Search found 38 matches

by Alex Kashou
Sat Dec 09, 2017 10:12 pm
Forum: Amphoteric Compounds
Topic: amphoteric compounds pH
Replies: 1
Views: 276

Re: amphoteric compounds pH

They will usually have a set pH but depending on how they act that pH can fluctuate. You do not need to know how to caclulate the pH of amphoteric molecules on the final though to my knowledge.
by Alex Kashou
Fri Dec 08, 2017 8:18 am
Forum: Shape, Structure, Coordination Number, Ligands
Topic: Determining whether ligand is mono-, bi-, or polydentate
Replies: 3
Views: 245

Re: Determining whether ligand is mono-, bi-, or polydentate

You can't really do that but the best way in my opinion is to just look at how many N's there are because in an organic molecule they usually have a lone pair making them some form of a chelating complex
by Alex Kashou
Wed Dec 06, 2017 4:19 pm
Forum: Properties & Structures of Inorganic & Organic Acids
Topic: What is electron-withdrawing Power?
Replies: 1
Views: 175

What is electron-withdrawing Power?

I'm confused what this means exactly? Is electron withdrawing power the ability to pull an electron (aka electronegativity) and how does this make something more stable when it loses a proton?
by Alex Kashou
Mon Dec 04, 2017 9:17 pm
Forum: Identifying Acidic & Basic Salts
Topic: 12.65
Replies: 1
Views: 228

12.65

I kinda get how they are determing whether each is an acid or a base, but idk if they are getting their info from somewhere to ensure that they are acids or bases. Especially for part d, how is KBr nuetral while KF is basic?
by Alex Kashou
Sun Dec 03, 2017 8:52 pm
Forum: Sigma & Pi Bonds
Topic: What is a localized and delocalized Bond?
Replies: 5
Views: 6248

What is a localized and delocalized Bond?

I have no idea what the terms mean to be honest. Is localized meaning that it is just sigma bonds?
by Alex Kashou
Sun Dec 03, 2017 8:50 pm
Forum: Properties & Structures of Inorganic & Organic Acids
Topic: K values
Replies: 2
Views: 176

Re: K values

The higher the K value, the stronger the acid dissociation. Remember that K determines how which way the reaction proceed and how much it proceeds in which direction. If the K is large, it proceeds in favorably in the forward direction and favors products. Therefore, K values >1 are in favor of prod...
by Alex Kashou
Wed Nov 29, 2017 6:01 pm
Forum: Lewis Acids & Bases
Topic: J19 [ENDORSED]
Replies: 1
Views: 148

J19 [ENDORSED]

How come the two reactants are forming strong acids? This doesn't make any sense to me? Is this just theoretical?
by Alex Kashou
Wed Nov 29, 2017 5:59 pm
Forum: Bronsted Acids & Bases
Topic: Difference between Complete equation and Net Ionic Equation? [ENDORSED]
Replies: 1
Views: 142

Difference between Complete equation and Net Ionic Equation? [ENDORSED]

So I am doing the J problems of acids and bases and I am confused on the difference between the complete equation and Net Ionic equation. I understand that the Net ionic equation. I can't tell when to exclude the chemicals that dissociate in water like Na+ or Cl-.
by Alex Kashou
Tue Nov 28, 2017 2:44 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: 11.89 Part b
Replies: 2
Views: 213

11.89 Part b

Why are all the values divided by 100 when calculating the K. I understand how they got the stoichiometric coefficients by making an ICE chart but there is no info that I see that indicates that the kPa needs to be divided by 100.
by Alex Kashou
Sun Nov 26, 2017 9:00 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Symmetrical Molecules
Replies: 3
Views: 210

Re: Symmetrical Molecules

Yes; for example, CH2Cl is symmetrical about the C but the Cl is more electronegative resulting in a greater pull towards that location of the symmetrical shape. Therefore, the molecule is polar because there is distinct dipole moment on one side of the molecule.
by Alex Kashou
Sun Nov 26, 2017 8:58 pm
Forum: Hybridization
Topic: Hybridization
Replies: 5
Views: 239

Re: Hybridization

It allows the molecule to create more openings for bonds with other molecules that, as a result, have a lower overall energy and therefore more stable.
by Alex Kashou
Fri Nov 24, 2017 9:44 am
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Calculating K from manipulations of Equation
Replies: 1
Views: 107

Calculating K from manipulations of Equation

Why do we square our K when we double our chemical equation? Similarly, why do we square root the K when we halve it as well?
by Alex Kashou
Fri Nov 24, 2017 9:39 am
Forum: Ideal Gases
Topic: 11.7 Part a
Replies: 3
Views: 257

11.7 Part a

Does anyone know why flask 3 is the flask that most resembles a reaction that has reached equilibrium because flask 3 and 4 look exactly the same to me in terms of molecules.
by Alex Kashou
Fri Nov 24, 2017 9:35 am
Forum: Hybridization
Topic: Hybridization of Single Bonded Oxygen
Replies: 1
Views: 144

Re: Hybridization of Single Bonded Oxygen

A single bonded oxygen is not hybridized because it has not converted to its lowest energy form. It has 2 open orbitals to open electrons with by default in its ground state, therefore making its first bonding unhybridized.
by Alex Kashou
Tue Nov 14, 2017 10:16 am
Forum: Dipole Moments
Topic: 4.25 part a
Replies: 2
Views: 154

4.25 part a

Ok so i understand that the dipoles in CH2Cl2 will point towards the Cl's because they are more electronegative and I see through structure how it can be polar. But doesn't it depend on where the Cl and H are placed in order to determine if it is polar. Because if the Cl are directly across from eac...
by Alex Kashou
Mon Nov 13, 2017 9:27 pm
Forum: Electronegativity
Topic: Isoelectronic [ENDORSED]
Replies: 11
Views: 542

Re: Isoelectronic [ENDORSED]

Atoms and ions have the same number of electrons. For example, Na+, Mg+2, F-, and Ne are isolectronic because they have the same amount of electrons.
by Alex Kashou
Sun Nov 12, 2017 8:29 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Molecular shape vs Electron arrangement
Replies: 2
Views: 173

Re: Molecular shape vs Electron arrangement

Molecular shape is the shape of the molecule that is formed as a result of the electron arrangement. Electron arrangement is the position of the electrons on a molecule, which help to determine the shape due to repulsion forces. Thus, where the electrons are placed and how many are in that region de...
by Alex Kashou
Sun Nov 12, 2017 8:27 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Bond Angles
Replies: 4
Views: 241

Re: Bond Angles

Yes. It is put in the notes and basically all the homework questions relating to molecular shape so I'm pretty positive.
by Alex Kashou
Wed Nov 08, 2017 6:19 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Unpaired Electrons [ENDORSED]
Replies: 7
Views: 330

Re: Unpaired Electrons [ENDORSED]

Draw out their orbitals by determining which subshell they are in. All the spots with only 1 "arrow" or electron in them is an unpaired electron.
by Alex Kashou
Tue Nov 07, 2017 10:14 am
Forum: Student Social/Study Group
Topic: DOWNLOAD PRACTICE MIDTERM HERE: Lyndon and Michael's session
Replies: 7
Views: 1109

Re: DOWNLOAD PRACTICE MIDTERM HERE: Lyndon and Michael's session

For number 1, how is the answer C24H42O21? Once I divided by the molar masses, I got 3.5967 moles of C, 6.2996 moles of H, and 3.15 moles of O. I divided all three by 3.15 to get the ratio 1.14 C, 2 H, and 1 O. Then I multiplied each number by 7 to get whole numbers and got C7H14O7 for the empirica...
by Alex Kashou
Tue Nov 07, 2017 10:06 am
Forum: Ionic & Covalent Bonds
Topic: oxidation state
Replies: 3
Views: 220

Re: oxidation state

Oxidation state is basically its charge or the state of an atom when it is not in its ground state (i.e. excited). Chlorine technically can have both positive and negative charges, although you will almost never see it with a positive oxidation state because it has such a large electron affinity and...
by Alex Kashou
Sat Nov 04, 2017 4:14 pm
Forum: Lewis Structures
Topic: Lewis Structure
Replies: 4
Views: 455

Re: Lewis Structure

When looking at a molecule that is complex like this, you should follow the way in which the elements are ordered. So ClONO2 would have cl on the far left connected to an O, then with an NO2 ion connected to that O as well. This is a general rule I learned in AP chem because we have not learned how ...
by Alex Kashou
Thu Nov 02, 2017 9:16 am
Forum: Lewis Structures
Topic: Question 3.95
Replies: 3
Views: 155

Re: Question 3.95

It is forming an octet because each Carbon has 2 single bonds to each H and then 1 single bond to the central carbon and last 2 loose electrons. In total that is 8. The central Carbon however has 2 single bonds to 2 of the carbons and 1 double bond which is also 8. Therefore, they all satisfy the oc...
by Alex Kashou
Wed Nov 01, 2017 6:36 pm
Forum: Lewis Structures
Topic: Question 3.95
Replies: 3
Views: 155

Re: Question 3.95

Its the C in the CH2 that has only 4 valence electrons because you do not calculate formal charges on hydrogen atoms. Thus, the solution manual is correct in finding the lowest energy form of this molecule. A better way to look at this is to actually draw out the CH2's that are connect to the centra...
by Alex Kashou
Tue Oct 31, 2017 10:08 am
Forum: Lewis Structures
Topic: 3.39 Format in Answer Sheet
Replies: 3
Views: 218

3.39 Format in Answer Sheet

So I was pretty sure I understood how to write the lewis structure for each of these compounds. However, in the answer sheet the structures are drawn based on their ions and not together. I was wondering why and do we always do this for molecules that are composed of ions.
by Alex Kashou
Tue Oct 31, 2017 10:05 am
Forum: Trends in The Periodic Table
Topic: 2.81 – Oxygen Anomaly
Replies: 2
Views: 187

Re: 2.81 – Oxygen Anomaly

The reason for this anomaly is because oxygen is the first element in its sub-shell to have a paired electron in one of its orbitals. Thus, there is added repulsion between those two electrons. Therefore, Oxygen wants to lose that electron so it can be even in all of the orbitals which is lower ener...
by Alex Kashou
Tue Oct 24, 2017 9:45 pm
Forum: Trends in The Periodic Table
Topic: Problem 2.67 (c) and (d)
Replies: 2
Views: 153

Re: Problem 2.67 (c) and (d)

The reason that as you go up a group electron affinity is higher is because the atomic radius is smaller and thus the electron that it is trying to gain is more easily "pulled" into the element. Think of it as a smaller circle with a center that emits a pull on the electrons. If the circle...
by Alex Kashou
Mon Oct 23, 2017 9:35 pm
Forum: Trends in The Periodic Table
Topic: 2.67 part B
Replies: 4
Views: 212

2.67 part B

I understand that electron affinity is the energy released when an electron is added to an atom. I also understand the trend that as you go up and to the right of the periodic table electron affinity increased. Therefore, why does Carbon have a higher electron affinity than nitrogen?
by Alex Kashou
Mon Oct 23, 2017 9:33 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Sequen of Orbitals
Replies: 4
Views: 215

Re: Sequen of Orbitals

Yes we are supposed to put the 4s after the 3d. This is because we are going by increasing energy levels and the 3d subshell is lower energy. However, the 4s subshell fills up before the 3d which is why in highschool we learned to write it 4s3d.
by Alex Kashou
Tue Oct 17, 2017 8:03 pm
Forum: DeBroglie Equation
Topic: Wavelike Properties
Replies: 3
Views: 348

Re: Wavelike Properties

Well it really depends on the experiment. In the photoelectric effect, it acts as a particle because it needs a certain amount of energy to eject a photon. Thus, each particle of light must act like a particle. However, in the De Brogile experiment with the slits, it was observed that there were dif...
by Alex Kashou
Sat Oct 14, 2017 9:31 am
Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
Topic: 1.57 [ENDORSED]
Replies: 1
Views: 127

1.57 [ENDORSED]

Lines in the Balmer series of the hydrogen spectrum are observed at 656.3, 486.1, 434.0, and 410.2nm. What is the wavelength of the next line in the series. Okay so I understand i need to use v=R(1/(n^2)- 1/(n^2)) (sorry its not perfect but you know the formula). I know the Balmer series starts n1=2...
by Alex Kashou
Thu Oct 12, 2017 5:38 pm
Forum: *Black Body Radiation
Topic: Black Body? [ENDORSED]
Replies: 13
Views: 1060

Re: Black Body? [ENDORSED]

A black body is any object that can absorb any incoming light. It is emits thermal heat due to its high absorption rate. However, if it gets too hot it starts to emit light (glow) from increased amounts of thermal radiation. Thus, all you really need to know is that it is a black body that can absor...
by Alex Kashou
Tue Oct 10, 2017 11:34 am
Forum: DeBroglie Equation
Topic: Chapter 1 #33 a [ENDORSED]
Replies: 1
Views: 169

Chapter 1 #33 a [ENDORSED]

The velocity of an electron that is emitted from a metallic surface by a photon is 3.6x10^3km/s.
a) What is the wavelength of the ejected electron?

I understand that I must use lambda=h/p and that p=mv. We have v and h is a constant so how do I get m?
by Alex Kashou
Mon Oct 09, 2017 6:33 pm
Forum: Properties of Light
Topic: Chapter 1 #3 c
Replies: 1
Views: 146

Chapter 1 #3 c

Which of the following happens when the frequency of electromagnetic radiation decreases? c) The extent of the change in the electrical field at a given point decreases. I am confused on how the question is worded to be honest. I understand that as frequency decreases the waves get wider but what do...
by Alex Kashou
Sun Oct 08, 2017 8:01 pm
Forum: Accuracy, Precision, Mole, Other Definitions
Topic: Sig Figs [ENDORSED]
Replies: 4
Views: 371

Re: Sig Figs [ENDORSED]

There is a link on his site that "everything you want to know about sig figs." However, the basics are that numbers like 40 have only 1 sig fig because there is no decimal after as compared to 40. which is 2 sig figs. Furthermore, 3.02 is 3 sig figs while 3.020 is 4 sig figs even though th...
by Alex Kashou
Thu Oct 05, 2017 10:08 am
Forum: Molarity, Solutions, Dilutions
Topic: G13 Homework Problem
Replies: 2
Views: 231

Re: G13 Homework Problem

Ok so to start this problem, you need to see that the solution was .2M of just 1L of solution. However, the florist added 3 more L to the solution. Thus, there are 4L total in the final solution. Using M1V1=M2V2, you can plug in the variables and get your answer. You should get .05M for the 4L solut...
by Alex Kashou
Mon Oct 02, 2017 9:39 pm
Forum: Balancing Chemical Reactions
Topic: States of Matter in Chemical Equations
Replies: 4
Views: 267

Re: States of Matter in Chemical Equations

Technically, it is not correct to write chemical reactions without their state of matter. Writing the state of the substance allows us to determine what is formed and later on, espeicially if there is a dissociation. For example, Aluminum metal (Al (s)) is written different than a dissociated alumin...
by Alex Kashou
Mon Oct 02, 2017 2:24 pm
Forum: Limiting Reactant Calculations
Topic: M11 Part A [ENDORSED]
Replies: 1
Views: 273

M11 Part A [ENDORSED]

A reaction vessel contains 5.77 g of white phosphorous and 5.77 g of oxygen. The first reaction to take place is the formation of phosphorus (III) oxide: P4 + 3 O2 --> P4O6(s). If enough oxygen is present, the oxygen can react futher with this oxide to produce phosphorus (V) oxide: P4O6 + 2 O2 --> P...

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