Hey All,
Does anyone know where we are assigned to go for the final? I know the rooms are either Moore 100 or CS76. My last name starts with E but I don't know where I am assigned, and I can't find any announcement that states where we are assigned.
Search found 38 matches
- Sat Mar 16, 2019 12:03 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Test Location 14B W19
- Replies: 3
- Views: 671
- Wed Mar 13, 2019 1:47 am
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: Flow of electrons
- Replies: 4
- Views: 787
Re: Flow of electrons
The cathode is always the site of reduction, hence electrons flow towards it, and the anode is always the site of oxidation, hence electrons flow away from it. The only time that they flow the opposite way is when an electrical current causes the non-favorable process to occur, driving electrons the...
- Wed Mar 13, 2019 1:29 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Positive Voltage
- Replies: 1
- Views: 277
Re: Positive Voltage
For galvanic cells, yes only a positive voltage or 0 is possible. Only electrolytic cells can have negative voltages.
The cathode should ideally have a positive E˚ and the anode should have a negative E˚, which should result in an E˚cell equal to a positive number or 0.
The cathode should ideally have a positive E˚ and the anode should have a negative E˚, which should result in an E˚cell equal to a positive number or 0.
- Wed Mar 13, 2019 1:26 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Test 2 #6 part c
- Replies: 1
- Views: 340
Re: Test 2 #6 part c
I believe that everyone gets different numbers, but I'll try to explain based on my numbers. In order to get the correct answer, you need to choose the species with the strongest reducing power and strongest oxidation power. In my case, Sn had the highest reducing power and an E of -0.14 V. Pb2+ had...
- Wed Mar 06, 2019 2:43 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Corrosion
- Replies: 3
- Views: 397
Re: Corrosion
I believe that if no problems for that section are assigned in the textbook for it, we don't really need to know it. Seeing that Lavelle did not really address corrosion in his lectures, so far, we may not need to know it.
- Wed Mar 06, 2019 2:37 pm
- Forum: First Order Reactions
- Topic: 1/2 life
- Replies: 7
- Views: 802
Re: 1/2 life
No, if you look at the equation, the half-life only takes into account the rate constant, which is dependent on temp and activation energy only.
- Wed Mar 06, 2019 2:20 pm
- Forum: General Rate Laws
- Topic: Difference between instantaneous and unique rate
- Replies: 3
- Views: 474
Re: Difference between instantaneous and unique rate
Looking at the equation, the instantaneous rate depicts the rate of either reactants or products at a very specific point in time. It is the derivative, and therefore the tangent line to the graph of the reaction. The instantaneous rate of a reactant and product can vary. However, the unique rate is...
- Wed Feb 27, 2019 3:11 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Cell Diagrams
- Replies: 4
- Views: 414
Re: Cell Diagrams
Yes, the order matters, as on the outside are the material of the cathode and anode, while on the inside, connected by the salt bridge represented by a || are the ions of the two materials, which will be balancing the charges to assure that the reaction doesn't all occur at once and the battery reac...
- Tue Feb 26, 2019 9:21 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 6L.3 part d
- Replies: 1
- Views: 233
Re: 6L.3 part d
So for this problem, there is a "hidden" component where water will appear in the reaction, creating an electric current that is then passed through a platinum cathode and anode. The two half-reactions would look like: 2H2O (l) --> O2(g) + 4H+ (aq) + 4e- anode (oxidation) O2 (g) + 2 H2O (l...
- Mon Feb 25, 2019 4:53 pm
- Forum: Student Social/Study Group
- Topic: Topic 6N
- Replies: 1
- Views: 1594
Re: Topic 6N
6N goes over the Nernst equation, which Lavelle announced won't be in Test 2. My best guess is that 6M is the cutoff for this week's test.
- Mon Feb 25, 2019 4:51 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Problem 6L.1
- Replies: 4
- Views: 824
Re: Problem 6L.1
To find the value of n, the number of electrons, you should try to find what the half reactions will look like. Make sure the charges, reactants and products are all balanced first. You will then be able to plug in n for the formula.
- Tue Feb 12, 2019 10:39 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Whether PV is significant
- Replies: 2
- Views: 294
Re: Whether PV is significant
This is because changes in the volume of the system affect a gas more than a liquid or solid. Most of the time we will be working with gases since they are capable of doing work by expansion. However, when adding energy to a liquid or solid, they will probably not expand much, if at all (assuming th...
- Tue Feb 12, 2019 10:19 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Sig Figs
- Replies: 1
- Views: 236
Re: Sig Figs
Dr. Lavelle mentioned in class that having the correct sig figs will account for 2 points out of a 120 pt test. Honestly, do not worry too much but definitely try to get the hang of using them correctly, as in future classes they may not be as lenient.
- Tue Feb 12, 2019 10:18 pm
- Forum: Student Social/Study Group
- Topic: temperature joke - very funny
- Replies: 1
- Views: 550
Re: temperature joke - very funny
Honestly surprised that Kelvin and Celsius would fight considering that an increase of 1C is 1K. I would at least expect a temporary alliance to defeat the evil Fahrenheit.
- Tue Feb 12, 2019 10:16 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Work done vs work on system
- Replies: 18
- Views: 3918
Re: Work done vs work on system
When work is done by a system, work is negative. This is because work is essentially in energy units (J or kJ), and work is how a system loses energy. Therefore, if a system does work, the system is losing that energy it had. When work is done on a system, that energy released is absorbed by the sys...
- Tue Feb 12, 2019 10:11 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Question on 7th edition 4G. 5
- Replies: 1
- Views: 220
Re: Question on 7th edition 4G. 5
So the Trans would have 3 orientations because it can either be on the y-axis in the configuration shown on the image or across from each other on the "x-plane". That is, a molecule on the left that sticks out and the one on the right inside the page, or the molecule on the right that stic...
- Tue Feb 12, 2019 9:57 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: practice midterm question
- Replies: 3
- Views: 410
Re: practice midterm question
Enthalpy change of combustion and enthalpy change of the reaction are not the same thing. To solve the change in enthalpy of the reaction, you have to use the enthalpy change of combustion. In this case this would be: DeltaH rxn = DeltaH of C2H6 - (DeltaH of C2H2 + 2 * DeltaH of H2) = -1560 - (-1300...
- Wed Feb 06, 2019 7:39 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Entropy as Temperature Increases
- Replies: 2
- Views: 354
Re: Entropy as Temperature Increases
Let me try to set up a situation for you: Entropy is essentially a measure of disorder. With that logic: Say we transfer 1000 J of energy to a system. This system is currently sitting at 283.15 K (10 C). Here the entropy would be 3.53 J/K, a high entropy. Then let's say we add 1000J of energy to a s...
- Wed Feb 06, 2019 7:02 pm
- Forum: Phase Changes & Related Calculations
- Topic: 4A3 7th Edition
- Replies: 3
- Views: 347
Re: 4A3 7th Edition
I would assume this is correct. Since the problem does not really mention any temperature change so trying to calculate for change in temperature using the heat capacity would get you 0.
- Wed Feb 06, 2019 6:37 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Chem 14B Midterm
- Replies: 3
- Views: 457
Re: Chem 14B Midterm
You are correct. Following the announcement we should only be responsible for anything from day 1 up until today, 2/6/19, which covered entropy. I am almost certain that Dr. Lavelle will go over some problems on Friday, so anything NEW we learn after entropy will most likely be reserved for Test 2. ...
- Wed Feb 06, 2019 6:31 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Determining Spontaneity of a Reaction
- Replies: 4
- Views: 545
Re: Determining Spontaneity of a Reaction
In terms of entropy, if the DeltaS value is positive, the reaction is spontaneous, while if the DeltaS value is negative, the reaction is non-spontaneous. This is a good way to remember this. Another way is when measuring the change in volume, if V1 is greater than V2, then the reaction is non-spont...
- Sat Feb 02, 2019 9:46 pm
- Forum: Calculating Work of Expansion
- Topic: Calculus in Chem
- Replies: 1
- Views: 235
Re: Calculus in Chem
An integral is a very complicated thing to explain (especially in writing), but here is a basic breakdown of why it is useful: In calculus, an integral allows us to determine the area under a graph using two reference points (the number at the bottom of the S shape, and the number at the top). This ...
- Sat Feb 02, 2019 8:40 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Enthalpy & Constant Pressure and Volume
- Replies: 2
- Views: 329
Re: Enthalpy & Constant Pressure and Volume
Mathematically, constant pressure deltaH would be represented as: deltaU = qP + w w = -P * deltaV, under constant pressure. Since deltaH = deltaU + (P * deltaV) deltaH = (qP - P * deltaV) + (P * deltaV) deltaH = qP Similarly, the heat content at constant volume, qV, will be the same as deltaH, becau...
- Sat Feb 02, 2019 7:53 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Problem 8.1 (c) 6th edition
- Replies: 2
- Views: 405
Re: Problem 8.1 (c) 6th edition
As far as I know, the coolant in a refrigeration coil does not absorb or release heat or matter. It simply changes its internal temperature to do all the necessary cooling via changes in the pressure within the coil. I found this link with the inner workings of a refrigerator which I hope does a bet...
- Sun Jan 27, 2019 12:09 am
- Forum: Ideal Gases
- Topic: OH and H3O
- Replies: 10
- Views: 1376
Re: OH and H3O
Calculating the pH and pOH from their concentrations is the easiest way to tell if an acid or base is strong or weak. pH of around 1 or lower is usually a strong acid, while 13 or higher is a strong base. Memorizing the list of the most common strong acids is a great plan too. It's also worth noting...
- Sun Jan 27, 2019 12:02 am
- Forum: Ideal Gases
- Topic: units for partial pressure of gases
- Replies: 6
- Views: 738
Re: units for partial pressure of gases
I believe if units are given in a problem, use the units given. In any case that you must convert from concentration to Ppressure using the ideal gas law, I would stick to using atmospheres, since Lavelle since to prefer using that.
- Sun Jan 27, 2019 12:00 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: State Function?
- Replies: 3
- Views: 354
State Function?
I'm a little confused as to what it means that enthalpy is a state function. I understand that we can add and subtract them freely, but I do not understand how that is related to it being a state function.
- Thu Jan 17, 2019 12:29 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Help on Question 6B.9 (7th edition)
- Replies: 2
- Views: 226
Re: Help on Question 6B.9 (7th edition)
Lavelle mentioned superacids, which have negative pH. This may be the case, but a better explanation is that a pH of 0 is equal to a 1 M concentration of H3O+ ions (10^0 = 1), so anything with molarity higher than 1 will be calculated to have a negative pH. A pH of 0.176, goes with an H3O+ concentra...
- Thu Jan 17, 2019 12:11 am
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: difficulties recognizing weak acids and bases
- Replies: 9
- Views: 1517
Re: difficulties recognizing weak acids and bases
So one dead giveaway of a wake acid or base is the presence of acidity or basicity constant (Ka or Kb respectively). Only a weak acid/base would have one of these. A chemical reaction involving a weak acid/base would have a double arrow, as some of the reactants would form back from the product thro...
- Wed Jan 16, 2019 5:15 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5I.7 7th edition
- Replies: 1
- Views: 242
Re: 5I.7 7th edition
This is an extremely rare case where Q=1, meaning there are exactly as many products as there are reactants. If no K value is given in the problem, try checking the charts in section 5G, which give the equilibrium constants at various temperatures. I don't think the problem would ask you to guess th...
- Wed Jan 16, 2019 5:10 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 7th Edition Question 6B.9
- Replies: 1
- Views: 184
Re: 7th Edition Question 6B.9
Technically, this is correct, because the H3O+ concentration is much higher than what it would normally be. This would probably mean this is a very strong acid (or a superacid) that can dissociate completely. Therefore, the OH- concentration is almost nothing. It's possible that the answer on the ba...
- Mon Jan 14, 2019 5:37 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 7th Edition HW Problem 5I.29
- Replies: 2
- Views: 192
Re: 7th Edition HW Problem 5I.29
I believe you would use 0.22 as the Ppressure of HCl because it was present at the start. As it is the only reactant present, the pressure present in the container has to come from the HCl, as there is nothing else within the container. (Side note: You would assume nothing else is present in the con...
- Mon Jan 14, 2019 4:52 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 12.29
- Replies: 1
- Views: 135
Re: 12.29
It usually depends on what operation you are performing (addition/subtraction or multiplication/division.) I'd say for pH, if the given numbers are molar concentrations or liters of solution, use the least possible numbers after the decimal. I know for 6B.5 on edition 7, which asks to calculate pH/p...
- Thu Jan 10, 2019 1:29 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Question about self-test 5I.2A
- Replies: 1
- Views: 118
Re: Question about self-test 5I.2A
I want to say that this could have been an error in the answer, as the problem does not allude to unit conversion, so you should assume that you have to use the given numbers. With the given Ppressure in kPa, Q would be less than K, meaning NH3 would be formed and the forward reaction is favored, bu...
- Thu Jan 10, 2019 1:12 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: H2O
- Replies: 5
- Views: 390
Re: H2O
Yes, any molecule in gas or aqueous form should be included in the equilibrium constant.
- Wed Jan 09, 2019 6:56 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 7th Edition - 5G.3 Mistake?
- Replies: 3
- Views: 272
Re: 7th Edition - 5G.3 Mistake?
Personally, I balanced the equation to get in the habit in case Lavelle gives us an unbalanced equation and doesn't ask us to balance it before finding an equilibrium constant. I heard from other students that the chemistry textbooks normally have some mistakes, so I want to say this is probably one...
- Tue Jan 08, 2019 6:35 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 7th Edition - 5G.3 Mistake?
- Replies: 3
- Views: 272
7th Edition - 5G.3 Mistake?
So I noticed that on part B of problem 5G.3 on page 408, the equation has 10 Nitrogen on one side, and 14 on the other. I noticed the rest of the equation is balanced, and that even the answer on the back shows the partial pressure to a power of 7. Is this a mistake with the textbook?
- Tue Jan 08, 2019 6:24 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Number 5G.5 question
- Replies: 1
- Views: 131
Re: Number 5G.5 question
First start with the formula for K: K = P product / P reactant In this case, the product is 2X, and the reactant is X 2 , which you can get from the balanced equation X 2 <=> 2X Now when taking into account the initial pressure given, 0.10 bar, this pressure accounts for the 11 original X 2 molecule...