Search found 30 matches
- Fri Dec 07, 2018 3:33 pm
- Forum: Bronsted Acids & Bases
- Topic: 6C.17 (7th edition)
- Replies: 2
- Views: 368
Re: 6C.17 (7th edition)
generally, the strength of an inorganic base is stronger than an organic base. So you can just write out BrO- is more basic than C17H19O3N.
- Fri Dec 07, 2018 3:29 pm
- Forum: Bronsted Acids & Bases
- Topic: Problem J.7 - 7th Ed.
- Replies: 4
- Views: 550
Re: Problem J.7 - 7th Ed.
The anion of the product is from the acid and cation of the product is from the base. The base is the cation with an OH- and the acid is a anion with a H+. So that you can write out the reactants and balance the equation.
- Fri Dec 07, 2018 3:19 pm
- Forum: Lewis Acids & Bases
- Topic: 6.5 (7th edition)
- Replies: 1
- Views: 491
Re: 6.5 (7th edition)
In Lewis acid and base theory, all the base are electron donors and all the acid are electron acceptors. They do not need to be in aqueous state, they can be either states, either gas, solid, liquid. And in this question, you can think of H2O2 to split into 2 OH one with the electron lone pair the o...
- Fri Nov 30, 2018 1:46 pm
- Forum: Lewis Acids & Bases
- Topic: HI or HCl: stronger acid
- Replies: 8
- Views: 10642
Re: HI or HCl: stronger acid
How to define strong acid and weak acid depends on the easiness to lose an electron. Since the bond of H and I is easier to break than H and Cl, it is easier for HI to lose H+ and thus it is a stronger acid than HCl.
- Fri Nov 30, 2018 1:43 pm
- Forum: Bronsted Acids & Bases
- Topic: J15
- Replies: 2
- Views: 347
Re: J15
C6H5OH(aq) + H2O(l) <--> C6H5O-(aq) + H3O+(aq)
The essence is to treat H+ as a proton and form H30+
The essence is to treat H+ as a proton and form H30+
- Fri Nov 30, 2018 12:14 pm
- Forum: Lewis Acids & Bases
- Topic: HF
- Replies: 5
- Views: 598
Re: HF
F's electronegativity is so strong that it is hard for it to fully release the H+. So it is hard to break the bond between H and F thus HF is a weak acid. But remember, HCl, HBr, HI are all strong acids.
- Tue Nov 20, 2018 10:31 am
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Sigma and Pi Bonds
- Replies: 5
- Views: 706
Re: Sigma and Pi Bonds
A single bond is always sigma bond since only s to s or p to p. But for double bond, the px to px is fixed, and the py and py, pz and pz are parallel side by side and they can form a sigma bond and pi bind.
- Tue Nov 20, 2018 10:06 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond Angles
- Replies: 3
- Views: 436
Re: Bond Angles
I think the answer means that all the angles of this compound is the same, cuz the two Cl atoms are the same.
- Tue Nov 20, 2018 10:02 am
- Forum: Hybridization
- Topic: Ethene (C2H4) hybridization
- Replies: 2
- Views: 690
Re: Ethene (C2H4) hybridization
Because the valance electron of carbon atom is four so it originally has 2 in 2s and 2 in sp. The two 2s's energy becomes higher and combine with one electron in p orbital to become sp2 and the left p electron is itself an orbital. You can regard sp2 as 3 orbitals and p as one orbital, with one elec...
- Thu Nov 15, 2018 11:56 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 6th Edition Ch4 Q7
- Replies: 2
- Views: 289
Re: 6th Edition Ch4 Q7
You can just do it by calculating how many bonded electron pair that S has and how many lone pairs it has and see what category of geometry structure that it falls into and you will remember the bond angle.
- Thu Nov 15, 2018 11:51 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Molecular Structure 4.111
- Replies: 2
- Views: 339
Re: Molecular Structure 4.111
C in CH3 has 4 bond with no lone electron pairs so it should be tetrahedral with bond angle 109.5 degree. And the C and N forms the triple bond so the bond angle should be 180 degree. for single bond it is sp3 hybridization so C in CH3 has 3 sigma while for triple bond, it is sp hybridization and C ...
- Thu Nov 15, 2018 11:43 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: 6th edition 4.67
- Replies: 2
- Views: 506
Re: 6th edition 4.67
The one with negative charge would have the lowest ionization energy because it gain one additional electron which is easy to lose. And the one with positive charge would have the highest ionization energy because it has already lost electrons to get octet structure and it is hard for it to lose one...
- Thu Nov 08, 2018 7:47 pm
- Forum: Electronegativity
- Topic: Problem 2D #11 (7th edition)
- Replies: 2
- Views: 331
Re: Problem 2D #11 (7th edition)
The electronegativity for N is 3.0 and for O is 3.5 So N3- is more electronegative than O2-.
- Thu Nov 08, 2018 7:38 pm
- Forum: Electronegativity
- Topic: Trend Exceptions
- Replies: 5
- Views: 557
Re: Trend Exceptions
When the element has full orbital or half full orbital structure, their structure is so stable that it is difficult for them to lose electrons, which means that it would require more energy to move one electron away from them, thus making their ionization energy higher.
- Thu Nov 08, 2018 7:34 pm
- Forum: Ionic & Covalent Bonds
- Topic: HW 3.77
- Replies: 4
- Views: 348
Re: HW 3.77
You can decide by calculating the difference in each element's electronegativity. So the answer should be HCl, CF4, and CO2.
- Sun Nov 04, 2018 8:34 am
- Forum: Ionic & Covalent Bonds
- Topic: Ionic character [ENDORSED]
- Replies: 5
- Views: 635
Re: Ionic character [ENDORSED]
You can see by calculating the difference of electronic affinity. C-F is larger than C-H
- Sun Nov 04, 2018 8:32 am
- Forum: Ionic & Covalent Bonds
- Topic: covalent bonds
- Replies: 3
- Views: 442
Re: covalent bonds
It depends on whether all of its electrons pair with the electron from the other element to form a bond. If not, then the number of covalent bond is not equal to the number of valence electrons
- Sun Nov 04, 2018 8:30 am
- Forum: Ionic & Covalent Bonds
- Topic: covalent bonds
- Replies: 2
- Views: 358
Re: covalent bonds
Because they have more than 4 electrons and due to the electrostatic force between electrons, they tend to attract more electrons to reach the 8-electron stable structure instead of losing them
- Thu Oct 25, 2018 12:05 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Question about Ce electron configuration
- Replies: 1
- Views: 346
Question about Ce electron configuration
Why Ce(Cerium)'s electron configuration is [Xe}4f15d16s1? why not with 5d26s1 or 4f26s1? Cuz the energy level of 4f is lower than 5d.
- Thu Oct 25, 2018 12:04 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Question about H electron configuration
- Replies: 3
- Views: 498
Question about H electron configuration
The textbook says for H and He atoms, since they have only one or two electrons which can occupy any orbitals, then how should we write the electron configuration for these 2 atoms? 1s1 1s2 or others?
- Thu Oct 25, 2018 9:35 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Question about 4s and 3d orbitals
- Replies: 1
- Views: 288
Question about 4s and 3d orbitals
I know that 4s shows lower energies than 3d orbital so the electrons will fill the 4s first. But why after 2e- occupied the 4s orbitas, 4s states lower energy?
- Sat Oct 20, 2018 9:10 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Lecture Question
- Replies: 4
- Views: 482
Re: Lecture Question
I think the course will only cover these 4 orbitals cuz more would be more complex.
- Sat Oct 20, 2018 9:09 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic Spectra
- Replies: 4
- Views: 484
Re: Atomic Spectra
You can use the formula to calculate the different energy and thus compare. Concrete number is the answer. Hope this will help.
- Sat Oct 20, 2018 9:07 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Uncertainty
- Replies: 3
- Views: 416
Re: Uncertainty
It is like a reciprocal process that since the electron's path will be deflected, if you know the p, then you won't know where it will be. if you know its position, then you won't know its p
- Mon Oct 08, 2018 2:00 pm
- Forum: Limiting Reactant Calculations
- Topic: Limiting Reactants M9 [ENDORSED]
- Replies: 2
- Views: 371
Re: Limiting Reactants M9 [ENDORSED]
The copper (II) nitrate is Cu(NO3)2, the copper(II) hydroxide is Cu (OH)2. In this case, no valance value change. Just write down all the reagents and products and try to use numerical numbers to balance it. Hope this would help.
- Mon Oct 08, 2018 1:55 pm
- Forum: Limiting Reactant Calculations
- Topic: Limiting Reactants M19
- Replies: 4
- Views: 460
Re: Limiting Reactants M19
First, use the product and the mass percentage to calculate the mass of C. H. N in the caffeine. And subtract these mass from the 0.376g to calculate the mass of O in the caffeine. Second, use the mass you get from the products to calculate the moles of C.H.N.O. Third, find the simplest proportion o...
- Mon Oct 08, 2018 1:52 pm
- Forum: Limiting Reactant Calculations
- Topic: Limiting Reactants M11
- Replies: 2
- Views: 903
Re: Limiting Reactants M11
You can calculate that you have 0.4657mol P4 while have 0.18 mole O2, which means O2 is in excess. So O2 is the limiting reagent. So the P4 will be consumed up and you would get 0.04657 mole P4O6. In the second reaction, you only have 0.036 mole O2 left, which is the limiting reagent. And you could ...
- Tue Oct 02, 2018 8:59 pm
- Forum: Limiting Reactant Calculations
- Topic: Percent Yield
- Replies: 5
- Views: 966
Re: Percent Yield
I think your theoretical yield is wrong. There are 2.0588 moles of NH3 in the reactant and they would produce 2.0588 moles of N2H4 which is about 32.94g produced. In this case, 25.5/32.95*100% is 76.5%
- Tue Oct 02, 2018 8:54 pm
- Forum: Empirical & Molecular Formulas
- Topic: Empirical Formula
- Replies: 5
- Views: 356
Re: Empirical Formula
I think you can just divide all the other bigger numbers by the smallest one and round them to by the significant figure rules. Cuz I think in this case, some roundoff is acceptable
- Mon Oct 01, 2018 9:04 pm
- Forum: SI Units, Unit Conversions
- Topic: Homework written in pencil or pen?
- Replies: 4
- Views: 376
Re: Homework written in pencil or pen?
The professor said written in whatever you want.