CHEMISTRY COMMUNITY

Eli Aminpour 2K

It depends. Combustion reactions vary because the definition is vague "hydrocarbons react with O2 to form water and carbon dioxide". I believe often, however, the reactants are all gaseous.

Eli Aminpour 2K

If there is no conducting solids on one side of the diagram.

Eli Aminpour 2K

It depends on the question. For some questions we will be told which is fast and which is slow. For most of the questions we have done in class and in the book, we are told the intermediate because we are given all the steps of the reaction.

Eli Aminpour 2K

compare the reaction rates when all other reactants remain constant except for C. The reaction rate doesn't change even though C does, meaning it isn't in the rate law because it is a zero order reactant.

Eli Aminpour 2K

Its the same as taking the derivative in calculus. We used it in thermodynamics to see what the effect of changing pressure or temperature would have on the system

Eli Aminpour 2K

Unless the question specifies which unit it wants in the answer, it doesn't matter. However, make sure the units match up with constants in the formula sheet and with K

Eli Aminpour 2K

Its a proportionality constant for the concentration of a reactant to the rate of reaction

Eli Aminpour 2K

today we talked in class about how when reactions are coupled, one of the steps may go so much faster than the other step that the overall reaction speed is determined by the slower step. The intermediate's concentration in this case wouldn't affect the overall reaction

Eli Aminpour 2K

It depends on the reaction and the amount of concentration available. Its too general to say all of one is faster than another

Eli Aminpour 2K

The inert electrode is necessary to make the electrons flow. You need this when the ions are aqueous or gaseous. You don't need it if there is a conducting solid.

Eli Aminpour 2K

In electrolysis, an electric current is passed through the substance. It is different than the chemical reaction that occurs in an galvanic cell. That is why you focus on the most positive standard reduction potentials

Eli Aminpour 2K

First, the inert electrode has to be placed in the cell diagram because the electrodes are made of aqueous solutions (meaning there are no conducting solids). The platinum tends to go on the right side of the cell diagram (cathode-reduction) because it only transfers electrons. It does not exchange ...

Eli Aminpour 2K

In class he referred to the hydronium ion as the standard, so i would use that.

Eli Aminpour 2K

when balancing redox reactions, the charges on both sides SHOULD add up to be equal to eachother.

Eli Aminpour 2K

that is usually how you do it.

Eli Aminpour 2K

yes, you can use that equation as long as temperature is constant.

Eli Aminpour 2K

don't write both half reactions as reductions. Make sure to write the complete oxidation and reduction reactions, and as the person above me said, labeling is good for that too.

Eli Aminpour 2K

If the element you are trying to find the oxidation number for is a transition metal, the oxidation number depends on the other elements in the compound. If its an ion, subtract the net oxidation numbers of the other elements in the compound (oxygen is almost always -2) from the total charge of the ...

Eli Aminpour 2K

It is on0 the sheet of constants and formula's we are given at the start of every test. (Cp(water) = 75.3 J. K-1mol-1)

Eli Aminpour 2K

Degeneracy is a property that is extremely difficult to measure in a lab, so often the CHANGE in degeneracy is measured. it can be increased moles of a substance or volume of a gas

Eli Aminpour 2K

Also, we used this equation in class to find the change in entropy when temperature is constant (as ice melts for example). If you want to find the change in entropy when temperature is not constant, use the equation delta S=n*C*ln(t2/t1)

Eli Aminpour 2K

Boltzmann's equation works when the change in internal energy of the system is 0. So, if you were to change temperature, that would change the internal energy. What is possible though to find the entropy at two different energies and subtract them from eachother

Eli Aminpour 2K

On tests and quizzes, I was told that if we need to assume standard conditions it will be explicitly stated in the problem

Eli Aminpour 2K

From what I've seen, we will be given a few steps or reactions and their enthalpy's and the final reaction. Then the question will ask us for the enthalpy change of the final reation.

Eli Aminpour 2K

I remember last quarter the rule was minus one on a test, and minus .5 on a quiz.

Eli Aminpour 2K

Molar heat capacity is the "heat required to raise the temp of 1 mole of a substance by one degree kelvin". Specific heat capacity is the "heat required to raise the temperature of 1 gram of a substance by one degree kelvin.

Eli Aminpour 2K

Just to edit what you wrote, Q is positive when the system absorbs energy. The change in entropy depends on whether heat is released or not. Sometimes its best to use your intuition on whether its negative or not. For example, the heat of vaporization (or the change in entropy from liquid to gas) of...

Eli Aminpour 2K

In class, it was defined as "the amount of heat released or absorbed at a constant pressure (qp=delta H). Its also a state property, meaning its value is determined by its current state.

Eli Aminpour 2K

an Isolated system can not exchange heat with its surroundings, but a closed system can. Neither system can exchange matter with its surroundings

Eli Aminpour 2K

I think there will be much more constants needed in 14B, so he may only post equations

Eli Aminpour 2K

H2CO3 is the formula for carbonic acid. It's Ka is higher than 10^-7 so it will act as an acid in water. Its conjugate base is HCO3-, which acts as a base in water. If your not sure whether or not a compound will act as a base or acid, check its Ka/Kb values or determine whether its the conjugate ba...

Eli Aminpour 2K

This was lectured on in class. The chemotherapy drug he referred to was Cisplatin. The long name for this drug is Cis-diamminedichloroplatinum (II), which contrasts with trans-diamminedicholoplatinum because of where the ammine or chloride groups are placed (next to or opposite of one another). Cisp...

Eli Aminpour 2K

There are a few ways to tell. Strong acids and bases have extremely high K values for the chemical reaction of their disassociation in water. There are patterns too related to these higher K values (meaning very little product was left behind). Metal hydroxides tend to be strong bases (metal +hydrox...

Eli Aminpour 2K

If the difference in electronegativity is greater, the dipole moment will be stronger.

Eli Aminpour 2K

the problem will usually call it just K, and depending on what other values they give you in the problem, those will determine whether it is referring to Kc and Kp. The importance i think is to know the difference between the two.

Eli Aminpour 2K

yes, make sure to know that a triple bond has two pi bonds but a double bond only has one.

Eli Aminpour 2K

protons are positively charged and attract electrons, but electrons are negatively charged and repulse other electrons. A lone pair causes an area of high electron density and causes distortions due to the electron-electron distortion. They don't take up more space, they just have a stronger negativ...

Eli Aminpour 2K

Count the functional groups (ions or molecules) attached to the central atom. This is the number of ligands you have

Eli Aminpour 2K

It was a radical. If you added up the valence electrons it had an odd number. HOCO does not have a charge so all the formal charges had to add up to zero. The way to make this happen is to have the carbon double bond to one oxygen, and single bond to another (this oxygen is bonded to the hydrogen). ...

Eli Aminpour 2K

First you need to check if the element can have an expanded octet. It should be in period three or higher (P, S, Cl, etc). If expanding the octet allows all the formal charges to become zero/ it forms a more stable molecule, than do it. Sometimes its obvious to do if there are 6 peripheral atoms and...

Eli Aminpour 2K

You need to understand resonance but I dont think new material from the most recent lecture will be on the midterm.

Eli Aminpour 2K

Normally, the problem will give you an atomic radius and you have to multiply by two to get the diameter (which becomes the uncertainty in position). But, this problem directly tells you that the uncertainty is just 1 % the radius, so there is no need to multiply by two and use the diameter. Try mul...

Eli Aminpour 2K

E=0.5mv^2 is the generic physics equation for kinetic energy. It really depends on what variables you are already given when you decide which formula to use. When discussing the photoelectric effect, it is more common to use the Kinetic energy equation.

Eli Aminpour 2K

We did that to the P orbital to demonstrate Hunds rule. Simply writing a superscript (3) after the P doesn't really show that each electron occupies its own orbital

Eli Aminpour 2K

The only two exceptions where the d orbital will first (that we know of in class up to this point) are chromium and copper. Other than those exceptions, the 4s will fill first than the 3d orbital.

Eli Aminpour 2K

The f block is a series of elements that would enter between group three and group four. The reason these elements are in the f block is because one or more of their outermost electrons is in the f orbital. If you were add the f block elements to the periodic table, it would expand in width.

Eli Aminpour 2K

the method you used to solve the problem works too, the problem is difficult because concerting cm^-1 to m^-1 is tricky. you have to multiply the 3600 cm^-1 by (100 cm/1 m) so that the centimeters cancel and you are left with meters in the denominator. This should give you the answer in the solution...

Eli Aminpour 2K

The photoelectric effect shows that light has properties of particles. In the experiment, they would shoot photons at certain pieces of metal, but if the photon did not reach the threshold energy, than no electron was ejected. They tested that same light (with the same frequency/wavelength), but the...

Eli Aminpour 2K

When balancing a combustion equation, try to start by balancing the carbon and hydrogen on the product side to match the reactants. Since its a combustion, you can always add more to the O2 (reactant) to balance it.

Eli Aminpour 2K

A trick to problems like these is to add the coefficients of the reactants and subtract that value from the sum of the coefficients of products. Make sure to balance the chemical equation first

Search found 50 matches