Search found 70 matches
- Sat Mar 09, 2019 3:45 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Equilibrium Constant and Temperature
- Replies: 2
- Views: 371
Re: Equilibrium Constant and Temperature
The assumption for delta G standard is that the temperature is at 25 degrees C or 298 K.
- Sat Mar 09, 2019 3:39 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 6M. 1 7th Edition
- Replies: 2
- Views: 290
Re: 6M. 1 7th Edition
The cell diagram is structured so that it indicates the anode is on the left of the salt bridge (||) and the cathode is on the right side.
- Sat Mar 09, 2019 3:35 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 14.97
- Replies: 2
- Views: 300
Re: 14.97
In the half reactions, F2(g) is being reduced, so this is the cathode, and HF(aq) is being oxidized, so this is the anode.
- Wed Mar 06, 2019 5:24 pm
- Forum: General Rate Laws
- Topic: Question 15.3, Sixth Edition
- Replies: 1
- Views: 292
Re: Question 15.3, Sixth Edition
The formula you can use for the reactant rate is R = -delta[R]/delta t. When you plug in the values for the change in [R], the value is negative. But since that value is also being multiplied by the negative in front of the equation, the overall answer will be positive. Since the rate of O2 is just ...
- Tue Mar 05, 2019 8:52 am
- Forum: General Rate Laws
- Topic: Rate Laws and Temperature
- Replies: 4
- Views: 451
Re: Rate Laws and Temperature
The constant k in the differential rate law depends on temperature and activation energy.
RATE = k[R]^n
RATE = k[R]^n
- Mon Mar 04, 2019 3:12 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: K
- Replies: 5
- Views: 528
Re: K
K = 0 then delta G = 0
K < 1 then delta G > 0
K > 1 then delta G < 0
K < 1 then delta G > 0
K > 1 then delta G < 0
- Wed Feb 27, 2019 3:43 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: E and Spontaneity
- Replies: 2
- Views: 281
E and Spontaneity
Is the cell reaction spontaneous if E is positive and nonspontaneous if E is negative?
- Tue Feb 26, 2019 12:02 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Writing Cell Diagrams
- Replies: 2
- Views: 251
Re: Writing Cell Diagrams
How do we find the half reactions? Some of them are straightforward, but others are really vague and it's difficult to pinpoint which compound to use.
- Tue Feb 26, 2019 11:51 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Writing Cell Diagrams
- Replies: 2
- Views: 251
Writing Cell Diagrams
How do we know what to write for the reduction/oxidation half reactions from a full reaction? Do we just look up the compound in the appendix and see which reaction matches?
- Mon Feb 25, 2019 6:18 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Pressure & K
- Replies: 1
- Views: 225
Pressure & K
Why does reaction free energy depend on pressure and K?
- Mon Feb 25, 2019 3:27 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Standard E [ENDORSED]
- Replies: 1
- Views: 174
Re: Standard E [ENDORSED]
An intensive property just means it doesn't depend on the amount of matter. The voltage difference is the same regardless of how many times the reaction occurs. I think it would be similar to something like delta H fusion/vaporization; it's a set value for that reaction at those certain conditions.
- Mon Feb 25, 2019 3:21 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Reaction Quotient [ENDORSED]
- Replies: 1
- Views: 489
Re: Reaction Quotient [ENDORSED]
In chemical equilibrium, the question will probably be asking about if the reaction stated is at equilibrium or not, and if not, then to explain why. (Q = K means equilibrium, Q not = K means not at equilibrium). It also might ask about the relationship between the amount of reactants or products, w...
- Mon Feb 25, 2019 3:17 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Calculations [ENDORSED]
- Replies: 3
- Views: 407
Re: Calculations [ENDORSED]
For delta G and delta H, the values for the most stable form of that element will be 0. Delta S will most likely still be a value greater than 0, unless it is a perfect crystal.
- Wed Feb 20, 2019 2:51 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Question 9.13 (Sixth Edition)
- Replies: 3
- Views: 474
Re: Question 9.13 (Sixth Edition)
For this problem, there are two variables that are changing: volume and temperature. In order to find total entropy, you need to solve for two equations and add the two together to get the total value. We can use delta S = nRln(V2/V1) for the change in volume and delta S = nRln(T2/T1) for the change...
- Wed Feb 20, 2019 2:49 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Salt Bridge
- Replies: 3
- Views: 345
Re: Salt Bridge
A salt bridge keeps the solutions of both anodes and cathodes neutral by basically providing opposite charges. This is so that electron transfer will continue. If the salt bridge isn't there, there will be a buildup of electrical charge on one side and the transfer of electrons will stop.
- Tue Feb 19, 2019 11:25 am
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: 9.81
- Replies: 2
- Views: 330
Re: 9.81
The standard values for Gibbs free energy for both of these compounds are in Appendix 2A. We can plug in these values into the products minus reactants formula for Gibbs free energy. Depending on if the delta G is positive or negative, we can determine if the forward or reverse reaction is more stab...
- Wed Feb 13, 2019 3:12 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: 9.35
- Replies: 2
- Views: 719
Re: 9.35
Container A has a greater number of particles than the other containers. Therefore, the entropy change is greater. In comparing monatomic with diatomic, there will be more of the monatomic particles because it needs twice as many particles to equal one diatomic particle.
- Wed Feb 13, 2019 3:09 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Equilibrium constant
- Replies: 3
- Views: 306
Re: Equilibrium constant
Yes. The units cancel out when dividing products by reactants.
- Wed Feb 13, 2019 2:25 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: 1 atm to 101.3 J/(atm*L)
- Replies: 2
- Views: 1591
Re: 1 atm to 101.3 J/(atm*L)
This will be on the constants and equations sheet.
- Sat Feb 09, 2019 11:43 am
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Ideal Behavior
- Replies: 3
- Views: 398
Re: Ideal Behavior
Yes, the solution says "Assume ideal behavior and 1 mol N2 gas."
- Sat Feb 09, 2019 11:40 am
- Forum: Calculating Work of Expansion
- Topic: Units
- Replies: 7
- Views: 718
Re: Units
I would just use atm for everything, especially because R constant units are (L*atm)/(K mol).
- Fri Feb 08, 2019 8:13 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Reaction Enthalpies
- Replies: 2
- Views: 339
Reaction Enthalpies
What is the general formula for solving for reaction enthalpies? I'm having a hard time solving for problems where it asks to "calculate the heat absorbed."
- Fri Feb 08, 2019 8:10 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Negative
- Replies: 4
- Views: 1123
Re: Negative
The first law of thermodynamics states that energy is neither created nor destroyed, therefore the overall amount of heat (q) needs to be the same. system + surroundings = universe In heat transfer, if one substance X is losing heat to another substance Y, then substance Y must be gaining the heat t...
- Fri Feb 08, 2019 8:08 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Relationship Between Temperature and Entropy
- Replies: 1
- Views: 221
Re: Relationship Between Temperature and Entropy
The same heat (q) with a lower temperature will yield a greater change in entropy. If the temperature is higher, there will be a smaller change in entropy for the same q value. Since delta S = q/T, if q is the same for two temperatures, the higher temperature means a greater denominator, therefore i...
- Fri Feb 08, 2019 7:33 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: monatomic ideal gas equation
- Replies: 1
- Views: 202
Re: monatomic ideal gas equation
I think it will be given on the constants sheet on the exam. But it won't hurt to remember that Cv = (3/2)R and Cp = (5/2)R.
- Mon Feb 04, 2019 3:23 pm
- Forum: Calculating Work of Expansion
- Topic: Work of Expansion
- Replies: 2
- Views: 302
Re: Work of Expansion
Yes. The definition of expansion work is "the work arising from a change in the volume of a system." The formula for expansion work is given by w = -(Pex)(delta V), where Pex is a constant external pressure.
- Mon Feb 04, 2019 3:19 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Isothermal reversible expansion
- Replies: 2
- Views: 303
Re: Isothermal reversible expansion
If the system is isothermal, that means that the system and surroundings do not exchange matter or energy between each other. This is the case for a reversible expansion because the temperature must be constant in order for the volume to fluctuate so that the pressure is kept constant.
- Mon Feb 04, 2019 3:16 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Degeneracy
- Replies: 8
- Views: 751
Re: Degeneracy
Degeneracy is the number of ways of achieving a given energy state, and can be found by relation of the Boltzmann equation.
- Mon Jan 28, 2019 2:28 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Heat Capacity
- Replies: 3
- Views: 209
Re: Heat Capacity
Something with a high heat capacity means that it would require a lot of heat to increase in temperature, which might make it a good insulator but a bad conductor of heat. Conversely, something with a low heat capacity means that it doesn't take much heat to increase the temperature, which might mak...
- Mon Jan 28, 2019 2:25 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Specific heat capacity
- Replies: 3
- Views: 508
Re: Specific heat capacity
We were given the formula q = (g)(Csp)(delta T), so we can just rearrange the variables to get Csp = q / (g * delta T). We would need to know q (energy), the mass of the substance (g), and the change in temperature (delta T).
- Mon Jan 28, 2019 2:20 pm
- Forum: Phase Changes & Related Calculations
- Topic: Heat Capacity
- Replies: 10
- Views: 963
Re: Heat Capacity
Heat capacity just refers to how much heat is needed to raise the temperature of some substance by 1 degree C. Molar heat capacity is how much heat is needed to raise the temperature of 1 mole of that substance by 1 degree C.
- Wed Jan 23, 2019 2:39 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Homework: 12.63, 6th edition
- Replies: 2
- Views: 339
Re: Homework: 12.63, 6th edition
We know that the formula for percent deprotonation, or percent ionization, is [H+]/[HA] times 100. in this problem, we are trying to find [H+] in order to plug it into the pH formula. The percent deprotonation and the concentration of [HA] (which is in this case benzoic acid) are given to us. 2.4% a...
- Wed Jan 23, 2019 2:34 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Specific Notation
- Replies: 5
- Views: 596
Re: Specific Notation
If PCl5 is aqueous, I would use [PCl5], and if PCl5 is gaseous, use P PCl5. Unless they specify to find partial pressure, I would just use the concentration notation.
- Tue Jan 22, 2019 11:02 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE chart
- Replies: 2
- Views: 260
Re: ICE chart
It depends on which direction the reaction proceeds. If there are some amount of both products and reactants, you can check to see if Q is larger or smaller than K to determine which way the equilibrium is shifting.
- Wed Jan 16, 2019 3:02 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Taking x away in a Ka calculation
- Replies: 5
- Views: 439
Re: Taking x away in a Ka calculation
This only applies if the change in composition (x) is less than 5% of the initial value. Usually if Ka is less than 10^-3, I would disregard the x.
- Wed Jan 16, 2019 2:58 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: % Ionization
- Replies: 3
- Views: 245
Re: % Ionization
After you do the ICE box method and find the equilibrium concentrations, you divide the equilibrium concentration of the conjugate acid or base by the initial concentration of the acid or base given and multiply that by 100. For example, if the chemical reaction was CH3COOH + H2O --> CH3COO- + H3O+,...
- Mon Jan 14, 2019 3:13 pm
- Forum: Ideal Gases
- Topic: Using Kc or Kp
- Replies: 13
- Views: 1043
Re: Using Kc or Kp
Use Kp when the reactants and products are gaseous, and use Kc when the reactants and products are aqueous.
- Thu Jan 10, 2019 2:42 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Difference between C and P?
- Replies: 4
- Views: 238
Re: Difference between C and P?
I would say to use Qp when the reactants and products are in gaseous state, and use Qc when the reactants and products are in aqueous state.
- Wed Jan 09, 2019 4:11 pm
- Forum: Ideal Gases
- Topic: K values
- Replies: 3
- Views: 299
Re: K values
The values in between mean that neither the reactants or products are favored.
- Mon Jan 07, 2019 4:10 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Calculating Equilibrium Concentrations
- Replies: 3
- Views: 257
Re: Calculating Equilibrium Concentrations
Most likely they will be given. Referring back to Chem 14A, we know the concentration of a strong acid or base because it is completely ionized. For weak acids and bases, we will learn how to use ICE tables to calculate them.
- Mon Dec 03, 2018 1:21 pm
- Forum: Naming
- Topic: Ch. 17 #29, 6th edition
- Replies: 1
- Views: 219
Re: Ch. 17 #29, 6th edition
The Roman numeral in the parentheses is the oxidation number of the transition metal. The sum of all charges inside the brackets must add up to the charge on the overall coordination compound. For this specific problem, you are trying to find out the oxidation number of the transition metal. To find...
- Mon Dec 03, 2018 1:14 pm
- Forum: Biological Examples
- Topic: 17.31
- Replies: 1
- Views: 141
Re: 17.31
The Roman numeral in the parentheses indicates the oxidation number of the transition metal in the coordination sphere, so that would mean Cobalt has a charge of +3. This would mean that there would need to be 3 Br to offset this positive charge, since Br has a charge of -1.
- Mon Dec 03, 2018 1:10 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Oxoacids
- Replies: 1
- Views: 197
Re: Oxoacids
The more electronegative atom stabilizes O- by withdrawing electron density. For example, comparing Cl - O and Br - O, Cl pulls the O- closer than Br does. This makes the oxoacid more likely to lose H+.
- Mon Nov 26, 2018 3:13 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Homework 9
- Replies: 3
- Views: 409
Re: Homework 9
Yes, since we've finished molecular shape and structure. We can technically do our homework problems based on any of the chapters, but it would be wise to focus on outlines 3, 4, and 5 because of the upcoming test this week.
- Mon Nov 26, 2018 3:06 pm
- Forum: Bond Lengths & Energies
- Topic: Covalent Bond Dissociation Energy
- Replies: 2
- Views: 314
Re: Covalent Bond Dissociation Energy
Dissociation energy is the energy required to break a bond. Bond multiplicity refers to how many bonds are between two atoms, and as the number of bonds increase, the dissociation energy also increases because it takes more energy to break multiple bonds. As atomic radius increases, dissociation ene...
- Mon Nov 26, 2018 3:03 pm
- Forum: Lewis Acids & Bases
- Topic: Lewis acid and base
- Replies: 5
- Views: 480
Re: Lewis acid and base
The outline on the class website says we need to know how to identify and draw them, as well as explain their characteristics and how they form coordinate covalent bonds.
- Mon Nov 19, 2018 2:19 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Degeneracy
- Replies: 4
- Views: 5234
Re: Degeneracy
Degenerate refers to orbitals with the same energy. For example, 2p would have three degenerate orbitals, 2px 2py 2pz, because they are in the same n=2 energy level.
- Mon Nov 19, 2018 2:17 pm
- Forum: Sigma & Pi Bonds
- Topic: Sigma and Pi Bonds [ENDORSED]
- Replies: 2
- Views: 327
Re: Sigma and Pi Bonds [ENDORSED]
Sigma bonds interact end to end, while pi bonds overlap side by side. Every bond contains one sigma bond. For example, a single bond would be one sigma bond. A double bond would be one sigma bond, one pi bond. A triple bond would be one sigma bond, two pi bonds.
- Mon Nov 19, 2018 2:14 pm
- Forum: Hybridization
- Topic: Bonds and Hybridization
- Replies: 1
- Views: 59
Re: Bonds and Hybridization
Yes, the number of bonds do not matter when looking at the regions of electron density.
- Wed Nov 14, 2018 2:31 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Lecture on 11/21
- Replies: 1
- Views: 284
Re: Lecture on 11/21
It depends on if we are ahead of the material by that day.
- Tue Nov 13, 2018 3:31 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: polarizing power vs polarizability
- Replies: 3
- Views: 352
Re: polarizing power vs polarizability
Polarizing power refers to the ability of cations to cause distortions in an anion. Polarizability could be seen as the opposite end, where it describes the ability of an anion to have their electrons become distorted by a cation.
- Tue Nov 13, 2018 1:16 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Formal Charge
- Replies: 4
- Views: 480
Re: Formal Charge
I think you should make sure the octets are filled first before you go on to check formal charges.
- Wed Nov 07, 2018 1:49 pm
- Forum: Ionic & Covalent Bonds
- Topic: ionic bonds and covalent character [ENDORSED]
- Replies: 2
- Views: 300
Re: ionic bonds and covalent character [ENDORSED]
He used the example of an Na+ ion and Cl- ion being bonded by a transfer of electrons. Even though this is technically an ionic bond, some of the negative charge from the Cl- ion is pulled toward the positive charge of the Na+ ion, and this happens in the bonding region. This is the "covalent&q...
- Mon Nov 05, 2018 3:28 pm
- Forum: Lewis Structures
- Topic: Double Bonds
- Replies: 7
- Views: 570
Double Bonds
After drawing the basic Lewis structure for a compound and calculating formal charges, how do you know when to add a double bond and how many of them to add?
- Mon Nov 05, 2018 2:53 pm
- Forum: Trends in The Periodic Table
- Topic: Periodic Trends in Relation
- Replies: 3
- Views: 772
Periodic Trends in Relation
Can someone explain the reasons behind the trends we see in the periodic table?
- Atomic radius
- Ionization energy
- Electronegativity
How do they relate to shielding effect and number of electrons or protons?
- Atomic radius
- Ionization energy
- Electronegativity
How do they relate to shielding effect and number of electrons or protons?
- Tue Oct 30, 2018 2:51 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: How to do e- configuration shorthand?
- Replies: 3
- Views: 324
Re: How to do e- configuration shorthand?
You would use [Xe], since that is the preceding inert gas in relation to Tl.
- Mon Oct 29, 2018 2:29 pm
- Forum: Lewis Structures
- Topic: 3.33 (6th Edition) Part C
- Replies: 2
- Views: 194
3.33 (6th Edition) Part C
Write the Lewis structure of ONF.
Why are there two electrons on top of the N in the Lewis structure?
Why are there two electrons on top of the N in the Lewis structure?
- Mon Oct 29, 2018 1:30 pm
- Forum: Resonance Structures
- Topic: Bond lengths
- Replies: 6
- Views: 432
Re: Bond lengths
I think the experimentally observed lengths will just be given, but they are basically going to be in between the single bond and double bond lengths because the actual length should be an average of the lengths from the resonance structures.
- Tue Oct 23, 2018 2:58 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Rydberg & Bohr
- Replies: 2
- Views: 1371
Rydberg & Bohr
Can someone explain the relationship between Rydberg's equation and Bohr frequency condition?
- Tue Oct 23, 2018 2:48 pm
- Forum: Einstein Equation
- Topic: λ=h/p vs λ=hc/E
- Replies: 6
- Views: 3817
Re: λ=h/p vs λ=hc/E
λ=h/p is the de Broglie wavelength equation. This is used to find the wavelength that is emitted by any moving particle since everything technically has wavelike properties, whether they are detectable or not. λ=hc/E is the equation to find quantum energy of a photon, from the photoelectric effect. ...
- Mon Oct 22, 2018 2:32 pm
- Forum: Photoelectric Effect
- Topic: Kinetic Energy Relationship
- Replies: 1
- Views: 122
Kinetic Energy Relationship
Does a higher frequency of light mean higher kinetic energy of ejected electrons?
- Mon Oct 15, 2018 2:14 pm
- Forum: Student Social/Study Group
- Topic: 6th Edition Answers
- Replies: 2
- Views: 1235
Re: 6th Edition Answers
Many people sell the physical copy of the solutions manual online, such as on the Facebook UCLA Free/For Sale group or the Textbook Buy/Sell group. Amazon also seems to be selling new/used copies.
- Mon Oct 15, 2018 2:11 pm
- Forum: Properties of Light
- Topic: List Of Equations
- Replies: 2
- Views: 133
Re: List Of Equations
E = hν (h=6.626 x 10^34 Js)
c = λν (c=3.00 x 10^8 m/s)
E(photon) - E(energy to remove e-) = E (excess) = EK(e-) = (mv^2)/2
E(n) = -(hR)/(n^2) (R = 3.29 x 10^15 s^-1)
λ = h/p
∆p ∆x ≥ h/4pi
I might be missing a few but most of these are on Outline 2 that is posted on the class website.
c = λν (c=3.00 x 10^8 m/s)
E(photon) - E(energy to remove e-) = E (excess) = EK(e-) = (mv^2)/2
E(n) = -(hR)/(n^2) (R = 3.29 x 10^15 s^-1)
λ = h/p
∆p ∆x ≥ h/4pi
I might be missing a few but most of these are on Outline 2 that is posted on the class website.
- Mon Oct 15, 2018 2:05 pm
- Forum: Properties of Light
- Topic: Measurable wavelength
- Replies: 2
- Views: 288
Re: Measurable wavelength
Professor Lavelle mentioned that wavelengths up to 10^-18 m would be detectable.
- Tue Oct 09, 2018 2:51 pm
- Forum: Photoelectric Effect
- Topic: Photoelectric Effect and Experiment
- Replies: 2
- Views: 172
Re: Photoelectric Effect and Experiment
Basically the photoelectric effect is when light (UV) is shined onto a metal surface, electrons in the metal surface become excited and they get emitted. Scientists did an experiment on this thinking that the more intense the light, the more electrons will be emitted. But they were proved wrong beca...
- Mon Oct 08, 2018 9:32 pm
- Forum: Properties of Light
- Topic: Exam
- Replies: 7
- Views: 651
Re: Exam
I think doing the practice problems are the most helpful since you're practicing how to solve questions that might essentially be asking the same question but just with a completely different wording. Also, I would think that really taking time to understand the concepts rather than memorizing them ...
- Mon Oct 08, 2018 2:34 pm
- Forum: Properties of Light
- Topic: Atomic Spectra 1.15 pg 26 (6th ed)
- Replies: 1
- Views: 85
Atomic Spectra 1.15 pg 26 (6th ed)
In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line. I understood that I had to kind of work backwards and start with convertin...
- Wed Oct 03, 2018 3:04 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Coefficients and Subscripts
- Replies: 4
- Views: 1638
Re: Coefficients and Subscripts
The subscript indicates what kind of compound it is, so if the subscripts are changed, the actual compound would change as well. For example, if we want to indicate there are two molecules of formaldehyde, we would write 2(CH2O) instead of C6H12O6 (subscripts multiplied by 2), which would then indic...
- Wed Oct 03, 2018 2:59 pm
- Forum: General Science Questions
- Topic: Systematic vs random error?
- Replies: 2
- Views: 559
Re: Systematic vs random error?
Systematic error refers to a lack of accuracy, while random error corresponds to a lack of precision. So if there is a large systematic error, the results would be similar to each other, but would be far off from the true value. If there is a large random error, the average of the results might be c...
- Tue Oct 02, 2018 9:51 am
- Forum: SI Units, Unit Conversions
- Topic: Week 1 Homework Assignment [ENDORSED]
- Replies: 16
- Views: 1302
Re: Week 1 Homework Assignment [ENDORSED]
On the grading portion of the syllabus, it says that we gets 3 points a week for the weekly online discussion, so that means we just have to either post or reply to a post to get those points?