Search found 33 matches
- Sun Jun 10, 2018 8:03 am
- Forum: Amphoteric Compounds
- Topic: As2O3
- Replies: 4
- Views: 998
Re: As2O3
In order for it to be amphoteric, it means that the oxide can react either with acid or base. In the case of As2O3 we have the reaction with acid: As2O3 + 6HCl --> 2AsCl3 + 3H2O, and reaction with base NaOH + As2O3 + 3H2O --> 2Na[As(OH)4]. It also applies to Bi2O3. Okay this was the answer I was ex...
- Sat Jun 09, 2018 9:46 am
- Forum: Amphoteric Compounds
- Topic: As2O3
- Replies: 4
- Views: 998
As2O3
How do we determine that As2O3 is amphoteric? I understand that it has acidic and basic characters, but how do I actually figure this out for this compound?
- Sat Jun 09, 2018 8:04 am
- Forum: Bronsted Acids & Bases
- Topic: J13
- Replies: 1
- Views: 340
J13
I understand part a and b of J13 where you calculate the empirical molecular formulas. I have some questions about part c. 1. Will we just be expected to know on a test that the formula C2H2O4 corresponds to (COOH)2? 2. I suppose in the overall equation the reason there are two sodium atoms attached...
- Fri Jun 08, 2018 7:26 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: ethylenediaminetetraacetato (edta)
- Replies: 6
- Views: 1435
ethylenediaminetetraacetato (edta)
Why is ethylenediaminetetraacetato (edta) not octadentate? There are two additional Oxygen atoms that have double bonds and therefore two lone pairs each. These pairs do not interact with the metal. Is it because the shape can't reach those two Oxygen atoms? Oxygen atoms with a formal charge of 0 ca...
- Fri Jun 01, 2018 11:31 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 4.25 a
- Replies: 2
- Views: 360
4.25 a
This problem asks to predict whether CH2Cl2 is polar or nonpolar. Can't the dipole moments of CH2Cl2 cancel out when H is across from H and Cl is across from Cl? Why do you assume H is across from Cl?
- Fri Jun 01, 2018 11:08 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: No central atom
- Replies: 1
- Views: 1389
No central atom
So when we draw up a Lewis structure for a molecule with no central atom are we unable to use the VSEPR notation (AXE)?
- Fri Jun 01, 2018 10:53 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Atoms with Resonance vs Atoms without
- Replies: 1
- Views: 282
Re: Atoms with Resonance vs Atoms without
In the VSEPR model, all bonds are treated as equivalent. Resonance doesn't play a role in determining the molecular shape. Just look at the number of bonding pairs and lone pairs to determine the shape of the molecule. This is my understanding and I hope it helps.
- Wed May 23, 2018 6:37 pm
- Forum: Octet Exceptions
- Topic: Radicals
- Replies: 2
- Views: 419
Radicals
When drawing Lewis structures, does the radical go on the most or least electronegative atom? What is more important in determining which atom it goes on, formal charge or electronegativity?
- Tue May 22, 2018 9:31 pm
- Forum: Ionic & Covalent Bonds
- Topic: 3.27 part C
- Replies: 1
- Views: 228
Re: 3.27 part C
The roman numeral 4 tells you that there is a +4 charge on Manganese. You can now finish solving the problem like the other ones in 3.27. If Mn has a +4 charge and O has a -2 charge (assumed because it requires 2 electrons to reach the nearest noble gas configuration), to balance the compound you ne...
- Tue May 22, 2018 9:18 pm
- Forum: Dipole Moments
- Topic: Do all covalent bonds have dipole nature?
- Replies: 1
- Views: 337
Do all covalent bonds have dipole nature?
Do all covalent bonds have dipole nature or are some covalent bonds, like C-H, so similar in electronegativity that they do not have any dipole nature? Where is the cut off if this is the case?
- Tue May 15, 2018 10:12 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: 3.67 part b
- Replies: 1
- Views: 332
3.67 part b
Why is ClO2 not more stable with a double bond on O and only 1 electron on Cl? The formal charge of the oxygen will turn to 0. Is it not more stable because this will make Cl's formal charge higher?
- Tue May 15, 2018 9:44 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Reducing formal charge number
- Replies: 3
- Views: 844
Reducing formal charge number
I understand how to calculate formal charges. What are the methods you can use to reduce them? I should be checking formal charges on every problem I do, correct?
- Tue May 15, 2018 9:26 pm
- Forum: Resonance Structures
- Topic: 3.59 part c resonance structure? [ENDORSED]
- Replies: 3
- Views: 460
3.59 part c resonance structure? [ENDORSED]
I'm confused about resonance structures. In part c of 3.59, should chlorine nitrate ClONO2 have a resonance structure because the double bond with oxygen can be on either O of NO2?
- Tue May 15, 2018 2:19 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: 3.59 [ENDORSED]
- Replies: 1
- Views: 607
3.59 [ENDORSED]
In chlorine monoxide ClO, when Cl has the radical, the formal charge of Cl is +1 and the formal charge of O is -1. Right? If O is given the radical then the formal charges are 0. Why does Cl have the radical?
- Sun May 13, 2018 11:52 pm
- Forum: Lewis Structures
- Topic: Dots or lines [ENDORSED]
- Replies: 5
- Views: 733
Dots or lines [ENDORSED]
Instead of drawing two dots, my TA saved time by drawing lines which represent two electrons around the element while working through examples in discussion. Can I do this on a test and not be marked down?
- Wed May 09, 2018 9:28 pm
- Forum: Empirical & Molecular Formulas
- Topic: Question 3 on midterm [ENDORSED]
- Replies: 8
- Views: 1209
Re: Question 3 on midterm [ENDORSED]
So i assumed oxygen was present in the compound as well, so I started solving for oxygen. I took each of the masses of the products, divided by the molar mass of that product so I could get the moles, then I used another conversion factor (mole of one element/the mole of each product) to get the mo...
- Wed May 09, 2018 8:21 pm
- Forum: Empirical & Molecular Formulas
- Topic: Question 3 on midterm [ENDORSED]
- Replies: 8
- Views: 1209
Question 3 on midterm [ENDORSED]
Why were we expected to know the makeup of nicotine? Every empirical and molecular formula problem we've seen in all the practice examples and everything we've covered in class included the elements Hydrogen and Oxygen in the makeup of the compound that underwent combustion. In this question you had...
- Tue May 08, 2018 12:35 pm
- Forum: Trends in The Periodic Table
- Topic: Octets and ionization energy
- Replies: 2
- Views: 392
Octets and ionization energy
Can someone explain to me how I can use “octets” to figure out which ionization energy is higher? Why is Oxygen’s ionization energy lower than Nitrogen’s?
- Sat May 05, 2018 1:40 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron Configuration Exceptions
- Replies: 3
- Views: 421
Re: Electron Configuration Exceptions
I don't believe all the elements in the column below the chromium and copper exceptions follow the same pattern because the electron configuration for Tungsten, an element two periods below Chromium, is [Xe] 4f14 5d4 6s2? Does anyone know why Tungsten does not follow the exception, but in the same p...
- Wed May 02, 2018 8:36 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Homework 2.43
- Replies: 2
- Views: 352
Homework 2.43
I thought Tungsten would follow the same rule as Chromium where the s orbital would only have 1 electron and the d orbital would have 5. Why is this not true? Does the rule stop applying after molybdenum and silver in the fifth period?
- Wed May 02, 2018 6:46 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: 2.17 homework problem
- Replies: 2
- Views: 333
2.17 homework problem
I don't understand why we don't count other orbitals when finding the number of orbitals inside of a sub shell. For part b in 2.17, l=2 so we know that it goes to the d orbital which has 5 spaces to fill. And the answer is 5 orbitals. But what about the s orbital and p orbital that comes before it? ...
- Sat Apr 28, 2018 10:09 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Nodal Planes [ENDORSED]
- Replies: 6
- Views: 825
Re: Nodal Planes [ENDORSED]
How would the presence or absence of a nodal plane influence the electron configuration? Does that mean that the electrons are more evenly distributed in an orbital with nodal planes than in one without nodal planes? The p-, d-, f- orbitals all have nodal planes and non-symmetric electron distribut...
- Sat Apr 28, 2018 10:02 pm
- Forum: Properties of Electrons
- Topic: Hydrogen Levels and Energy [ENDORSED]
- Replies: 3
- Views: 541
Re: Hydrogen Levels and Energy [ENDORSED]
Electrons in hydrogen in lower n-levels have lower energy because they are closer to their attractor, a positively charged nucleus which contains protons and therefore are more satisfied and using less energy. For the Lyman series which includes ultraviolet light the lower energy level is n=1. I'm n...
- Tue Apr 24, 2018 6:26 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic Spectra Post Module #29 [ENDORSED]
- Replies: 3
- Views: 541
Re: Atomic Spectra Post Module #29 [ENDORSED]
If you divide the 11 Joules of energy by the amount of energy per photon you calculated in the first step, you will get the number of photons of infrared radiation generated.
- Sat Apr 21, 2018 8:44 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Discrepancy in Rydberg equation [ENDORSED]
- Replies: 1
- Views: 168
Discrepancy in Rydberg equation [ENDORSED]
At the end of the post module for atomic spectra I understand that when deriving the equation you end up with -R[1/n1^(2)-1/n2^(2)]. Why does the solutions manual under problem 1.15 have the equation listed R[1/n1^(2)-1/n2^(2)] with no negative out in front? Bonus question: is there a way to do 1.15...
- Sat Apr 21, 2018 7:09 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Baseball through sensors experiment [ENDORSED]
- Replies: 5
- Views: 682
Re: Baseball through sensors experiment [ENDORSED]
I read online that hand dryers and urinals have infrared motion sensors. So we cannot see the light when our hands or bodies hit it because the detecting light is not in the visible region.
- Wed Apr 18, 2018 6:47 pm
- Forum: Properties of Light
- Topic: Homework 1.15
- Replies: 3
- Views: 566
Homework 1.15
How do you get the formula v=R(1/(n1)^2-1/(n2)^2)? I see it in the solutions manual but can't understand where it came from.
- Sun Apr 15, 2018 3:08 pm
- Forum: Properties of Light
- Topic: Quantized v. Discrete
- Replies: 5
- Views: 514
Re: Quantized v. Discrete
Adding on to this! in lecture on 4/11/18 he mentioned "the energy of an electron in the H-atom changes as a function of n" What is n? Is it a discrete variable? Because the output of the function is energy, what does n represent? I think what Dr. Lavelle meant is that the function n descr...
- Sun Apr 15, 2018 2:57 pm
- Forum: Photoelectric Effect
- Topic: What is a vacuum?
- Replies: 7
- Views: 845
What is a vacuum?
The photoelectric experiment must be done "in a vacuum." When an experiment is done in a vacuum what does this mean and what does this look like?
- Sun Apr 15, 2018 2:13 pm
- Forum: Photoelectric Effect
- Topic: Video module worked example [ENDORSED]
- Replies: 1
- Views: 167
Video module worked example [ENDORSED]
The question was, "If 3.61 X 10^(19) J is required to remove an electron with zero kinetic energy from a metal surface, what would be the longest wavelength light that could do this?" The video proceeded and combined the equations E=hv and c=(wavelength)Xv in order to find the wavelength, ...
- Sat Apr 07, 2018 8:17 pm
- Forum: SI Units, Unit Conversions
- Topic: why do I not use avogadro's number
- Replies: 5
- Views: 1946
Re: why do I not use avogadro's number
You use Avogadro's number when you are working with moles because 1 mole is equal to approximately 6.022 X 10^(23) atoms/molecules/etc.. The question doesn't ask for anything related to moles. It's interesting because it's actually giving you another method to find how many atoms there are in Beryll...
- Fri Apr 06, 2018 5:25 pm
- Forum: Balancing Chemical Reactions
- Topic: H.3
- Replies: 3
- Views: 552
H.3
In exercise H.3, why is it written SiH4 instead of H4Si? I read that Carbon and Hydrogen come before the other atoms and then the rest follow in alphabetic order (Hill System). Is this an exception or am I just confused?
- Fri Apr 06, 2018 1:28 pm
- Forum: Empirical & Molecular Formulas
- Topic: Which mass of Hydrogen should I use?
- Replies: 3
- Views: 990
Which mass of Hydrogen should I use?
Throughout section E's exercises in the solution manual, the mass of Hydrogen is approximated to be 1.01 g/mol. While in section F of the solution manual, the mass of Hydrogen is approximated to be 1.0079 g/mol. Using 1.01 g/mol changed my answer by a hundredth in a couple problems. Is there a reaso...