CHEMISTRY COMMUNITY

Swetha Sundaram 1E

k would be the rate constant of the forward reaction. k' would be the rate constant of the reverse reaction.

Swetha Sundaram 1E

No, a catalyst isn't a record of the cows you own

Swetha Sundaram 1E

At least from what I understand about it, I think one would just act as a cover whereas the other one would become part of the catalyst?? I'm not sure about this though.

Swetha Sundaram 1E

Right so when you compare them in separate reactions, we essentially cancel them out which is why they are not shown in the final reaction equation.

Swetha Sundaram 1E

I thought that derivations were fair game.

Swetha Sundaram 1E

I thought that we keep it to whatever units they give us. Unless they give us another piece of information that deals with another unit then we would convert it.

Swetha Sundaram 1E

Why did the liquid smell good?

Because it didn't past gas.

Swetha Sundaram 1E

Chemistry doesn't just matter, it is matter.

Swetha Sundaram 1E

The atom asks the electron, "why are you small?" The electron replies, "because I have a low charge!

Swetha Sundaram 1E

504754253 wrote:what kind of car do chemist drive? mercedes benzene

That was sodium funny...i slapped my neon that one

Swetha Sundaram 1E

The noble gases walk into a bar. No one reacts.

Swetha Sundaram 1E

504754253 wrote:how come every time i tell a joke there is no reaction?!

good one

Swetha Sundaram 1E

I have a similar question and also on part c why is it written as ||Ce4+,Ce3+| because I thought it was supposed to be written as ||Ce4+|Ce3+

Swetha Sundaram 1E

For Test 2 will we be provided a similar page to that of Appendix 2b to help us determine what half-reactions and standard cell potential values we will have to use?

Swetha Sundaram 1E

For this question, I was confused in how oxidation numbers were distributed in the original question because I thought Ag was +1 and Br was -1 and they stayed the same throughout because the ions split but this does not make sense in regards to reduction/oxidation half-reactions.

Swetha Sundaram 1E

yes thats correct

Swetha Sundaram 1E

we can't use the regular w=-p*deltaV is the irreversible equation, also the pressure isn't constant from point b to c

Swetha Sundaram 1E

Going from point B to point C, we are told that it is a reversible reaction so we use the equation that is w--nRTln(V2/V1)

Swetha Sundaram 1E

I try to tell chemistry jokes, but sometimes there's just no reaction.

Swetha Sundaram 1E

What did the Fe2+ say to the H+ that turned into H2?

"I'm sorry I reduced you! I swear it was an oxidant!"

Swetha Sundaram 1E

Both benzene and 1-propanol both have 12 atoms compared to the 6 atoms for methanol. And benzene has a more rigid planar ring structure so 1-propanol has the highest standard molar entropy of all three.

Swetha Sundaram 1E

Correct me if I'm wrong, but 3/2R represents a monatomic gas, 5/2R represents a diatomic gas, and 7/2R represents a polyatomic gas?

Swetha Sundaram 1E

Have you heard that entropy isn't what it used to be?

Swetha Sundaram 1E

I'm pretty sure Sfinal -Sinitial works to solve most problems.

Swetha Sundaram 1E

Molar entropy would be entropy content of one mole of substance under a standard state. Residual molar entropy is more specific in that it is the entropy at zero Kelvin.

Swetha Sundaram 1E

As Vincent said above, I would agree in saying that integrals are used because they represent the value of the sum between two values.

Swetha Sundaram 1E

Yes I agree with Sammy. Also note that when they say mention constant pressure in the problem. The Specific Heat Capacity can be found by 5/2 multipled by R. And for constant volume the specific heat capacity can be found by 3/2 multiplied by R.

Swetha Sundaram 1E

I think Delta H is only equal to q with a subscript "p" because the pressure has to remain constant for the equation to hold

Swetha Sundaram 1E

I think that it does count, but I would do one of the assigned problems just in case. If anything, it's extra practice :)

Swetha Sundaram 1E

The subscript c on the delta H represents that it's the standard enthalpy value for a combustion reaction.

Swetha Sundaram 1E

I think we have to use different methods depending on what we're given in the problem.

Swetha Sundaram 1E

Watch out for the enthalpy pirate.....he'll steal your joules.

Swetha Sundaram 1E

The enthalpy change for the water in the ice cube will be composed of two terms: the heat to melt the ice at 0 degrees Celsius and the heat required to raise the ice form 0 degrees Celsius to the final temperature.

Swetha Sundaram 1E

Even though class is cancelled today, it says that campus is still open so will the review sessions held in CS 24 and 50 still be taking place?

Swetha Sundaram 1E

From what I understand, I believe it depends on the type of molecule. For instance, if you're comparing HCl vs. HF, you can determine that HCl is a stronger acid by looking at the bong length (HCl has a long, weak bond). However, if you're comparing HClO2 vs. HClO, you can determine that HClO2 is a ...

Swetha Sundaram 1E

Well PF5 has a neutral charge and by adding the F- ion, it results in the overall compound having a negative charge.

Swetha Sundaram 1E

Well if the lone pairs weren't taken into account then it could just be trigonal planar but I think those two extra lone pairs on the iodine cause the chloride ions to have a bond angle of 90 degrees rather than 120 degrees.

Swetha Sundaram 1E

For the Chapter 4 test, do we have to know what type of molecular orbital an unpaired electron would occupy? Or anything about bond order in general?

Swetha Sundaram 1E

The name of the transition metal never really changes, it's just that when naming the molecules you use their latin names rather than the ones that appear on the periodic table.

Swetha Sundaram 1E

For the molecule ICl3 can someone please explain to me why its molecular shape is T-shaped and not trigonal planar?

Swetha Sundaram 1E

But in part b, there are two areas of electron density and it's linear so I thought that there wouldn't be any lone pairs. But the answer says that there may be lone pairs.

Swetha Sundaram 1E

What do chemists call a benzene ring with iron atoms replacing the carbon atoms?

A ferrous wheel.

Swetha Sundaram 1E

Okay cool, thanks guys!

Swetha Sundaram 1E

I am a [censored], a planet, and I can measure heat? What am I?

Mercury

Swetha Sundaram 1E

What can eat a lot of iron without getting sick?

Rust

Swetha Sundaram 1E

What did the scientist say when he found 2 atoms of helium?

HeHe

Swetha Sundaram 1E

An element can have either ionic or covalent bonds, but an ionic bond can have covalent character and vice versa.

Swetha Sundaram 1E

Some atoms are stronger and essentially more stable if you can make it a double or triple bond.

Swetha Sundaram 1E

So we don't need to determine which bonds will be shaded or be represented by spaced lines?

Swetha Sundaram 1E

Lewis structures and the rest of chapter 3 is going to be on the midterm right?

Swetha Sundaram 1E

For the Week 3 test, we just need to know the end of Chapter 1 and Chapter 2, not Chapter 3 right?

Swetha Sundaram 1E

From what I understand the further the atoms the electrons are from the nucleus, the more energy they have.

Swetha Sundaram 1E

I think gamma rays would work, but UV light is just easier to use. I'm not completely sure though

Swetha Sundaram 1E

I think our Week 3 HW can be either chapter 1 or 2, and then next week (week 4) will be chapter 2 for sure since he just started teaching us about it.

Swetha Sundaram 1E

So each element and molecule have their own unique spectral pattern or fingerprint.

Swetha Sundaram 1E

The photoelectric experiment has to be done under a vacuum because otherwise the ejected electrons interact with molecules in the air.

Swetha Sundaram 1E

Hi! This may seem like a silly question, but I wasn't too sure about how to go about solving this problem. The question is: Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 105 m.s-1. The work function for sodium is 150.6 kJ.mol-1. How much energy is required to r...

Swetha Sundaram 1E

For this problem, in part a) I first converted KCl, K2S, and K3PO4 from grams to moles and then I added each of the moles together which was 2.29 x 10^-2 mole and then I divided that by 0.5 L because Molarity multipled by Volume = moles and got 4.58 x 10^-2M. In part b) I used the grams of K2S to fi...

Swetha Sundaram 1E

Hey! Can anybody help me set up problem L.35 because I know I first have to balance the three reactions and then convert the tons into grams, but then afterwards do I basically work backwards from 8 mol NaBr to the mol of Fe using stoichiometry?

Search found 59 matches