CHEMISTRY COMMUNITY

hannahtweedy

Don't you find the oxidation of the metal then match it equally and with an opposite charge for the ligand?

hannahtweedy

Doesn't it have to do with equilibrium?

hannahtweedy

The general review sessions have had a bit of everything... But incorporate multiple chapters in one question

hannahtweedy

It's better to do it this way... but does anybody know if it's a necessity to be correct?

hannahtweedy

What kind of thing do you think we could be asked regarding ligands

hannahtweedy

Does that mean that formal charge and the dipole movement are related/similar concepts?

hannahtweedy

Also if you do a Lewis structure, and there are unbonded valence electrons on the central atom, it's a Lewis base

hannahtweedy

Would the equation:

valence electrons - non-bonding valence electrons - (bonding electrons/2)

also work?

hannahtweedy

I would believe so? Sort of like whichever value is easiest to achieve with the elements at hand to achieve the desired results

hannahtweedy

E=R(1/n2^2-1/n1^2) is the equation to specifically find the change in energy. The E= -hR/n^2 is for one specific energy level

hannahtweedy

I would assume it's possible because both involve the wave-like nature of light. I would think you could possibly include Schrodinger's in there as well with them.

hannahtweedy

a) First, you convert the mmol to mol - keeping in mind since there's 2 Na in Na2CO3 the molarity will be doubled. Then you can divide the values in the formula: 0.002015/0.16 --> 0.013 L

hannahtweedy

All the ones listed so far are the only ones we went over in Step Up

hannahtweedy

Hi everybody!

There's a come-and-go study group this Tuesday from 3p until 7p in Sproul Hall's 6th Floor lounge. Anybody's welcome to come and leave whenever they would like to leave.

hannahtweedy

I just did it using the little equations!

Spherical nodes : n - l - 1
Number of angular nodes: l
Total nodes: n-1

hannahtweedy

https://youtu.be/Aoi4j8es4gQ I found this video pretty helpful clarifying it all

hannahtweedy

According to the text book, it’s used to calculate the wave function for any particle and the corresponding energy E

hannahtweedy

The Paschem series and Brackett series were also mentioned in a hw question. Can anybody explain these better?

hannahtweedy

Follow the GroupMe link!

hannahtweedy

Particles have mass while photons do not... both still have momentum though!

hannahtweedy

When this occurs would momentum still have the same function and measure as when mass exists?

hannahtweedy

You're invited to my new group '14A - Lavelle' on GroupMe. Click here to join: https://groupme.com/join_group/39693612/gWBYOk

For scheduling only- leave content questions on chem community please

hannahtweedy

More specifically, how would I find the mass percentages given a full balanced equation

hannahtweedy

Polyethylene is a hydrocarbon polymer used to produce food-storage bags and many other flexible plastic items. A combustion analysis of a 0.00126-g sample of polyethylene yields 0.00394-g of CO2 and 0.00161-g of H20. What is the empirical formula of polyethylene? I've balanced the equation but now I...

hannahtweedy

Nancy, I emailed you!

hannahtweedy

So the best thing that I found, was to make a chart of the elements as I go Fe2P(s)+S(s)-->P4S10(s)+FeS(s) 2 - Fe - 1 1 - P - 4 1 - S - 11 The left has the number of elements in the reactant side and the right is the product side. As I balance one, I change it all the ones affected. For example, sta...

hannahtweedy

1: convert 1kg to 1000 g 2: you'll need to convert first to moles (value given of H20 in grams * 1 Mol H20) / (atomic mass of H20g) atomic mass found by using periodic table 3: Now we have the number of H20 moles so we can use Avogadro's Number (molecules/moles) to convert moles to molecules by mult...

hannahtweedy

Jocelyn is right, you can't do anything with this problem without balancing the equation first to make sure to account for the Law of Conservation of Mass. The next step would be calculating the number of moles that are actually given from the mass in grams. Use this information to determine which i...

hannahtweedy

Hi everybody! My name is Hannah. A few of us are starting a weekly chemistry study group Thursdays at 4:30-6:30 at Sproul Hall. Depending on availability, we'll meet in a lounge or one of the study rooms - either way, we'll meet in the lobby. I'll post again if there are any changes to the informati...

CHEMISTRY COMMUNITY

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Re: Charge on ligands? [ENDORSED]

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