CHEMISTRY COMMUNITY

Manvir2K

An activated complex is the same as the transition state, which is not the same thing as an intermediate.

Manvir2K

It is an intermediate because it was formed during the reaction and got used up during the reaction-> no need to include it in the overall reaction.

Manvir2K

In this case, the answer to e is none. I think if the catalyst is on the rate-determining step, it lowers the activation energy which increases the rate constant.

Manvir2K

As long as you keep the units the same throughout the problem, you should get the same answer. Just make sure to use the constants that give you the same units.

Manvir2K

In the solutions manual, the answer is ClO- + I- -> IO- + Cl-. I am not sure which one is right though.

Manvir2K

I think the chloride ion is the intermediate because an intermediate has to be formed during the reaction. Cl already existed before the reaction took place, which is the reason it is not the the intermediate.

Manvir2K

This method works for 27 because it is in first order, while 35 is in second order. I think calculating the half lives that have occurred and multiplying the number by the half-life only works for 1st order.

Manvir2K

I think you might have converted the initial concentration from mol to mol incorrectly.

Manvir2K

If it is a galvanic cell, the more positive E° will be the cathode, and the less positive will be the anode since that is the only way for the cell to be spontaneous.

Manvir2K

When commenting on the entire reaction, the overall order should be given-the sum of all the orders of the reactants

Manvir2K

The left side is always there anode for a galvanic cell.

Manvir2K

Another commonly used inert conductor is graphite.

Manvir2K

I think galvanic cell is an electrochemical cell.

Manvir2K

Yes. When the book only has deltaS, it is only talking about deltaS of the system. Spontaneity can be found if we have total S.

Manvir2K

Since Enthalpy is a state function, it has an additive property. It does not matter what path was taken to reach the destination.

Manvir2K

I think it means refining (purifying) a metal through electrolysis which is using a direct electrical current to allow s non-spontaneous chemical reaction to occur.

Manvir2K

How do you get -6.01 kJ/mol or 4.35 kJ/mol from appendix 2A?

Manvir2K

The heat is negative because 40.0 kJ of energy is being transferred from a large reservoir to another reservoir.

Manvir2K

The net mole is 2 (4 on products side-2 on reactants side), but you only want one mole of H2. So then you divide it by 3 to get 1 mole of H2. Because of that, change in moles is 2/3 (I think).

Manvir2K

In a reversible reaction, delta S is equal to 0 because all energy that is put into the system is able to be converted into useful work, so there is no change in entropy.

Manvir2K

∆S°is constant because the difference between the two ∆S°values is the same. This is because no matter what two values are taken, the difference for both values will be the same.

Manvir2K

I think it means that the change is so small that it does not matter in the long run.

Manvir2K

It does maximum work because less energy is lost as heat, while irreversible is done faster which causes more heat to be lost into the surroundings

Manvir2K

Internal energy is a state function, but work is not. Therefore, how the change in internal energy occurred doesn't matter since it will always be 0 in isothermal system. However, the path that work takes is important and needs to be calculated, since it doesn't always equal 0 in an isothermal syste...

Manvir2K

Since entropy is a state function, it doesn't matter what path was used to get to the final condition. Therefore, to find entropy for irreversible system, you can use the same formula that is used for reversible system since it doesn't matter how the final entropy was reached.

Manvir2K

Yes, this formula is used when Pressure it constant.

Manvir2K

Dr. Lavelle's Examples:
Open: beaker of water because water can evaporate and no insulation is involved
Closed: sealed beaker of water because no evaporation or insulation is involved
Isolated: combustion of glucose I na bomb calorimeter because nothing is exchanged with the surroundings

Manvir2K

Done By The System: q= -
Done On the System: q= +

Manvir2K

Since there is more heat supplied when trying to convert water into vapor than water into liquid, steam causes more severe burns because the enthalpy of condensation/sublimation is a large value.

Manvir2K

Since enthalpy is a state function, all one has to do is change the sign in the reverse reaction.

Manvir2K

Since bond enthalpy reveals the energy amount present in the bond of atoms, bond enthalpy will allow us to figure out how much energy is needed to break or form a bond. They can only be used if everything is in the gas phase

Manvir2K

This is what I get from the internet and the book: I understand heat as transferring thermal energy between two things at different temperatures, while thermal energy is not being transferred, but is rather the sum of the kinetic and potential energies.

CHEMISTRY COMMUNITY

Search found 32 matches

Re: HW 15.85

Re: question 15.47

Re: HW 15.95 e

Re: Units for rate

Re: 15.101(a) Overall Reaction

Re: 15.47

Re: 15.27 vs 15.35

Re: 15.19

Re: Cell potential

Re: Terminology "first-order" [ENDORSED]

Re: Galvanic cell set up

Re: Inert Electrodes [ENDORSED]

Re: Galvanic vs electrochemical [ENDORSED]

Re: Is spontaneity determined by entropy or free energy?

Re: Hess's Law

Re: Electrolytically Refined

Re: 9.15

Re: 9.5

Re: 8.117

Re: 9.47 delta S = 0

Re: Van't Hoff Eq.

Re: dS, dV, dW

Re: Work and Reversible Process [ENDORSED]

Re: isothermal system

Re: irreversible system

Re: which w formula to use

Re: Is there a way specific way to approach into seeing if open closed or isolated?

Re: Done By The System vs. Done On the System

Re: Why does steam cause severe burns?

Re: reaction enthalpies

Re: Bond enthalpies

Re: Heat vs thermal energy