Search found 20 matches

by Naama 1A
Fri Dec 08, 2017 10:03 pm
Forum: Bronsted Acids & Bases
Topic: Bronsted acids in products
Replies: 2
Views: 174

Re: Bronsted acids in products

I believe that conjugate acids/bases found on the products side are considered Bronsted acids/bases as well. Especially due to the reversibility of many reactions, I don't think that they are only found on one side.
by Naama 1A
Fri Dec 08, 2017 8:25 am
Forum: Lewis Acids & Bases
Topic: HF
Replies: 4
Views: 255

Re: HF

I think that since the bond between H and F is so strong, it would be harder to separate them and give up the hydrogen ion (which would make it a Bronsted acid). Because of the strength of the bond, it is considered a weak acid.
by Naama 1A
Wed Nov 29, 2017 8:48 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Chemical Equilibrium Part 2 Question #12
Replies: 1
Views: 139

Re: Chemical Equilibrium Part 2 Question #12

We use the equilibrium constant expression: Kc=[Br]^2/[Br2]. In this case, we know Kc and [Br2], so we simply solve for the unknown [Br], which ends up being C.
by Naama 1A
Wed Nov 29, 2017 6:48 am
Forum: Naming
Topic: Iron v ferrate in coordination compound naming
Replies: 8
Views: 1578

Re: Iron v ferrate in coordination compound naming

To clarify, we use the latin names with suffix -ate if the complex ion is an anion. So for K4[Fe(CN)6], the overall charge of the complex ion is 4-, therefore this would be potassium hexacyanoferrate(II). If the complex ion is a cation or neutral, like Fe(CO)5, we call this pentacarbonyliron.
by Naama 1A
Sun Nov 26, 2017 9:54 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: 11.41
Replies: 2
Views: 175

Re: 11.41

You can figure out the equilibrium concentration of CO2 using the information given--convert 17.4mg CO2 to moles, then find the concentration by dividing by .250L. The ratio of CO2 to NH3 is 1:2, therefore the NH3 concentration is twice as much. Then use the Kc formula to get 1.58x10^-8 (remember th...
by Naama 1A
Sun Nov 26, 2017 8:00 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7726
Views: 1046131

Re: Post All Chemistry Jokes Here

What TV show do Cesium and Iodine love watching together?
CSI!
by Naama 1A
Sun Nov 19, 2017 3:30 pm
Forum: Naming
Topic: Example 17.1
Replies: 2
Views: 166

Re: Example 17.1

The compound is sodium dichloridobis(oxalato)platinate(IV). The roman numerals indicate the oxidation state of the Pt, which in this case is +4.
by Naama 1A
Fri Nov 17, 2017 9:41 am
Forum: Determining Molecular Shape (VSEPR)
Topic: Electron Density
Replies: 3
Views: 195

Re: Electron Density

If you connect all the outer atoms to each other, you will see that they form triangles on each side. In total, 8 triangles are formed, which accounts for why it is termed "octahedral"
by Naama 1A
Sat Nov 11, 2017 1:22 pm
Forum: Trends in The Periodic Table
Topic: Isoelectronic [ENDORSED]
Replies: 4
Views: 312

Re: Isoelectronic [ENDORSED]

Isoelectronic means that they have the same number of electrons. Something isoelectronic to F- would have 10 electrons. Anything that doesn't have 10 electrons is therefore not isoelectronic.
by Naama 1A
Sat Nov 11, 2017 1:17 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Bond Angles [ENDORSED]
Replies: 3
Views: 172

Re: Bond Angles [ENDORSED]

By looking at the structure of bonding groups around a central atom, you can deduce the bond angles. Trigonal bipyramidal has angles of 90, 120, and 180 degrees. This can be determined by looking at the different planes along which the bonding groups lie. Three bonding atoms in a single plane implie...
by Naama 1A
Tue Nov 07, 2017 9:04 pm
Forum: Student Social/Study Group
Topic: DOWNLOAD PRACTICE MIDTERM HERE: Lyndon and Michael's session
Replies: 7
Views: 1146

Re: DOWNLOAD PRACTICE MIDTERM HERE: Lyndon and Michael's session

Can someone help me out with problem 4b? I tried using the wavelength of the ejected electron to find velocity through the De Broglie equation. Then I found the total KE, added it to the work function (after converting from moles) and got the total photon energy. Then I used E=hv to solve for freque...
by Naama 1A
Tue Oct 31, 2017 6:53 am
Forum: Heisenberg Indeterminacy (Uncertainty) Equation
Topic: problem help
Replies: 5
Views: 885

Re: problem help

Since the uncertainty in position is +/- 5m, the total range of uncertainty/ delta x is 10m. (-5 to 5=10).
by Naama 1A
Wed Oct 25, 2017 6:37 am
Forum: Electron Configurations for Multi-Electron Atoms
Topic: unpaired electrons [ENDORSED]
Replies: 4
Views: 401

Re: unpaired electrons [ENDORSED]

Electrons are parallel when filling sub-orbitals such as Px, Py, and Pz. Generally, we first assign a spin up electron to each sub-orbital, so the electrons have parallel spins. We then fill the unpaired electrons with the opposite spin. If you had something like 2p^2, I think the electrons in the p...
by Naama 1A
Wed Oct 25, 2017 6:22 am
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Electron Configuration writing
Replies: 8
Views: 383

Re: Electron Configuration writing

It depends on the problem. If we're just writing out full electron configurations I tend not to write out all the sub-orbitals. Conceptually, though, it helps to think about the sub-orbitals in order to understand how the orbitals fill and how electrons are paired.
by Naama 1A
Sun Oct 22, 2017 4:15 pm
Forum: Wave Functions and s-, p-, d-, f- Orbitals
Topic: Electron density distribution?
Replies: 2
Views: 191

Re: Electron density distribution?

A nodal plane is a plane between lobes of a p or d orbital, where there is zero probability of finding an electron. A non-symmetric electron density distribution means that the distribution is dependent upon either theta or phi, from the angular wave function. All s-orbitals, however, are independen...
by Naama 1A
Sat Oct 21, 2017 10:07 pm
Forum: Properties of Light
Topic: the quantum world
Replies: 7
Views: 376

Re: the quantum world

Lyman series emission lines fall in the UV band, Balmer in the visible region, and Paschen lines are infrared.
by Naama 1A
Thu Oct 12, 2017 8:50 pm
Forum: Photoelectric Effect
Topic: Photoelectric Effect: Post Module Assessment Q. 28, 29, and 30
Replies: 12
Views: 627

Re: Photoelectric Effect: Post Module Assessment Q. 28, 29, and 30

You divide by the number of atoms in a mole because the question asks for the energy required to remove ONE electron, not a whole mole.
by Naama 1A
Thu Oct 12, 2017 8:42 pm
Forum: Properties of Light
Topic: 1.23
Replies: 4
Views: 273

Re: 1.23

I would assume that these types of conversions will be given, but it never hurts to have a couple memorized :) I think we are mostly expected to know prefixes.
by Naama 1A
Sat Oct 07, 2017 3:13 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7726
Views: 1046131

Re: Post All Chemistry Jokes Here

What do you call Iron blowing in the wind?
Febreeze.
by Naama 1A
Thu Oct 05, 2017 11:51 pm
Forum: Limiting Reactant Calculations
Topic: Limiting Reactant info [ENDORSED]
Replies: 6
Views: 403

Re: Limiting Reactant info [ENDORSED]

The smaller amount of moles is limiting but you must consider the stoichiometric coefficients on the reactants side. If the ratio of coefficients is not one to one then the smaller amount of moles calculated from masses given may not actually be limiting.

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