CHEMISTRY COMMUNITY

Rohan Chaudhari- 1K

So functional groups are on the final?

Rohan Chaudhari- 1K

Yes it would be the slow step

Rohan Chaudhari- 1K

A nucleophile is a chemical species that donates an electron pair to an electrophile to form a chemical bond in relation to a reaction

Rohan Chaudhari- 1K

You can aso use this equation for first order:

[A]=[Ainitial]e^(-k*t)

Rohan Chaudhari- 1K

Half life of first order reactions is linear while for second order it is not

Rohan Chaudhari- 1K

Yes you are right. Since C is a zero order, its concetration is ignored when determinining the rate of A and B

Rohan Chaudhari- 1K

Its 1-39 plus some of the integrated problems in the end of the section.

Rohan Chaudhari- 1K

You can also just use [A]=[A]initial * e^-kt, which is just a simplified verision of the ln[A]=-kt+ln[A]initial equation

Rohan Chaudhari- 1K

My TA said you should know how to derive them

Rohan Chaudhari- 1K

How do you calculate the time it takes for something to get to 15% of its initial concetration and 1/9th of its initial condition if you are given only its half life?

Rohan Chaudhari- 1K

It's usually on the left, but you can write it on the right.

Rohan Chaudhari- 1K

N is the number of moles

Rohan Chaudhari- 1K

Why is it AgBr+e- ==>Br- + Ag and not just Br + e- ==> Br-?

Rohan Chaudhari- 1K

There is no need to know how to derive anything, but knowing how to derive can be helpful for solving the problems, how the equations relate to one another, and thinking through the problems.

Rohan Chaudhari- 1K

For the problem 9.69, do you just multiply the deltaG of the NADH reaction by 3 and divide it by the delta G of the reaction for ATP?

Rohan Chaudhari- 1K

An intensive property does not rely on the mass of the substance while an extensive property does.

Rohan Chaudhari- 1K

Delta S of the universe must equal 0, which happens in reversible reactions at equilibriums.

Rohan Chaudhari- 1K

All reactions at equillibrium are reversible as the nature of equilibirums (flow in both directions) requires the reaction to be reversible.

Rohan Chaudhari- 1K

The Kekule structure looks like this (https://www.google.com/search?q=Kekule+ ... 9WukM-NQWM:).

Rohan Chaudhari- 1K

Its residual molar entropy, therefore SO2F2 must be a mole.

Rohan Chaudhari- 1K

Delta S can only be zero in an equilibrium, one way to think about that could be that disorder and order are equal. Likewise, entropy in the universe is always increasing.

Rohan Chaudhari- 1K

Just to add on, spontaneity refers to the fact that the reaction is favored to occur. An example of this concept would be a boulder on a hill, as it would likely roll down the hill.

Rohan Chaudhari- 1K

There is no direct correlation between the two as they are dependent on different things.

Rohan Chaudhari- 1K

Since gasoline is inputted into the engine and stuff is also outputted(heat/gas), it is an open system.

Rohan Chaudhari- 1K

1 atm is equal to 760 torr. The unit for P in w=-PdeltaV is usually in atm as the answer to this equation is then usually converted to J using (101.325J/L*atm).

Rohan Chaudhari- 1K

"Assuming that the heat capacity of an ideal gas is independent of temperature, calculate the entropy change associated with raising the temperature of 1.00 mol of ideal gas atoms reversibly from 37.6 C to 157.9 C at a) constant pressure and b) constant volume" What exactly is the question...

Rohan Chaudhari- 1K

The reason it is negative is because the temperature raises, meaning that the reaction had to release energy. The reason it is just q=C*deltaT is because it is the equation for the calorimeter, which does not include mass.

Rohan Chaudhari- 1K

A reversible process is one where you can go backwards in the process at any time without increasing entropy. This can only happen during an equilibrium.

Rohan Chaudhari- 1K

The exercise in question- A constant-volume calorimeter was calibrated by carrying out a reaction known to release 3.50 kJ of heat in 0.200L of solution in the calorimeter, (q=-3.50kJ) resulting in a temperature rise of 7.32C. In a subsequent experiment, 100.0 mL of 0.200 M HBr(aq) and 100.0 mL of 0...

Rohan Chaudhari- 1K

Work and heat are two different forms of energy transfer. Work is the mechanical transfer of energy while heat is the thermal.

Rohan Chaudhari- 1K

A dead plant does not transfer heat with its surroundings so it is not an open loop.

Rohan Chaudhari- 1K

Can someone please explain what the different work equations are and when you use them? I'm having trouble identifying which to use in the homework.

CHEMISTRY COMMUNITY

Search found 32 matches

Re: Functional Groups

Re: Reaction Mechanism Steps

Re: What are nucleophiles?

Re: Equation variations

Re: Half Life for First Order vs Second Order

Re: 15.17

Re: Homework Problems

Re: problem 15.23B

Re: Kinetics Test/Final

15.27

Re: Galvanic cell set up

Re: n

14.15a

Re: Midterm

Problem 9.69

Re: Extensive vs Intensive

Re: delta S(system) vs delta S(surroundings)

Re: equilbrium = reversible

Re: 8.77

Re: 9.25 Avogadro's Number?

Re: ΔS(universe)

Re: Spontaneous

Re: What is the relationship between reversibility and spontaneity of a reaction?

Re: Car Engine [ENDORSED]

Re: Units

Question 9.7

Re: Ch 8 #53 Part b

Re: Reversible Processes

8.25

Re: Work vs. Heat

Re: living plant

Work equations