Search found 63 matches
- Fri Mar 16, 2018 11:55 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Cell Potential sign
- Replies: 4
- Views: 662
Cell Potential sign
When you reverse standard cell potentials, do the signs change?
- Fri Mar 16, 2018 4:29 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: What has greater residual entropy at 0K?
- Replies: 5
- Views: 1098
What has greater residual entropy at 0K?
The question I am confused about is what has greater residual entropy at 0K: NO or BF3?
For this question, do we look at the masses, or do we draw out the Lewis structures to figure out the answers?
For this question, do we look at the masses, or do we draw out the Lewis structures to figure out the answers?
- Fri Mar 16, 2018 4:27 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Knowing what has a higher heat capacity
- Replies: 2
- Views: 550
Knowing what has a higher heat capacity
Without doing any calculations, how do we know that ethane has a higher heat capacity than ethene? This was one of the questions in practice problems, but I am not sure how we can automatically come to that conclusion.
- Mon Mar 12, 2018 1:42 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: 9. 35 and Cv vaues
- Replies: 1
- Views: 354
9. 35 and Cv vaues
Can someone explain the different Cv values for each of the gases in the solution manual? Because each process is isochoric, I thought originally that the Cv would always equal 3/2R in the containers, but this is incorrect. Can someone explain the reasoning behind why the Cv values have to be differ...
- Sat Mar 10, 2018 1:35 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Activated Complexes [ENDORSED]
- Replies: 1
- Views: 316
Activated Complexes [ENDORSED]
How do you draw a proposed activated complex for a reaction? For example, in 15.85, the third part of the question asks us to do this.
Can someone explain the process of drawing out the activated complex?
Thank you
Can someone explain the process of drawing out the activated complex?
Thank you
- Fri Mar 09, 2018 12:40 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Arrhenius Equation [ENDORSED]
- Replies: 7
- Views: 843
Re: Arrhenius Equation [ENDORSED]
To be add on for when we use the Arrhenius Equation, it is clear we need to use it if we are working with the Boltzmann distribution e^-Ea/R, which gives the fractions of collisions wth energy,Ea, or greater temp at T. In this case, A would be the frequency factor or pre-exponential factor (includes...
- Fri Mar 09, 2018 12:30 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: 15.9 part c
- Replies: 3
- Views: 627
Re: 15.9 part c
Because a rate constant is "constant" then it will not change, no matter what experiment you pick. This is done with two different experiments because sometimes there may have been an error the first time with calculating k.
- Fri Mar 09, 2018 12:19 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Effect of Activation Energy on a Reaction [ENDORSED]
- Replies: 2
- Views: 322
Effect of Activation Energy on a Reaction [ENDORSED]
If a reaction has a low activation energy, does it change much with temperature? Can someone explain the logic behind this question and why the reaction barriers are easier to overcome?
- Sat Mar 03, 2018 3:35 pm
- Forum: General Rate Laws
- Topic: Test 3
- Replies: 2
- Views: 421
Test 3
For test 3, do we need to know what Lavelle went over in Lecture on Friday before he taught about reaction mechanisms? This would include material like the pseudo-rate law (1st and 2nd order) and the equation k=k'/[B]o^m[C]o^l. These equations/concepts are not in the reading for 15.1-15.6 in the boo...
- Thu Mar 01, 2018 11:18 pm
- Forum: First Order Reactions
- Topic: 15.23 [ENDORSED]
- Replies: 1
- Views: 335
15.23 [ENDORSED]
For 15.23, I am confused on why we use the equation ln[A]o/[A]t=kt, because I thought that the equation for first order half life reaction is used when it is written as: [A]t-[A]0=-kt. Can someone explain when we have to use this equation in our homework versus the other equation in our homework? I ...
- Thu Mar 01, 2018 8:44 pm
- Forum: General Rate Laws
- Topic: 15.19 [ENDORSED]
- Replies: 2
- Views: 380
Re: 15.19 [ENDORSED]
to calculate the order of b, use experiments 2 and 3. increasing the concentration of B by the ratio 3.02/1.25 increases the rates by (3.02/1.25)^2, and this makes B second order.
- Wed Feb 28, 2018 10:05 pm
- Forum: Second Order Reactions
- Topic: 15.39
- Replies: 2
- Views: 412
15.39
Can someone explain why in the solutions manual 0.055 mol A/L is equal to 0.37 [A]o? I am confused on how this conclusion came through, but I understand where the 0.055 value came from.
- Sun Feb 25, 2018 8:55 pm
- Forum: General Rate Laws
- Topic: 15.3
- Replies: 2
- Views: 421
15.3
What does it mean when the question asks you to find the unique rate of the reaction? Can someone explain the process to figuring it out? Thanks!
- Thu Feb 22, 2018 8:24 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Creating a Cell Diagram with solids
- Replies: 2
- Views: 380
Creating a Cell Diagram with solids
When do we use platinum in our cell diagrams, and is there another solid that we can choose from for our diagram? Can someone list the rules/cases in which we include platinum (or other solids) in our diagrams?
- Thu Feb 22, 2018 8:20 pm
- Forum: Balancing Redox Reactions
- Topic: Reaction E [ENDORSED]
- Replies: 5
- Views: 669
Re: Reaction E [ENDORSED]
This is because the E potential does not change. Its sign never changes, because potential doesn't change even if the reaction is reversed.
- Thu Feb 22, 2018 8:12 pm
- Forum: Balancing Redox Reactions
- Topic: Does order matter?
- Replies: 7
- Views: 907
Re: Does order matter?
I do not think order matters as long as your reactants and products are on their respective sides.
- Sat Feb 17, 2018 8:17 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Electrodes in Cell Diagrams
- Replies: 2
- Views: 312
Electrodes in Cell Diagrams
Are there more rules in regards to when we use platinum in our cell diagrams? Other than the fact that we use it when the reaction has no conducting solids. Can someone list the rules/cases in which we include platinum in our diagrams?
- Fri Feb 16, 2018 2:38 am
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: S=klnW
- Replies: 7
- Views: 3468
Re: S=klnW
you use S=klnW when you are trying to find the entropy when dealing with the fact that molecules can be rearranged in various ways. You will use the Boltzman's constant and then multiply that by the degeneracy, which show the multiple states the molecules can occupy/be in. This gives you the total d...
- Wed Feb 14, 2018 11:19 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Hess's Law
- Replies: 5
- Views: 686
Hess's Law
What is the property of enthalpy that allows us to use Hess's Law?
- Wed Feb 14, 2018 10:20 pm
- Forum: Van't Hoff Equation
- Topic: Van't Hoff
- Replies: 9
- Views: 1132
Re: Van't Hoff
From the notes that I took, you can use Van't Hoff when you have two different temperatures and you are trying to calculate the K, accounting for the face that you need to subtract temperatures to find the deltaT.
- Fri Feb 09, 2018 1:07 am
- Forum: Balancing Redox Reactions
- Topic: Standard Reduction Potential
- Replies: 3
- Views: 461
Re: Standard Reduction Potential
You can balance the half reactions like you would normally when balancing equations, and you can check your answer by making sure the charges on either side of the reaction are the same
- Fri Feb 09, 2018 1:05 am
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Different Gibbs Free Energy values
- Replies: 1
- Views: 287
Re: Different Gibbs Free Energy values
in G(products)-G(reactants) you are basing the values for G based on standard calculated values, not accounting for non-ideal temperatures and pressures. However, the equation deltaG=deltaH-TdeltaS accounts for the free energy with varying conditions.
- Fri Feb 09, 2018 1:02 am
- Forum: Balancing Redox Reactions
- Topic: Anode vs cathode
- Replies: 6
- Views: 649
Re: Anode vs cathode
Yes, that is true. The anode is always the oxidation half reaction and the cathode corresponds to the reduction half reaction.
- Fri Feb 02, 2018 2:05 am
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Molar Entropy
- Replies: 2
- Views: 462
Re: Molar Entropy
Another questioned was asked about molar entropy, and I found this helpful: the word "molar" is clear to show that we need Avogadro's number in our equation, because it is the number of units in one mole of any substance. And because the molar entropy is the entropy of one mole of a substa...
- Fri Feb 02, 2018 1:54 am
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: 9.43
- Replies: 3
- Views: 415
Re: 9.43
I believe deltaS is referring to the reaction happening, so it would be delta S of the reaction. I guess if the "universe" being referred to is the entire system in our reaction of hot and cold water, where you are adding hot and cold water's entropies, then you would be finding the deltaS...
- Tue Jan 30, 2018 10:23 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Comparing 9.1 and 9.3
- Replies: 3
- Views: 399
Re: Comparing 9.1 and 9.3
In question 1, the entropy is referring to that of the surroundings, which means that the rate of entropy generation will be a negative number. But in question 3, the entropy we are calculating is referring to the system's, and when we talk about deltaS of the system, the deltaS is positive
- Thu Jan 25, 2018 1:23 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Combustion Equations [ENDORSED]
- Replies: 4
- Views: 455
Re: Combustion Equations [ENDORSED]
In combustion, the product water would always be liquid. We know this because the phase of water is based on the temperature by which the reaction is occurring. Reactions occurring at the standard room temperature, 25 degrees C, will produce water as a liquid. This is the case for the combustion rea...
- Thu Jan 25, 2018 1:17 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: constant volume vs constant pressure
- Replies: 3
- Views: 438
Re: constant volume vs constant pressure
Yes, you would because there are different equations for constant pressure or constant volume. If the case were constant pressure you would have to know that deltaH=Qp, so internal energy for example would be deltaU=deltaH. If the case were constant volume, you would use Q=deltaH-PdeltaV. These equa...
- Thu Jan 25, 2018 12:31 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: 8.65
- Replies: 3
- Views: 441
Re: 8.65
When using Hess's Law in this example, you actually don't need to end up with N2 in the final equation. You just need to cancel out the two NO2's because those are present in both equations. In the solutions manual, I believe they just show you that N2+5/2O2 gives you N2O5 just to show you a model o...
- Wed Jan 17, 2018 3:12 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Calculating Reaction Enthalpies with Bond Enthalpies
- Replies: 2
- Views: 261
Re: Calculating Reaction Enthalpies with Bond Enthalpies
another helpful tip that i found was that in the book, like in number 67, you are asked to "estimate" the enthalpy of formation. I think that the key word "estimate" is a hint that you can use the method of bond enthalpies. If the question asks you for a more specific value and n...
- Wed Jan 17, 2018 3:09 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Hw 8.67 part b
- Replies: 2
- Views: 321
Re: Hw 8.67 part b
This number comes from the fact that standard heat of atomization is the amount of heat energy required to produce one mole of gaseous atoms from the element in its standard state. because it is a single carbon and not part of the bond, we use the value for atomizing Carbon, which is a set value giv...
- Wed Jan 17, 2018 3:05 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.67 moving from a gas to a liquid
- Replies: 1
- Views: 213
8.67 moving from a gas to a liquid
in the problems in 8.67, do we subtract the change in enthalpy based on the physical change of vaporization because we are moving from gas to a liquid product? i know that vaporization is moving from liquid to vapor, and that reaction needs heat so it is endothermic for example, if the problem had t...
- Thu Jan 11, 2018 9:30 pm
- Forum: Phase Changes & Related Calculations
- Topic: Superheating
- Replies: 6
- Views: 3328
Re: Superheating
When a gas or vapor is above its boiling point, it is said to be superheated. Supercooling is the melting of a solid above its freezing point which is very difficult because most times, the solid will almost always melt at the same temperature for a given pressure.
- Thu Jan 11, 2018 9:25 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.31 b)
- Replies: 2
- Views: 289
Re: 8.31 b)
the equation for C at constant volume for a monatomic gas is C=3/2R, and R is the set value for this gas, 8.3145 J*K^-1*mol^-1. By multiplying this value by 3/2, you get the value for C as 12.5 *K^-1*mol^-1.
- Thu Jan 11, 2018 9:19 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.51
- Replies: 3
- Views: 223
Re: 8.51
you can get the enthalipies for CO2 and H20 by looking at appendix 2A, they are given as -241.82 kJ/mol for water and -393.15 kJ/mol for CO2. These are the delta Hs for these specific compounds, but others are also listed in that section of the chem book. After getting these delta H values, you can ...
- Sat Dec 09, 2017 4:29 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Chemical Equilibrium in Test 4 #6
- Replies: 3
- Views: 579
Re: Chemical Equilibrium in Test 4 #6
How do u know the reaction is the reverse reaction though?
- Sat Dec 09, 2017 4:02 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Chemical Equilibrium in Test 4 #6
- Replies: 3
- Views: 579
Chemical Equilibrium in Test 4 #6
In this question, My answer for x was -1.5 after doing the ice table and solving for x. However, x is negative and I was wondering what you need to do in this question to get a positive number?
- Fri Dec 08, 2017 9:13 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: Acid Rain [ENDORSED]
- Replies: 1
- Views: 399
Acid Rain [ENDORSED]
Can someone explain what we are supposed to know about acid rain? Do we need to know what acids cause it, like H2SO4, H2CO3 and NO?
- Thu Dec 07, 2017 4:05 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: the effect of expansion on a system
- Replies: 1
- Views: 311
the effect of expansion on a system
What happens when expansion increases on a system at equilibrium? Would the reaction shift right or left? I am confused as to how to understand how the system would respond to this change.
- Wed Dec 06, 2017 9:40 pm
- Forum: Ionic & Covalent Bonds
- Topic: polarizing power
- Replies: 1
- Views: 328
Re: polarizing power
polarizing power has to do with describing cations and their ability to pull in electrons from ions (it is the electron pulling power of the ion). Smaller cations with a high charge are more likely to have high polarizing power when bonding with large anions because they want to give up their electr...
- Wed Dec 06, 2017 9:56 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: dipole moment chapter 4 test [ENDORSED]
- Replies: 3
- Views: 929
dipole moment chapter 4 test [ENDORSED]
Why is it that for number 1 on test 4, there are no dipole moments for PO4^3- and PCl^5? I thought that there are dipole moments because the arrows point towards the negative oxygens (for PO4^3-) or negative chlorine molecules (PCl^5)? Can someone explain how to know if there is a dipole moment or n...
- Tue Nov 28, 2017 10:43 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 11.49 question
- Replies: 1
- Views: 182
Re: 11.49 question
you do plus x if it is a product being formed, and you do minus x for the reactant (because you are losing the reactant as it is being decomposed to form the product)
- Tue Nov 28, 2017 1:07 pm
- Forum: Ideal Gases
- Topic: Kc to Kp Conversion
- Replies: 5
- Views: 926
Re: Kc to Kp Conversion
On one of the chemical equilibrium models, there are questions that Dr. Lavelle wrote that ask you to convert concentrations to pressures and vice versa. Yes, you would use the equation PV=nrt, and know that concentration is equal to P/rt. I would definitely study this because it was one the module ...
- Sat Nov 25, 2017 1:03 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: test 4 question
- Replies: 3
- Views: 473
test 4 question
Will LeChatlier's principle be on test 4? for example, do we need to know how equilibria responds to changes in conditions? This is shown in Part 4 Chemical Equilibrium's module
- Sat Nov 25, 2017 9:49 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: solvents in K
- Replies: 3
- Views: 573
solvents in K
are solvents included in equilibrium concentrations? This was on the post assessment part b for the module, and I am not sure how to figure this out.
- Mon Nov 20, 2017 6:31 pm
- Forum: Ideal Gases
- Topic: 11.13
- Replies: 2
- Views: 468
11.13
Why does a have the answer 1/PBCl3^2, instead of just writing PBCL3^2? Why is the inverse partial pressure the correct answer in this case? Because in b, the answer is just the two aqueous concentrations multiplied together, without any inverse equation. Can someone explain how to do part a in terms...
- Mon Nov 20, 2017 5:24 pm
- Forum: Ideal Gases
- Topic: solving 11.7
- Replies: 2
- Views: 381
solving 11.7
How do you know which flask represents equilibrium in this question? For equilibrium, does it occur when the number of double molecules equal the number of single molecules in the flask? I am having a hard time understanding how the diagram shows equilibrium.
- Wed Nov 15, 2017 9:09 pm
- Forum: Dipole Moments
- Topic: Polar molecules relation to lone pair electrons
- Replies: 2
- Views: 744
Polar molecules relation to lone pair electrons
For determining whether a molecule is polar or not, do we have to look at if the molecule has any lone pair electrons? Do lone pair electrons affect the dipole moment in any way?
- Wed Nov 15, 2017 9:07 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: trigonal planar vs. t-shaped
- Replies: 5
- Views: 3521
Re: trigonal planar vs. t-shaped
an atom is trigonal planar if it has three regions of electron density and the angles are at 120 degrees evenly, like an equilateral triangle. it is t-shaped if you have three regions of electron density, but one of these regions consists of a lone pair of electrons. the lone pair electrons cause th...
- Tue Nov 07, 2017 5:52 pm
- Forum: Electronegativity
- Topic: electronegativity chart
- Replies: 11
- Views: 1788
Re: electronegativity chart
another way that I remember it is that electronegative elements like in group 17 really want to have additional electrons to reach the noble gas configuration (reach the noble gas state). this is the opposite of group 1 because they form cations and want to lose electrons to reach the noble gas conf...
- Tue Nov 07, 2017 5:49 pm
- Forum: Ionic & Covalent Bonds
- Topic: Order of Electrons Lost by Ions
- Replies: 2
- Views: 653
Re: Order of Electrons Lost by Ions
There is a special rule for the 3d orbital. the lowest energy state for the electron configuration is made when the d orbital has either 5 electrons or 10 electrons. This is why you would remove from the 4s orbital first if you had to on a homework problem. when there are 5 electrons in the d orbita...
- Thu Nov 02, 2017 11:58 pm
- Forum: Dipole Moments
- Topic: S+ and S- Dipole Moment
- Replies: 4
- Views: 10936
Re: S+ and S- Dipole Moment
No, they wouldn't have the notation of S2- or S5+. Dipole moments is the measure of net polarity in a molecule and the plus and minus signs are used to to point towards either the positively charged element or towards the negatively charged element. They occur when there is a separation of charge.
- Thu Nov 02, 2017 11:48 pm
- Forum: Bond Lengths & Energies
- Topic: Bond Order
- Replies: 6
- Views: 1104
Re: Bond Order
Bond order is found by counting the number of bonds. So if it is a triple bond, there are three bonds connecting the two elements together. The bond order of H2 is equal to 1 because to connect two hydrogens, you need a single bond.
- Wed Oct 25, 2017 11:23 pm
- Forum: Properties of Light
- Topic: Homework?
- Replies: 2
- Views: 419
Re: Homework?
From what he have been doing in lecture, this week homework in Outline 2 on the 14A website is based on Chapter 2, with the introduction to orbitals and periodic table trends. So if you are looking at Outline 2, it corresponds with Week 4 's lecture notes. Also, Test 3 next week does cover the rest ...
- Wed Oct 25, 2017 11:20 pm
- Forum: Lewis Structures
- Topic: drawing Lewis structures [ENDORSED]
- Replies: 2
- Views: 419
Re: drawing Lewis structures [ENDORSED]
To be honest, I think its a rule that is just set and there is not much of a strict reasoning behind it. I think that in the case of sulfate, having the S in the center allows for symmetry for the Lewis structure, as it would be difficult is putting 4 oxygens in the center. So, symmetry is a valid r...
- Mon Oct 16, 2017 10:23 pm
- Forum: Properties of Light
- Topic: Module for Atomic Spectra Question 26
- Replies: 2
- Views: 281
Module for Atomic Spectra Question 26
In the module, this question is being asked: Can molecular spectroscopy be used to identify molecules? If so why is it possible?
Can someone explain the answer for this question?
Can someone explain the answer for this question?
- Mon Oct 16, 2017 8:31 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: The negative sign
- Replies: 2
- Views: 370
Re: The negative sign
Energy can be a negative answer-this just means that the electron emits energy as it is going down an energy level. however, wavelength and frequency cannot be negative answers, so if, for example, you need to further in the problem find the wavelength after finding the energy, make the energy posit...
- Mon Oct 16, 2017 8:30 pm
- Forum: Photoelectric Effect
- Topic: Post Module #19
- Replies: 3
- Views: 550
Re: Post Module #19
The photoelectric effect shows that light (electromagnetic radiation) acts as particles with particle-like properties. Therefore, d would not explain the photoelectric effect because d is an equation for wave-like properties, like wavelength.
- Wed Oct 11, 2017 4:23 pm
- Forum: Limiting Reactant Calculations
- Topic: Net moles produced (Test question) [ENDORSED]
- Replies: 2
- Views: 382
Re: Net moles produced (Test question) [ENDORSED]
I was wondering if anyone knew if there was a key available online to check the work for Test 1 Questions that we made mistakes on?
- Wed Oct 11, 2017 9:29 am
- Forum: Photoelectric Effect
- Topic: Photoelectric Effect: Post Module Assessment Q. 28, 29, and 30
- Replies: 12
- Views: 1402
Re: Photoelectric Effect: Post Module Assessment Q. 28, 29, and 30
For m, the mass would be the mass of an electron. Therefore you would plus in 9.10939*10^-31 kg in the equation 1/2mv^2
- Tue Oct 10, 2017 11:51 pm
- Forum: Properties of Light
- Topic: HW 1.37
- Replies: 1
- Views: 287
Re: HW 1.37
To solve this problem, you need to use the equation lambda=h/(mv) for both the proton and the neutron. lambha proton=h/mv. lambdaproton=(6.63*10^-34 J*s)/(1.673*10^-27kg*2.75*10^5 m/s) lambda proton=1.44 pm lambda neutron=h/mv lambdaneutron=(6.63*10^-34 J*s)/(1.675*10^-27 kg*2.75*10^5 m/s) lambda ne...
- Mon Oct 02, 2017 9:36 pm
- Forum: Balancing Chemical Reactions
- Topic: States of Matter in Chemical Equations
- Replies: 4
- Views: 765
Re: States of Matter in Chemical Equations
It is not correct to write the chemical equation without identifying the states of matter because you need information on the states of matter to understand the equation fully. It is necessary to write the states of matter in parenthesis because it tells you what type of experiment is occurring (ex....
- Mon Oct 02, 2017 9:31 pm
- Forum: SI Units, Unit Conversions
- Topic: Formula Units [ENDORSED]
- Replies: 9
- Views: 1307
Re: Formula Units [ENDORSED]
A formula unit is the group of ions that match the formula of the smallest unit of an ionic compound. When the question is asking for the number of formula units, the procedure is to first calculate the number of moles by dividing the mass of the sample given by the molar mass of the compound. Then,...