Search found 50 matches
- Sat Mar 17, 2018 3:02 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Are you made of copper? Cause I Cu in a relationship with me.
- Sat Mar 17, 2018 2:57 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Avogadro says, "Hey ladies, take my number: 6.02 X 10^23"
- Sat Mar 17, 2018 2:54 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Helium walks into a bar. The bartender says "We do not serve noble gases here." He does not react.
- Fri Mar 09, 2018 9:48 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Anyone know any jokes about sodium?
Na.
Na.
- Fri Mar 09, 2018 9:46 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Chemistry jokes are sodium funny! I slapped my neon that one.
- Fri Mar 09, 2018 9:42 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Finding k [ENDORSED]
- Replies: 2
- Views: 729
Re: Finding k [ENDORSED]
Hi! We can find k by first finding the rate law, through comparing the change in concentrations versus the change in initial rates. After doing this, we will then find the order of each of the reactants and can write the rate law. since the rate law is initial rate = k[reactant 1][reactant2] and so ...
- Thu Mar 01, 2018 11:30 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
What fruit contains Barium and double Sodium? BaNaNa
- Thu Mar 01, 2018 11:28 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
What is a cation afraid of? A dogion
- Thu Mar 01, 2018 11:28 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
What do you call a tooth in a glass of water? A one molar solution
- Sat Feb 24, 2018 2:04 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
I wish I was adenine so I could get paired with U
- Sat Feb 24, 2018 2:03 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Hey baby, I've got my ion you!
- Sat Feb 24, 2018 2:01 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Forget Hydrogen, you're my number one element
- Fri Feb 16, 2018 6:13 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Are you a carbon sample? Cuz I want to date you.
- Fri Feb 16, 2018 6:11 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
Aha! The element of surprise.
- Fri Feb 16, 2018 6:07 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 2989225
Re: Post All Chemistry Jokes Here
All the good chemistry jokes Argon
- Sun Feb 11, 2018 10:09 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: About the unit for standard gibbs free energy of a reaction
- Replies: 2
- Views: 437
Re: About the unit for standard gibbs free energy of a reaction
Hi! From looking at some of the answers in the solution manual, I don't think you divide the Gibb's free energy by the coefficient of a molecule in a reaction.
- Sun Feb 11, 2018 10:05 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Vaporization of Water
- Replies: 1
- Views: 341
Re: Vaporization of Water
Hi! I think the Gibbs free energy is zero because the system is at equilibrium. The rate of reaction for liquid water turning into a gas is the same as the rate of reaction for gas turning into a liquid.
- Sun Feb 11, 2018 10:02 pm
- Forum: Van't Hoff Equation
- Topic: 11.116
- Replies: 2
- Views: 562
Re: 11.116
Hi. To add onto that, the explicit equation we can use is lnK = (delta G)/(-RT) or e^((delta G)/(-RT)). We can then find this answer and plug it into the Van't Hoff's Equation.
- Sun Feb 04, 2018 10:03 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Standard Entropy of Vaporization for Mercury
- Replies: 1
- Views: 392
Re: Standard Entropy of Vaporization for Mercury
Mercury has a high entropy of vaporization because there are metallic bonds between the mercury atoms, which make it more organized.
- Sun Feb 04, 2018 9:55 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Equations
- Replies: 2
- Views: 435
Re: Equations
Another useful way to memorize the different types of equations, is to see what factors ARE changing. For example, in the equation delta S = Cm/v*ln(T2/T1), we know that the volume is constant because it is specific heat for a constant volume. We know that temperature is changing, and since pressure...
- Sun Feb 04, 2018 9:46 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: 9.13 Equation Confusion
- Replies: 3
- Views: 478
9.13 Equation Confusion
Hi all. I was wondering why in question 9.13, the solution manual says to use the equation delta S = nRln (T2/T1). Isn't the equation for entropy change involving temperature nC(T2/T1)?
- Sat Jan 27, 2018 9:12 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Second Law Explanation
- Replies: 1
- Views: 388
Re: Second Law Explanation
Hi! The second law of thermodynamics states that total entropy can never decrease over time for an isolated system, and stays constant if the system is in equilibrium or in a reversible process. We use this law because it correlates with spontaneity, as spontaneity is a function of entropy.
- Sat Jan 27, 2018 9:05 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Question 8.31
- Replies: 7
- Views: 1013
Question 8.31
Hi! I was looking at question 8.31 in the textbook and I was confused because for calculating both Cpm and Cvm the book used the R value 8.31 J/mol*K but uses the temperature change in degrees Celsius. Why is there such a discrepancy? Thanks!
- Sat Jan 27, 2018 8:33 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Spontineity
- Replies: 5
- Views: 679
Spontineity
Hi all! I am still confused as to what the actual definition of spontaneity is, if we do not use the word "disorder." I know Dr. Lavelle went over it in class, but a little clarification would be much appreciated!
- Sun Jan 21, 2018 3:59 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Work Equation Derivation
- Replies: 1
- Views: 359
Work Equation Derivation
Hi! I was just wondering if we will be required to know the derivation for the work equation, w = (-p)*(delta v), involving the integral for the exam.
- Sun Jan 21, 2018 3:50 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: ∆nRT in Reactions with no ∆n
- Replies: 2
- Views: 510
Re: ∆nRT in Reactions with no ∆n
Hi! I believe that is true, that no work is being done, because if there is no increase or decrease in the net amount of moles of gas being produced, the volume of the container will not need to change and thus no work is being done.
- Sun Jan 21, 2018 3:47 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Energies
- Replies: 1
- Views: 398
Re: Bond Energies
Hi! When elements form bonds they are in a more stable state and thus have a lower potential energy. Thus, when we form bonds energy is released as atoms move to this lower potential energy. This value is negative, as energy is being released (energy of products (atoms in a bond) < energy of reactan...
- Sun Jan 14, 2018 8:24 pm
- Forum: Phase Changes & Related Calculations
- Topic: Heating Curve Question
- Replies: 2
- Views: 413
Re: Heating Curve Question
Hi Grace, I think higher heat capacities have less steep slopes because specific heat means the amount of heat required to raise the temperature of 1g of the substance by 1 degree Celcius. Therefore, a substance with higher heat capacity requires more heat to raise the temperature, and therefore the...
- Sun Jan 14, 2018 8:17 pm
- Forum: Phase Changes & Related Calculations
- Topic: Another 8.41 Question
- Replies: 3
- Views: 549
Re: Another 8.41 Question
Hi Grace, Since q simply represents the amount of heat transferred to a system, q ice = -q water. The ice, the system, is gaining heat while the water, the surrounding, is loosing the same amount of heat. Therefore, when we substitute q for m*c*(t final - t initial) we put a negative in front of the...
- Sun Jan 14, 2018 8:09 pm
- Forum: Phase Changes & Related Calculations
- Topic: kJ vs. kJ/mol
- Replies: 3
- Views: 1517
Re: kJ vs. kJ/mol
Hi Rucha, We use KJ/mole usually when we want to know the enthalpy of formation for a certain molecule. However, when we are finding the change in enthalpy for an overall reaction we only use KJ because we are not finding the change for any molecule in particular, so we cannot use KJ/mole. Hope this...
- Fri Dec 08, 2017 10:27 am
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: 12.49
- Replies: 1
- Views: 374
Re: 12.49
Hi! From my understanding, either pKb or Kb are acceptable for understanding how strong a base is. In table 21.1 we se HBrO has pKa = 8.69. We know that since pKb = 14 - pKa, we find that pKb for BrO- is 5.31. Since the lower the Kb value the stronger the base, 5.31 < 5.79, we can conclude that BrO-...
- Fri Dec 08, 2017 10:21 am
- Forum: Amphoteric Compounds
- Topic: Determining Amphoteric Compounds
- Replies: 3
- Views: 716
Re: Determining Amphoteric Compounds
HI! In addition, it may be helpful to know a couple of the amphoteric oxides so they are easier to recognize. The textbook gives the example of BeO, Al2O3, Ga2O3, GeO2, As2O3, In2O3, SnO and SnO2, Sb2O3, PbO and PbO2, and finally Bi2O3. Hope that helps :)
- Wed Nov 29, 2017 8:15 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Change in Equilibrium for Aqueous Solutions
- Replies: 2
- Views: 479
Change in Equilibrium for Aqueous Solutions
Hi! In equilibrium, if there is compression the reaction will favor the side which has the least moles of gas. Does this also apply to aqueous solutions? If not, how do changes in pressure affect changes in equilibrium for aqueous solutions?
- Wed Nov 29, 2017 8:07 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: ICE box
- Replies: 3
- Views: 728
Re: ICE box
Hi, although most of the times reactants are -x and products are +x, this is only true when we know that Q < K and thus favors products. If we find that Q > K, then reactants are favored, and the reactants are +x while the products are -x.
- Wed Nov 29, 2017 8:04 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Problem 11.45
- Replies: 1
- Views: 392
Re: Problem 11.45
Hi! I am going to explain how to do part a, which is very similar to the other two parts. First, we must construct the equilibrium reaction equation. Cl2 (g) <-> 2Cl (g) Now, since the problem says there is 2.0 mmol of Cl2 and a 2.0L vessel, we can calculate the molarity of the Cl2 gas, which is fou...
- Wed Nov 29, 2017 7:51 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 11.53 sig figs
- Replies: 1
- Views: 311
Re: 11.53 sig figs
Hi! For question 53, when we use the ICE box to find the equilibrium concentrations for H2, I2, and 2HI, we use subtraction. For finding the equilibrium concentration of H2, we take 0.133 M and subtract 0.800 M. The result is we have 0.053 M of H2, which is only 2 significant figures. When we calcul...
- Sat Nov 18, 2017 8:22 pm
- Forum: Biological Examples
- Topic: Other Biological Examples
- Replies: 5
- Views: 963
Re: Other Biological Examples
Hi! I found this very interesting article about the uses and importance of copper in the body. Hope you find it interesting too!
http://www.drlwilson.com/articles/coppe ... ndrome.htm
http://www.drlwilson.com/articles/coppe ... ndrome.htm
- Sat Nov 18, 2017 8:13 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Chelating Complexes
- Replies: 5
- Views: 617
Chelating Complexes
Hi! I was just wondering how exactly we determine if a compound can form chelating complexes. I was having some difficulty with question 17.35, and some guidance would be greatly appreciated!
- Sat Nov 11, 2017 7:15 pm
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: Polar vs nonpolar vs ionic
- Replies: 11
- Views: 28267
Re: Polar vs nonpolar vs ionic
Hi Jason. Another rule of thumb is if the electronegativity difference between the two atoms is less than 0.5, than generally we assume the molecule is nonpolar. If the difference is greater than 0.5 but less than 1.5, we can assume the molecule is polar. Hope this helps!
- Sat Nov 11, 2017 7:11 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Polarity in Molecular Shape
- Replies: 1
- Views: 189
Polarity in Molecular Shape
Hi! I was just wondering if a molecule's polarity affects its VSEPR shape. Since the electrons are being pulled unequally, will that affect the bond angles in the shape?
- Wed Nov 01, 2017 10:12 am
- Forum: Ionic & Covalent Bonds
- Topic: Ionic vs. Covalent Bonds
- Replies: 3
- Views: 784
Ionic vs. Covalent Bonds
Hi! I was just wondering how we can predict an ionic or covalent bond will form. Is it typically that a nonmetal and metal form an ionic bond, and two nonmetals form covalent bonds? Also with regards to polarity, how do we determine precisely if a molecule is polar or non polar. I remember in high s...
- Wed Nov 01, 2017 10:05 am
- Forum: Coordinate Covalent Bonds
- Topic: Coordinate Covalent Bond Definition
- Replies: 3
- Views: 2018
Coordinate Covalent Bond Definition
Hi! I was still a little unclear as to what coordinate covalent bonds are exactly. From what I understand, when a central atom of a molecule does not have a full octet, another atom can bond to this central atom and share electrons. The other atom which attaches to the central atom forms a coordinat...
- Wed Oct 25, 2017 11:41 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: s and d valence electrons
- Replies: 1
- Views: 285
s and d valence electrons
Hi! I was just wondering if when we have a transition metal, do the valence electrons come from the d block or the s block? Also, does the d orbital have lower energy than the s orbital? For example, in Iron, does 4s2 or 3d6 have higher energy? Thank you!
- Wed Oct 25, 2017 11:20 pm
- Forum: Ionic & Covalent Bonds
- Topic: Inert Pair Effect [ENDORSED]
- Replies: 1
- Views: 909
Inert Pair Effect [ENDORSED]
Could someone please explain the inert pair effect and how exactly that relates to the concept of variable valence? Thank you!
- Wed Oct 18, 2017 10:36 pm
- Forum: Trends in The Periodic Table
- Topic: Which is larger O - or S 2- ? [ENDORSED]
- Replies: 3
- Views: 2572
Re: Which is larger O - or S 2- ? [ENDORSED]
S^-2 is also larger because it has more electrons in its outer shell, which causes repulsion. This is called the shielding effect, and leads to S^-2 having a greater atomic radius than O^-
- Wed Oct 18, 2017 10:27 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Schrodinger's Equation gives shape of orbitals?
- Replies: 1
- Views: 498
Re: Schrodinger's Equation gives shape of orbitals?
Hi! I believe the atomic orbitals are all various solutions to Schrodinger's equation. The solutions are called wave functions, synonymous to atomic orbitals, to remind us that electrons have wave like properties.
- Tue Oct 10, 2017 10:01 pm
- Forum: Photoelectric Effect
- Topic: Chapter 1, Question 1.23
- Replies: 3
- Views: 423
Re: Chapter 1, Question 1.23
In addition to converting keV to Joules, another way to start this problem is to use the equation:
wavelength = (hc)/E
h and c are both constants, so we only need to plug in our value for energy for Joules to start the problem. Hope this helps!
wavelength = (hc)/E
h and c are both constants, so we only need to plug in our value for energy for Joules to start the problem. Hope this helps!
- Tue Oct 10, 2017 9:53 pm
- Forum: Properties of Light
- Topic: Chapter 1 Question 9
- Replies: 4
- Views: 652
Re: Chapter 1 Question 9
Hi! Something to also remember for solving this problem is that Hertz can be converted to seconds^-1. This way, when you are solving the problem the units will cancel and solving the problem will be easier to follow. Hope this helps!
- Thu Oct 05, 2017 7:25 pm
- Forum: Limiting Reactant Calculations
- Topic: M.9
- Replies: 4
- Views: 727
Re: M.9
To add on to that response, I also think it is important to remember which precipitate is going to form at the end of the reaction. You only include the ions which make up the precipitate as the reactants on the left side, and only include the precipitate on the right side. While it is possible to a...
- Thu Oct 05, 2017 7:02 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: G25
- Replies: 4
- Views: 721
Re: G25
Hi! I believe in Ramya's explanation of her way to solve the problem, she forgot to mention that she found the amount of moles in 10 mL of the solution, instead of 4.9 * 10^-7 molecules per Liter. I solved it in this fashion and got the same answer! Hope this helps.