1/K is the reciprocal of K for that reaction
if you know the value of K of the forward reaction (for example 5) and the exercise asks you to find the K of the reverse reaction, you can find it by calculating the reciprocal of K of the forward reaction (in our example 1/5 which is 0.2)
Search found 21 matches
- Mon Dec 04, 2017 10:19 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: What is 1/K? [ENDORSED]
- Replies: 4
- Views: 1536
- Mon Dec 04, 2017 10:11 pm
- Forum: Bronsted Acids & Bases
- Topic: Bronsted Acid and Base vs Lewis Acid and Base
- Replies: 3
- Views: 710
Re: Bronsted Acid and Base vs Lewis Acid and Base
Bronsted: H+
- Bronsted acids are proton donor
- Bronsted bases are proton acceptor
Lewis: e-
- Lewis acids are e- acceptor and they accept a lone pair
- Lewis bases are e- donor and the donate a lone pair
- Bronsted acids are proton donor
- Bronsted bases are proton acceptor
Lewis: e-
- Lewis acids are e- acceptor and they accept a lone pair
- Lewis bases are e- donor and the donate a lone pair
- Mon Dec 04, 2017 10:08 pm
- Forum: Amphoteric Compounds
- Topic: 12.17 part b
- Replies: 3
- Views: 712
Re: 12.17 part b
1) It is a nonmetal so this means that it forms acidic oxides
2) it takes e- so it is an electron acceptor
2) it takes e- so it is an electron acceptor
- Mon Dec 04, 2017 10:05 pm
- Forum: Properties & Structures of Inorganic & Organic Bases
- Topic: Strong Acids and Weak Bases
- Replies: 1
- Views: 496
Strong Acids and Weak Bases
I have some problems recognizing when a acid is stronger than another acid and when a base is weaker than anther base. Can someone explain me how to do it?
- Sat Dec 02, 2017 3:58 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: Strong acid vs weak acid [ENDORSED]
- Replies: 7
- Views: 1024
Re: Strong acid vs weak acid [ENDORSED]
• STRONG ACID PRODUCES MORE PROTOS IN SOLUTION THAN A WEAK ACID • STRON ACIDS ALMOST COMPLETELY IONIZED IN SOLUTION. HCl, HBr, etc. • CALCULATIONS INVOLVING STRON ACIDS (OR BASE): APPROXIMATE BY ASSUMING 100% IONIZED (DISSOCIATED) THEREFORE 0.1M HCl (Aq) IMPLIES 0.1M H3O+(Aq) AND 0.1M Cl- (Aq) WHAT ...
- Mon Nov 27, 2017 10:54 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Ex 17.37 [ENDORSED]
- Replies: 1
- Views: 380
Ex 17.37 [ENDORSED]
Exercise number 17.34 for point c and d. Can you tell me why the coordination number of [PtCl2(en)2]^2+ is 6 and the coordination number of [Cr(edta)]^-1 is also 6?
- Mon Nov 27, 2017 10:49 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: polydentate and monodentate
- Replies: 1
- Views: 313
polydentate and monodentate
How do you determine that an atom is mono dentate? do you have to look at the lone pairs or at the bonds?
- Thu Nov 16, 2017 5:50 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3009824
Re: Post All Chemistry Jokes Here
What do you do with a sick chemist?
if you can't helium and you can't curium, then you might as well barium
if you can't helium and you can't curium, then you might as well barium
- Thu Nov 16, 2017 5:48 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3009824
Re: Post All Chemistry Jokes Here
What is the chemical formula for banana?
BaNa2
BaNa2
- Wed Nov 08, 2017 11:26 pm
- Forum: Limiting Reactant Calculations
- Topic: Limiting Reactant
- Replies: 3
- Views: 634
Re: Limiting Reactant
Firstly I usually find the moles for each of the reactant and then through a ratio (moles of first reactant : x = stoichiometric number first reactant : stoichiometric number second reactant) I calculate the amount of moles of the second reactant I should need and then I compare the moles that I hav...
- Wed Nov 08, 2017 11:18 pm
- Forum: Electronegativity
- Topic: Electronegativity and Bond Strength
- Replies: 4
- Views: 1857
Re: Electronegativity and Bond Strength
Bond strength and electronegativity are not really strictly related, but bond strength is more connected with the length of the atomic radius: smaller the atomic radius is, stronger the bond will be. In fact between CF4, CCl4, and CBr4, CF4 has the strongest bond because in all the three molecules w...
- Wed Nov 01, 2017 11:37 pm
- Forum: *Shrodinger Equation
- Topic: What do I need to know
- Replies: 1
- Views: 488
Re: What do I need to know
you just have to know that it describes the path/wavelength/orbital of an e- and it is a cos or sen function. You do not need to know the actual equation.
- Wed Nov 01, 2017 11:25 pm
- Forum: Trends in The Periodic Table
- Topic: Trends in the periodic table
- Replies: 3
- Views: 606
Re: Trends in the periodic table
Electron Affinity is the energy associated with the addition of an electon to a gaseous atom. It increases from left to right (period) and decreases from the top to the bottom (group)
- Thu Oct 26, 2017 11:02 am
- Forum: Trends in The Periodic Table
- Topic: d5 and d10 e- exception
- Replies: 4
- Views: 1989
Re: d5 and d10 e- exception
Yes, all the elements in group 11 and 6 are considered exceptions and so they act like Cr and Cu
- Thu Oct 26, 2017 10:58 am
- Forum: Quantum Numbers and The H-Atom
- Topic: Homework Question 2.17 part d
- Replies: 5
- Views: 665
Re: Homework Question 2.17 part d
l=0 --> s --> 1 orbital, 2 electrons
l=1--> p --> 3 orbitals, 6 electron
l=2 --> d --> 5 orbitals, 10 electrons
l=3 --> f --> 7 orbitals, 14 electrons
l=1--> p --> 3 orbitals, 6 electron
l=2 --> d --> 5 orbitals, 10 electrons
l=3 --> f --> 7 orbitals, 14 electrons
- Thu Oct 19, 2017 12:04 am
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic Spectra Module Question 44
- Replies: 2
- Views: 560
Re: Atomic Spectra Module Question 44
the answer is B because
a) you have to use the following formula in order to get the frequency --> frequency= R (1/n^2 - 1/n^2) [in this case n=4 and n=1 so frequency= R (1/16 - 1)
b) once you get the frequency you just have to use the formula wavelength= c(speed of light)/frequency
a) you have to use the following formula in order to get the frequency --> frequency= R (1/n^2 - 1/n^2) [in this case n=4 and n=1 so frequency= R (1/16 - 1)
b) once you get the frequency you just have to use the formula wavelength= c(speed of light)/frequency
- Wed Oct 18, 2017 11:47 pm
- Forum: Properties of Light
- Topic: Wavelength and Frequency
- Replies: 3
- Views: 626
Re: Wavelength and Frequency
we know that c= frequency x wavelength. c is a constant (speed of light), so from the first formula we can get that frequency=c/wavelength, from this you can see that frequency and wavelength are inversely proportional. In fact as the value of the wavelenght increases the value of the frequency decr...
- Tue Oct 10, 2017 11:22 am
- Forum: Properties of Light
- Topic: Photoelectric Effect Post-Module Assessment (33A, 34B)
- Replies: 1
- Views: 412
Photoelectric Effect Post-Module Assessment (33A, 34B)
33. Molybdenum metal must absorb radiation with a minimum frequency of 1.09 x 1015 s-1 before it can emit an electron from its surface. What is the minimum energy needed to produce this effect? If molybdenum is irradiated with 194 nm light, what is the maximum possible kinetic energy of the emitted ...
- Tue Oct 10, 2017 11:19 am
- Forum: Properties of Light
- Topic: Photoelectric Effect Post-Module Assessment (28B) [ENDORSED]
- Replies: 1
- Views: 432
Photoelectric Effect Post-Module Assessment (28B) [ENDORSED]
28. Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 105 m.s-1. The work function for sodium is 150.6 kJ.mol-1. How much energy is required to remove an electron from one sodium atom? What is the frequency of the incident light on the sodium metal surface? Could y...
- Thu Oct 05, 2017 4:48 pm
- Forum: Empirical & Molecular Formulas
- Topic: F. 9
- Replies: 2
- Views: 1655
Re: F. 9
Firs you have to find the empirical formula (which is C8H8O3) then you have to calculate the atom ratio (which is, in this case, 8:8:3)
- Thu Oct 05, 2017 4:42 pm
- Forum: Empirical & Molecular Formulas
- Topic: Identifying Empirical and Molecular Formulas [ENDORSED]
- Replies: 13
- Views: 8941
Re: Identifying Empirical and Molecular Formulas [ENDORSED]
The empirical formula shows the relative numbers of atoms of each element present in the compound (It is the simplest positive integer ratio of atoms present in a compound)
The molecular formula shows the actual numbers of atoms of each element in a molecule
The molecular formula shows the actual numbers of atoms of each element in a molecule