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Naama 1A

I believe that conjugate acids/bases found on the products side are considered Bronsted acids/bases as well. Especially due to the reversibility of many reactions, I don't think that they are only found on one side.

Naama 1A

I think that since the bond between H and F is so strong, it would be harder to separate them and give up the hydrogen ion (which would make it a Bronsted acid). Because of the strength of the bond, it is considered a weak acid.

Naama 1A

We use the equilibrium constant expression: Kc=[Br]^2/[Br2]. In this case, we know Kc and [Br2], so we simply solve for the unknown [Br], which ends up being C.

Naama 1A

To clarify, we use the latin names with suffix -ate if the complex ion is an anion. So for K4[Fe(CN)6], the overall charge of the complex ion is 4-, therefore this would be potassium hexacyanoferrate(II). If the complex ion is a cation or neutral, like Fe(CO)5, we call this pentacarbonyliron.

Naama 1A

You can figure out the equilibrium concentration of CO2 using the information given--convert 17.4mg CO2 to moles, then find the concentration by dividing by .250L. The ratio of CO2 to NH3 is 1:2, therefore the NH3 concentration is twice as much. Then use the Kc formula to get 1.58x10^-8 (remember th...

Naama 1A

What TV show do Cesium and Iodine love watching together?
CSI!

Naama 1A

The compound is sodium dichloridobis(oxalato)platinate(IV). The roman numerals indicate the oxidation state of the Pt, which in this case is +4.

Naama 1A

If you connect all the outer atoms to each other, you will see that they form triangles on each side. In total, 8 triangles are formed, which accounts for why it is termed "octahedral"

Naama 1A

Isoelectronic means that they have the same number of electrons. Something isoelectronic to F- would have 10 electrons. Anything that doesn't have 10 electrons is therefore not isoelectronic.

Naama 1A

By looking at the structure of bonding groups around a central atom, you can deduce the bond angles. Trigonal bipyramidal has angles of 90, 120, and 180 degrees. This can be determined by looking at the different planes along which the bonding groups lie. Three bonding atoms in a single plane implie...

Naama 1A

Can someone help me out with problem 4b? I tried using the wavelength of the ejected electron to find velocity through the De Broglie equation. Then I found the total KE, added it to the work function (after converting from moles) and got the total photon energy. Then I used E=hv to solve for freque...

Naama 1A

Since the uncertainty in position is +/- 5m, the total range of uncertainty/ delta x is 10m. (-5 to 5=10).

Naama 1A

Electrons are parallel when filling sub-orbitals such as Px, Py, and Pz. Generally, we first assign a spin up electron to each sub-orbital, so the electrons have parallel spins. We then fill the unpaired electrons with the opposite spin. If you had something like 2p^2, I think the electrons in the p...

Naama 1A

It depends on the problem. If we're just writing out full electron configurations I tend not to write out all the sub-orbitals. Conceptually, though, it helps to think about the sub-orbitals in order to understand how the orbitals fill and how electrons are paired.

Naama 1A

A nodal plane is a plane between lobes of a p or d orbital, where there is zero probability of finding an electron. A non-symmetric electron density distribution means that the distribution is dependent upon either theta or phi, from the angular wave function. All s-orbitals, however, are independen...

Naama 1A

Lyman series emission lines fall in the UV band, Balmer in the visible region, and Paschen lines are infrared.

Naama 1A

You divide by the number of atoms in a mole because the question asks for the energy required to remove ONE electron, not a whole mole.

Naama 1A

I would assume that these types of conversions will be given, but it never hurts to have a couple memorized :) I think we are mostly expected to know prefixes.

Naama 1A

What do you call Iron blowing in the wind?
Febreeze.

Naama 1A

The smaller amount of moles is limiting but you must consider the stoichiometric coefficients on the reactants side. If the ratio of coefficients is not one to one then the smaller amount of moles calculated from masses given may not actually be limiting.

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Re: Bronsted acids in products

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