Search found 10 matches

by Anna Lapuos 3C
Sun Oct 29, 2017 11:45 pm
Forum: Lewis Structures
Topic: Homework 3.71 [ENDORSED]
Replies: 3
Views: 197

Homework 3.71 [ENDORSED]

How do we know which structure would more likely make the dominant contribution to a resonance hybrid? Does it have to do with the structure with the lower energy?
by Anna Lapuos 3C
Sun Oct 29, 2017 11:36 pm
Forum: Lewis Structures
Topic: Lewis Structures
Replies: 10
Views: 377

Re: Lewis Structures

I was wondering the same thing but I think we only need to include it when we're instructed to do so.
by Anna Lapuos 3C
Sun Oct 22, 2017 3:07 am
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Electron Configuration of Th [ENDORSED]
Replies: 3
Views: 254

Electron Configuration of Th [ENDORSED]

Why is the electron configuration of Thorium [Re] 7s2, 6d2? I thought Th would be part of the f-block?
by Anna Lapuos 3C
Sat Oct 21, 2017 10:07 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Homework 2.29 (c)
Replies: 2
Views: 171

Re: Homework 2.29 (c)

Oh, I see! Thank you!
by Anna Lapuos 3C
Sat Oct 21, 2017 6:18 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Homework 2.29 (c)
Replies: 2
Views: 171

Homework 2.29 (c)

Why is n squared? Do we only square it if it's the only thing that's given? It's a bit unclear to me because we don't have to square it when there's other given information.
by Anna Lapuos 3C
Sun Oct 15, 2017 3:11 am
Forum: Properties of Electrons
Topic: Problem 1.33
Replies: 2
Views: 201

Problem 1.33

Why is work function = 16.565 x 10^-18 J? That is, is the work function always going to be attained by multiplying Planck's constant (h) with frequency ?
by Anna Lapuos 3C
Fri Oct 13, 2017 10:05 pm
Forum: Einstein Equation
Topic: Ek = 1/2 me v^2
Replies: 3
Views: 259

Ek = 1/2 me v^2

Ek = 1/2 me v^2

In this formula for kinetic energy, will me always be 9.109 x 10^-31 kg?
by Anna Lapuos 3C
Sun Oct 08, 2017 12:31 am
Forum: Accuracy, Precision, Mole, Other Definitions
Topic: E.15 [ENDORSED]
Replies: 10
Views: 662

Re: E.15 [ENDORSED]

You use, m = nM.

The molar mass of NaHSO4 is 120.06 and you plug this value in for M, thus, the equation would look like this:

m = (0.20 mol)(120.06 g mol-1) = 24.01 g
by Anna Lapuos 3C
Sat Oct 07, 2017 11:22 pm
Forum: SI Units, Unit Conversions
Topic: Sig Figs [ENDORSED]
Replies: 16
Views: 1834

Re: Sig Figs [ENDORSED]

I think that the rule of final and trailing zeros are what poses the most challenge to me. Thank you for all the clarifications regarding rules of zeros. It was definitely helpful.

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