Search found 50 matches
- Sun Mar 18, 2018 2:13 pm
- Forum: *Carboxylic Acids
- Topic: Functional Groups
- Replies: 5
- Views: 2484
Re: Functional Groups
My TA said we will probably have to identify them in complex molecules but not have to draw them individually.
- Sun Mar 18, 2018 2:12 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Homework 14.15c : KOH in cell diagram
- Replies: 2
- Views: 478
Re: Homework 14.15c : KOH in cell diagram
Yes you can use just OH because K is not involved in the redox reactions.
- Sun Mar 18, 2018 2:10 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Adiabatic System
- Replies: 5
- Views: 856
Re: Adiabatic System
Doesn't necessarily mean it is always reversible, but it will always be transferred as work because q=0.
- Sun Mar 18, 2018 2:08 pm
- Forum: General Rate Laws
- Topic: The Collision Model and Activated Complex Model
- Replies: 3
- Views: 765
Re: The Collision Model and Activated Complex Model
Collision theory has to collide at same time, same orientation and enough energy to overcome the activation energy.
- Sun Mar 18, 2018 2:07 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Phase changes and entropy
- Replies: 5
- Views: 835
Re: Phase changes and entropy
Delta H is equal to q at a constant pressure.
- Sun Mar 18, 2018 2:03 pm
- Forum: *Identifying Primary, Secondary, Tertiary, Quaternary Carbons, Hydrogens, Nitrogens
- Topic: Final
- Replies: 3
- Views: 1475
Re: Final
I would assume both just complex because you'd have to understand what the functional groups are
- Sun Mar 18, 2018 2:01 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Putting an Ice cube into a glass of water
- Replies: 4
- Views: 1356
Re: Putting an Ice cube into a glass of water
You're right--you do need delta H of fusion because heat is lost from ice to water.
- Sun Mar 18, 2018 1:58 pm
- Forum: Second Order Reactions
- Topic: Derivations
- Replies: 4
- Views: 988
Re: Derivations
It is postitive because y=mx+b so the slope is positive.
- Sun Mar 18, 2018 1:58 pm
- Forum: Second Order Reactions
- Topic: Derivations
- Replies: 4
- Views: 988
Re: Derivations
For the first question, in the integrated rate law, kt is positive, so that is why we use pos slope.
- Sun Mar 18, 2018 1:49 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Kinetically controlled reactions
- Replies: 2
- Views: 466
Re: Kinetically controlled reactions
Yes Alexander is right. Even though a reaction might be thermodynamically favorable, it still has to overcome an activation energy.
- Sun Mar 18, 2018 1:46 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Cp and Cv
- Replies: 5
- Views: 817
Re: Cp and Cv
Cp and Cv are usually just used for different conditions, either constant pressure or constant volume. I'm not sure when u would switch.
- Sun Mar 18, 2018 1:44 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: steady state vs pre equilibrium
- Replies: 3
- Views: 580
Re: steady state vs pre equilibrium
Pre equilibrium is easy to use but is not as flexible at steady state approximations which is usually used for complex mechanisms.
- Sun Mar 18, 2018 1:42 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Maximum Work
- Replies: 3
- Views: 628
Re: Maximum Work
It is a part of the laws of thermodynamics.
- Sun Mar 18, 2018 1:40 pm
- Forum: Phase Changes & Related Calculations
- Topic: carbon
- Replies: 4
- Views: 607
Re: carbon
You have to sublimize Carbon to the gaseous state because deltaH has to have them all as gasses.
- Fri Mar 16, 2018 10:09 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Strength of Reducing Agents and Strength of Oxidizing Agents
- Replies: 3
- Views: 927
Re: Strength of Reducing Agents and Strength of Oxidizing Agents
OIL RIG Oxidation is losing (electrons) and Reduction is gaining (electrons)
- Fri Mar 16, 2018 10:08 pm
- Forum: *Nucleophiles
- Topic: nucleophile?
- Replies: 4
- Views: 1427
Re: nucleophile?
The molecule that is substituting the leaving group.
- Fri Mar 16, 2018 10:08 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: 15.109
- Replies: 2
- Views: 404
Re: 15.109
In order to subtract the 1/T and 1/T' you have to have a common denominator. so you multiply both by the others denominator.
- Fri Mar 16, 2018 9:48 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.91
- Replies: 1
- Views: 338
Re: 14.91
The anode is more negative so it makes sense that it is receiving negative electrolytes.
- Fri Mar 16, 2018 9:44 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.99
- Replies: 1
- Views: 330
Re: 8.99
This is the idea that in a perfect system q(metal)+q(water)=0 so making overall q(water) negative, will be equal to q(metal).
- Fri Mar 16, 2018 9:33 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: 8.51b
- Replies: 1
- Views: 320
Re: 8.51b
Yes it is because it is already in kJ/mol
- Fri Mar 16, 2018 9:21 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Work and derivations
- Replies: 2
- Views: 480
Re: Work and derivations
For calculating delta n (change in moles) we look at gas phase molecules in the chem equation because those are the only ones that will affect work done. In this problem, were given 6mol H20 and 6 mol CO2 in gas phase on products, totaling 12 moles, and 6 mol O2 on gas phase on the reactants (we ign...
- Fri Mar 16, 2018 9:17 pm
- Forum: Balancing Redox Reactions
- Topic: determining cathode from anode
- Replies: 11
- Views: 1836
Re: determining cathode from anode
You would look at the standard cell potentials. The most positive is the cathode. Also, cathode-(anode) should be positive.
- Fri Mar 16, 2018 9:13 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Degeneracy
- Replies: 1
- Views: 371
Re: Degeneracy
Number of orientations raised to the number of molecules. This tells you all of the possible orientations the molecules can have.
- Fri Mar 16, 2018 9:11 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: 15.61
- Replies: 2
- Views: 341
Re: 15.61
We didn't go over this derivation and also are not responsible for knowing it.
- Fri Mar 16, 2018 9:10 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: delta S for reversible and irreversible reactions
- Replies: 1
- Views: 440
Re: delta S for reversible and irreversible reactions
When it is reversible, the system is at equilibrium so it =0. When deltaS >0 the reaction is spontaneous, which is a part of the second law of thermodynamics
- Fri Mar 16, 2018 9:07 pm
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: 14.119
- Replies: 2
- Views: 756
Re: 14.119
The half reactions only include the elements that are being oxidized or reduced. The net ionic equation will include all elements (and spectator ions) to balance the two sides.
- Fri Mar 16, 2018 9:03 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: S and delta S
- Replies: 4
- Views: 591
Re: S and delta S
S is the residual entropy while delta S is the change in entropy.
- Fri Mar 16, 2018 9:02 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: electrode surface area and voltage
- Replies: 1
- Views: 1414
Re: electrode surface area and voltage
Cell potential only depends on concentration so electrode surface area doesn't affect it.
- Sun Jan 14, 2018 5:26 pm
- Forum: Phase Changes & Related Calculations
- Topic: 8.41
- Replies: 4
- Views: 432
Re: 8.41
You have to solve by melting the ice, and then by bringing the liquid to the final temperature (which is endothermic/requiring heat). Heat absorbed by ice cube = (50g/18.02g*mol )(6.01*10^3 J*mol^-1) + 50g*4.184J*C^-1 *g^-1 * (Final Temperature-0 degrees C) Heat released by liquid water = (400g)(4.1...
- Sun Jan 14, 2018 5:15 pm
- Forum: Phase Changes & Related Calculations
- Topic: 8.45 part C
- Replies: 2
- Views: 316
Re: 8.45 part C
I used a ratio so I set up 358.8kj/4 molCS2 = 415kj/x moles and then I solved for x.
- Sun Dec 10, 2017 12:45 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Percent Ionization Formula
- Replies: 1
- Views: 732
Re: Percent Ionization Formula
The amount ionized(starting-ending)/starting amount *100 would be the percentage
- Sun Dec 10, 2017 12:39 am
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Effect of water
- Replies: 2
- Views: 343
Re: Effect of water
It depends on if the reactants or products are aqueous. If they were, adding water would change the molarity and thus the reaction and how it proceeds.
- Sun Dec 10, 2017 12:38 am
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Test 4 #6
- Replies: 2
- Views: 409
Re: Test 4 #6
For my test 4 #6, There were only 3 values? A + B <---> 2C. If you are asking about the 2 on the 2C, it would come into play for the change line of the ICE table (and be 2x instead of x).
- Sun Dec 10, 2017 12:36 am
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Adding Water
- Replies: 2
- Views: 315
Re: Adding Water
^^^ Yes I also believe this to be right. The equation would specify by including the physical properties of the reactants and products in the equation. If any were aqueous then you would know to watch out for that
- Sun Dec 10, 2017 12:34 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Compression effect on a system
- Replies: 2
- Views: 390
Re: Compression effect on a system
Just to expand, the equation will shift towards the side with less moles of gas in an attempt to reduce the pressure and return to equilibrium
- Sun Dec 10, 2017 12:33 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Significant figures in calculations
- Replies: 1
- Views: 359
Re: Significant figures in calculations
Yes it would be the same number of SF as the K value
- Sun Dec 10, 2017 12:32 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Changing Stoichiometric Coefficients
- Replies: 2
- Views: 1590
Re: Changing Stoichiometric Coefficients
The coefficients are superscripts for equilibrium expressions so when it said half coefficients, I put the half in the superscript of the x. If it said double all coefficients, you would have x^2
- Wed Nov 15, 2017 1:13 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Bond Order
- Replies: 5
- Views: 640
Re: Bond Order
The .5 in bond order indicates resonance. 1.5 bond order is going to be the average of single and double bonds in a resonance hybrid
- Wed Nov 15, 2017 1:09 pm
- Forum: Bond Lengths & Energies
- Topic: Factors that control bond length
- Replies: 3
- Views: 3621
Re: Factors that control bond length
For covalent, the difference in electro negativity will determine if the bond is either polar or non polar. And yes the increasing number of bonds decreases the bond length. Higher bond order (number of bonds) indicated more attraction between electrons and the atoms will be held closer together
- Wed Nov 15, 2017 1:04 pm
- Forum: Electronegativity
- Topic: Isoelectronic [ENDORSED]
- Replies: 11
- Views: 1452
Re: Isoelectronic [ENDORSED]
Also means they have the same electronic structure and will have similar chemical properties
- Wed Nov 15, 2017 1:02 pm
- Forum: Octet Exceptions
- Topic: Why do octets expand?
- Replies: 4
- Views: 560
Why do octets expand?
I have memorized that there can be octet expansions for elements in the 3rd period and beyond but I don't think I really understand why that is? I usually remember things better when I understand everything versus just memorizing so can someone please explain? Thanks!
- Wed Nov 15, 2017 12:57 pm
- Forum: Hybridization
- Topic: Hybridization beyond d orb
- Replies: 1
- Views: 176
Hybridization beyond d orb
We have mostly just looked at the hybridizations of elements with a maximum of d orbitals, but what would the hybridization for an atom with say an f orbital look like?
- Wed Nov 15, 2017 12:53 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron Configuration of Gallium
- Replies: 3
- Views: 3353
Re: Electron Configuration of Gallium
Yes, even though you fill the 4s before the 3d orbital, you should write it in order of ascending energy, which would be 3d then 4s. This also makes it easier to see what electrons will be ionized (from the highest energy orbital)
- Wed Nov 15, 2017 12:50 pm
- Forum: Lewis Structures
- Topic: Expanded Valence Shell
- Replies: 2
- Views: 287
Re: Expanded Valence Shell
I believe that in general, not more that 16 electrons will be involved
- Wed Nov 15, 2017 12:46 pm
- Forum: Sigma & Pi Bonds
- Topic: # of sigma and pi bonds [ENDORSED]
- Replies: 4
- Views: 570
Re: # of sigma and pi bonds [ENDORSED]
And in each double/triple bond, the first bond will be a sigma bond, and then the successive bond(s) will be pi bonds
- Sun Oct 29, 2017 8:27 pm
- Forum: Properties of Electrons
- Topic: Ending Frequency [ENDORSED]
- Replies: 3
- Views: 594
Re: Ending Frequency [ENDORSED]
If you are talking about the Bohr frequency model (just because it includes E and results in frequency) then you are going to use the delta E/change in energy
- Sun Oct 29, 2017 8:24 pm
- Forum: Properties of Electrons
- Topic: Energy level question [ENDORSED]
- Replies: 2
- Views: 458
Energy level question [ENDORSED]
Why is it that n=1 is the lowest energy level?
- Tue Oct 10, 2017 1:03 pm
- Forum: Properties of Light
- Topic: chapter 1 question 27
- Replies: 2
- Views: 279
Re: chapter 1 question 27
Okay so you were right to want to use E=h·ν but you rearrange it because v ("nu" or frequency)=c/λ so we can use E=hc/λ =(6.626·10^-34 Js)·( 2.997·10^8m/s)/ (470·10-9 m)=4.225*10^-19 J. The lamp emits 32J/s so in 2 seconds, the lamp emits (32*2=) 64J. So we use E(per mol of photons)=N(phot...
- Tue Oct 10, 2017 12:43 pm
- Forum: Properties of Light
- Topic: Photoelectric Effect Post-Module Assessment (28B) [ENDORSED]
- Replies: 1
- Views: 430
Re: Photoelectric Effect Post-Module Assessment (28B) [ENDORSED]
The work function is given to us in kJ/mol but we want it per electron so we use Avogadro's constant. First I converted kJ to J by multiplying my 10^3 because that's what's easiest for me in terms of conversions. (150*10^3 J/mol) x (1 mol/6.02*10^23)...moles cancel out so we are left with 2.50*10^-1...
- Tue Oct 03, 2017 6:23 pm
- Forum: Significant Figures
- Topic: Sig Figs in 0.0380 [ENDORSED]
- Replies: 5
- Views: 963
Sig Figs in 0.0380 [ENDORSED]
In class, Lavelle said there were 3 sig figs and I was just confused on which zero was included in the 3 SF? Thanks!