Search found 12 matches

by venning-1J
Thu Oct 05, 2017 6:05 pm
Forum: Limiting Reactant Calculations
Topic: M11
Replies: 5
Views: 1023

Re: M11

Thanks!
by venning-1J
Thu Oct 05, 2017 5:45 pm
Forum: Limiting Reactant Calculations
Topic: Homework Problem M.19 Help
Replies: 4
Views: 555

Re: Homework Problem M.19 Help

how do you know there are 2 mol of N and H?
by venning-1J
Thu Oct 05, 2017 4:59 pm
Forum: Limiting Reactant Calculations
Topic: M11
Replies: 2
Views: 278

M11

A reaction vessel contains 5.77 g of white phosphorus and 5.77 g of oxygen. The first reaction to take place is the formation of phosphorous (III) oxide, P406; P4 (s) + 3O2 (g) --> P406(s). IF enough oxygen is present, the oxygen can react further w/ this oxide to produce phosphorus (V0 oxide, P4010...
by venning-1J
Thu Oct 05, 2017 3:44 pm
Forum: Limiting Reactant Calculations
Topic: M5
Replies: 2
Views: 329

M5

I dont understand why in the final reaction, only 2 mol of Br2 are produced. Can some one explain? M.5 Solve this exercise without using a calculator. The reaction 6 ClO2 + 2BrF3 -> 6ClO2F + Br2 is carried out with 12 mol ClO2 and 5 mol BrF3. (b) Estimate how many moles of each product will be produ...
by venning-1J
Wed Oct 04, 2017 4:11 pm
Forum: Molarity, Solutions, Dilutions
Topic: G5
Replies: 1
Views: 257

G5

A student prepared a solution of sodium carbonate by adding 2.111 g of the solid to a 250.0-mL volumetric ask and adding water to the mark. Some of this solution was transferred to a buret. What volume of solution should the student transfer into a ask to obtain (a) 2.15 mmol Na ; (b) 4.98 mmol CO32...
by venning-1J
Wed Oct 04, 2017 3:22 pm
Forum: Molarity, Solutions, Dilutions
Topic: G5 from fundamentals!
Replies: 3
Views: 266

Re: G5 from fundamentals!

for part b,(b) 4.98 mmol CO3 ; would there be 3 moles of CO3 for every mole of Na2CO3?
by venning-1J
Tue Oct 03, 2017 11:26 pm
Forum: Molarity, Solutions, Dilutions
Topic: E 29 part c
Replies: 8
Views: 910

E 29 part c

Im having trouble figuring out part c. E.29 A chemist measured out 8.61 g of copper(II) chloride tetrahydrate, CuCl2 4H2O. (a) How many moles of CuCl2 4H2O were measured out? 0.0417 mol (b) How many moles of Cl ions are present in the sample? .0834 mol [i] (c) How many H2O molecules are present in t...
by venning-1J
Tue Oct 03, 2017 10:55 pm
Forum: Molarity, Solutions, Dilutions
Topic: Calculating moles of only one element in a compound
Replies: 2
Views: 486

Re: Calculating moles of only one element in a compound

Never mind. I figured it out, im just not sure if my reasoning is correct. Is it 0.0134 mol of cu2+ because there is one mole of cu in the compound? (1:2 ratio in CuBr2)
by venning-1J
Tue Oct 03, 2017 10:48 pm
Forum: Molarity, Solutions, Dilutions
Topic: Calculating moles of only one element in a compound
Replies: 2
Views: 486

Calculating moles of only one element in a compound

How do I approach this?
I foound that the molecular mass of the compound is 223.35 gmol and I divided it by 3 g to get that the compound has .0134 moles. How do I find the amount of moles of only cu^2+ ions?

Calculate the amount (in moles) of (a) Cu^2+ ions in 3.00 g of CuBr2
by venning-1J
Tue Oct 03, 2017 10:17 pm
Forum: Molarity, Solutions, Dilutions
Topic: Writing formulas
Replies: 1
Views: 139

Writing formulas

In problem E9 we have to write a formula. Are we expected to know this for fridays assessment?

E9) Epsom salts consist of magnesium sulfate heptahydrate. Write its formula.
by venning-1J
Tue Oct 03, 2017 10:16 pm
Forum: Molarity, Solutions, Dilutions
Topic: Writing formulas
Replies: 4
Views: 334

Writing formulas

In problem E9 we have to write a formula. Are we expected to know this for fridays assessment?

E9) Epsom salts consist of magnesium sulfate heptahydrate. Write its formula.
by venning-1J
Tue Oct 03, 2017 9:45 pm
Forum: Molarity, Solutions, Dilutions
Topic: converting grams of substance to molecules
Replies: 1
Views: 135

converting grams of substance to molecules

Can someone help me out with this problem? Calculate the amount of urea molecules, OC(NH2)2, in 2.3 x 10^5 g of urea I first divided 230000 by 60 (molecular mass of the compound) and then multiplied this number by avogadros constant to get an answer of 2.3 x 10^27 mol. However, the books answer is 3...

Go to advanced search