From the midterm practice test,
6. a) Arrange S2-, Cl-, and P3- in order of increasing ionic radius.
Since they all have the same number of electrons, wouldn't their radii be the same length?
Search found 19 matches
- Sat Dec 09, 2017 11:05 pm
- Forum: Trends in The Periodic Table
- Topic: Isoelectronic Ionic Radius
- Replies: 2
- Views: 426
- Sat Dec 09, 2017 10:44 pm
- Forum: Photoelectric Effect
- Topic: Midterm Practice Test #4b
- Replies: 3
- Views: 1396
Midterm Practice Test #4b
A newly designed laser pointer with a certain frequency is pointed at a sodium metal surface. An electron is ejected from the metal surface with wavelength 1.10 nm. What is the frequency of the light from the laser pointer? The work function of sodium is 150.6 kJ∙mol-1. I got 2.89 x 10^17 Hz and was...
- Thu Dec 07, 2017 10:47 pm
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Electron Withdrawing Power
- Replies: 3
- Views: 1002
Electron Withdrawing Power
What is an atom's electron withdrawing power? Is it the same as electronegativity?
- Wed Dec 06, 2017 9:31 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Relative Acidity Concept Question
- Replies: 4
- Views: 694
Relative Acidity Concept Question
If an atom has a higher electronegativity, is it a stronger acid?
- Mon Dec 04, 2017 7:56 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Chem. Equilibrium Part 3 Post-Assess. #19
- Replies: 3
- Views: 598
Re: Chem. Equilibrium Part 3 Post-Assess. #19
@Suhail's reply
I know when we assume x is small we can drop the -x, but how come the square after .0482 is dropped as well? Like in the first equation it is .0482^2-x but the second equation is just .0482.
I know when we assume x is small we can drop the -x, but how come the square after .0482 is dropped as well? Like in the first equation it is .0482^2-x but the second equation is just .0482.
- Mon Dec 04, 2017 4:56 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Chem. Equilibrium Part 3 Post-Assess. #19
- Replies: 3
- Views: 598
Chem. Equilibrium Part 3 Post-Assess. #19
19. 0.482 mol N2 and 0.933 mol O2 are placed in a 10.0 L reaction vessel and form N2O (dinitrogen oxide): 2N2(g) + O2(g) ⇌ 2N2O(g) KC = 2.0 x 10^-37 What is the composition of the equilibrium mixture? A. [N2] = 0.0482 mol.L-1; [O2] = 0.0933 mol.L-1; [N2O] = 6.6 x 10-21 mol.L-1 B. [N2] = 0.0933 mol.L...
- Wed Nov 29, 2017 11:00 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Chem. Equilibrium Part 2 Post-Module Assess. #26 [ENDORSED]
- Replies: 2
- Views: 646
Chem. Equilibrium Part 2 Post-Module Assess. #26 [ENDORSED]
26. A mixture initially consisting of 0.250 N2 (g) and 0.500 M H2 (g) reacts to form NH3 (g) which is 0.15 M NH3 (g) at equilibrium. Calculate the concentration of N2 (g) at equilibrium for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g).
A. 0.18 M
B. 0.10 M
C. 0.33 M
D. 0.40 M
A. 0.18 M
B. 0.10 M
C. 0.33 M
D. 0.40 M
- Wed Nov 29, 2017 9:21 pm
- Forum: Ideal Gases
- Topic: Chem. Equilibrium Part 1B Post-Module Assess. #44 [ENDORSED]
- Replies: 1
- Views: 478
Chem. Equilibrium Part 1B Post-Module Assess. #44 [ENDORSED]
Calculate the concentration of CO(g) in mol.m^-3 at 423 K and 0.8 atm using R = 8.206 × 10-5 m^3.atm.K^-1.mol^-1 and assuming only CO(g) is present. A. 23 mol.m-3 B. 2.3 mol.m-3 C. 0.23 mol.m-3 D. 4.6 mol.m-3 E. None of the above After using the ideal gas law and cancelling out the units, I'm left w...
- Wed Nov 29, 2017 11:03 am
- Forum: Naming
- Topic: 17.31 (d) (diaqua)
- Replies: 1
- Views: 277
17.31 (d) (diaqua)
Sodium bisoxalato (diaqua) ferrate (III)
Why is diaqua in parenthesis?
Why is diaqua in parenthesis?
- Tue Nov 28, 2017 10:47 pm
- Forum: Naming
- Topic: Adding o to end of anion name
- Replies: 1
- Views: 281
Adding o to end of anion name
I know ide changes to ido, ate changes to ato, and ite changes to ito. But how can I tell if an anion originally ends in ide, ate, or ite?
- Tue Nov 28, 2017 10:18 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Chelates
- Replies: 2
- Views: 407
Chelates
How do ligands "form a ring of atoms"?
- Sat Nov 25, 2017 11:54 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: KC/KP/QC/QP
- Replies: 2
- Views: 7629
KC/KP/QC/QP
Sorry I'm a little confused. What's the difference between KC, KP, QC, and QP?
- Mon Nov 06, 2017 11:13 pm
- Forum: Limiting Reactant Calculations
- Topic: Post-Module Assess. #31 and #33
- Replies: 1
- Views: 370
Post-Module Assess. #31 and #33
For both questions: 2A + 1B ---> 3C
31. 1 mol B reacts with 2 mol A, but there is only 1 mol A present, so it is the limiting reagent.
How much of B would be used?
33. What is the maximum amount of product that can be produced?
Can someone please explain this to me?
31. 1 mol B reacts with 2 mol A, but there is only 1 mol A present, so it is the limiting reagent.
How much of B would be used?
33. What is the maximum amount of product that can be produced?
Can someone please explain this to me?
- Mon Nov 06, 2017 11:07 pm
- Forum: Empirical & Molecular Formulas
- Topic: Post-Module Assess. #14
- Replies: 2
- Views: 499
Re: Post-Module Assess. #14
Thanks!
- Mon Nov 06, 2017 9:30 pm
- Forum: Empirical & Molecular Formulas
- Topic: Post-Module Assess. #14
- Replies: 2
- Views: 499
Post-Module Assess. #14
339.20 g of a cobalt metal is reacted with fluorine gas to produce 996.08 g of a compound. What is the empirical formula of the new compound?
How do I solve this?
How do I solve this?
- Mon Nov 06, 2017 11:04 am
- Forum: Lewis Structures
- Topic: 11/5 Review Sess. [S3N3]^-1
- Replies: 2
- Views: 838
Re: 11/5 Review Sess. [S3N3]^-1
Thanks!
- Sun Nov 05, 2017 10:52 pm
- Forum: Lewis Structures
- Topic: 11/5 Review Sess. [S3N3]^-1
- Replies: 2
- Views: 838
11/5 Review Sess. [S3N3]^-1
How would the Lewis Structure for [S3N3]^-1 look like? Is it circular?
- Mon Oct 30, 2017 3:06 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: 3.49 (c) Oxygen's electrons
- Replies: 3
- Views: 857
3.49 (c) Oxygen's electrons
How come the solutions manual shows oxygen as having 5 electrons when the periodic table's oxygen has 6 electrons?
- Sun Oct 22, 2017 5:01 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: 2.43 (a) Silver
- Replies: 4
- Views: 555
2.43 (a) Silver
How come the ground-state electron configuration for silver is [Kr]4d^10 5s^1? I put [Kr]4d^9 5s^2 as my answer but I don't seem to understand how that's incorrect.