation, please share it.

Merzia Subhan 1L

this problem is similar to example 9.6 on page 329, you have to add up the entropies from the three reversible steps of heating the water to 100 deg C, phase changing, then bringing it back down to 85 degrees C. All these added will be the same entropy of vaporizing water at 85 deg C in one irrevers...

Merzia Subhan 1L

I was wondering about when to use Cp or Cv or whether to just use R. In 9.13, we have to assume ideal behavior: During the test of an internal combustion engine,3.00 L of nitrogen gas at 18.5 degrees Celsius was compressed suddenly and irreversibly to 0.500 L by driving in a piston. in the process, ...

Merzia Subhan 1L

A closed system can exchange energy with its surroundings but not matter. An isolated system can exchange neither matter nor energy with its surroundings.

Merzia Subhan 1L

I am having some trouble with 8.73(a). The question is "Use the bond enthalpies in Table 8.6 and 8.7 to estimate the reaction enthalpy for a) 3C2H2 --> C6H6" I looked up the molecular structure for both molecules. C2H2 has two carbons bonded with a triple bond and hydrogens attached to the...

Merzia Subhan 1L

You would use the formula delta U = q + w. q =deltaH. w = delta n*R*T. We assume it is at room temperature so you use 298K for T. n is 1 bc 3 moles of gas are produced and 2 moles of gas were there initially. The enthalpy is in kJ so don't forget to convert it into Joules when adding to the w bc the...

Merzia Subhan 1L

I also have a question about this. Why do both water and steam exist at 100 F? Doesn’t water evaporate at 100 F so wouldn’t it always turn into steam at 100F?

Merzia Subhan 1L

When volume is constant, Delta V is 0 because delta V is final volume - initial volume. The formula for work, stated above, would indicate that work is then 0. If pressure is constant, work could still be done, if volume changes as well

Merzia Subhan 1L

I would recommend sticking with Joules throughout the calculation of a problem and converting to kJ at the end because for specific heat, the values are in Joules and you might accidentally use kJ and mess up

Merzia Subhan 1L

For standard enthalpy of formation, I know it is the formation of 1 mole of a substance using its elements in their most stable form, so is it just the pure elements in their standard state, or can it ever be molecules of different elements combined in their standard state?

Merzia Subhan 1L

Enthalpy is the internal energy plus pressure and volume. Because enthalpy is total potential energy of a system, you have to take into account how external pressure and the volume affect the system.

Merzia Subhan 1L

Heat capacity is an extensive property because, as it is the heat required to raise the temperature of an object by 1 deg. C, it is dependent on the amount of the object--kJ/deg. C. To get it to be an intensive property, you would divide the heat capacity by the amount of substance present.This is c...

CHEMISTRY COMMUNITY

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Re: test 2

Pre equilibrium approach

Powers of Concentrations in Rate Law`

Re: 15.17

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: Post All Chemistry Jokes Here

Re: HW 15.19a

Re: HW 15.19a

Re: Pseudo-First-Order Reaction

Re: 15.51

15.51

Re: k

Re: zero order in rate laws

15.35

Re: 14.11

Re: Entropies of Condensation

Re: 9.27a

Re: 9.19

9.13

Re: Closed vs. Isolated

8.73 (a) [ENDORSED]

Re: 8.49

Re: Why does steam cause severe burns?

Re: Constant Volume vs Constant Pressure

Re: Heat Capacity

Re: Standard Reaction Enthalpy

Re: enthalpy

Re: Intensive vs. Extensive