CHEMISTRY COMMUNITY

Meghanhe1l

It would be different only by stoichiometry

Meghanhe1l

yes it is

Meghanhe1l

The y axis is lnk

Meghanhe1l

The oxidation reaction is simply the reverse of the reduction reaction, so its potential is the flipped reduction potential.

Meghanhe1l

Water is implied in the aqueous species of your cell diagram, so you do not need to externally include them. However, the presence of H+ and OH- needs to be specified by including them in your cell diagram.

Meghanhe1l

Oxidation states refer to the number of electrons an element wants to gain or lose so to reach a neutral state.

Meghanhe1l

H20 is implied when you have aqueous solutions, so you do not need to include it in the cell diagram. However, you would need to include H+

Meghanhe1l

The only case where T does not necessarily have to be in kelvins is when you are calculating delta T. In that case, celcius would also work.

Meghanhe1l

Max work assumes that all change in energy (delta G) is translated to work

Meghanhe1l

I am having trouble visualizing a cell that only has solid-state species as well as a solid conductor. How would such a cell operate?

Meghanhe1l

How do we know, based on a question, whether we should use standard G or just G

Meghanhe1l

When do we know when to use the molar representation of G instead of the parameter representation of G (Gr)? The textbook states that the n value within G can either be considered the number of moles or be taken as a constant, thus changing the units that G is expressed in.

Meghanhe1l

We did go over thus in class. The equation relies on the fact that the internal energy of gases depends on temperature and the fact that there are three translational directions by which the molecule can move.

Meghanhe1l

Would we ever need the mass of the calorimeter to find its specific heat in any question?

Meghanhe1l

Under what conditions is q the same as delta H?

Meghanhe1l

Reversible expansion is change in pressure performed very very slowly, so the work done is done in small increments. Therefore, the total work done would be the sum of all the small increments, resulting in more work done than if the change in pressure were to happen all at once (irreversible expans...

Meghanhe1l

The ideal gas constant and the heat capacity for water, as well as the conversion factor between atmospheres and joules are the constants that we should know. However, everything is provided for us are on the constants and equations, so no memorization is needed.

Meghanhe1l

There is no difference. Ka and K are both descriptions of equilibrium -- they have no fundamental difference. Ka is just a more specified name

Meghanhe1l

Adding onto what Noah said, the changed equilibrium concnetrations of the products and reactants is what leads to a different equilibrium constant

Meghanhe1l

The nitrate, perchlorate and sulfate ions are also spectator ions

Meghanhe1l

When neither the products nor reactants are favored at equilibrium, that means that at equilibrium, the ratio of reactants to products is closer to 1:1

Meghanhe1l

K has no units because when elaborated, the units cancel out. The k equation we use is technically an abbreviation.

Meghanhe1l

That would depend on what information you are using to find your concentration. If you are using a given k and the equilibrium concentrations of all the other reactants and products, then the coefficient would be in the exponent. If you are using an ice table, then the coefficient would be multiplie...

Meghanhe1l

In our notes, it says that we should be familiar with the role fo of CO2, H2CO3 and HCO3- in maintaining blood at pH 7.4. However, this is chapter 13 material on buffers. How much of this topic should we know for the final?

Meghanhe1l

In lecture, we were told to "see textbook for the role that CO2, H2CO3, HCO3- play in maintaining blood at pH 7.4." When I consulted the textbook, blood pH was only discussed in the buffers chapter (ch 13). I am wondering if we will be tested on this on the final.

Meghanhe1l

The textbook states that with greater electronegativity on the central atom, the higher the acidity of the compound. Yet it also states that the greater the atomic size of the central atom, the greater the acidity. Because electronegativity goes up going up a group, and radius goes up going down a g...

Meghanhe1l

How do sig figs apply to pH calculations?

Meghanhe1l

Drawing the lewis structures and finding the overall formal charge of the ion will always allow us to deduce the charge

Meghanhe1l

A single bond consists of a single sigma bond. A double bond consists of a sigma bond and a pi bond. A triple bond consists of a sigma bond and 2 pi bonds.

Meghanhe1l

The definition of a bidentate ligand is that it has "2 bonding sites" -- is this referring to 2 bonding sites on the ligand, or that the ligand binds to 2 sites on the same cation?

Meghanhe1l

Polarizing power is the ability to polarize another atom. So cations have high polarizing power because they have higher electrostatic pulls to neighbouring from their positive charge, and anions are highly polarizable since they have an abundance of electrons.

Meghanhe1l

I agree with you. Double bonds would lower the formal charge

Meghanhe1l

The name of the compound would indicate if it were cis or trans, and using the VSEPR model to find the molecule configuration would allow us to determine polarity

Meghanhe1l

Do higher order bonds take up more space than a single bond since there are more electrons in that electron density?

Meghanhe1l

Either is correct.

Meghanhe1l

Even though certain atomic orbitals would support the observed number of bonds in a molecule, they don’t always support the observed bond angles. For instance, in nh3, there are three unpaired electrons in nitrogen’s atomic orbitals that correctly support the three h bonds; however, these three bond...

Meghanhe1l

Because double bonds include a pi bond that prevents rotation, they are more stable.

Meghanhe1l

Because electrons are not static and do not follow a specific course, their distribution is constantly changing. By chance, this fluctuation may result in the electrons being more concentrated on one side of the atom, causing a temporary dipole; this is how London dispersion forces arise. Regular di...

Meghanhe1l

To answer your second question, no covalent bond is 100% covalent -- they all have some ionic character. Thus the determining factors of ionic bond strength all apply to covalent bonds as well, including electronegativity and thus polarizing power.

Meghanhe1l

Hydrogen bonds are a special type of dipole-dipole bonds where hydrogen is bonded to O, N, or F. These are three very electronegative atoms, so they have greater polarizing power, and thus a stronger dipole and a stronger bond than other dipole-dipole bonds.

Meghanhe1l

In question 2.67 for the 6th edition textbook, it states that C has a higher electron affinity than N even though N is further right on the periodic table. Why is that?

Meghanhe1l

Do diagonal relationships only apply for isoelectronic atoms?

Meghanhe1l

In the textbook, it wrote the electron configuration of Cerium as [XE] 4f1 5d1 6s2. Why is it 4f1 if Cerium is the second element in the f-block row?

Meghanhe1l

Why is a full f orbital 4f14 when there are 15 elements in that row (lanthanum to lutetium)?

Meghanhe1l

The only rule regarding Ms is that it can take on values of either +0.5 or -0.5 (spin up or spin down). It does not depend of any of the previous quantum numbers.

Meghanhe1l

The roman numerals specify the atom's ionic form for the atoms that can gain/lose differing number of electrons.

Meghanhe1l

The Schrodinger equation is used to derive the quantum numbers, which elucidate the shapes of the atoms. For instance, the square of the wave function that comes from the Schrodinger equation tells us the probability density of the elections, which informs us on the shape of the atomic orbitals.

Meghanhe1l

Hello, I am wondering if we are required to include the units in every term of within our calculations, or if simply writing the units of our final answer is enough. For instance, if we were calculating frequency, would we have to write v=(3x10^8m/s)/(4x10^-12m)?

Meghanhe1l

For a metal to eject electrons, the ENERGY of the incoming radiation must match or exceeds the required energy to eject the election. Because E=hv and v is inversely proportional to wavelength (c=wavelength x v), that means that the wavelength of the incoming radiation, rather than the intensity, de...

Meghanhe1l

What is the difference between spectral lines and a diffraction pattern in terms of waves and aborption? Also what is the difference between absorption and emission spectra?

Meghanhe1l

The series can be identified as follows: If the electron is making a transition from a higher energy level to n=2, then it is Balmer Series. If the electron is making a transition from a higher energy level to n=1, then it is Lyman Series. To find what color is emitted, we can first use the Bohr for...

Meghanhe1l

When we have multi-electon atoms, the shielding effect and the different electrostatic energies that result when you have different numbers of protons impact the performance of the electrons.

Meghanhe1l

The answer is B because the energy difference from n=5 to n=1 is greater than the difference from n=4 to n=2. Because E=hv and h is a constant, then the greater energy difference can be reflected only in a difference in frequency, meaning that the released energy when passing from n=5 to n=1 would h...

Meghanhe1l

Hi, I am trying to enroll in the APP PLF Sessions; however, when I go to the Peer Learning page on myUCLA, it says that I have "no upcoming peer learning passes". How should I proceed?

Meghanhe1l

Energy of photon + Energy to remove election = Kinetic energy of ejected election
hv-(circle with a slash, which is the work function or threshold energy) = 0.5mv^2

Meghanhe1l

Today during our test, our TA told us that states are not required for our reactons

Meghanhe1l

Hello, I am wondering if we are still handing in our 7 homework questions on Friday, or if we are now handing them in during our discussions. Thanks!

Meghanhe1l

When we are calculating volume we use the equation M1V1=M2V2, where M=mol/L and we are given both M1 and M2 as well as one of the Vs. Because we are using mol/L in our calculations, we must remain uniform and keep all our calculations in L.

Meghanhe1l

Hi I'm wondering what resources we are allowed to reference during our tests. If we will be given a periodic table, I would love to know which one it is so I can familiarize myself with it, as with any other resource we will be given.

Meghanhe1l

Does anyone know when the UAs host their office hours or where I could find that information? Thanks!

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