Search found 71 matches
- Sat Mar 17, 2018 7:28 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Catalyst vs Intermediate
- Replies: 1
- Views: 405
Catalyst vs Intermediate
Would it be safe to say that the difference between a catalyst and an intermediate is that an intermediate is produced in one step and consumed in the following step and a catalyst is used in one step and can be a product of a following step?
- Sat Mar 17, 2018 7:01 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: 15.69
- Replies: 1
- Views: 373
15.69
In the solutions's manual, the A's seem to be cancelled out. Why can we do this, when the question says that they are different values?
- Sat Mar 17, 2018 6:11 pm
- Forum: Second Order Reactions
- Topic: Half-lives of first order versus second order
- Replies: 1
- Views: 401
Half-lives of first order versus second order
For some of the homework problems in Chapter 15, the problem asked to find the time it would take for the concentration to get to 1/4 or 1/8 of its original value. For a first order reaction, I worked it out that if the half life was, for example, 100 seconds and this was the value for the initial c...
- Sat Mar 17, 2018 5:04 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Collision Theory vs Transition State Theory [ENDORSED]
- Replies: 1
- Views: 390
Collision Theory vs Transition State Theory [ENDORSED]
Is the Transition State Theory just a more broad concept than the Collision theory?
- Sat Mar 17, 2018 2:27 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Using Appendix 2A
- Replies: 2
- Views: 540
Using Appendix 2A
For some of the problems in Chapter 14, we have notice that when comparing two cell potentials from Appendix 2A, the lower or more negative cell potential means that half-reaction is an anode and therefore the more positive one is the cathode. However, in other questions when using Appendix 2A, some...
- Sat Mar 17, 2018 2:15 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.27
- Replies: 1
- Views: 298
14.27
For this type of problem, is it recommended to not multiply by F and then at the end just cancel out the F's. Or will we get the same answer if we multiply and divided by F?
- Wed Mar 07, 2018 7:10 pm
- Forum: First Order Reactions
- Topic: half-lives of first order versus second order
- Replies: 3
- Views: 568
half-lives of first order versus second order
When a question asks "how much time will elapse in a first order reaction for the concentration of A to decrease to 1/8[A] (not), I plug in ln(1/8) = -kt + (ln(1)) and I seem to get the right answer every time. However, if it were a second-order reaction and I tried using the same method, for e...
- Wed Mar 07, 2018 4:57 pm
- Forum: Zero Order Reactions
- Topic: Units of K based on the order
- Replies: 3
- Views: 1122
Units of K based on the order
Can someone explain why the units of k for zero, first, and second order reactions are mol/L sec, s^-1, and L/mol sec, respectively?
- Fri Mar 02, 2018 2:59 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: E = E^o - (RT/nF) ln Q [ENDORSED]
- Replies: 4
- Views: 661
E = E^o - (RT/nF) ln Q [ENDORSED]
When using this formula, what values of R and T would we use?
- Thu Mar 01, 2018 10:29 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Example 14.4 [ENDORSED]
- Replies: 1
- Views: 285
Example 14.4 [ENDORSED]
Mercury is a toxic heavy metal pollutant whose concentration in aqueous solution depends in part on the redox properties of compounds containing mercury. Suppose you are studying the properties of mercury. You might need to construct an electro- chemical cell; you then would need to write down the c...
- Thu Mar 01, 2018 10:21 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Order of Cell Diagrams [ENDORSED]
- Replies: 1
- Views: 261
Order of Cell Diagrams [ENDORSED]
In cell diagrams, how do we order the compounds or molecules on one of the sides of the salt bridge. For example, for the anode, are we supposed to order the electrodes in a specific order? Like by alphabetical order of states or by reactants then products? I'm not sure this question made any sense.
- Thu Mar 01, 2018 9:55 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Salt Bridge [ENDORSED]
- Replies: 1
- Views: 299
Salt Bridge [ENDORSED]
What would be an example of a reaction that does not need a salt bridge and therefore we would not put double lines in the cell diagram?
- Thu Mar 01, 2018 5:06 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Finding the value of n
- Replies: 1
- Views: 311
Finding the value of n
This is a question about Self-Test 14.3A: The reaction taking place in a nicad (nickel–cadmium) cell is Cd(s) + 2 Ni(OH)3(s) --> Cd(OH)2(s) + 2 Ni(OH)2(s), and the cell potential when fully charged is 1.25 V. What is the reaction Gibbs free energy? I understand that we are supposed to use the formul...
- Thu Mar 01, 2018 11:47 am
- Forum: First Order Reactions
- Topic: 15.21
- Replies: 3
- Views: 1095
15.21
The problem is: Beta blockers are drugs that are used to manage hypertension. It is important for doctors to know how rapidly a beta blocker is eliminated from the body. A certain beta blocker is eliminated in a rst-order process with a rate constant of 7.6 10 3 min 1 at normal body temperature (37 ...
- Thu Mar 01, 2018 11:36 am
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: 15.19
- Replies: 4
- Views: 545
15.19
For this problem, I am getting the right numbers however they are off by several powers of 10. For part c, why is the value of k = 2.85 x10^12? I found that k was equal to 2.85 when dividing 8.7 by (1.25^5). Then when I tried finding the initial rate from the given concentrations, I got a number tha...
- Thu Mar 01, 2018 11:08 am
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: 15.15 [ENDORSED]
- Replies: 5
- Views: 754
15.15 [ENDORSED]
What are the orders of the reactants for this question?
- Thu Feb 22, 2018 11:20 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.15c
- Replies: 1
- Views: 279
14.15c
In the cell diagram for this part, why is there a KOH instead of simply OH?
- Thu Feb 22, 2018 9:57 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.13d
- Replies: 3
- Views: 470
14.13d
Why are the half reactions Au+(aq) + e- --> Au(s) and Au(s) --> Au3++ 3e-?
- Thu Feb 22, 2018 9:49 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: double lines between anode and cathode
- Replies: 3
- Views: 582
double lines between anode and cathode
Are the double lines between the anode and cathode always used, or is there any situation where the cell diagram would not have the double lines?
- Thu Feb 22, 2018 9:47 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.13c
- Replies: 1
- Views: 232
14.13c
How did the solutions manual get the anode and cathode reactions that they got for part c of 14.13? How do we know to separate HCl?
- Thu Feb 22, 2018 9:41 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Metals in Cell Diagrams
- Replies: 3
- Views: 502
Metals in Cell Diagrams
Does the metal always have to be a solid to be used as an electrode?
- Fri Feb 16, 2018 9:20 am
- Forum: Balancing Redox Reactions
- Topic: The use of H3O+ versus H+
- Replies: 2
- Views: 894
The use of H3O+ versus H+
When balancing the redox reaction, we have to balance the oxygens by adding H2O, but then it causes there to be a difference of hydrogens on the reactant side versus product side. When balancing these hydrogens, should we use H3O + or H+?
- Tue Feb 13, 2018 3:36 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: calorimeter problems
- Replies: 2
- Views: 403
Re: calorimeter problems
Yes, for a bomb calorimeter problem, the equation for q is q=CdeltaT
- Tue Feb 13, 2018 3:01 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Constant Volume
- Replies: 2
- Views: 232
Re: Constant Volume
At constant volume, w = 0, therefore, the equation delta U = q +w would be delta U = q. However, q would only be equal to delta H if the reaction was also at constant pressure.
- Tue Feb 13, 2018 2:56 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Delta H at constant pressure
- Replies: 2
- Views: 365
Re: Delta H at constant pressure
Delta H is not necessarily equal to 0 at constant pressure. At constant pressure delta H is equal to q. Therefore if q were equal to 0 at constant pressure, then delta H would also be 0
- Tue Feb 13, 2018 2:40 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Isothermal Process
- Replies: 1
- Views: 484
Isothermal Process
If in an isothermal process there is no change in temperature, why wouldn't the value of q be 0, since the equation is q = mCdeltaT. Why isn't this delta T equal to 0 due to the fact that the process is isothermal?
- Tue Feb 13, 2018 2:35 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Isothermal Systems and deltaU
- Replies: 2
- Views: 314
Re: Isothermal Systems and deltaU
yes. Thus making w = -q
- Sun Feb 11, 2018 9:44 am
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: 9.13 - Use of Cv
- Replies: 2
- Views: 295
9.13 - Use of Cv
In the "Errors in the solution manual", when finding the entropy due to the change in temperature, Cv is used and has a value of 5/2R. I understand why it would be 5/2R instead of 3/2R since it is a diatomic molecule. However, I do not understand why Cv was used, since there was a change i...
- Sat Feb 10, 2018 9:46 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.99: Enthalpy Values
- Replies: 2
- Views: 432
8.99: Enthalpy Values
Hydrochloric acid oxidizes zinc metal in a reaction that produces hydrogen gas and chloride ions. A piece of zinc metal of mass 8.5 g is dropped into an apparatus containing 800.0 mL of 0.500 m HCl(aq). If the initial temperature of the hydrochloric acid solution is 25 C, what is the nal temperature...
- Sat Feb 10, 2018 9:00 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.85 Part C
- Replies: 1
- Views: 460
8.85 Part C
The oxidation of nitrogen in the hot exhaust of jet engines and automobile engines occurs by the reaction N2 (g) + O2 (g) 2 NO (g) ΔHo = +180.6 kJ Part C: When the oxidation of N2 to NO was completed in a bomb calorimeter, the heat absorbed was measured as 492 J. What mass of nitrogen gas was oxidiz...
- Sat Feb 10, 2018 8:54 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: delta H vs delta H naught
- Replies: 2
- Views: 1180
delta H vs delta H naught
Is it correct to say that the units of delta H are only in kJ or J and that the units of delta H naught are only in kJ/mol or J/mol?
- Sat Feb 10, 2018 8:15 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpies
- Replies: 2
- Views: 336
Bond Enthalpies
When using bond enthalpies to solve for the enthalpy of formation, does it only give us the value of the compound in its gas form?
- Sat Feb 10, 2018 8:14 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Table 8.3
- Replies: 1
- Views: 378
Table 8.3
Question 8.67 asked us to use tables 3, 6, and 7. For part A, we have to find the enthalpy of formation of H20, and we do this using bond enthalpies which are found in tables 6 and 7. However, this only gives us the enthalpy of water in the gas form. Therefore we have to use the formula ∆Hvap = H(va...
- Sat Feb 10, 2018 7:52 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.65
- Replies: 1
- Views: 345
8.65
In the solution's manual, they show the reaction that we are trying to get which is N2 + 5/2 O2 --> N2O5. Then they add the two given equations together and solve for the enthalpy of this new reaction. Then they set the enthalpy of this reaction set equal to the enthalpy of formation of N2O5 minus t...
- Thu Feb 08, 2018 8:33 am
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Extensive Property?
- Replies: 3
- Views: 458
Re: Extensive Property?
An extensive property is dependent on the amount of matter present, while an intensive property does not depend on this amount. An extensive property would be heat capacity, for example. This is because the larger the amount of the substance, the more heat that is required to raise its temperature.
- Sun Feb 04, 2018 8:26 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: thermodynamically favored
- Replies: 6
- Views: 1355
Re: thermodynamically favored
just free energy
- Sun Feb 04, 2018 8:26 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond enthalpies vs. enthalpy of formation
- Replies: 1
- Views: 332
Re: Bond enthalpies vs. enthalpy of formation
The key word here is formation. The formation of bonds requires energy. When finding enthalpies of formation for an entire reaction using the change in enthalpy at standard state of molecules, you can rely on enthalpy's status as a state function and subtract the change in enthalpy of the reactants ...
- Sun Feb 04, 2018 7:46 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: 8.53
- Replies: 2
- Views: 326
Re: 8.53
The balanced equation would be CO(g) + H2O(g) →CO2(g) + H2(g). Water vapor is water but in gas form. Hydrogen gas is H2.
- Sat Jan 27, 2018 3:25 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Utotal of Ideal Gas
- Replies: 3
- Views: 492
Re: Utotal of Ideal Gas
The molar heat capacity for a monatomic gas at constant volume, C (v,m) is 3/2R. Therefore when we use the equation q = nC(m)deltaT, we get q = n 3/2RdeltaT, when we plug in our molar heat capacity for a monatomic gas. Since this molar heat capacity is at constant volume, delta V = 0 and therefore w...
- Fri Jan 26, 2018 10:41 am
- Forum: Phase Changes & Related Calculations
- Topic: 8.41
- Replies: 6
- Views: 775
8.41
Why when calculating the heat of the ice cube do we use the specific heat capacity of water (4.184)? Why wouldn't we use the specific heat capacity of ice (2.108)?
- Fri Jan 26, 2018 10:32 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.57 Hess's Law [ENDORSED]
- Replies: 3
- Views: 955
Re: 8.57 Hess's Law [ENDORSED]
The first step in finding the change in enthalpy of combustion reactions is creating each combustion reaction and balancing each equation. The problem gives you the compounds in which you have to make a combustion reaction for. For each compound you add 02 as a reactant and the products would be CO2...
- Sun Jan 21, 2018 11:05 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: the sign of q
- Replies: 5
- Views: 495
the sign of q
How do we determine whether the sign on q is positive or negative, if we are only given the number and not the sign? For example, if it said that it required 5.5 kJ of heat. How would we know if that value was positive or negative?
- Sun Jan 21, 2018 10:58 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Homework Problem
- Replies: 2
- Views: 254
Re: Homework Problem
This relates to the concept of rotational kinetic energy. The more complex a molecule, such as being composed of molecules versus being monatomic, the greater the molar heat capacity due to rotational kinetic energy and translational kinetic energy.
- Sun Jan 21, 2018 10:47 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Converting L·atm to Joules
- Replies: 3
- Views: 9308
Re: Converting L·atm to Joules
It would also be the same as using the differing values of R, depending on the units. 8.314 J·K-1·mol-1 = 8.206 x 10-2 L·atm·K-1·mol-1. Therefore you could multiply your answer that is in L·atm by (8.314 J·K-1·mol-1/8.206 x 10-2 L·atm·K-1·mol-1)
- Sun Jan 21, 2018 10:40 pm
- Forum: Calculating Work of Expansion
- Topic: Test 1
- Replies: 3
- Views: 457
Test 1
Will there be reversible processes on Test 1?
- Tue Jan 16, 2018 8:19 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Heat Capacity: U vs H
- Replies: 2
- Views: 164
Heat Capacity: U vs H
In regards to heat capacity, is it safe to assume that when we are finding the heat capacity at constant volume, we use U and when we are finding the heat capacity at constant pressure, we use H? Also, ignoring heat capacity, when we are simply finding delta H, is it always at a constant pressure, o...
- Sun Jan 14, 2018 5:29 pm
- Forum: Phase Changes & Related Calculations
- Topic: Isolated vs Closed Systems
- Replies: 2
- Views: 210
Isolated vs Closed Systems
What is the difference between an isolated and closed systems in relevance to question 8.1?
- Fri Dec 08, 2017 10:41 pm
- Forum: Bronsted Acids & Bases
- Topic: 12.27
- Replies: 1
- Views: 253
Re: 12.27
For part b, the first step would be to use the formula: M(initial)V(initial) = M(final)V(Final) The initial M is given: .025 The initial volume is given: 200mL --> .200L The final volume is also given: 250mL --> .250 Therefore by solving (.200)(.025) = (.250)x, you get the final concentration is equ...
- Fri Dec 08, 2017 5:10 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Lewis Structure of [HgF2(OH2)2]+
- Replies: 1
- Views: 314
Lewis Structure of [HgF2(OH2)2]+
What would the Lewis Structure of [HgF2(OH2)2]+ look like, since Hg is part of the d elements?
- Fri Dec 08, 2017 12:25 am
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: 12.7
- Replies: 2
- Views: 531
Re: 12.7
Conjugate bases is the compound remaining after an acid has donated a proton (H+). Therefore in reference to this problem, the conjugate base would be drawn by removing the one H atom, which is the H+ proton that the acid donates. The conjugate base of the given acid would just be without the Hydrog...
- Fri Dec 08, 2017 12:13 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: If K is large or small
- Replies: 1
- Views: 593
Re: If K is large or small
Yes that is correct. The value of K is found by dividing the concentrations of the products by the concentrations of the reactants. Therefore, K would be small if there was a much higher value for the concentration of reactants than for the products, therefore there are more reactants than products
- Thu Dec 07, 2017 11:45 pm
- Forum: Bronsted Acids & Bases
- Topic: Lone Pair of Bronsted
- Replies: 1
- Views: 195
Lone Pair of Bronsted
Do Bronsted Bases always have a lone pair? Is this the defining characteristic to determine that the base is Bronsted?
- Thu Dec 07, 2017 11:03 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Cubic equations [ENDORSED]
- Replies: 2
- Views: 283
Re: Cubic equations [ENDORSED]
Cubic equations form due to "x" being in the change part of the ICE table. In terms of simplifying the cubic equation, when K < 10^-3, it is taken out of the cubic equation, since it is nearing 0 and will get answers that are different than the actual answer.
- Tue Nov 28, 2017 5:57 pm
- Forum: Ideal Gases
- Topic: Kc to Kp Conversion
- Replies: 5
- Views: 939
Re: Kc to Kp Conversion
The concentration would be in reference to the specific molar concentration of the compound whose partial pressure is being used in the equation.
- Tue Nov 28, 2017 5:49 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Ch 11 #47
- Replies: 1
- Views: 1065
Re: Ch 11 #47
The first step is to find the moles of PCl5 from the given amount of PCl5 in grams, which is 1.0g. You would divide the 1.0g by the molar mass of PCl5 to get the amount of moles, which came out to be .019 moles of PCl5 For the I portion of the table: PCl5: .019, PCl3: 0, Cl2: 0 For the C portion of ...
- Sun Nov 26, 2017 2:15 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Homework Help 11.43
- Replies: 1
- Views: 279
Re: Homework Help 11.43
The equation used for this problem would be K = (Pn2)(Po2)/(Pno)^2. The equilibrium relation is equal to the Pressures of the reactants divided by the products, but for this the produce NO has a stoichiometric coefficient of 2, which is why it is squared.
- Sun Nov 26, 2017 1:55 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Test #4
- Replies: 1
- Views: 226
Re: Test #4
Test 4 covers material up to HW 11.63
- Sun Nov 19, 2017 3:52 pm
- Forum: Hybridization
- Topic: Filling the hybrid orbitals?
- Replies: 12
- Views: 1893
Re: Filling the hybrid orbitals?
Each carbon in C2H2 is sp^2 hybridized. There are two carbons in the equation, which means the hybridization is 2sp^2
- Sun Nov 19, 2017 3:21 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Cis- & Trans-
- Replies: 3
- Views: 274
Re: Cis- & Trans-
Trans isomers tend to be non polar or less polar than cis isomers, which tend to be polar, which is a characteristic of their higher boiling points and lower melting points
- Sun Nov 12, 2017 12:00 pm
- Forum: Hybridization
- Topic: Electron Promotion of Carbon [ENDORSED]
- Replies: 2
- Views: 993
Electron Promotion of Carbon [ENDORSED]
In the book, it says that an electron is promoted in carbon, in order for carbon to have four valence electrons. Why do we write the electron configuration as [He] 2s^2 2p^2, when for most carbons in a molecule, we promote an electron so it is [He] 2s^1 2p^3? In other words why don't we just write t...
- Sun Nov 12, 2017 11:41 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: When to Use Radicals [ENDORSED]
- Replies: 2
- Views: 391
Re: When to Use Radicals [ENDORSED]
More electronegative elements have higher tendencies to pull electrons towards themselves. Therefore, the higher electronegative an electron the more likely the will want to obtain a full octet. For example, in the case of nitrogen monoxide (NO), there are 11 valence electrons that need tone placed ...
- Sun Nov 05, 2017 6:50 pm
- Forum: Lewis Structures
- Topic: Problem 3.59 Part A
- Replies: 4
- Views: 625
Re: Problem 3.59 Part A
Based on the periodic table, chlorine has seven valence electrons and oxygen has 6 electrons which is equal to 13 valence electrons, illustrating a violation of the octet rule, since it is an odd number of valence electrons. Therefore, chlorine would be without an 8th valence electrons, since there ...
- Sat Nov 04, 2017 5:36 pm
- Forum: Electronegativity
- Topic: ELECTRON AFFINITY
- Replies: 7
- Views: 1618
Re: ELECTRON AFFINITY
In relation to increasing electron affinity across a row, how would the electron affinities of the halogens compare to the electron affinities of the noble gases, if they are in the same row. For example, how would Chlorine and Argon relate in terms of electron affinity?
- Sat Oct 28, 2017 2:40 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron Configuration Exceptions [ENDORSED]
- Replies: 3
- Views: 536
Re: Electron Configuration Exceptions [ENDORSED]
My TA had said that they do continue down the columns, however we would not be asked specific questions about the electron configurations of those elements on the tests. We would only need to know that chromium and copper are exceptions to the electron configuration rule
- Sat Oct 28, 2017 2:34 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron configuration for Fe^2+ [ENDORSED]
- Replies: 2
- Views: 937
Re: Electron configuration for Fe^2+ [ENDORSED]
First, we can look at the electron configuration of Fe which is [Ar] 4s^2 3d^6, but we put it in the form [Ar] 3d^6 4s^2, based on 3 being at a lower energy level than 4. Fe 2+ needs to donate two valence electrons and these come from the highest energy level which would be 4s. For chromium it is mo...
- Thu Oct 19, 2017 9:37 am
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Wavelength Units
- Replies: 5
- Views: 697
Re: Wavelength Units
For most problems it is preferred that the value of the wavelength is in nanometers because it is then easier to see where along the electromagnetic spectrum the wavelength falls. Also, it could be useful to have the value in nanometers for when the next part of the questions asks for what type of r...
- Wed Oct 18, 2017 10:45 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Why don't we use the Rydberg equation from the book?
- Replies: 8
- Views: 941
Re: Why don't we use the Rydberg equation from the book?
There are also times where it would be faster to use the formula that the book had given us, which would be why they included it in the first place. However, the formula from the lecture better illustrates what is occurring as the change from one level to another occurs. If a question asked specific...
- Thu Oct 12, 2017 6:14 pm
- Forum: Properties of Light
- Topic: 1.23
- Replies: 4
- Views: 613
Re: 1.23
I know that we need to know some of the conversions and constants, but would we have to know that 1 eV is equal to 1.6022 x 10^-19 J for the test. Or would we just need to know how to use the number in the problem to get our answer and not memorize it.
- Thu Oct 12, 2017 1:13 pm
- Forum: Properties of Light
- Topic: Wavelengths and Frequency of Electromagnetic Radiation [ENDORSED]
- Replies: 7
- Views: 1076
Wavelengths and Frequency of Electromagnetic Radiation [ENDORSED]
For future tests about the Quantum World and the Properties of Light, will we need to know the range of wavelengths of visible light (400 - 700nm). Also, will we need to know what color is seen at which wavelength. For example, will a test problem have us solve for the wavelength and then have us de...
- Sat Oct 07, 2017 3:37 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: E9 [ENDORSED]
- Replies: 5
- Views: 4794
Re: E9 [ENDORSED]
Step 1: Since we know are calculating for formula units, we want to convert our grams of the compound to moles so we can use Avogadro's number which is 6.022 x 10^23 formula units/ mol 5.15g MgSO4 7H20 x 1 mol MgSO4 7H2O/ 246.48gMgSO4 7H2O (this is the molar mass of the compound). The grams would ca...
- Thu Oct 05, 2017 3:53 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: E9 [ENDORSED]
- Replies: 5
- Views: 4794
E9 [ENDORSED]
The question is: Epsom salts consist of magnesium sulfate heptahydrate. Write its formula. (a) How many atoms of oxygen are in 5.15 g of Epsom salts? (b) How many formula units of the compound are present in 5.15g? (c) How many moles of water molecules are in 5.15 g of Epsom salts? For part a, I und...