Gwen Peng 1L wrote:Yes it was assumed it was in equilibrium so you could've solved using the equation E standard=(0.05916/n)*log(K) or E standard=(RT/nF)*ln(K)
Hope this helps :)
Would the .05916/n term be negative?
Gwen Peng 1L wrote:Yes it was assumed it was in equilibrium so you could've solved using the equation E standard=(0.05916/n)*log(K) or E standard=(RT/nF)*ln(K)
Hope this helps :)