Search found 31 matches

by Kara Justeson 1B
Wed Jun 13, 2018 8:48 pm
Forum: Lewis Acids & Bases
Topic: HI or HCl: stronger acid
Replies: 8
Views: 516

Re: HI or HCl: stronger acid

is this an exception to the general trend? Because I thought more electronegative atoms formed stronger acids.
by Kara Justeson 1B
Sun Jun 10, 2018 9:07 pm
Forum: Lewis Structures
Topic: Central atom and octet rule?
Replies: 12
Views: 537

Re: Central atom and octet rule?

In response to the question above asking when it's ok to have less than 8 electrons, I think you just have to look at the formal charge and see what makes it the closest to neutral. I'm not completely sure though.
by Kara Justeson 1B
Sun Jun 10, 2018 8:45 pm
Forum: Dipole Moments
Topic: Dipole Moment understanding
Replies: 5
Views: 332

Re: Dipole Moment understanding

I think a dipole moment is when there is an uneven sharing of the charges between the atoms. It relates to the partial negatives and partial positives on the atoms due to electronegativity differences. For example in H20 the Hydrogens have a partial positive and the Oxygen has a partial negative whi...
by Kara Justeson 1B
Sun Jun 10, 2018 8:39 pm
Forum: Bronsted Acids & Bases
Topic: Bronsted vs Lewis Acids and Bases
Replies: 5
Views: 367

Re: Bronsted vs Lewis Acids and Bases

Yes, Bronstead Acid is a H+ donor, while a Bronstead base is a H+ acceptor. Lewis Acid acid accepts the electron pair while the Lewis base donates the electron pair. I think the difference is just in the way they define the exchange.
by Kara Justeson 1B
Sun Jun 03, 2018 11:52 pm
Forum: Hybridization
Topic: Hybrid Orbitals
Replies: 3
Views: 179

Re: Hybrid Orbitals

does this mean that it could have an s and a pz but not the px or py (like h2)? would the orbitals not go in order?
by Kara Justeson 1B
Sun Jun 03, 2018 11:47 pm
Forum: Shape, Structure, Coordination Number, Ligands
Topic: 4 ligands shape?
Replies: 6
Views: 182

Re: 4 ligands shape?

I might be wrong, but I thought we didn't have to know how to tell the difference for this class. Based off what I understood from lecture I think we were just supposed to know that both types have four ligands.
by Kara Justeson 1B
Sun Jun 03, 2018 11:44 pm
Forum: Lewis Acids & Bases
Topic: Acids/Bases and Lewis Acids/Bases
Replies: 2
Views: 102

Re: Acids/Bases and Lewis Acids/Bases

I think it has to do with different ways scientists classified acids and bases. I think they're just alternate ways to define them based on their properties.
by Kara Justeson 1B
Sun May 27, 2018 9:00 pm
Forum: Ionic & Covalent Bonds
Topic: Difference between polar covalent and ionic bond?
Replies: 2
Views: 221

Re: Difference between polar covalent and ionic bond?

For this you would look at the difference in their electronegativities. If the bond is classified as covalent based on the electronegativity difference, but it has a high difference thats closer to the measure for ionic bonds, it's more likely to be polar covalent. You can tell it's ionic if the dif...
by Kara Justeson 1B
Sun May 27, 2018 8:54 pm
Forum: Lewis Structures
Topic: Single electron
Replies: 5
Views: 117

Re: Single electron

I think with how you're asking why it doesn't just become a cation, it's because a radical is still a neutral atom (it has no charge since the protons=neutrons). So if it gained or lost an electron, it would become an ion. So it needs the presence of another (or multiple) atoms to pair it's single e...
by Kara Justeson 1B
Sun May 27, 2018 8:46 pm
Forum: Octet Exceptions
Topic: expanded octets
Replies: 5
Views: 265

Re: expanded octets

I'm not completely sure, but I think with the expanded octet it can hold up to as many electrons as the largest orbital of that element. For example, if it had a 3d subshell, since it has a d orbital it should be able to hold up to 10 electrons in the expanded octet.
by Kara Justeson 1B
Thu May 17, 2018 10:51 pm
Forum: Formal Charge and Oxidation Numbers
Topic: Formula Provided
Replies: 6
Views: 261

Re: Formula Provided

In response to the question right above this one, the formal charge also lets you know which structure would be correct since there as sometimes multiple ways you could draw the structure. Since the correct structure is the one thats the most stable (or with the formal charge they give you in that i...
by Kara Justeson 1B
Thu May 17, 2018 10:26 pm
Forum: Ionic & Covalent Bonds
Topic: Configurations
Replies: 4
Views: 147

Re: Configurations

Just like was said above, you remove the outermost electrons because they are furthest from the nucleus and therefore they have the least amount of pull. Since it's the furthest out, it's the most loosely bound. That would make them the easiest to remove.
by Kara Justeson 1B
Thu May 17, 2018 8:34 am
Forum: Ionic & Covalent Bonds
Topic: How to tell which elements will be most likely to form a covalent bond
Replies: 8
Views: 233

Re: How to tell which elements will be most likely to form a covalent bond

I think when you're trying to determine whether a bond is ionic or covalent, you look at the electronegativity difference between the 2 atoms. If the difference is greater than 2 its ionic and if its less than 1.5 its covalent. You would find the electronegativity values on a chart in the book. I ho...
by Kara Justeson 1B
Sun May 13, 2018 9:13 pm
Forum: Resonance Structures
Topic: Radicals
Replies: 13
Views: 598

Re: Radicals

the concept of a radical is that it is any atom that has an unpaired valence electron, but I'm not sure how we use them.
by Kara Justeson 1B
Wed May 09, 2018 11:59 am
Forum: Trends in The Periodic Table
Topic: Zeff HW 2.37
Replies: 2
Views: 152

Re: Zeff HW 2.37

For electrons in the s orbital, they're less shielded than electrons in the p-orbital and therefore the s orbital would have a higher Zeff value. Since Zeff is the positive charge the electron experiences, the less shielding and closer they are to the nucleus, the higher their zeff will be. So, I th...
by Kara Justeson 1B
Tue May 08, 2018 4:25 pm
Forum: Trends in The Periodic Table
Topic: Increasing Ionic radius
Replies: 2
Views: 161

Re: Increasing Ionic radius

Since all of these ions have the same configuration which would be the configuration of Ar (they're isoelectronic), you would order them based on the number of protons they have. Since p has the fewest number of protons, it would pull the electrons the least and therefore have the largest ionic radi...
by Kara Justeson 1B
Wed May 02, 2018 10:36 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Homework 2.43 [ENDORSED]
Replies: 5
Views: 182

Re: Homework 2.43 [ENDORSED]

I think for Ag, its because a fully filled or half filled d orbital is more stable, so it will try to be at either 5 or 10 electrons if possible. However, I'm not completely sure if it would then fill the 4d before the 5s or if it fills in the normal order but then transfers the electron to the 4d o...
by Kara Justeson 1B
Wed May 02, 2018 10:15 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Homework 2.43
Replies: 2
Views: 100

Re: Homework 2.43

I think like the person who posted before me that the reason Tungsten isn't the same as Chromium is because Chromium is one of the two exceptions mentioned in lecture. So Tungsten should be following the normal pattern since Chromium is the one that is unusual.
by Kara Justeson 1B
Wed May 02, 2018 10:12 pm
Forum: Quantum Numbers and The H-Atom
Topic: 2.17 homework problem
Replies: 2
Views: 108

Re: 2.17 homework problem

I believe for this part it's because they give you the angular momentum quantum # (l). Since they told you l=2, like you said you know it would be the d subshell. Because they told you l=2 you're only looking at that particular subshell not including the s or p.
by Kara Justeson 1B
Tue May 01, 2018 12:50 am
Forum: Electron Configurations for Multi-Electron Atoms
Topic: Homework 2.43 [ENDORSED]
Replies: 5
Views: 182

Re: Homework 2.43 [ENDORSED]

I might be wrong, but if I understand this correctly, the f block shown on the periodic table is inserted in the d block following Ba. Since Tungsten occurs after this block of elements, the f configuration would have to be considered.
by Kara Justeson 1B
Tue May 01, 2018 12:44 am
Forum: Heisenberg Indeterminacy (Uncertainty) Equation
Topic: 1.55 part c
Replies: 1
Views: 67

Re: 1.55 part c

Since the energy we found in part b was Joules per molecule, you would multiply it by avogadro's number (which gives the number of molecules in a mol) in order to convert the energy to the number of joules per mol.
by Kara Justeson 1B
Tue May 01, 2018 12:41 am
Forum: Heisenberg Indeterminacy (Uncertainty) Equation
Topic: 1.55 part b
Replies: 2
Views: 95

Re: 1.55 part b

I might be wrong but I think the equation used for this problem was just E=hv. In part a you would find the frequency based on the given wavelength, and in part b, you would use the frequency you found in part a and just plug it into the equation E=hv.
by Kara Justeson 1B
Sun Apr 22, 2018 10:16 pm
Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
Topic: Problem 1.15 Textbook
Replies: 6
Views: 274

Re: Problem 1.15 Textbook

for reference the problem says: in the uv spectrum of atomic hydrogen, a line is observed at 102.6nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line. I understand how you find n=3 as being one of the en...
by Kara Justeson 1B
Sun Apr 22, 2018 9:59 pm
Forum: Einstein Equation
Topic: eV to Joules [ENDORSED]
Replies: 1
Views: 134

Re: eV to Joules [ENDORSED]

You would use the constant given where 1 ev= 1.602x10^-19 J
by Kara Justeson 1B
Sun Apr 22, 2018 9:45 pm
Forum: Photoelectric Effect
Topic: Homework Problem #33
Replies: 4
Views: 154

Re: Homework Problem #33

I think for that part you have to use the equation "Ephoton = Ek + work function" based on the correct answer. But I'm also a little confused about this equation and when to use it in general.
by Kara Justeson 1B
Sun Apr 15, 2018 10:13 pm
Forum: Properties of Light
Topic: Wavelength and frequency proportions [ENDORSED]
Replies: 5
Views: 161

Re: Wavelength and frequency proportions [ENDORSED]

The equation is c=hv (speed=wavelength x frequency). Since c (speed) is a constant if wavelength decreased, frequency would have to increase in order for the constant c to remain the same (3.00 x 10^8). Essentially, the wavelength and frequency have to equal the constant c when they're multiplied to...
by Kara Justeson 1B
Sun Apr 15, 2018 10:08 pm
Forum: SI Units, Unit Conversions
Topic: conversion from Fahrenheit to kelvin
Replies: 3
Views: 177

Re: conversion from Fahrenheit to kelvin

I think you have to go through celsius first, but you can do it all in one step. So you could do (F-32)x (5/9) +273.15 to convert to Kelvin.
by Kara Justeson 1B
Sun Apr 15, 2018 10:02 pm
Forum: SI Units, Unit Conversions
Topic: chemical formula [ENDORSED]
Replies: 4
Views: 217

Re: chemical formula [ENDORSED]

For the molecular and empirical formulas, if you only had the molecular structure (i think you're talking about the 3d pictures with different colors representing different atoms), you could count the number of each type of atom represented and use that to directly write the molecular formula (one c...
by Kara Justeson 1B
Sun Apr 15, 2018 9:46 pm
Forum: SI Units, Unit Conversions
Topic: Quiz 1
Replies: 6
Views: 291

Re: Quiz 1

The empirical formula would be the smallest ratio of the elements. For example if the molecular formula was C4H10, the empirical formula would be C2H5 (divided by a ratio of 2). Whereas the molecular formula tells you how many atoms are in that compound.
by Kara Justeson 1B
Sun Apr 15, 2018 9:40 pm
Forum: SI Units, Unit Conversions
Topic: chemical formula [ENDORSED]
Replies: 4
Views: 217

Re: chemical formula [ENDORSED]

I believe the 2 in 2Na is acting as a coefficient, so you would have 2 mols of Na whereas Na2 would change the structure of the atom. Na2 would be 2 Na bonded together while 2Na is still an unbound Na but in with a stochiometric coefficient so the ratios allow the chemical reaction to be balanced.
by Kara Justeson 1B
Sun Apr 15, 2018 9:20 pm
Forum: Properties of Light
Topic: HW chapter 1 question 3
Replies: 5
Views: 271

Re: HW chapter 1 question 3

Also since we know E=hv, since h is a constant if v(the frequency) decreases then E would decrease so D) is not correct. Going off the other equations we know we can also see that answers A) and B) don't represent the correct relationships between the terms. For A) the speed would not decrease becau...

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