CHEMISTRY COMMUNITY

Hannah Pham 1D

If you think about the definition of an intensive property where the value does not depend on anything else (anything external), then you can see that anything with an intensive property won't depend on moles. E is an intensive property, so it checks out.

Hannah Pham 1D

The problem would have to tell us.

Hannah Pham 1D

We can't use all forms of energy in the same way.

Hannah Pham 1D

The path doesn't affect the end value of free energy, so we can just add and subtract them up.

Hannah Pham 1D

Just check the rest of outline 4 that we didn't cover on the midterm!

Hannah Pham 1D

What's the difference between spontaneous and unstable?

Hannah Pham 1D

Follow the outlines and do whatever is on the homework! That consistently works for me when I'm studying for tests.

Hannah Pham 1D

In the sixth edition of the textbook, what problems should we go up to for test 2? (When do the Nerst Equation problems start?

Hannah Pham 1D

Mya Majewski 1L wrote:for question 8, isn't the answer going to be Kb x 3^8?

the formula is S=KblnW, so you need to take the natural log of 3 to the 8th power

Hannah Pham 1D

For #6, how do we know that work is equal to 0?

Hannah Pham 1D

I'm confused on #4, too. What equations are relevant?

Hannah Pham 1D

Will we need to use derivatives and integrals on the midterm? Or did we just do that to derive the equations that we use now?

Hannah Pham 1D

What's a quick way to know if something is open, closed, or isolated? It gets confusing.

Hannah Pham 1D

What homework problems should I go up to in outline 4 for the midterm if I'm using the sixth edition textbook? I know we stop before Gibb's Free Energy, but I'm not sure which homework problem that corresponds to.

Hannah Pham 1D

Take volume into account. The reaction will favor the side with fewer moles.

Hannah Pham 1D

He gave us two equations that were the same thing, just in different forms. The integral and the other equation mean the same thing; it's just different math.

Hannah Pham 1D

When dealing with work and heat, you have to take into account every step in the process of the change, not just the final and initial values.

Hannah Pham 1D

It shouldn't matter unless they specify! Make sure you know what the question is asking though.

Hannah Pham 1D

It really depends on your TA, but to be safe, just do material that we learned this week or las week.

Hannah Pham 1D

Yes, we all get them back this week!

Hannah Pham 1D

When can we use the ideal gas law?

Hannah Pham 1D

In chem14a, we drew lewis dot structures, and through that, we saw if something was an acid or a base.

Hannah Pham 1D

Condensation is exothermic because it releases heat. You see this in real life when you have a cold drink and condensation forms water droplets on the side of the cup.

Hannah Pham 1D

The test will probably cover acids and bases, too. I think it will most likely cover lectures from the first two weeks.

Hannah Pham 1D

If you break down the word into parts, you can deduce the meaning, too! Auto would indicate that autoprotolysis happens itself, hinting that it involves the same molecule. Proto can tell you that it involves protons.

Hannah Pham 1D

Only changes in temperature change the K value.

Hannah Pham 1D

We have to keep in mind if any of the reactants or products are solids or liquids because we don't factor them in when we calculate the equilibrium constant, K.

Hannah Pham 1D

You can tell what are reactants or products if you know the equation for the chemical reaction. If the problem doesn't just straight out give it to you, you can figure it out yourself based on context clues from the problem.

Hannah Pham 1D

For this class, I think we just need to use this equation when we convert from concentration to partial pressure, so when you are solving for Kc, you need concentrations and when you are solving for Kp, you need partial pressures.

Hannah Pham 1D

Other answers explained the reasoning, but basically you use brackets when solving for Kc and use parentheses when solving for Kp.

Hannah Pham 1D

Kc is used when the units of the equilibrium concentrations are moles per liter. Kp is used when using partial pressure. It’s basically the same thing but with different units.

Hannah Pham 1D

I honestly find all of his resources helpful, so I do all the problems in the book, watch the modules, and go to workshops when I need extra help on a topic. That’s just generally how I prepare for a test in his class.

Hannah Pham 1D

Chelates are in the shape of rings, making them pretty easy to distinguish.

Hannah Pham 1D

I think it is safe to just study the sheet posted on Lavelle's website because it has a lot of common ligands that we should probably know.

Hannah Pham 1D

Which lone pair and bonding pair shapes do we need to know? I know there are bent and trigonal pyramidal, but which other ones would we need to know for test 3?

Hannah Pham 1D

We only need to know the trends, not the exact bond lengths.

Hannah Pham 1D

Dipoles can cancel each other out so the molecule would not be polar.

Hannah Pham 1D

That definition seems correct. It's basically identical to the one from lecture today!

Hannah Pham 1D

im pretty sure you can use them interchangeably

Hannah Pham 1D

bond angles for pentagona bipyramidal are 72 and 90 degrees

Hannah Pham 1D

ions are charged

Hannah Pham 1D

Hydrogen bonding takes more energy to break because it is stronger than most intermolecular forces.

Hannah Pham 1D

What's the relationship between polarization and dipole moments? What's the difference?

Hannah Pham 1D

How do we figure out if i bond is a sigma bond or a pi bond?

Hannah Pham 1D

HCl has a permanent dipole moment because H becomes slightly positive because it gives its electron to Cl which becomes slightly negative.

Hannah Pham 1D

What type of bonds do metalloids form?

Hannah Pham 1D

Can someone provide a brief, undetailed list of the octet exceptions we have learned so far?

Hannah Pham 1D

Double bonds are stronger than single bonds and require more energy to break. Triple bonds are stronger than double bonds. They all have different lengths because they have different strengths.

Hannah Pham 1D

Non metals cannot form cations; instead, they form anions and metals form cations.

Hannah Pham 1D

Removing the second electron is a lot harder because of the net charge of the atom becomes more positive after removing the first electron, so removing the second electron requires more energy.

Hannah Pham 1D

Do we need to know electron configurations for test 2?

Hannah Pham 1D

What does ionization mean exactly?

Hannah Pham 1D

I've been doing the homework problems, but I don't think some of the homework problems for the Quantum World will be on the test just yet. I think all the homework problems up to 2.41 in the sixth edition can be on the test, but everything after will not (2.45-2.93). Can someone double check this?

Hannah Pham 1D

We get an equation sheet for most of the relevant equations, like we did during AP exams.

Hannah Pham 1D

Light does not have a rest mass, so you can't calculate the mass of light.

Hannah Pham 1D

The electron is still removed, but it just does not have kinetic energy.

Hannah Pham 1D

You don't need to use avogadro's number in this problem because it says calculate in moles.

Hannah Pham 1D

We'll be given the formulas, so we don't need to know them by name. We just need to focus on the concepts he lectured on for the first test.

Hannah Pham 1D

Does the homework for week 2 need to be problems about the quantum world? Can we still do problems from fundamentals for homework this week?

Hannah Pham 1D

You can multiply it by 100 to get an integer and then divide by the greatest common factor to be super exact, but just rounding it would most likely be better.

Hannah Pham 1D

Try to take it one element at a time. Write out how many of each element there is in the reactants and do the same for the products. Then, add coefficients where necessary. It's easiest taking it step by step.

Hannah Pham 1D

Remembering conversions generally just happens over time with practice through homework and classwork problems. To convert from g to kg, divide by 1000.

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