Search found 32 matches

by Manvir2K
Tue Mar 13, 2018 4:00 pm
Forum: Reaction Mechanisms, Reaction Profiles
Topic: HW 15.85
Replies: 2
Views: 145

Re: HW 15.85

An activated complex is the same as the transition state, which is not the same thing as an intermediate.
by Manvir2K
Tue Mar 13, 2018 3:54 pm
Forum: Reaction Mechanisms, Reaction Profiles
Topic: question 15.47
Replies: 4
Views: 167

Re: question 15.47

It is an intermediate because it was formed during the reaction and got used up during the reaction-> no need to include it in the overall reaction.
by Manvir2K
Tue Mar 13, 2018 3:35 pm
Forum: Arrhenius Equation, Activation Energies, Catalysts
Topic: HW 15.95 e
Replies: 2
Views: 128

Re: HW 15.95 e

In this case, the answer to e is none. I think if the catalyst is on the rate-determining step, it lowers the activation energy which increases the rate constant.
by Manvir2K
Thu Mar 08, 2018 1:03 pm
Forum: Method of Initial Rates (To Determine n and k)
Topic: Units for rate
Replies: 4
Views: 293

Re: Units for rate

As long as you keep the units the same throughout the problem, you should get the same answer. Just make sure to use the constants that give you the same units.
by Manvir2K
Thu Mar 08, 2018 12:57 pm
Forum: General Rate Laws
Topic: 15.101(a) Overall Reaction
Replies: 2
Views: 131

Re: 15.101(a) Overall Reaction

In the solutions manual, the answer is ClO- + I- -> IO- + Cl-. I am not sure which one is right though.
by Manvir2K
Thu Mar 08, 2018 12:52 pm
Forum: Reaction Mechanisms, Reaction Profiles
Topic: 15.47
Replies: 4
Views: 199

Re: 15.47

I think the chloride ion is the intermediate because an intermediate has to be formed during the reaction. Cl already existed before the reaction took place, which is the reason it is not the the intermediate.
by Manvir2K
Thu Mar 08, 2018 12:48 pm
Forum: Second Order Reactions
Topic: 15.27 vs 15.35
Replies: 3
Views: 271

Re: 15.27 vs 15.35

This method works for 27 because it is in first order, while 35 is in second order. I think calculating the half lives that have occurred and multiplying the number by the half-life only works for 1st order.
by Manvir2K
Thu Mar 01, 2018 4:07 pm
Forum: Method of Initial Rates (To Determine n and k)
Topic: 15.19
Replies: 4
Views: 190

Re: 15.19

I think you might have converted the initial concentration from mol to mol incorrectly.
by Manvir2K
Thu Mar 01, 2018 4:02 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Cell potential
Replies: 5
Views: 196

Re: Cell potential

If it is a galvanic cell, the more positive E° will be the cathode, and the less positive will be the anode since that is the only way for the cell to be spontaneous.
by Manvir2K
Thu Mar 01, 2018 3:59 pm
Forum: First Order Reactions
Topic: Terminology "first-order" [ENDORSED]
Replies: 5
Views: 220

Re: Terminology "first-order" [ENDORSED]

When commenting on the entire reaction, the overall order should be given-the sum of all the orders of the reactants
by Manvir2K
Sat Feb 24, 2018 2:40 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Galvanic cell set up
Replies: 8
Views: 252

Re: Galvanic cell set up

The left side is always there anode for a galvanic cell.
by Manvir2K
Sat Feb 24, 2018 2:40 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Inert Electrodes [ENDORSED]
Replies: 3
Views: 194

Re: Inert Electrodes [ENDORSED]

Another commonly used inert conductor is graphite.
by Manvir2K
Sat Feb 24, 2018 2:36 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Galvanic vs electrochemical [ENDORSED]
Replies: 2
Views: 115

Re: Galvanic vs electrochemical [ENDORSED]

I think galvanic cell is an electrochemical cell.
by Manvir2K
Thu Feb 15, 2018 12:38 pm
Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
Topic: Is spontaneity determined by entropy or free energy?
Replies: 4
Views: 317

Re: Is spontaneity determined by entropy or free energy?

Yes. When the book only has deltaS, it is only talking about deltaS of the system. Spontaneity can be found if we have total S.
by Manvir2K
Thu Feb 15, 2018 12:35 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Hess's Law
Replies: 5
Views: 249

Re: Hess's Law

Since Enthalpy is a state function, it has an additive property. It does not matter what path was taken to reach the destination.
by Manvir2K
Thu Feb 15, 2018 12:34 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Electrolytically Refined
Replies: 1
Views: 54

Re: Electrolytically Refined

I think it means refining (purifying) a metal through electrolysis which is using a direct electrical current to allow s non-spontaneous chemical reaction to occur.
by Manvir2K
Sun Feb 11, 2018 2:36 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: 9.15
Replies: 3
Views: 162

Re: 9.15

How do you get -6.01 kJ/mol or 4.35 kJ/mol from appendix 2A?
by Manvir2K
Sat Feb 10, 2018 4:59 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: 9.5
Replies: 3
Views: 133

Re: 9.5

The heat is negative because 40.0 kJ of energy is being transferred from a large reservoir to another reservoir.
by Manvir2K
Sat Feb 10, 2018 4:52 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: 8.117
Replies: 2
Views: 166

Re: 8.117

The net mole is 2 (4 on products side-2 on reactants side), but you only want one mole of H2. So then you divide it by 3 to get 1 mole of H2. Because of that, change in moles is 2/3 (I think).
by Manvir2K
Sat Feb 10, 2018 4:42 pm
Forum: Entropy Changes Due to Changes in Volume and Temperature
Topic: 9.47 delta S = 0
Replies: 2
Views: 125

Re: 9.47 delta S = 0

In a reversible reaction, delta S is equal to 0 because all energy that is put into the system is able to be converted into useful work, so there is no change in entropy.
by Manvir2K
Fri Feb 02, 2018 4:20 pm
Forum: Van't Hoff Equation
Topic: Van't Hoff Eq.
Replies: 5
Views: 398

Re: Van't Hoff Eq.

∆S°is constant because the difference between the two ∆S°values is the same. This is because no matter what two values are taken, the difference for both values will be the same.
by Manvir2K
Fri Feb 02, 2018 4:12 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: dS, dV, dW
Replies: 2
Views: 108

Re: dS, dV, dW

I think it means that the change is so small that it does not matter in the long run.
by Manvir2K
Fri Feb 02, 2018 4:10 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: Work and Reversible Process [ENDORSED]
Replies: 2
Views: 116

Re: Work and Reversible Process [ENDORSED]

It does maximum work because less energy is lost as heat, while irreversible is done faster which causes more heat to be lost into the surroundings
by Manvir2K
Sun Jan 28, 2018 3:51 pm
Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
Topic: isothermal system
Replies: 4
Views: 185

Re: isothermal system

Internal energy is a state function, but work is not. Therefore, how the change in internal energy occurred doesn't matter since it will always be 0 in isothermal system. However, the path that work takes is important and needs to be calculated, since it doesn't always equal 0 in an isothermal syste...
by Manvir2K
Sun Jan 28, 2018 3:45 pm
Forum: Calculating Work of Expansion
Topic: irreversible system
Replies: 2
Views: 116

Re: irreversible system

Since entropy is a state function, it doesn't matter what path was used to get to the final condition. Therefore, to find entropy for irreversible system, you can use the same formula that is used for reversible system since it doesn't matter how the final entropy was reached.
by Manvir2K
Sun Jan 28, 2018 3:42 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: which w formula to use
Replies: 2
Views: 103

Re: which w formula to use

Yes, this formula is used when Pressure it constant.
by Manvir2K
Sat Jan 20, 2018 1:23 pm
Forum: Thermodynamic Systems (Open, Closed, Isolated)
Topic: Is there a way specific way to approach into seeing if open closed or isolated?
Replies: 9
Views: 332

Re: Is there a way specific way to approach into seeing if open closed or isolated?

Dr. Lavelle's Examples:
Open: beaker of water because water can evaporate and no insulation is involved
Closed: sealed beaker of water because no evaporation or insulation is involved
Isolated: combustion of glucose I na bomb calorimeter because nothing is exchanged with the surroundings
by Manvir2K
Sat Jan 20, 2018 1:18 pm
Forum: Concepts & Calculations Using First Law of Thermodynamics
Topic: Done By The System vs. Done On the System
Replies: 3
Views: 133

Re: Done By The System vs. Done On the System

Done By The System: q= -
Done On the System: q= +
by Manvir2K
Sat Jan 20, 2018 1:10 pm
Forum: Phase Changes & Related Calculations
Topic: Why does steam cause severe burns?
Replies: 4
Views: 162

Re: Why does steam cause severe burns?

Since there is more heat supplied when trying to convert water into vapor than water into liquid, steam causes more severe burns because the enthalpy of condensation/sublimation is a large value.
by Manvir2K
Sat Jan 13, 2018 4:35 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: reaction enthalpies
Replies: 3
Views: 118

Re: reaction enthalpies

Since enthalpy is a state function, all one has to do is change the sign in the reverse reaction.
by Manvir2K
Sat Jan 13, 2018 4:32 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Bond enthalpies
Replies: 2
Views: 111

Re: Bond enthalpies

Since bond enthalpy reveals the energy amount present in the bond of atoms, bond enthalpy will allow us to figure out how much energy is needed to break or form a bond. They can only be used if everything is in the gas phase
by Manvir2K
Sat Jan 13, 2018 4:25 pm
Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
Topic: Heat vs thermal energy
Replies: 2
Views: 100

Re: Heat vs thermal energy

This is what I get from the internet and the book: I understand heat as transferring thermal energy between two things at different temperatures, while thermal energy is not being transferred, but is rather the sum of the kinetic and potential energies.

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