CHEMISTRY COMMUNITY

Solene Poulhazan

If you search with the key word "French Toast" you can access the practice final exam. This could be useful in determining how the real final will be. Chem Mod: This is incorrect. French Toast gives practice problems but is not indicative of how the final will be structured. Your final wil...

Solene Poulhazan

I'm a little unclear about oxidation numbers. How do I calculate them and how does knowing this help describe coordination compounds?

Solene Poulhazan

I'm a little confused about hybridization as well. How does this relate to these orbitals?

Solene Poulhazan

Why do chemists like nitrates so much?
They're cheaper than day rates.

Solene Poulhazan

I'm not sure If I understand the question, but I found a chart on molecular shapes that may be useful for you!
Hope this helps!

: Molecular Shape

Solene Poulhazan

You can look at the number of electron groups and the number of bonding groups (and lone pairs). This will help you identify the molecular shape.

Solene Poulhazan

This is t-shaped because there are 5 electron groups, 3 bonding groups and 2 lone pairs. A trigonal planar arrangement only has 3 electron groups.

Solene Poulhazan

The less there are of bonding groups, the more lone pairs are present.

Solene Poulhazan

Is this something we need to know for the exam?

Solene Poulhazan

This represents the overall charge of the molecule.

Solene Poulhazan

Water has 8 electrons around the central oxygen atom. This means there are four electron pairs arranged in a tetrahedral shape. There are two bonding pairs and two lone pairs.

Solene Poulhazan

In terms of electronegativity: the greater the electronegativity difference, the greater the bond polarity and therefor the greater the bond strength will be.

Solene Poulhazan

Once you find the number of valence electrons for each element in the compound, you can figure out how many bonds need to be formed for each element.

Solene Poulhazan

Are there more exceptions to electron configurations other than chromium and copper?

Solene Poulhazan

I believe that we can just follow the same trends for both of these concepts. For electron affinity and ionization energy, it increases across a period and decreases down a group.

Solene Poulhazan

For which formula do we need to use ∆P and ∆X in?

Solene Poulhazan

I think the equation you are looking for is simply E=hv

Solene Poulhazan

a)
wavelength = 589nm convert it to m, 5.89 x10^-7 m

Then, you can use the formula E= hc/wavelength

E = (6.626 x 10^-34)(2.99 x 10^8) / (5.89 x 10^-7)
= 3.37 x 10^-19 J

Solene Poulhazan

I don't think the model that we have learned this far, meaning the rydberg equation, allows us to do so.

CHEMISTRY COMMUNITY

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Re: Final Layout

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