CHEMISTRY COMMUNITY

Mitch Walters

There is a negative because of the fact that the heat is leaving your body and going into the surroundings.

Mitch Walters

I think just being able to identify the different functional groups is all that is expected of us.

Mitch Walters

Concentration of reactants decreases.

Mitch Walters

The rate constant is an experimentally determined value for a specific reaction at a specific temperature. It essentially tells you the instantaneous rate of change.

Mitch Walters

The answer should be zero, since you would have a negative exponent in the denominator, and a positive exponent in the numerator, so when added together they should equal zero.

Mitch Walters

k' just means a different rate constant. This is because we are treating a second order reaction as if it's a first order reaction, so it must have a different rate constant.

Mitch Walters

All of the concentrations except for one, of the reactants are super high in a pseudo first order reaction. This is done in order to keep the reactants essentially constants.

Mitch Walters

Mitch Walters

You have to to experiment by looking at how much the rate changes from your initial amount. If it changes by double it is a first order. If it quadruples it is second order. The important thing to note is that it has nothing to do with the coefficients of your chemical equation.

Mitch Walters

Find the concentration of H+ ions, and then take the negative log of that concentration.

Mitch Walters

Draw the salt bridge to show that you have finished the oxidation portion of the reaction, and that you are moving onto the reduction portion.

Mitch Walters

I prefer to go in the order of what is happening. So with oxidation I start off with some kind of solid and then move to the positive ion. With reduction I start with the positive ion and then move to the solid.

Mitch Walters

I believe that the template usually has the anode on the left, but I don't think it physically needs this to work.

Mitch Walters

Salt bridges allow electron transfer between two solutions.

Mitch Walters

I think that the current keeps going. But there is no change in current.

Mitch Walters

No that makes sense, because you can't actually calculate anything when it's at zero.

Mitch Walters

It shouldn't matter, because when you add them together you always end up with the original reaction.

Mitch Walters

Wait new thought, if you're taking a solid and adding it to water, then the entropy would increase, because you now you have an aqueous solution.

Mitch Walters

If you're adding particles wouldn't that increase the entropy?

Mitch Walters

It probably can't hurt, but you shouldn't need to know it.

Mitch Walters

Any reaction that has a negative delta G.

Mitch Walters

I believe free expansion is when there is no opposing pressure on a system, so it is allowed to expand without doing any work. Irreversible expansion is what allows for the maximum amount of work.

Mitch Walters

I think that this question is flawed, because it presupposes that a vacuum is a system. But a vacuum is simply nothing, so it seems wrong to think of it a system.

Mitch Walters

No, an isolated system cannot be affected in any way by the surroundings.

Mitch Walters

One way of thinking of entropy is simply a measure of energy that becomes unusable. If we know that there is a fixed amount of usable energy in any given system, then it follows that there is also a fixed amount of entropy in a given system as well. If there is a fixed amount it must at some point r...

Mitch Walters

Reversible means that the two pressures are essentially equal and that an infinitesimal change can cause expansion. Irreversible is when no such change can occur.

Mitch Walters

It would be a process where q=0 and w=some number.

Mitch Walters

I always think of things in terms of potential energy. Whatever formation has the lowest potential energy should be the most stable.

Mitch Walters

State properties can be added because only specific points matter when looking at the states. The paths that are taken don't matter, so we can add the relevant points and forget the rest.

Mitch Walters

It is a way of measuring a specific form of energy.

Mitch Walters

The ocean.

Mitch Walters

I would think you should ignore the d orbital. So just write Ag+.

Mitch Walters

In endothermic energy is being consumed, in other words it requires energy in order to function. In an exothermic reaction energy is being released. Often times, exothermic reactions are used to power endothermic reactions.

Mitch Walters

Just look to see if the atom has access to a d-orbital, that’s the biggest clue you will get!

Mitch Walters

I’m curious about this as well!

Mitch Walters

When you are adding your electrons to their orbitals, remember to put an electron in each orbital before you fill your orbitals.

Mitch Walters

Why do we assume that the H2O is a liquid?

Mitch Walters

Effective nuclear charge decreases as you go down a group because you are adding orbitals as you go down, in other words the electron is being added into a new orbital that is farther away from the nucleus. This increases the shielding because there are more electrons in between the nucleus and the ...

Mitch Walters

Fluorine is in the perfect place to fit that trend. It's in the top corner, so it makes sense that it would be the most electronegative.

Mitch Walters

This might be something that can only be known from experimental values.

Mitch Walters

A question that I have that is related to this topic is, can an electron change spin? Or will it always have the same spin no matter what?

Mitch Walters

I've been wondering about this too. It seems that we have to assume that something is both a particle and a wave until we know which one it is? But perhaps this is wrong. An explanation would be wonderful.

Mitch Walters

I find reading the textbook to be invaluable.

Mitch Walters

I don't understand why the balmer series is specific to the visible light portion of the spectrum and the lyman series is specific to the UV portion. Maybe this is a stupid question? Could someone please explain.

Mitch Walters

Hi Dr. Lavelle,

I just wanted to say thank you for all of the great resources you've provided for us so far. You're a fantastic instructor!

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