Search found 31 matches

by princessturner1G
Sun Jun 10, 2018 1:05 pm
Forum: Hybridization
Topic: Electron densisty
Replies: 5
Views: 277

Re: Electron densisty

Electron density is the number of bonds and unpaired electrons around an atom. Bonds, whether single, double or triple and unpaired electrons count as one region of electron density. If there are 3 bonds attached to an atom and one pair of unpaired electrons, it has 4 regions of electron density.
by princessturner1G
Sat Jun 09, 2018 1:44 pm
Forum: Shape, Structure, Coordination Number, Ligands
Topic: coordination number=polydentate number?
Replies: 5
Views: 146

Re: coordination number=polydentate number?

Does coordination number include double bonds?
by princessturner1G
Sat Jun 09, 2018 1:07 pm
Forum: Shape, Structure, Coordination Number, Ligands
Topic: Coordination Number
Replies: 2
Views: 104

Re: Coordination Number

That is correct. For example, [Fe(CN)6]4- has a coordination number of six.
by princessturner1G
Sat Jun 09, 2018 1:05 pm
Forum: Shape, Structure, Coordination Number, Ligands
Topic: Polydentate
Replies: 5
Views: 249

Re: Polydentate

There have to be two different atoms which have lone pairs for it to be polydentate, correct?
by princessturner1G
Sun Jun 03, 2018 10:02 pm
Forum: Hybridization
Topic: basics of hybridization
Replies: 18
Views: 602

Re: basics of hybridization

When do you use hybridization and what is the main point of it?
by princessturner1G
Sun Jun 03, 2018 10:01 pm
Forum: Hybridization
Topic: VSEPR
Replies: 11
Views: 504

Re: VSEPR

VSEPR stands for "Valence-Shell-Electron-Pair-Repulsion". It is used for molecular geometry.
by princessturner1G
Sun Jun 03, 2018 1:20 am
Forum: Determining Molecular Shape (VSEPR)
Topic: Bond angles [ENDORSED]
Replies: 3
Views: 131

Bond angles [ENDORSED]

How do lone pairs affect the bond angles for each shape? Does the bond angle increase or decrease due to lone pairs?
by princessturner1G
Sun May 27, 2018 8:31 pm
Forum: Sigma & Pi Bonds
Topic: Sigma and pi
Replies: 12
Views: 629

Re: Sigma and pi

Yes, a double bond is one sigma plus one pi bond. While a triple bond is a sigma bond plus two pi bonds.
by princessturner1G
Sun May 20, 2018 11:09 pm
Forum: Formal Charge and Oxidation Numbers
Topic: oxidation
Replies: 7
Views: 316

Re: oxidation

So when you are dealing with oxidation states, you will generally have a + or -, because almost any element can have e- added or taken away in order to get to the nearest noble gas configuration. The goal is to get an octet. An example from chapter 3 HW is 3.23, Cl can have -1 or +7. This is becaus...
by princessturner1G
Sun May 20, 2018 5:12 pm
Forum: Electronegativity
Topic: Electronegativity difference
Replies: 3
Views: 235

Electronegativity difference

Why is the Mg-Cl bond considered to be ionic?
by princessturner1G
Sun May 20, 2018 4:05 pm
Forum: Ionic & Covalent Bonds
Topic: Polar covalent bonds
Replies: 2
Views: 103

Polar covalent bonds

Can someone explain what a polar covalent bond is? The book states "A bond in which ionic contributions to the resonance result in partial charges", but I am not entirely sure what that means.
by princessturner1G
Thu May 17, 2018 8:55 am
Forum: Lewis Structures
Topic: Central atom
Replies: 7
Views: 223

Re: Central atom

Wait, where are you guys getting ionization energy from? I thought the central atom has to be the element that was the least electronegative, which is why C is the central atom since it has the electronegativity Ionization energy follows the same trend as electronegativity, so you can think of it a...
by princessturner1G
Mon May 14, 2018 9:10 pm
Forum: Ionic & Covalent Bonds
Topic: 3.33 b
Replies: 2
Views: 112

Re: 3.33 b

With the double bond between carbon and oxygen, this satisfies the octet rule. Now all the atoms have eight electrons.
by princessturner1G
Sun May 06, 2018 4:52 pm
Forum: Molarity, Solutions, Dilutions
Topic: Moles [ENDORSED]
Replies: 2
Views: 166

Moles [ENDORSED]

What does the concept "the moles of solute stay the same"?
Can someone give me an example and how I would apply it?
by princessturner1G
Sun May 06, 2018 3:55 pm
Forum: Molarity, Solutions, Dilutions
Topic: Test 1. Q 2
Replies: 3
Views: 317

Re: Test 1. Q 2

I did not have the same version of the test, but here is what I think are the correct steps: So, it says that 50.0 mL of .200M of NiCl2 aqueous solution is prepared (called electrolyte). An electrode surface is placed into the solution, and after the electrodeposition process, some of the Ni is dep...
by princessturner1G
Sat May 05, 2018 11:50 pm
Forum: Molarity, Solutions, Dilutions
Topic: Test 1, Q1
Replies: 2
Views: 218

Test 1, Q1

a)A solution of anhydrous iron chloride, FeCl3, is prepared by dissolving 10g of salt to 1L water. What is the concentration of chloride ions of the above solution? b) The above solution is diluted with 1L of 0.100 M potassium chloride, KCL, solution. What is the concentration of chloride ions after...
by princessturner1G
Wed May 02, 2018 10:44 pm
Forum: Wave Functions and s-, p-, d-, f- Orbitals
Topic: 2.19
Replies: 3
Views: 116

2.19

How do we know how many subshells there are when we are given an n value?

For example, "How many subshells are there in the shell with n=4?"
by princessturner1G
Fri Apr 27, 2018 4:50 pm
Forum: Photoelectric Effect
Topic: Test 2 #7 [ENDORSED]
Replies: 3
Views: 168

Re: Test 2 #7 [ENDORSED]

Could someone explain how to do #7 from test 2 Thanks You use the equation Energy of a photon-work function=Kinetic Energy. Since it is asking for the maximum wavelength kinetic energy equals 0. The energy of the photon is then equal to the work function. The energy of the photon= 9.02 x 10^-19 J. ...
by princessturner1G
Fri Apr 27, 2018 3:11 pm
Forum: Photoelectric Effect
Topic: Test 2 final question [ENDORSED]
Replies: 15
Views: 533

Re: Test 2 final question [ENDORSED]

It is 1 thousand electrons. 1 electron per one photon.
by princessturner1G
Tue Apr 24, 2018 5:27 pm
Forum: Properties of Electrons
Topic: Homework 1.15
Replies: 1
Views: 175

Re: Homework 1.15

First, you would start by finding the velocity using v=c/lambda. You are given the wavelength in the problem, which is 102.6 nm (102.6x10^-9 m). Once you solve for the velocity you can use the equation v=R((1/(n final)^2)-(1/(n initial^2)). You know that n1=1 because it is in the ultraviolet spectru...
by princessturner1G
Tue Apr 24, 2018 5:12 pm
Forum: Einstein Equation
Topic: Homework number 1.25a [ENDORSED]
Replies: 3
Views: 217

Re: Homework number 1.25a [ENDORSED]

Yadira Flores 1G wrote:What units would the final answer be in?


The final answer would be in Joules, since it is asking for the energy.
by princessturner1G
Sun Apr 22, 2018 6:39 pm
Forum: Ideal Gases
Topic: Reading the textbook [ENDORSED]
Replies: 115
Views: 74621

Re: Reading the textbook [ENDORSED]

yazminedesan1F wrote:what's the best way to learn the material for someone who's not so familiar with chemistry concepts?


Completing the pre-assessment and the post-assessment are extremely helpful. I recommended doing these and watching the videos as well.
by princessturner1G
Sat Apr 21, 2018 3:04 pm
Forum: Photoelectric Effect
Topic: Photoelectric Post-Module [ENDORSED]
Replies: 3
Views: 149

Photoelectric Post-Module [ENDORSED]

Hello, I am having trouble answering the following question on the photoelectric post-module assessment. Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 105 m.s-1. The work function for sodium is 150.6 kJ.mol-1. Answer the following three questions. A. What is th...
by princessturner1G
Mon Apr 16, 2018 10:10 pm
Forum: Properties of Light
Topic: 1.13 (b)
Replies: 6
Views: 213

Re: 1.13 (b)

You know it is the Balmer series because the wavelength is 486 nm. When you look at Table 1.1, 486 nm is closest to the wavelength of blue light. Since blue light is a type of visible light, you know that it is the Balmer Series.
by princessturner1G
Mon Apr 16, 2018 10:05 pm
Forum: Properties of Light
Topic: HW 1.15
Replies: 4
Views: 169

Re: HW 1.15

I think n=1 because in the problem it states that it is in the ultraviolet spectrum. We learned that for the ultraviolet region that corresponds to the Lyman series. The Lyman series is from higher energy levels to the n=1 level. This is how we would know n is one.
by princessturner1G
Sat Apr 14, 2018 4:13 pm
Forum: Significant Figures
Topic: Expected mastery of Significant Figures
Replies: 6
Views: 284

Re: Expected mastery of Significant Figures

I think by the next test we should be able to use the correct amount of sig figs. Remember always use the lowest number of sig figs and don't round until the end!
by princessturner1G
Thu Apr 12, 2018 12:59 pm
Forum: Molarity, Solutions, Dilutions
Topic: Units - L or mL? [ENDORSED]
Replies: 15
Views: 592

Re: Units - L or mL? [ENDORSED]

The answer usually should be in L. If it is given to you in mL, it is usually easier to multiply it by 10^-3.
by princessturner1G
Tue Apr 10, 2018 10:54 pm
Forum: Molarity, Solutions, Dilutions
Topic: Fundamentals G.5 (part a)
Replies: 1
Views: 90

Re: Fundamentals G.5 (part a)

Remember that M= mol/liters or Liters= mol/M so to calculate the volume we would have to find M first. You can find this by 2.111g/(105.99gmol^-1)(.2500L) = 0.07967 M Now that you have M you can solve for volume by plugging into in V= mol/M V= (2.15*10^-3 mol Na+)/ (0.07967 molL^-1 Na2CO3)(2mol Na+)...
by princessturner1G
Sun Apr 08, 2018 9:10 pm
Forum: Limiting Reactant Calculations
Topic: M11 HW
Replies: 4
Views: 204

Re: M11 HW

On exams, we have to prove it so it is definitely best to do the calculations.
by princessturner1G
Sun Apr 08, 2018 9:02 pm
Forum: Balancing Chemical Reactions
Topic: Balancing the Equation
Replies: 9
Views: 395

Re: Balancing the Equation

A helpful trick is if the equation is unbalanced and the amount of molecules is odd multiply it to get an even coefficient.
by princessturner1G
Sun Apr 08, 2018 1:47 pm
Forum: Balancing Chemical Reactions
Topic: possible test question
Replies: 1
Views: 114

Re: possible test question

My TA said we should memorize the common names of compounds because there is a chance we can be tested on it in the future.
Hope that helps!

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