CHEMISTRY COMMUNITY

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k' is the rate constant for the reverse reaction, and the K ( equilibrium constant ) would be equal to k ( forward reaction ) / k' ( reverse reaction )

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You will definitely be given different trials of the reaction, the rates and the concentrations!

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I think you should know all the chemical kinetic order reactions, that we use to graph.

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This only means that integrating gives different values, and k would be negative or positive, depending on the equation.

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This is true. For a zero order, Rate = K(conc) raised to power 0. So it is just K.

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Zero order is where the reactants are in excess and is a solvent/ liquid and hence the change in its concentration would just be insignificant.

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The more positive the reduction potential, the more favourable it is to get reduced, and thus, the better oxidising agent it is.
And the same is true vice versa.

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We include an inert electrode when either the anode and cathode are either gas/aqueous and both the reactants and the products are in that same phase.
So for example,
A hydrogen( gas ) electrode would require a platinum electrode.

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The only way of knowing n is by balancing the half reactions - so, that the electrons lost and gained tally.

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You will have to flip it if it is not given in terms of reduction potential.

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The cathode is where it is reduction, and thus, the potential will be positive(because it is always written in terms of reduction potential) and the other one will be the anode(which causes oxidation to occur - loss of electrons which we can see from the equation given), and thus we know that is the...

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It is better to use H+ because H30+ would cause us to balance oxygen again, and thus, H+ would be a better option to use.

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It all depends first on whether the equation represents an exothermic or endothermic reaction.
If G is negative, it is said to be a spontaneous reaction.

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We can use it, for ideal gases and monoatomic ones, but with the plethora of equations we have, we would mostly never come across a time to use it.

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What would the right answer be in the last question of the test? How would we go about it: b) Consider the above reaction at equilibrium ( Kc= 0.046 given above), fully describe what will happen if the volume is decreased at constant temperature. How do I do this question? if volume decreases, conce...

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Degeneracy is determined as the number of atoms involved raised to the power of possible states.

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Here, we notice the average change. If the temperature is already very high, then the particles are already moving around a lot and fast, so the change in disorder would be minuscule. But from a low temperature system, the change in the disorder is more visible, and hence the entropy change is highl...

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In a reversible process, it is the sum of infinitely small steps and leads to the expending of the entire energy of the system, and thus is said to be most work done. This never happens in reality, and thus reversible systems are said to be an ideal system. Whereas, in irreversible processes, not al...

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The naught sybol stands for absolute value, thus, its value at standard conditions, almost like its ideal value, when all conditions are said to be standard. This requires the pressure and temperature to be a particular value. And while measuring other values of H, we use this value as the reference...

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It is because, although the temperature of steam is 100 degree Celsius as well, it contains more heat that is used up to change the phase from water to steam. And this heat is also instrumental in burns, and is clearly missing in just water at 100 degree Celsius. Thus, steam causes more of a burn th...

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Its exothermic, because it releases heat and is the opposite of the process that requires heat to change phase.

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Enthalpy is denoted by delta H and that is only final - initial and is a state property.
q though, he will explain further but it denotes the value of heat and that depends on its entire path, where it gains/loses heat.

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Usually, the list of acids and bases remain a constant and we always know what they give us.
But if not, we have to figure out from the lewis structures after we draw them, or from the very formula, if it is given.

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Same number of moles, so no change in direction of equilibrium!
And temperature is as explained above.

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If delta H is positive, the increase in temperature will favour forward reaction, and if delta H is negative, it favours reverse reaction.

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It includes chemical equilibrium, Le Chatelier's principle, as well as acids and bases.

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I am aware that change in pressure does not affect the equilibrium constant K, but when I googled it, it said when there is an increase in pressure, the reaction shifts towards the direction of lesser number of moles, and there is a decrease in pressure, then it shifts towards the side with more mol...

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In most questions, pressure is usually in atm, so use an appropriate R and make all units cancel out!

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Virtually no difference between how we calculate Q and K, but they just tell us different things ( which - either reactant or product is in excess and which side the equilibrium sits)

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Only Kp is measured in terms of partial pressure, always? when it comes to a reaction that is homogeneous (gas), but both Kc and even Qc are always measured in terms of concentration?

CHEMISTRY COMMUNITY

Search found 30 matches

Re: k'

Re: Determining the order

Re: Final Equations

Re: Slope = -k

Re: zero order rate?

Re: Example of a zero order rxn

Re: Reducing Agent/ Oxidizing Agent Strength in Metals

Re: Writing Cell Diagrams

Re: Moles of electrons?

Re: flipping the sign of anodes

Re: determining cathode from anode

Re: H+ vs H3O+

Re: Stability

Re: ΔU= 3/2nRT

Test Question

Re: Degeneracy

Re: Entropy as Temperature Increases

Re: Reversible Processes

Re: Enthalpy Symbol

Re: steam vs. water

Re: Endothermic or Exothermic

Re: Enthalpy and q

Re: How to tell acids and bases

Re: question from module

Re: Part 4 Post-Module Question

Re: test 1 [ENDORSED]

Effect of Pressure

Re: Units

Re: Q and K [ENDORSED]

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