CHEMISTRY COMMUNITY

Elena 1H

I think thats correct, and yes oxoacid an oxyacid are the same thing.

Elena 1H

An amphoteric compound can function as an acid or a base depending on whether the other compound in the reaction is an acid or a base. It will act as the opposite of the other compound in the reaction

Elena 1H

If they have no effect of the pH then you can leave them out of the equation. The two examples he gave in class were Na⁺ and Cl^-

Elena 1H

I think the VSEPR shape is determined by the number of regions of electron density and the molecular shape is the actual shape of the molecule once the lone pairs have been accounted for. My TA used IF 4 + as an example. It has 5 regions of electron density so its VSEPR shape is trigonal bipyramidal...

Elena 1H

sigma bonds overlap end-to-end and pi bonds overlap side-to-side if that helps

Elena 1H

My TA gave us a helpful chart: Regions of e- density e- arrangement ------------------------------------------------------------- 2 linear 3 trigonal planar 4 tetrahedral 5 trigonal bipyramidal 6 octahedral And also remember the VSEPR formula: AXE A= central atom X= number of bound atoms E= number o...

Elena 1H

A dipole occurs between two covalently bonded atoms where one is more electronegative than the other. This difference creates a separation of electrical charges

Elena 1H

A rod shape is stronger than a spherical shape because a rod shape allows the positive and negative charges on the molecule to be closer together, since pentane is in a rod shape it has a higher melting point than 2-dimethylpropane

Elena 1H

I think the overall formal charge should be the same for each resonance structure, the formal charges of the individual elements in the molecule could be different because of the different bond placements, but overall I think it should be the same.

Elena 1H

I dont think professor Lavelle has gone over covalent radius yet, if hes even going to.

Elena 1H

Today in the review session we were also given an equation for finding the number of electrons using l, 4l+2

Elena 1H

I dont think we need to know the e- configuration for an atom in its excited state we just need to be able to recognize when its in its excited state. Im pretty sure if it violates one of the three rules (pauli, hund, aufbau) then its in the excited state

Elena 1H

^Yes because 4d is at a lower energy level than 5s

Elena 1H

Having a full octet means the atom is more stable and therefore less reactive because it does not need to gain or lose any electrons.

Elena 1H

Its because of half shell stability, N has 3 electrons in the 2p orbital so half the 2p orbital is filled. O has 4 electrons and in order to become more stable it wants to lose the electron to achieve half shell stability.

Elena 1H

They are basically the same equation E=hc/λ is just the derived version of E=hv since v=c/λ.

Elena 1H

Use that equation and plug in the values/constants then since E is the energy for one photon just multiply by the amount of photons to get the answer

Elena 1H

I initially used the derived equation λ=hc/E but I realized it was easier to just use λ=c/v because all the values are given to you, but yes you are on the right track

Elena 1H

from c=λv you solve for v and get v=c/λ. You substitute c/λ for v in the E=hv equation and get E=hc/λ

Elena 1H

Not necessarily because De Broglie cannot be used for light but it can be used for things with mass.

Elena 1H

I agree it definitely needs to be converted so maybe just check your conversion values.

Elena 1H

Im pretty sure its always the combustion element + oxygen ---> H2O + CO2 so yes? Im not sure what you mean by "solve for"

Elena 1H

its also a book by Carol Weston

Elena 1H

It depends on the values you have and what you are solving for. Its not always necessary to rearrange equations it just depends on what you're given to begin with.

Elena 1H

Units depend on the question. If it asks for specific units convert to those units. If it doesn't then use whatever units are used for the given values. The important thing is to use the same units when you are actually calculating the values.

Elena 1H

He just plugged in the values. h and c are constants (planck's constant and the speed of light) and they will always be given to us. E is the value given in the problem (3.61 x 10^-14 J). by solving the equation (lambda=hc/E) you get the answer in meters which he then converted to nano meters.

Elena 1H

Amplitude is the height of the wave, wavelength is the distance from crest to crest or trough to trough

CHEMISTRY COMMUNITY

Search found 27 matches

Re: Section 12.10

Re: Amphoteric Compiund

Re: Writing the chemical equation for proton transfers

Re: Molecular vs. VSEPR shape

Re: Pi/Sigma bonds clarification

Re: VSEPR

Re: Meaning of a dipole

Re: Pentane vs. 2-dimethylpropane

Re: Resonance Structures

Re: Periodic Trends

Re: 2.29

Re: HW Problem 2.39

Re: 3d before 4s

Re: Stability of Cl vs Cl-

Re: Unicorn practice test 6d.

Re: Difference Between Equations [ENDORSED]

Re: Hw problem 1.59 [ENDORSED]

Re: Test #2: Q6 [ENDORSED]

Re: Combining E=hv and c=ƛv [ENDORSED]

Re: Wavelength and De Broglie Equation [ENDORSED]

Re: DeBrogile Module

Re: Combustion Reaction [ENDORSED]

Re: What is the speed of life though

Re: formula for light problems

Re: Units for Wavelengths [ENDORSED]

Re: help on the question from Fridays lecture [ENDORSED]

Re: wavelength description [ENDORSED]