Search found 62 matches

by Kelly Kiremidjian 1C
Fri Mar 16, 2018 10:30 am
Forum: General Science Questions
Topic: Class [ENDORSED]
Replies: 3
Views: 336

Re: Class [ENDORSED]

no
by Kelly Kiremidjian 1C
Wed Mar 14, 2018 12:18 am
Forum: Second Order Reactions
Topic: Test 3 #8
Replies: 2
Views: 217

Test 3 #8

8.) In a 2nd order reaction, a reactant has a known half-life of 3.00 minutes and an initial concentration of 5.00 M. How much time (in seconds) will it take for the concentration of this reactant to drop to 2.00 M?

Could someone explain how they did this question?
by Kelly Kiremidjian 1C
Wed Mar 14, 2018 12:15 am
Forum: Entropy Changes Due to Changes in Volume and Temperature
Topic: Midterm Question 6B
Replies: 1
Views: 190

Re: Midterm Question 6B

For this question I used the equation deltaS=nCvln(T2/T1) You need to find the moles first, however using PV=nRT. Everything is given besides moles, so you can solve for n: n=(1.00 atm)(53.48L)/(.08206)(303K) to get n=2.15 moles. You can then use n to solve for change in entropy, using Cv as 3/2R be...
by Kelly Kiremidjian 1C
Wed Mar 14, 2018 12:11 am
Forum: Phase Changes & Related Calculations
Topic: Midterm, Question 4B
Replies: 2
Views: 132

Re: Midterm, Question 4B

For this question I used deltaU=q+w Since the internal energy of a system decreased by 1763 kJ, deltaU=-1763. It also gives you the value for w, saying that the system did 1357 kJ of work. When a system does work its negative. so w=-1357. From there you can solve for q, and you should get q= -406 kJ...
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 11:17 pm
Forum: Reaction Mechanisms, Reaction Profiles
Topic: Reaction Mechanisms on test 3?
Replies: 2
Views: 102

Re: Reaction Mechanisms on test 3?

no the test only covers 15.1-15.6
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 11:14 pm
Forum: Kinetics vs. Thermodynamics Controlling a Reaction
Topic: Kinetics Test
Replies: 2
Views: 143

Re: Kinetics Test

My TA told us that test 3 would cover #1-39 from chapter 15
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 3:06 pm
Forum: General Rate Laws
Topic: Test #3 Problems
Replies: 3
Views: 164

Re: Test #3 Problems

my TA said it was #1-39
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 2:29 pm
Forum: Administrative Questions and Class Announcements
Topic: Test 3 - Chapter 15 homework
Replies: 3
Views: 156

Re: Test 3 - Chapter 15 homework

my TA told us questions #1-39 will be covered on test 3!
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 2:27 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Test 2
Replies: 4
Views: 176

Re: Test 2

You would have to find delta G for both half reactions and then add them to find delta G of the entire reaction. Once you have that you can solve for E (standard potential of cell). This problem is very similar to 14.27 if you have the solutions manual
by Kelly Kiremidjian 1C
Mon Mar 05, 2018 2:22 pm
Forum: General Rate Laws
Topic: Average rate of consumption
Replies: 2
Views: 85

Average rate of consumption

When finding average rate of consumption of R, I know the equation is (- delta[R]/delta t) because the concentration of R would be decreasing during the reaction. But when stating the rate, is it always positive? Textbook question 15.3 part a has the rate of consumption of NO2 as a positive rate so ...
by Kelly Kiremidjian 1C
Thu Mar 01, 2018 12:12 pm
Forum: Method of Initial Rates (To Determine n and k)
Topic: 15.15 [ENDORSED]
Replies: 5
Views: 198

Re: 15.15 [ENDORSED]

Both of the reactants are first order because their concentrations are directly proportional to the rate increase factor.
by Kelly Kiremidjian 1C
Thu Mar 01, 2018 8:56 am
Forum: General Rate Laws
Topic: half life vs rate
Replies: 2
Views: 108

Re: half life vs rate

The normal rate of the reaction is the concentration of a reactant or product to be consumed or formed over a given time unit.

Half-life of a reaction is the amount of time needed for the reactant concentration to decrease by half its original concentration.

hope this helps!
by Kelly Kiremidjian 1C
Sat Feb 24, 2018 6:30 pm
Forum: General Rate Laws
Topic: Units for 15.3 Part B
Replies: 4
Views: 177

Re: Units for 15.3 Part B

I think they put that just to distinguish that they were referring to moles of oxygen. I don't think we would have to put that in every problem
by Kelly Kiremidjian 1C
Thu Feb 22, 2018 10:12 am
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Conducting Metal
Replies: 1
Views: 77

Re: Conducting Metal

Generally if you have a metal solid in your reaction you don't need to add the Pt(s). If you only have elements in the (aq) or (l) state you must add the metal conductor so electron transfer can occur.
by Kelly Kiremidjian 1C
Thu Feb 22, 2018 10:03 am
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: 14.55
Replies: 2
Views: 121

Re: 14.55

You don't have to switch the sign of Eº if when calculating Eºcell you always use Eºcathode-Eºanode.

If you prefer to use the method where you add the Eºcathode and Eºanode you must flip the Eºanode.
by Kelly Kiremidjian 1C
Tue Feb 13, 2018 11:19 am
Forum: Gibbs Free Energy Concepts and Calculations
Topic: 11.15
Replies: 2
Views: 138

Re: 11.15

the question states that the reaction is at 1200K
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 11:21 pm
Forum: Administrative Questions and Class Announcements
Topic: Homework
Replies: 1
Views: 110

Re: Homework

yeah every week
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 11:20 pm
Forum: Calculating Work of Expansion
Topic: Reversible vs irreversible
Replies: 4
Views: 152

Re: Reversible vs irreversible

If a reaction goes in both directions, it is at equilibrium, and therefore it is reversible.
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 11:16 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Test 1 Question 1c
Replies: 3
Views: 119

Re: Test 1 Question 1c

Bond enthalpies are the least accurate way to calculate enthalpy of formation because they are averages
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 11:14 pm
Forum: Gibbs Free Energy Concepts and Calculations
Topic: Midterm
Replies: 2
Views: 122

Re: Midterm

He said we won't have to specifically derive any formulas but need to know how the formulas relate to each other and be able to substitute parts of equations when necessary
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 4:33 pm
Forum: Administrative Questions and Class Announcements
Topic: No class on Wednesday?
Replies: 2
Views: 208

Re: No class on Wednesday?

yes, Dr. Lavelle announced in lecture today that there will be no class on Wednesday.
by Kelly Kiremidjian 1C
Mon Feb 12, 2018 4:33 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: Practice Midterm Karen Leung #8 [ENDORSED]
Replies: 4
Views: 270

Re: Practice Midterm Karen Leung #8 [ENDORSED]

For part b you calculate the delta S for changing temperature and then add it to your answer from part a.
so you do deltaS=nRln(t2/t1)
n= moles of both the argon gas and the neon gas
by Kelly Kiremidjian 1C
Sat Feb 10, 2018 6:53 pm
Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
Topic: Problem 9.75
Replies: 1
Views: 119

Re: Problem 9.75

I asked about this at a step-up session and the UA said we would not be expected to know that!
by Kelly Kiremidjian 1C
Sat Feb 10, 2018 6:50 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: 9.85
Replies: 1
Views: 111

Re: 9.85

For part C, it asks if the entropy of the system is primarily a result of changes in positional disorder or thermal disorder. The system here is the solution, so if you imagine potassium nitrate dissolving in water it makes logical sense that the entropy, or disorder of the system is mostly the pota...
by Kelly Kiremidjian 1C
Mon Feb 05, 2018 9:51 pm
Forum: Gibbs Free Energy Concepts and Calculations
Topic: Chapter 11 #17
Replies: 2
Views: 96

Re: Chapter 11 #17

I got this too. I think it's a mistake in the answer key
by Kelly Kiremidjian 1C
Mon Feb 05, 2018 9:49 pm
Forum: Gibbs Free Energy Concepts and Calculations
Topic: 9.63
Replies: 4
Views: 144

Re: 9.63

Thermodynamic stability occurs when a system is in its lowest energy state. Therefore, compounds with positive free energy are said to be unstable while compounds with negative free energy are said to be stable.
by Kelly Kiremidjian 1C
Mon Feb 05, 2018 9:46 pm
Forum: Gibbs Free Energy Concepts and Calculations
Topic: 11.17
Replies: 10
Views: 338

Re: 11.17

I also got -2.74 kJ.mol-1. I think the there's a mistake in the answer key
by Kelly Kiremidjian 1C
Mon Feb 05, 2018 1:29 pm
Forum: Entropy Changes Due to Changes in Volume and Temperature
Topic: 9.21
Replies: 3
Views: 120

9.21

In #21, where do they get the value of Kb? Also can someone explain this question I'm confused what we are calculating
by Kelly Kiremidjian 1C
Thu Feb 01, 2018 3:11 pm
Forum: Entropy Changes Due to Changes in Volume and Temperature
Topic: Question 8.13
Replies: 3
Views: 96

Re: Question 8.13

In addition, when a system is irreversible, we can see it as expanding into a vacuum. This means that the ∆Ssurroundings will be equal to zero because there is no change of entropy in a pressure-less reservoir. However, this is very different from a reversible system, for which the ∆Stotal of the un...
by Kelly Kiremidjian 1C
Fri Jan 26, 2018 10:19 am
Forum: Phase Changes & Related Calculations
Topic: Homework Exercise 8.43 and Phase Changes
Replies: 1
Views: 93

Re: Homework Exercise 8.43 and Phase Changes

When looking at a heating curve, you have heat supplied on the x axis and temperature on the y axis. The plateau's represent the phase change. The first plateau is solid changing to liquid, and the second plateau is liquid changing to gas. Notice there is no temperature change during the phase chang...
by Kelly Kiremidjian 1C
Fri Jan 26, 2018 10:09 am
Forum: Thermodynamic Systems (Open, Closed, Isolated)
Topic: Iron Rusting: Exo or Endo? [ENDORSED]
Replies: 4
Views: 663

Re: Iron Rusting: Exo or Endo? [ENDORSED]

I think iron rusting would be exothermic since it gives off heat
by Kelly Kiremidjian 1C
Thu Jan 25, 2018 3:05 pm
Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
Topic: The sign of q
Replies: 5
Views: 192

Re: The sign of q

q is postitive is heat is added to the system and q is negative is heat is removed from the system.
by Kelly Kiremidjian 1C
Mon Jan 22, 2018 9:13 am
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Question 85
Replies: 1
Views: 85

Re: Question 85

For part B, you must use the gas law, PV=nRT. In this problem we are given everything except for moles, so you can rearrange the equation to look like n=PV/RT. Then you can plug the given numbers in. n=(1.00 atm)(5.45 L)/ (0.08206)(273K) n=0.243 mol Now that you have moles of Nitrogen, you can multi...
by Kelly Kiremidjian 1C
Sat Jan 20, 2018 5:21 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: 8.51 [ENDORSED]
Replies: 2
Views: 96

Re: 8.51 [ENDORSED]

the standard enthalpies of formation should be in the back of the textbook in appendix 2A
by Kelly Kiremidjian 1C
Sat Jan 20, 2018 5:10 pm
Forum: Concepts & Calculations Using First Law of Thermodynamics
Topic: 8.49
Replies: 2
Views: 150

8.49

In #49, how do you know that PΔV is negative?
by Kelly Kiremidjian 1C
Wed Jan 17, 2018 10:12 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: 8.61
Replies: 3
Views: 134

Re: 8.61

hi, I was confused about this too but a TA explained it to me. Since there is no ammonia (NH3) in the desired reaction, the ammonia from the reactions with known enthalpies must be cancelled out. To do this, the ammonia must be on different sides of the two reactions it appears in. Since H2 appears ...
by Kelly Kiremidjian 1C
Tue Jan 16, 2018 11:41 am
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Hess's Law
Replies: 3
Views: 132

Re: Hess's Law

Hess's law states that the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states. This is useful for us in calculating change in enthalpy's because we can then use reactions with known enthalpy's and manipulate them to find the enthalpy of the d...
by Kelly Kiremidjian 1C
Tue Jan 16, 2018 11:36 am
Forum: Concepts & Calculations Using First Law of Thermodynamics
Topic: Q 8.13
Replies: 9
Views: 332

Re: Q 8.13

No. In this question, it says that the cooling system that surrounds the cylinder absorbs 974 kJ of heat. If the system that surrounds the cylinder is absorbing heat, this means that the cylinder is releasing this heat and that is why it is negative. Heat absorbed by the cylinder would be positive, ...
by Kelly Kiremidjian 1C
Tue Jan 16, 2018 11:30 am
Forum: Phase Changes & Related Calculations
Topic: 8.37
Replies: 3
Views: 112

Re: 8.37

For part a, you know that the vaporization of 0.579 moles of Ch4 requires 4.76 kJ of heat, so all you have to do is divide the amount of heat by the moles to find the enthalpy (kJ/mol). 4.76 kJ/0.579 mol=8.22 kJ/mol For part b it is very similar but instead of being given moles, you are given grams....
by Kelly Kiremidjian 1C
Fri Dec 08, 2017 9:56 pm
Forum: Bronsted Acids & Bases
Topic: 12.17 How can you determine if an oxide is acidic, basic, or amphoteric
Replies: 1
Views: 180

Re: 12.17 How can you determine if an oxide is acidic, basic, or amphoteric

ad trouble with this question too. Reading page 468-469 in the textbook really helped me. It says at the end of section 12.3: metals form basic oxides, nonmetals form acidic oxides, and the elements on a diagonal line from beryllium to polonium and several d-block metals form amphoteric oxides. Ther...
by Kelly Kiremidjian 1C
Mon Dec 04, 2017 11:35 pm
Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
Topic: 11.73 d
Replies: 2
Views: 130

Re: 11.73 d

Dr. Lavelle mentioned in lecture a quick way to do this problem. Since pressure is increasing and volume is decreasing. When that happens, you know that if there are more moles on the left, the reaction shifts right. If there are more moles on the right, the reaction shifts left. In this case there ...
by Kelly Kiremidjian 1C
Mon Dec 04, 2017 11:30 pm
Forum: Acidity & Basicity Constants and The Conjugate Seesaw
Topic: 12.17
Replies: 3
Views: 155

Re: 12.17

I had trouble with this question too. Reading page 468-469 in the textbook really helped me. It says at the end of section 12.3: metals form basic oxides, nonmetals form acidic oxides, and the elements on a diagonal line from beryllium to polonium and several d-block metals form amphoteric oxides. h...
by Kelly Kiremidjian 1C
Mon Dec 04, 2017 11:27 pm
Forum: Conjugate Acids & Bases
Topic: HW 12.3
Replies: 3
Views: 176

Re: HW 12.3

I believe what you learned in high school was right. A conjugate base should only have the different of one hydrogen
by Kelly Kiremidjian 1C
Mon Dec 04, 2017 11:25 pm
Forum: Bronsted Acids & Bases
Topic: 12.39
Replies: 2
Views: 164

12.39

Chapter 12 #39 asks: 12.39 Using data in Tables 12.1 and 12.2, place the following acids in order of increasing strength: HNO2, HClO2, NH3OH, (CH3)2NH2 Considering we won't have these tables to use during the exam, are we expected to be able to place acids in order of strength? If so, could someone ...
by Kelly Kiremidjian 1C
Mon Nov 27, 2017 8:38 pm
Forum: Hybridization
Topic: Lone Pairs in Hybridization
Replies: 4
Views: 272

Lone Pairs in Hybridization

Can anyone explain how to write the hybridization of a compound with a lone pair? Does hybridization rely solely on the amount of regions of electron density or just the number of bonds excluding lone pairs?

thanks
by Kelly Kiremidjian 1C
Sun Nov 26, 2017 3:47 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Post Assessment Equilibrium Part 2 #30
Replies: 2
Views: 209

Re: Module Part 2 #30

Hey Sabrina, so when you convert everything to molarity values you get 0.167 M of Carbon and .05 M of H20. Those are the initial amount for of C and H20 in the ice table. Since Carbon is a solid it does not have an effect on the equilibrium values. We know the equilibrium concentration of H2 is 0.04...
by Kelly Kiremidjian 1C
Fri Nov 24, 2017 10:00 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Post Assessment Chemical Equilibrium Part 2 #29 [ENDORSED]
Replies: 6
Views: 380

Post Assessment Chemical Equilibrium Part 2 #29 [ENDORSED]

Can anyone explain #29 from the Chemical Equilibrium Part 2 Post Assessment? Here it is 29. A researcher fills a 1.00 L reaction vessel with 1.84 x 10-4 mol of BrCl gas and heats it to 500 K. At equilibrium, only 18.3 % of the BrCl gas remains. Calculate the equilibrium constant, assuming the follow...
by Kelly Kiremidjian 1C
Sun Nov 19, 2017 7:22 pm
Forum: Hybridization
Topic: Electron density question
Replies: 4
Views: 218

Re: Electron density question

yes each lone pair counts as another region of electron density
by Kelly Kiremidjian 1C
Sun Nov 19, 2017 5:37 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: HW Question 4.27
Replies: 4
Views: 161

Re: HW Question 4.27

By replacing the -CH- in Benzene with a Nitrogen atom the dipole moments no longer cancel so it becomes a polar molecule.
by Kelly Kiremidjian 1C
Wed Nov 08, 2017 9:53 am
Forum: Lewis Structures
Topic: 3.67B and Radicals
Replies: 2
Views: 136

Re: 3.67B and Radicals

Yes, this molecule has an odd number of electrons(19). So the two oxygens would both have octets. But there are not enough electrons for chlorine to have an octet. Chlorine then has one lone pair, and one single electron.
by Kelly Kiremidjian 1C
Wed Nov 08, 2017 9:50 am
Forum: Electronegativity
Topic: 3.79
Replies: 3
Views: 284

Re: 3.79

Also remember that atoms with a similar number of valence electrons are more likely to equally share electrons and have a more covalent character. This is in contrast to ionic character, where one atom is monopolizing the electrons.
by Kelly Kiremidjian 1C
Sun Nov 05, 2017 7:28 pm
Forum: Formal Charge and Oxidation Numbers
Topic: 3.49
Replies: 3
Views: 255

3.49

Can anyone explain 3.49? I had the correct lewis structure but am not getting the formal charge correct. For part A, I had Formal Charge of Oxygen= 6 valence e - (1 lone pair +6/2) which gives a +2 charge, and the book says Oxygen has a +1 charge. For Nitrogen I had Formal Charge of Nitrogen=5 valen...
by Kelly Kiremidjian 1C
Sun Nov 05, 2017 9:29 am
Forum: Electron Configurations for Multi-Electron Atoms
Topic: 3.9
Replies: 2
Views: 123

3.9

Can anyone explain 3.9 from the homework problems? I am confused on what the question is asking for. Also for the given electron configurations
a.) [Ar] 3d7
b.[Ar]3d6

are these possible? Doesn't the 4s orbital need to be filled for to have an electron in 3d?

thanks
by Kelly Kiremidjian 1C
Tue Oct 24, 2017 10:22 pm
Forum: Trends in The Periodic Table
Topic: 2.59
Replies: 1
Views: 102

2.59

Can anyone explain #59 from Chapter 2? Aren't the ions isoelectronic?

thanks!
by Kelly Kiremidjian 1C
Sun Oct 22, 2017 10:18 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: 2. 39 [ENDORSED]
Replies: 5
Views: 285

Re: 2. 39 [ENDORSED]

I had the same question....so you can determine wether the electron is in the excited state or not by seeing if it correctly spaced in the boxes?
by Kelly Kiremidjian 1C
Sun Oct 22, 2017 6:23 pm
Forum: Wave Functions and s-, p-, d-, f- Orbitals
Topic: XYZ [ENDORSED]
Replies: 4
Views: 241

XYZ [ENDORSED]

Hi!
I did electron configuration in high school using the 2p61, 2p62, 2p63 model... can someone please explain the x,y,z we are using in this class more clearly? thanks!
by Kelly Kiremidjian 1C
Fri Oct 13, 2017 9:50 pm
Forum: Photoelectric Effect
Topic: Photoelectric Effect Post-Module Assessment 32B, 33 [ENDORSED]
Replies: 2
Views: 254

Re: Photoelectric Effect Post-Module Assessment 32B, 33 [ENDORSED]

For 32B you know Kinetic energy of the electron and you know the work function so you are able to solve for the energy of the photon. KE=4.200 x10^-19 J Work function=3.607 x 10^-19 J, which you know from the previous question because there was zero kinetic energy. So then you do: Energy(photon)=Kin...
by Kelly Kiremidjian 1C
Fri Oct 13, 2017 9:40 pm
Forum: Photoelectric Effect
Topic: Question 34 from Photoelectric Effect Post Module Assessment
Replies: 1
Views: 170

Question 34 from Photoelectric Effect Post Module Assessment

Can anyone help me with question 34 from this post assessment? I said C for #33 which was correct but couldn't figure out #34. Thanks! 33. Molybdenum metal must absorb radiation with a minimum frequency of 1.09 x 1015 s-1 before it can emit an electron from its surface. Answer the following two ques...
by Kelly Kiremidjian 1C
Thu Oct 05, 2017 5:21 pm
Forum: Molarity, Solutions, Dilutions
Topic: E9 [ENDORSED]
Replies: 5
Views: 884

Re: E9 [ENDORSED]

dividing by 246.48 g.mol^-1 gives the molar mass of the entire thing, and it just asks for oxygen so you multiply by 11 because there are 11 moles of Oxygen in the equation. Then after you convert to atoms
by Kelly Kiremidjian 1C
Thu Oct 05, 2017 5:07 pm
Forum: Limiting Reactant Calculations
Topic: M11
Replies: 5
Views: 617

Re: M11

I have the same question.Couldn't quite follow the solutions manual

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