Search found 87 matches
- Wed Mar 14, 2018 4:17 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Question 15.63
- Replies: 2
- Views: 469
Re: Question 15.63
For this question and problems like this where two rate constants at two different temperatures for the same reaction and the activation energy is given as well, use the Arrhenius equation to find the answer.
- Tue Mar 13, 2018 6:53 pm
- Forum: General Rate Laws
- Topic: 15.19 solving for K
- Replies: 2
- Views: 386
Re: 15.19 solving for K
The book changed the mmol to mol in this problem I believe.
- Tue Mar 13, 2018 6:51 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Test Grading
- Replies: 4
- Views: 825
Re: Test Grading
I don't remember him saying anything about dropping our lowest test. Maybe you're thinking of another class?
- Mon Mar 05, 2018 8:13 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Test 2 Question 7
- Replies: 1
- Views: 304
Re: Test 2 Question 7
The reaction the question asks you to calculate the standard potential for is actually Cr(s), not Cr3+. So, you need to use the equation you mentioned and also 2Cr3+ + 6e- -> 2Cr(s). However, the same species (Cr) is being reduced in both equations, and when the same species is involved in both step...
- Mon Mar 05, 2018 7:10 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: 15.19
- Replies: 3
- Views: 557
Re: 15.19
You look for two reactions where there is a difference in concentrations for just one of the reactants, then use this and the change in the rate to get the order of that reactant. Repeat this to get the orders of the others reactants. Once you have all the orders, you can pick any trial you want, pl...
- Mon Mar 05, 2018 3:28 pm
- Forum: Balancing Redox Reactions
- Topic: Reducing power
- Replies: 2
- Views: 394
Re: Reducing power
Yep, both things you said are right. The standard reduction potential for Br2 is 1.07 V and for I2 it is 0.54V. So Br2 has a greater tendency to get reduced, meaning it has a lower reducing power since it is worse at reducing other species, and it has a stronger oxidizing power since it has a higher...
- Fri Mar 02, 2018 9:30 pm
- Forum: Zero Order Reactions
- Topic: Difference between zero, first, second [ENDORSED]
- Replies: 3
- Views: 2438
Re: Difference between zero, first, second [ENDORSED]
Let's say we have a reaction A -> B. For zero order reactants, the rate at which the reaction occurs is not affected by the concentration of that reactant. So if [A] is 1.0M in one reaction but [A] is 2.0M in another reaction, the rate at which the reaction occurs will be the same for both concentra...
- Wed Feb 28, 2018 5:13 pm
- Forum: General Rate Laws
- Topic: 15.17 and 15.19 [ENDORSED]
- Replies: 2
- Views: 426
Re: 15.17 and 15.19 [ENDORSED]
Yep, it's just the sum of the individual orders
- Wed Feb 28, 2018 5:11 pm
- Forum: Second Order Reactions
- Topic: positive slope in second ordre graph
- Replies: 2
- Views: 1371
Re: positive slope in second ordre graph
The graph is plotting 1/concentration against time and since as time increases, the concentration of a reactant will decrease, but since the y axis is 1/concentration, the y value will increase as time goes on since the y value will increase as concentration decreases because it is in the denominator
- Wed Feb 28, 2018 5:09 pm
- Forum: General Rate Laws
- Topic: Overall order [ENDORSED]
- Replies: 6
- Views: 1009
Re: Overall order [ENDORSED]
We don't need to know negative or fractional orders but if you know the orders of all the reactants you should know that the overall order is just the sum of those individual orders
- Tue Feb 20, 2018 9:44 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.35
- Replies: 1
- Views: 271
Re: 14.35
If temperature isn't stated then you can assume a reaction is at standard temperature (25 Celsius)
- Tue Feb 20, 2018 9:00 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 14.37(c)
- Replies: 1
- Views: 307
Re: 14.37(c)
H2 and Cl2 are on different sides of the salt bridge but they are both products. The cell reaction is 2HCl -> H2 +Cl2
- Tue Feb 20, 2018 8:18 pm
- Forum: Balancing Redox Reactions
- Topic: 14.5 a-ox numbers
- Replies: 1
- Views: 323
Re: 14.5 a-ox numbers
The oxygen that is bonded to the bromine got reduced to -2
- Tue Feb 20, 2018 8:13 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Cell diagram/equation
- Replies: 2
- Views: 364
Re: Cell diagram/equation
If the equation is flipped then the sign of the voltage is switched too, but the reaction will be the same with reactants and products on opposite sides
- Wed Feb 14, 2018 2:28 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Constant Pressure
- Replies: 2
- Views: 402
Re: Constant Pressure
For a constant volume, not pressure, the work is 0 so U=q=H. The example you stated says U=q at constant volume
- Wed Feb 14, 2018 2:22 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: given two temperatures and 2 volumes solve for delta S
- Replies: 2
- Views: 1361
Re: given two temperatures and 2 volumes solve for delta S
You need to add the change in entropy due to the change in volume to the change in entropy due to the change in temperature. So basically, you do two different equations and add them together. I think it is assumed that the pressure is 1 atm, so you can calculate n with PV=nRT
- Mon Feb 12, 2018 6:36 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: partial pressure units
- Replies: 1
- Views: 280
Re: partial pressure units
Nope it doesn't matter because the ratio will be the same so Q/K will be the same regardless of units of pressure
- Sun Feb 11, 2018 8:59 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Finding Temperature Where Reaction is Spontaneous
- Replies: 2
- Views: 355
Re: Finding Temperature Where Reaction is Spontaneous
If you find it where G=0, you can figure out exactly what the temperature needs to be greater than or less than depending on the entropy for the reaction to be spontaneous
- Sat Feb 10, 2018 8:02 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 8.65
- Replies: 1
- Views: 344
Re: 8.65
Your method was totally fine, but just be careful of what the question wants you to do. It may ask for you to do the problem a specific way, but if it doesn't the way you did it was perfectly fine and will get the same result as the other way for other questions
- Thu Feb 08, 2018 9:29 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Intensive Property of Standard Cell Potential
- Replies: 3
- Views: 769
Re: Intensive Property of Standard Cell Potential
The value of the specific heat itself is intrinsic because it will always be the same for some molecule at some phase. The specific heat does not change as mass does, the heat/energy does
- Tue Feb 06, 2018 9:28 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Pressure and Volume
- Replies: 3
- Views: 451
Re: Pressure and Volume
For ratios the units do not matter as long as they are the same for pressure and volume. With temperature it is different since you are adding a factor of 273 to turn celsius into kelvin but for pressure and volume, converting between units is multiplication or division, so the ratio will always be ...
- Tue Feb 06, 2018 9:25 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: How cold is that iced tea tho
- Replies: 1
- Views: 323
Re: How cold is that iced tea tho
You need to set the heat gained by the ice equal to the heat lost by the tea and dont forget to include the heat of fusion for the ice tho.
- Mon Feb 05, 2018 5:16 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: deriving how delta G relates to work
- Replies: 2
- Views: 501
Re: deriving how delta G relates to work
If you remember the curve on a PV graph for a reversible pathway, it curves downward and the area under this curve is the work. The curve looks like this: https://upload.wikimedia.org/wikipedia/ ... m_work.png
- Mon Feb 05, 2018 5:13 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Reversible Reaction Total Entropy
- Replies: 1
- Views: 256
Re: Reversible Reaction Total Entropy
The heat of the system doesnt change since the surroundings keep it stable and the heat of the surroundings doesnt change because it is a reservoir
- Sun Feb 04, 2018 10:30 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Pulley and Vacuum
- Replies: 2
- Views: 418
Re: Pulley and Vacuum
If you imagine a piston thats controlled by a weight and that weight is slowly removed, then the system will slowly expand and do work
- Sat Feb 03, 2018 4:56 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: 9.65
- Replies: 6
- Views: 767
9.65
Can someone help me figure out how to do 9.65? It asks "Which of the following compounds become less stable with respect to the elements as the temperature is raised: a. PCl5 (g) b. HCN (g) c. NO (g) d. SO2 (g)"
- Fri Feb 02, 2018 9:47 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: 9.35 [ENDORSED]
- Replies: 5
- Views: 663
Re: 9.35 [ENDORSED]
I believe it's saying that there are 1 mol of atoms in a, b, and c, but in b and c those atoms bind together to form diatomic molecules so then there are .5 moles of particles for b and c so a has the most particles.
- Thu Feb 01, 2018 3:05 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Question 8.13
- Replies: 3
- Views: 410
Re: Question 8.13
If it was not irreversibly, some of the equations we use would not work because irreversible reactions occur at constant temperature but if it was not irreversible there would be a change in temperature
- Thu Feb 01, 2018 3:03 pm
- Forum: Calculating Work of Expansion
- Topic: Expansion
- Replies: 3
- Views: 437
Re: Expansion
If the volume is expanding then the system is doing work
- Mon Jan 29, 2018 4:38 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: formula for standard entropy
- Replies: 5
- Views: 788
Re: formula for standard entropy
Yes they are the same just with S replacing H
- Sat Jan 27, 2018 1:52 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Spontaneous Reactions [ENDORSED]
- Replies: 2
- Views: 188
Re: Spontaneous Reactions [ENDORSED]
We haven't gone over how to calculate whether or not a reaction is spontaneous. The examples Dr. Lavelle gave in lecture were obvious examples like how gas would spontaneously expand in its container and it would never spontaneously bunch up in its container, but for more ambiguous processes there a...
- Sat Jan 27, 2018 1:49 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Reversible isothermal expansion
- Replies: 4
- Views: 453
Re: Reversible isothermal expansion
I highly doubt we will need to show the derivations. Dr. Lavelle just showed us the derivations so we understand where the formulas came from so we wouldn't blindly memorize these formulas without knowing where they came from
- Mon Jan 22, 2018 9:11 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Textbook example 8.6
- Replies: 1
- Views: 205
Re: Textbook example 8.6
Since the system is at a constant volume, the work is 0, so the change in internal energy is equal to heat, so delta U = q.
- Mon Jan 22, 2018 9:08 pm
- Forum: Phase Changes & Related Calculations
- Topic: Problem 8.71
- Replies: 1
- Views: 234
Re: Problem 8.71
We didn't cover the concepts of this question in class so you don't need to know how to do it. 71 isn't listed as one of the homework problems to choose from on the syllabus. If you want to figure it out for your own sake no one's stopping you, just read the section that covers it in the book!
- Mon Jan 22, 2018 9:06 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: 8.53
- Replies: 1
- Views: 249
Re: 8.53
The question gives you heat capacity, not molar heat capacity. When you are given molar heat capacity, you need to multiply by the number of moles so the units cancel to leave units of energy, but with heat capacity all you need to do is multiply it by the change in temperature to get units of energ...
- Mon Jan 22, 2018 9:01 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Positional (Residua) Entropy
- Replies: 1
- Views: 281
Re: Positional (Residua) Entropy
Positional entropy is related to how many positions an object, like an atom, can be in.
- Thu Jan 18, 2018 9:36 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Reaction Enthalpy v. Enthalpy of Formation
- Replies: 4
- Views: 298
Re: Reaction Enthalpy v. Enthalpy of Formation
It will probably be stated in the question and only one of these will probably be given to you to solve a problem. If both are given, you may need to combine the two methods or choose to do either method if the problem can be solved like that
- Thu Jan 18, 2018 9:29 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 8.41
- Replies: 3
- Views: 543
Re: 8.41
The temperature of the water is higher than 0 degrees Celsius so you need to take the amount of energy it takes to melt the given amount of ice first and consider that in your calculations.
- Tue Jan 16, 2018 9:36 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Acids and Bases
- Replies: 3
- Views: 307
Re: Acids and Bases
It may not be needed for anything in 14B but for 14BL there are acid/base labs
- Tue Jan 16, 2018 9:34 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Problem 8.75 (b)
- Replies: 3
- Views: 288
Re: Problem 8.75 (b)
Definitely draw out the lewis structures! It will help tremendously and if you dont it is very likely you will miss at least one bond.
- Sat Jan 13, 2018 2:00 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Formation
- Replies: 3
- Views: 289
Re: Formation
Remember that the periodic table is split into metals and nonmetals and that metals are typically solids at standard conditions and nonmetals are typically gases. Also, remember that mercury and bromine are liquids at standard conditions!
- Tue Jan 09, 2018 8:09 pm
- Forum: Phase Changes & Related Calculations
- Topic: Endo and Exothermic Ways to Remember
- Replies: 28
- Views: 11616
Re: Endo and Exothermic Ways to Remember
For me I think about how they sound. The "en" in endothermic sounds like in and the "ex" in exothermic reminds me of exit.
- Tue Jan 09, 2018 8:06 pm
- Forum: Phase Changes & Related Calculations
- Topic: Phase Changes [ENDORSED]
- Replies: 3
- Views: 293
Re: Phase Changes [ENDORSED]
It may also be helpful to know that fusion is another term that is the same phase change as melting (solid to liquid)
- Tue Dec 05, 2017 6:00 pm
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Strong Acids/Bases
- Replies: 3
- Views: 481
Re: Strong Acids/Bases
Their equilibrium constants are basically infinity since there are hardly any reactants, so no
- Mon Dec 04, 2017 8:34 pm
- Forum: Lewis Acids & Bases
- Topic: 12.119
- Replies: 1
- Views: 337
Re: 12.119
When the hydrogen is removed from boric acid, the oxygens will experience a more negative charge. Boron has a low electronegativity, so it cannot help stabilize the anion
- Mon Dec 04, 2017 8:30 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: F and Cl in acids
- Replies: 2
- Views: 1041
Re: F and Cl in acids
The strengths for these acids depend on different factors. Since the H-F bond is shorter than the H-Cl bond, HF is less likely to dissociate than HCl, so it is a weaker acid. However, in the case of C2O2HF3 and C2O2HCl3, the strength of the acid depends on electronegativity. Since F is more electron...
- Mon Nov 27, 2017 9:11 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Chemical Equilibrium Part 2 Post-Module #19 & 27
- Replies: 2
- Views: 315
Re: Chemical Equilibrium Part 2 Post-Module #19 & 27
Did you make sure to omit the solid molecule from the calculations? Solids are not included in equilibrium constant equations
- Mon Nov 27, 2017 8:58 pm
- Forum: Hybridization
- Topic: Lone Pairs in Hybridization
- Replies: 4
- Views: 735
Re: Lone Pairs in Hybridization
It solely relies on the amount of areas of electron density, including the lone pairs
- Mon Nov 27, 2017 8:57 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: When to use ICE box
- Replies: 2
- Views: 787
Re: When to use ICE box
The ICE box is used when the problem involves using both equilibrium and initial concentrations of the products and reactants
- Mon Nov 27, 2017 8:39 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 11.1 Homework
- Replies: 2
- Views: 270
Re: 11.1 Homework
The equilibrium constant does not change with a change in pressure
- Sun Nov 26, 2017 3:05 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: chemical equilibrium part 2 module #12
- Replies: 1
- Views: 228
Re: chemical equilibrium part 2 module #12
The chemical equilibrium constant Kc=[Br]^2/[Br2]. So you take the square root of the product of Kc and Br2 to get the answer, which is C
- Tue Nov 21, 2017 1:59 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Aqueous and Gaseous Phases
- Replies: 3
- Views: 380
Re: Aqueous and Gaseous Phases
If there are both gases and aqueous molecules in a reaction then you will need to use PV=nRT to find the concentration of the gases, then find Kc.
- Mon Nov 20, 2017 10:04 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Homework question 17.33
- Replies: 4
- Views: 459
Re: Homework question 17.33
You need to take into account the molecular shapes. It needs to be possible for multiple electron pairs to bind to the transition metal with the molecular shape of the ligand
- Mon Nov 20, 2017 10:00 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Part D; Question 17.33
- Replies: 1
- Views: 293
Re: Part D; Question 17.33
The molecule's shape matters in this case. It will be trigonal planar around each carbon, so only two oxygen atoms will be able to bond to the metal at a time.
- Thu Nov 16, 2017 10:28 pm
- Forum: Hybridization
- Topic: Double sigma v. pi bonds
- Replies: 4
- Views: 508
Re: Double sigma v. pi bonds
There is no such thing as a double sigma bond. A double bond consists of one sigma bond and one pi bond. A triple bond consists of one sigma bond and two pi bonds.
- Tue Nov 14, 2017 11:45 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 2 Lone Pairs and 2 Bonding Pairs vs 1 Lone Pair and 2 Bonding Pairs
- Replies: 2
- Views: 525
Re: 2 Lone Pairs and 2 Bonding Pairs vs 1 Lone Pair and 2 Bonding Pairs
The bond angle for the molecule with 2 bonds and 1 lone pair would be greater than the bond angle for the molecule with 2 bonds and 2 lone pairs since more lone pairs means more repulsion
- Tue Nov 14, 2017 8:30 pm
- Forum: Hybridization
- Topic: Superscript
- Replies: 3
- Views: 851
Re: Superscript
The superscript is showing how many p-orbitals have been hybridized. So in sp, one p-orbital is hybridized, sp^2 has two hybridized, and sp^3 has three hybridized.
- Sat Nov 11, 2017 4:25 pm
- Forum: Resonance Structures
- Topic: Determining Best Lewis Structure [ENDORSED]
- Replies: 2
- Views: 516
Re: Determining Best Lewis Structure [ENDORSED]
In the best lewis structure, the formal charge for every atom in the molecule, not just the central atom, will be as close to 0 as possible
- Sat Nov 11, 2017 4:23 pm
- Forum: Octet Exceptions
- Topic: Expanding an Octet [ENDORSED]
- Replies: 2
- Views: 467
Re: Expanding an Octet [ENDORSED]
I think what you're getting at is if there is a negative formal charge, then it should go on the most electronegative atom. This happens since the more electronegative atom will draw in electrons stronger, so it would be more stable for the more electronegative atom to have more electrons resulting ...
- Sat Nov 11, 2017 4:17 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: See-saw [ENDORSED]
- Replies: 2
- Views: 412
See-saw [ENDORSED]
For the See-saw vsepr shape is the bond angle between the two equatorial atoms 120 or less than 120?
- Thu Nov 09, 2017 4:05 pm
- Forum: Lewis Structures
- Topic: double bonds in NO3-
- Replies: 2
- Views: 1850
Re: double bonds in NO3-
If there were 3 double bonds then nitrogen would have more than an octet (it would have 12 electrons in its valence shell) but nitrogen is only in the second period so it cannot have more than 8 valence electrons. Also, this would make the formal charges of nitrogen and oxygen much farther from 0, w...
- Wed Nov 08, 2017 11:00 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: delta v
- Replies: 4
- Views: 579
Re: delta v
Yes, this is correct
- Wed Nov 08, 2017 10:05 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterm Topics
- Replies: 1
- Views: 263
Midterm Topics
Will we need to know what the Lyman and Balmer series are for the midterm? Thanks!
- Wed Nov 08, 2017 10:00 pm
- Forum: Lewis Structures
- Topic: HW 3.103
- Replies: 1
- Views: 301
Re: HW 3.103
For molecules with many carbon atoms, you probably need to make a carbon ring. In this case, make a carbon ring, then put oxygens on carbons opposite from each other, and put the one hydrogen on the other carbons. The carbon-oxygen bonds will be double bonds, and the bonds between carbons that are b...
- Wed Nov 08, 2017 9:55 pm
- Forum: Ionic & Covalent Bonds
- Topic: Polar vs. Non-polar
- Replies: 11
- Views: 1054
Re: Polar vs. Non-polar
We don't need to know how to calculate a dipole moment. We only need to know what it is and determine if there is one
- Mon Nov 06, 2017 10:39 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Xenon Tetrafluoride?
- Replies: 4
- Views: 1373
Re: Xenon Tetrafluoride?
This molecule, and all molecules with a square planar shape are rather rare. You don't need to know the element as long as you know how to draw the lewis structure. Once you have the lewis structure down, you can see the regions of electron density and see if they are lone pairs or bonds, then this ...
- Thu Nov 02, 2017 8:54 pm
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: Increasing Covalent Character of Silver Halides
- Replies: 1
- Views: 1784
Re: Increasing Covalent Character of Silver Halides
As you go down the halogen group, they decrease in ionization energy and electron affinity, so they decrease in electronegativity as well. Therefore, the difference in electronegativity between silver and the halide will decrease as you go down the halogen group. So, since an large difference is cha...
- Thu Nov 02, 2017 8:49 pm
- Forum: Trends in The Periodic Table
- Topic: Carbon vs. Nitrogen Ionization Trend
- Replies: 3
- Views: 3064
Re: Carbon vs. Nitrogen Ionization Trend
The trends are just general trends. In general, the ionization energies of elements will decrease down the periodic table and increase across. However, there are multiple exceptions. These trends are just in general, they do not apply to every single case. We didn't go over specific exceptions to th...
- Thu Nov 02, 2017 8:47 pm
- Forum: Bond Lengths & Energies
- Topic: Ionic Character and Covalent Character
- Replies: 2
- Views: 494
Re: Ionic Character and Covalent Character
I think we will be given electronegativity values of each element, then using these values, we find the differences in electronegativities between the two elements bonded. If the difference is greater than 2, the bond is ionic. If the difference is less than 1.5, it is covalent. There are rough esti...
- Tue Oct 31, 2017 2:02 pm
- Forum: Trends in The Periodic Table
- Topic: Chapter 2, Question 85
- Replies: 1
- Views: 264
Re: Chapter 2, Question 85
When we were doing those graph/chart things with quantum mechanics and exciting electrons to higher energy levels, as we increased the energy level, the differences in energy between them kept decreasing. So as you get higher and higher, the differences between energy levels and subshells become les...
- Tue Oct 31, 2017 1:57 pm
- Forum: Octet Exceptions
- Topic: F orbitals
- Replies: 4
- Views: 750
Re: F orbitals
Yes, any atom that has a principle quantum number of n=4 or greater can have electrons in the f subshell
- Tue Oct 31, 2017 1:56 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron Configuration for Bi3+
- Replies: 2
- Views: 2213
Re: Electron Configuration for Bi3+
For the d sublevel, you need to subtract one from the principle quantum number, so it would be 5d. For the f sublevel, you need to subtract two form the principle quantum number, so it would be 4f.
- Thu Oct 26, 2017 9:42 pm
- Forum: Trends in The Periodic Table
- Topic: Periodic Trends
- Replies: 2
- Views: 271
Re: Periodic Trends
The second ionization energy is the energy required to take the next electron after an electron is already taken from an atom. They have numerical values, but I don't think those can be determined with anything we've learned. To determine whether it is higher than lower or something, treat it like y...
- Thu Oct 26, 2017 9:32 pm
- Forum: Ionic & Covalent Bonds
- Topic: Ionic vs. Covalent Bonds [ENDORSED]
- Replies: 8
- Views: 1091
Re: Ionic vs. Covalent Bonds [ENDORSED]
A covalent bond is between nonpolar, or atoms with little charge. An ion is between two ions which have very high charge in comparison. Elements want a full octet, or achieve the noble gas configuration, because this configuration is the most stable. What holds the two atoms together in an ionic bon...
- Tue Oct 24, 2017 9:39 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: No f- orbital questions? [ENDORSED]
- Replies: 4
- Views: 665
Re: No f- orbital questions? [ENDORSED]
I'm pretty sure all you have to know is that energy levels n=4 and after have f-orbitals, the f-orbitals are l=3, and ml= -3,-2,-1, 0, 1, 2, 3.
- Tue Oct 24, 2017 9:33 pm
- Forum: Photoelectric Effect
- Topic: Work function v. Ionization Energy
- Replies: 2
- Views: 3392
Re: Work function v. Ionization Energy
The work function is typically related to the photoelectric effect where photons hit a solid metal and if the energy of a photon is higher than the work function, then the electrons are ejected from the metal. For ionization energy, the energy is related to the energy required to remove an electron ...
- Mon Oct 16, 2017 11:09 pm
- Forum: Properties of Light
- Topic: emission and absorption spectrum
- Replies: 3
- Views: 690
Re: emission and absorption spectrum
The values of the lines will be the same since the energy levels for each element are constant. The lines only change as you change elements. The difference is in what is measured. If the wavelengths/frequencies of light that are being released by the atom are measured, it results in an emission spe...
- Mon Oct 16, 2017 11:06 pm
- Forum: DeBroglie Equation
- Topic: Homework Problems
- Replies: 3
- Views: 468
Re: Homework Problems
If you go to the website and you go to lecture outlines, it can be found in outline 2. It is: Read: Ch 1 Do Problems: 3, 5, 7, 9, 11, 13, 15, 21, 23, 25, 27, 33, 37, 39, 41, 43, 55, 57, 59, 65, 67, 69 Read: Ch 2 (Omit Table 2.1) Do Problems: 1, 13, 17, 19, 21, 23, 25, 27, 29, 31, 33, 37, 39, 41, 43,...
- Mon Oct 16, 2017 7:26 pm
- Forum: Properties of Electrons
- Topic: Hydrogen Series
- Replies: 4
- Views: 562
Re: Hydrogen Series
I highly doubt that we need to memorize those series since they aren't in the textbook and I believe they haven't been covered in class either.
- Mon Oct 16, 2017 7:24 pm
- Forum: Properties of Electrons
- Topic: Electromagnetic Spectrum
- Replies: 2
- Views: 392
Re: Electromagnetic Spectrum
You don't need to memorize the exact values for each type of electromagnetic radiation. However, we do need to know that visible light is around 400-700 nanometers, and having rough estimates of the other electromagnetic waves would probably be a good idea.
- Sat Oct 14, 2017 10:29 pm
- Forum: DeBroglie Equation
- Topic: Post-Module Assessment #35 [ENDORSED]
- Replies: 2
- Views: 679
Post-Module Assessment #35 [ENDORSED]
Calculate the wavelength of a 275 kg single-seat electric car traveling at a speed of 125 km.hr-1. Do electric cars have wavelike properties? A. λ = 6.94 x 10-38 m , Yes B. λ = 6.94 x 10-38 m , No C. λ = 1.93 x 10-38 m , Yes D. λ = 1.93 x 10-38 m , No The correct answer is B. The wavelength is so sm...
- Thu Oct 12, 2017 8:24 pm
- Forum: Properties of Light
- Topic: Figure 1.9
- Replies: 4
- Views: 523
Re: Figure 1.9
It is not required to memorize the exact values for each type of electromagnetic radiation, but you should know that visible light is around 400-700 nanometers. It would probably be a good idea to have some approximation of each type memorized, but Dr. Lavelle said that we did not need to memorize t...
- Mon Oct 09, 2017 10:23 pm
- Forum: Properties of Light
- Topic: Chapter 1 Problem 7b
- Replies: 3
- Views: 330
Re: Chapter 1 Problem 7b
Alright, thank you!
- Mon Oct 09, 2017 8:42 pm
- Forum: Properties of Light
- Topic: Chapter 1 Problem 7b
- Replies: 3
- Views: 330
Chapter 1 Problem 7b
"When an electron beam strikes a block of copper, x-rays with a frequency of 2.0 x 10^18 Hz are emitted. What is the wavelength (in picometers) of these x-rays?" I got an answer of 150 pm but the back of the book says 150 nm. I'm pretty sure this is just a typo, especially since the questi...
- Thu Oct 05, 2017 8:15 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Molarity and Dilution [ENDORSED]
- Replies: 7
- Views: 2152
Re: Molarity and Dilution [ENDORSED]
In this case it is possible to use the MiVi = MfVf equation. Mi = 9.85M and Vi = .075L and Vf = .125L. So, if you multiply Mi by Vi then divide this product by Vf you end up with 5.91M. Another way you could solve this problem is simply converting the grams into moles, which would be .739 mol, then ...
- Thu Oct 05, 2017 8:08 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: G. 21
- Replies: 3
- Views: 575
Re: G. 21
You first need to calculate the amount of moles for each compound by dividing the given masses by the molar masses resulting in .00671 mol KCl, .00453 mol K2S, and .00236 mol K3PO4. Therefore, there are .00671 mol K in KCl, .00906 mol K in K2S, and .00472 mol K in K3PO4 for .0205 mol K total and .00...
- Wed Oct 04, 2017 9:12 pm
- Forum: SI Units, Unit Conversions
- Topic: Sig Figs
- Replies: 12
- Views: 3310
Re: Sig Figs
There are 2 sig figs in 460. In this case, the 4 and the 6 are significant. All nonzero numbers are significant, so in 123.45, there are five sig figs. Also, all zeros in front of a number without a decimal point in front of them are insignificant, so in 00460, there would still be just two sig figs...