CHEMISTRY COMMUNITY

Nandhini_2K

Yes, it will be provided.

Nandhini_2K

Also why don't we calculate the order for reactant C?

Nandhini_2K

Part A asks to calculate the order for each reactant.

The solution Manuel uses experiment 2 and 3 to solve for the order with respect to B. Why can't we use experiment 1 and 2?

Nandhini_2K

Information regarding review sessions have been posted on the website now.

Nandhini_2K

Yes, everything is posted on his website now.

Nandhini_2K

Did Dr.Lavelle mention how many questions the final might cover?

Nandhini_2K

When there's no solid already in the rxn. Both the anode and cathode needs a solid.

Nandhini_2K

During your week 9 discussion

Nandhini_2K

Yes you need add Pt(s) when there's no solid.

Nandhini_2K

If delta G is negative: favors products and spontaneous in forward rxn.
If delta G is positive: favors reactants and non-spontaneous in forward rxn.

Nandhini_2K

Yes balancing redox reactions will be on it.

Nandhini_2K

When delta G is negative the product is favored and spontaneous in forward rxn. When delta G is positive reactants are favored and non spontaneous in forward rxn and spontaneous in reverse rxn.

Nandhini_2K

I believe so, but Dr. Lavelle will probably mention more details the day we get our midterms back.

Nandhini_2K

Negative = Spontaneous
Positive = Non-Spontaneous

Nandhini_2K

The TA's also have the answer key for the midterm questions if you want to take a look at it before you get your midterm back.

Nandhini_2K

Either J or KJ. The final answer in J can be turned to KJ by simply dividing it by 1000.

Nandhini_2K

The test will provide the reaction similar to the homework problems.

Nandhini_2K

Don't compare these two problems because 9.13 has an error. Check the errors in solution manual on the class website. :)

Nandhini_2K

O2 is 0 at standard state. All diatomic elements such as N2, O2, H2, will be zero and any single element from the periodic table.

Nandhini_2K

When we're solving for Enthalpy using standard enthalpy of formation method pure substances are zero.

Nandhini_2K

I think it really depends on what is given in the problem already.

Nandhini_2K · Re: Due date for Discussion Questions Due Sunday at 11:59pm

Due Sunday at 11:59pm

Nandhini_2K

The higher the Ka value the weaker the acid. Since H2SO4 doesn't have a ka value at all it is a strong acid.

Nandhini_2K

Practice problems from homework, the audio-visual focus topic post-assessment, and UA workshop worksheets.

Nandhini_2K

My Plf recommended memorizing this list.

Nandhini_2K

Solids and Liquids don't affect the reactant amount at equilibrium, so we leave them out.

Nandhini_2K

My TA said test 1 will be on Equilibrium and Acid & Base. Also, I doubt topics not discussed during the lecture will show up on the test.

Nandhini_2K

Catalysts has no effect on the Equilibrium composition, but simply speeds up the process to Equilibrium.

Nandhini_2K

R = 0.0821 atm x L / mol x K

Nandhini_2K

I take sessions with AAP for this class, doing homework and practice problems works best for me.

Nandhini_2K

I think Bar and atm are used interchangeably because the values are close.

Nandhini_2K

Caution don't trip!

Nandhini_2K

I round my final solution to keep my answer most accurate as possible.

Nandhini_2K

Yea I don't remember this being covered so probably not

Nandhini_2K

We don't need to remember the special cases just the main ones.

Nandhini_2K

Should look at its VSPER formula and that will take both the lone pairs and bonds into consideration to determine the shape.

Nandhini_2K

We don’t need to draw the geometric shapes, but we should know how it looks and it’s lewis structure.

Nandhini_2K

What do you call a clown who's in jail? A silicon.

Nandhini_2K

By formal charge starting from the lowest close to the zero.

Nandhini_2K

The lone pair is more excited than bonding electron pairs.

Nandhini_2K

Yes, that is correct. The formal charge as close to zero as possible and is not canceling out each other.

Nandhini_2K

The trend for electronegativity and Ionization energy is the same and because of that I think if the element has lower ionization energy it would also be low electronegativity.

Nandhini_2K

Can C have 1 Lone pair and 1 bond? Does this violate the octet rule?

Nandhini_2K

The number of valence electrons for each group.

Nandhini_2K

Making chemistry puns instead of doing actual work, more like...

Nandhini_2K

The ground state electron configuration for Ag+ is [kr] 4d^10 and has no unpaired electrons. The ground state electron configuration for just Ag is [kr] 4d^9 5s^2 but remember we cannot have 4d^9. An electron from 5s^2 will transfer to 4d^9 to become stable. The 4d^9 will become 4d^10. The Ag+ is [k...

Nandhini_2K

What is the difference between Electron Affinity and Electronegativity both seem too similar? Are there any specific ways to distinguish them?

Nandhini_2K

So how do we know when the element’s a “special case”? Do we only write, for example, 4d^10 5s^1 instead of 4d^9 5^2 when the element is near 4d^5 or 4d^10? All the elements in the column Cr and Cu have this special case, but e- configuration should never be 3d^4 and 3d^9 because it should change t...

Nandhini_2K

It goes from s,p,d,f.
s holds 2 electrons
p holds 6 electrons
d holds 10 electrons
f holds 12 electrons

Nandhini_2K

The 4s orbitals are lower than 3d.

Nandhini_2K

What was Avogadro’s favorite board game?
Moleoply

Nandhini_2K

Yes, that is correct. You would take the E from part a (3.37 x 10^-19) multiply by Avogadro's number (6.022 x 10^23)

Nandhini_2K

We have to use sig figs to our final answer to every problem and the right units.

Nandhini_2K

Can someone please tell me what they got for the first problem on this question. I thought I got it right, but it was marked wrong. (Either the molecular or empirical is fine since I can find out the other one). Thank you! I got that question marked down too because I missed an Oxygen. I believe th...

Nandhini_2K

The class is not graded on a curve, but there's still two more tests, one midterm, and a final to catch up if you scored low.

Nandhini_2K

Why are chemists great for solving problems? They have all the solutions.

Nandhini_2K

The workshop sessions provided by Prof Lavelle are similar to AAP

Nandhini_2K

Chemistry jokes are sodium funny

Nandhini_2K

This forum is very helpful!

Nandhini_2K

Makes me feel better seeing many of you feel the same way as me. The first day of the lecture was overwhelming, but the UA step up, workshops, and the online video modules have been really helpful. Hoping that the tests are similar to the practice assessments on the video module.

Search found 60 matches