Search found 28 matches
- Sun Jun 03, 2018 11:06 pm
- Forum: Hybridization
- Topic: Sigma Bonds
- Replies: 5
- Views: 708
Re: Sigma Bonds
Also, sigma bonds are those formed between orbitals end-to-end, so they allow bound atoms to rotate, unlike pi bonds.
- Sun Jun 03, 2018 11:04 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: AXE formula
- Replies: 32
- Views: 12318
Re: AXE formula
Yes. A represents the center atom, X represents atoms bonded to the center atom, and E represents lone electron pairs. X and E together represent regions of electron density.
Each AXE formula corresponds to a different molecular structure shown in the chart posted by Jack.
Each AXE formula corresponds to a different molecular structure shown in the chart posted by Jack.
- Sun Jun 03, 2018 10:58 pm
- Forum: Sigma & Pi Bonds
- Topic: Sigma and Pi bonds
- Replies: 3
- Views: 579
Re: Sigma and Pi bonds
We would likely be given a bond (single, double, or triple) and be asked to find the number of sigma/pi bonds. We should also be able to identify the fact that sigma bonds are two orbitals bonding end-to-end where bond atoms can rotate, whereas pi bonds are two orbitals bonding side-by-side where bo...
- Thu May 24, 2018 9:59 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Formal charge with ions
- Replies: 4
- Views: 808
Re: Formal charge with ions
The last answer explains it well. The charge of the ion should be the same as the formal charge. This is why the formal charges of atoms and molecules should be equal to 0 if they are not ionized.
- Thu May 17, 2018 7:50 pm
- Forum: Lewis Structures
- Topic: Radicals
- Replies: 2
- Views: 368
Re: Radicals
I don't see any way for that to happen because each orbital can only contain two electrons, and by definition, a radical is an atom, molecule, or ion with an unpaired valence electron.
- Thu May 17, 2018 7:42 pm
- Forum: Lewis Structures
- Topic: HW 3.41 part c)
- Replies: 1
- Views: 299
Re: HW 3.41 part c)
Yes, a lot of complex organic molecules are structured like this. This is because organic molecules may contain certain "functional groups" that give the molecules specific properties. For example, COOH is a carboxyl group and NH2 is an amino group. Writing the groups separately in the che...
- Thu May 17, 2018 7:35 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Formal Charge
- Replies: 3
- Views: 601
Re: Formal Charge
Yes, correct.
- Sun May 13, 2018 12:12 am
- Forum: Formal Charge and Oxidation Numbers
- Topic: Oxidation Number & Bonds
- Replies: 6
- Views: 2594
Re: Oxidation Number & Bonds
Cl will basically always become Cl- (oxidation number -1) to achieve a full octet. Gaining one electron is much easier than losing 7 electrons. Some other elements, however, have almost equally likely oxidation states. One example is Cu, which can become Cu+ (oxidation number +1) or Cu2+ (oxidation ...
- Sun May 13, 2018 12:07 am
- Forum: Ionic & Covalent Bonds
- Topic: radicals [ENDORSED]
- Replies: 9
- Views: 1181
Re: radicals [ENDORSED]
These atoms or molecules are found whenever the number of valence electrons is odd, leaving one unpaired valence electron.
- Fri May 11, 2018 3:05 pm
- Forum: Lewis Structures
- Topic: Ionic vs Covalent
- Replies: 5
- Views: 758
Re: Ionic vs Covalent
Usually, ionic bonds are between metals and non-metals, whereas covalent bonds are between non-metals and other non-metals.
- Sun May 06, 2018 2:03 pm
- Forum: Trends in The Periodic Table
- Topic: Atomic Radius [ENDORSED]
- Replies: 4
- Views: 712
Re: Atomic Radius [ENDORSED]
As you go across a period, there are more protons as well as electrons and unlike going down in a group, all the electrons are in the same shell. When more protons and more electrons are added (electrons to the same shell), the attraction is greater and the electrons are pulled in, decreasing atomic...
- Sun May 06, 2018 1:59 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: HW 2.29 [ENDORSED]
- Replies: 4
- Views: 654
Re: HW 2.29 [ENDORSED]
The Pauli Exclusion Principle states that no two electrons in an atom can have the same four quantum numbers. Since in b) and d), ml is given, we know there can only be two electrons described by these numbers (one with ms=+1/2 and one with ms=-1/2). So the value of ml doesn't actually matter. It's ...
- Fri May 04, 2018 2:01 pm
- Forum: Trends in The Periodic Table
- Topic: Issues with 7th Edition Textbook
- Replies: 3
- Views: 473
Re: Issues with 7th Edition Textbook
Thanks so much! It's patienceolsen@gmail.com
- Fri May 04, 2018 2:02 am
- Forum: Trends in The Periodic Table
- Topic: Ionization Energy
- Replies: 4
- Views: 577
Re: Ionization Energy
Ionization energy refers to the energy required to remove an electron from an atom while electron affinity refers to the energy released when an electron is added to an atom. The trends for both correlate. For example, a halogen element (group 17) is very likely to gain an electron, so it will have ...
- Thu May 03, 2018 11:19 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Question 1.19 Help
- Replies: 2
- Views: 381
Re: Question 1.19 Help
You can also use the formula for the number of electrons that can occupy a subshell: ml=2l+1
For (b), you would plug in l=2 to get ml=5 and for (c), you would plug in l=1 to get ml=3.
For (b), you would plug in l=2 to get ml=5 and for (c), you would plug in l=1 to get ml=3.
- Thu May 03, 2018 11:08 pm
- Forum: Trends in The Periodic Table
- Topic: Ionization Energy
- Replies: 4
- Views: 577
Re: Ionization Energy
Yes, lower is just meant to be a relative term and doesn't correspond to a specific value. An element with a lower IE is more likely to become a cation than an element with a higher IE because it doesn't take as much energy to remove an electron from the element with lower IE.
- Thu May 03, 2018 11:00 pm
- Forum: Trends in The Periodic Table
- Topic: Issues with 7th Edition Textbook
- Replies: 3
- Views: 473
Issues with 7th Edition Textbook
I made a terrible mistake by purchasing the 7th edition textbook because the questions in this textbook do not align with the questions in the 6th edition textbook, even though it says on the Chem 14A website that the 7th edition textbook is fine to use. For Fundamentals and Chapter 1, I was able to...
- Thu May 03, 2018 10:29 pm
- Forum: Properties of Electrons
- Topic: Electron Affinity
- Replies: 4
- Views: 759
Re: Electron Affinity
Electron affinity is the amount of energy released when an electron is added to a neutral atom. It can also be understood as the likelihood of an atom to accept an electron, so the halogens have the greatest electron affinity of all elements. Noble gases, being in a stable state, have the lowest ele...
- Thu May 03, 2018 8:12 pm
- Forum: Ionic & Covalent Bonds
- Topic: Octet
- Replies: 7
- Views: 1028
Re: Octet
Also, the eight electrons come from two electrons in the s-orbital and six electrons in the p-orbital for most atoms. Hope this clarifies things a bit.
- Fri Apr 20, 2018 10:41 am
- Forum: Photoelectric Effect
- Topic: Lyman vs. Balmer vs. Paschen vs. Brackett?
- Replies: 3
- Views: 1385
Re: Lyman vs. Balmer vs. Paschen vs. Brackett?
The last comment is correct. Series are defined by the amount of energy they contain, and wavelengths in the Lyman series, for example, are grouped together because the light has enough energy to reduce an electron to its ground state (n=1). The Lyman series represents the UV spectrum, Balmer repres...
- Thu Apr 19, 2018 11:37 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Lyman and Balmer Series
- Replies: 3
- Views: 467
Re: Lyman and Balmer Series
To add on to previous answers, the Lyman series represents the highest energy series (UV), with enough energy to reduce electrons to the lowest energy level n=1. The Balmer series represents the second highest energy series (visible light), with enough energy to reduce electrons to the energy level ...
- Thu Apr 19, 2018 10:06 pm
- Forum: General Science Questions
- Topic: Notation
- Replies: 3
- Views: 688
Re: Notation
I don't think there should be any special reason for this difference. Either way, the difference doesn't concern us because it wouldn't affect our marks.
- Wed Apr 11, 2018 1:43 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Parent acids
- Replies: 1
- Views: 484
Re: Parent acids
By the Arrhenius theory, an acid is any compound that releases a hydrogen ion into solution when dissolved. There are other acids (Brønsted–Lowry and Lewis) that go beyond this theory but that's irrelevant to the question. Basically, the release of a hydrogen ion in solution is one way to define a c...
- Wed Apr 11, 2018 1:27 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Homework problem G13
- Replies: 1
- Views: 334
Re: Homework problem G13
Refer to the answer for https://lavelle.chem.ucla.edu/forum/viewtopic.php?f=10&t=30583 . The first step is to find the molarity of the diluted solution. The person asking the question above solved this by using the dilution formula M1V1 = M2V2. This formula is based on the fact that the number o...
- Wed Apr 11, 2018 1:07 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Fundamentals HW G.13
- Replies: 1
- Views: 447
Re: Fundamentals HW G.13
Find the moles of NH4NO3 in each 100. mL sample:
0.050 mol NH4NO3/L * 0.100 L = 0.0050 mol NH4NO3
In each molecule of NH4NO3, there are 2 nitrogen atoms. Multiply by this ratio to find the moles of nitrogen:
0.0050 mol NH4NO3 * 2 mol N/1 mol NH4NO3 = 0.0100 mol N
Each plant receives 0.0100 mol N.
0.050 mol NH4NO3/L * 0.100 L = 0.0050 mol NH4NO3
In each molecule of NH4NO3, there are 2 nitrogen atoms. Multiply by this ratio to find the moles of nitrogen:
0.0050 mol NH4NO3 * 2 mol N/1 mol NH4NO3 = 0.0100 mol N
Each plant receives 0.0100 mol N.
- Tue Apr 10, 2018 11:39 pm
- Forum: Properties of Electrons
- Topic: Electromagnetic Field [ENDORSED]
- Replies: 7
- Views: 860
Re: Electromagnetic Field [ENDORSED]
Anyone please correct me if I'm wrong but I think it's arbitrary which field points in which direction, and it's only done this way for convention. What matters is that the waves propagate at right angles to one another.
- Tue Apr 10, 2018 11:29 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Outline 1 (Molarity,solutions, Dilutions) #25
- Replies: 2
- Views: 345
Re: Outline 1 (Molarity,solutions, Dilutions) #25
Find molarity (M) of the original solution: 5.00 g KMnO4/0.15000 L soln * 1 mol KMnO4/158.04 g KMnO4 = 0.211 mol/L = 0.211 M Find how many moles of KMnO4 are present in 20.00 mL of this solution using molarity from previous step: 0.211 mol/L * 0.02000 L = 0.00422 mol KMnO4 Find molarity of the new s...
- Tue Apr 10, 2018 11:09 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Formula Units
- Replies: 6
- Views: 16805
Re: Formula Units
Formula units are basically empirical formulas for ionic compounds, but in most questions just represent molecules (in their simplest, empirical form). For example, E.9 (b) asks for the number of formula units of magnesium sulfate heptahydrate in a 5.15 g sample of the compound. This question is sol...