Search found 65 matches
- Fri Mar 15, 2019 10:34 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Catalysts
- Replies: 4
- Views: 633
Re: Catalysts
Definitely not for the overall rate law. As for the rate law for an elementary step, that's a really good question. My guess is no because I think that the only things in the rate law are supposed to be the reactants in the overall equation.
- Fri Mar 15, 2019 10:32 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: K Constant
- Replies: 1
- Views: 243
Re: K Constant
K tells you the ratio of products to reactants. When more products are being formed, the forward rate constant is going to greater than the reverse constant. This means that k/k' is going to be greater than one, which aligns with what we would expect from K since there are more products than reactan...
- Fri Mar 15, 2019 11:17 am
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Solution Manual Q
- Replies: 1
- Views: 228
Solution Manual Q
I noticed that for a lot of the Nernst equation problems, the solution manual combines partial pressures and concentrations in the expression for Q. For example, in problem 6N.3 Q is written as (.075M)^2(1 atm)/(1.0M)^2(1 atm) Does this mean that in general we don't have to convert the partial press...
- Sat Mar 09, 2019 12:37 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: differential rate law equation
- Replies: 3
- Views: 371
Re: differential rate law equation
I'm also confused about this. Is there ever a case where we have to use the differential rate law or will we always be able to use the integrated form?
- Sat Mar 09, 2019 12:36 pm
- Forum: Zero Order Reactions
- Topic: Half Life and k
- Replies: 11
- Views: 1730
Re: Half Life and k
the equation of half life is always t(1/2)=ln2/kr.
The proof for this is given in 7B.2 in the 7th edition textbook.
The proof for this is given in 7B.2 in the 7th edition textbook.
- Sat Mar 09, 2019 12:33 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: zero order
- Replies: 2
- Views: 271
Re: zero order
I think it might be zero because it doesn't depend on the concentration of any reactants.
- Thu Feb 28, 2019 10:29 pm
- Forum: Balancing Redox Reactions
- Topic: Problem K3 D
- Replies: 2
- Views: 346
Re: Problem K3 D
I was confused about this too. Is it possible that there's a typo in the book? I feel like it should be this:
cl2---> HCLO+2Cl-
It seems weird to have cl2 on both sides of the equation.
cl2---> HCLO+2Cl-
It seems weird to have cl2 on both sides of the equation.
- Thu Feb 28, 2019 10:23 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Test 2
- Replies: 4
- Views: 493
Re: Test 2
For the seventh edition you should look at the following chapters:
Gibbs Free Energy: 4J, 5G, 5J
Electrochem: 6K, 6L, 6M
Gibbs Free Energy: 4J, 5G, 5J
Electrochem: 6K, 6L, 6M
- Thu Feb 28, 2019 10:18 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Organization of cell diagrams
- Replies: 9
- Views: 793
Re: Organization of cell diagrams
What do you do if there's a liquid? I think someone mentioned that Hg(l) is some exception, is that true?
- Thu Feb 21, 2019 7:07 pm
- Forum: Van't Hoff Equation
- Topic: Practice Problems
- Replies: 3
- Views: 517
Practice Problems
Did anyone find any practice problems specifically related to Van't Hoff's equation? Is there every a case where you have to use this relationship instead of just calculated the different G values at each temperature and dividing those by RT?
- Thu Feb 21, 2019 7:04 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Free Energy and Pressure
- Replies: 1
- Views: 216
Free Energy and Pressure
Why does the free energy depend on pressure?
- Thu Feb 21, 2019 7:03 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Free Energy and Work Relationship
- Replies: 2
- Views: 293
Free Energy and Work Relationship
What's the relationship between free energy and work?
- Wed Feb 13, 2019 9:07 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: adding entropy
- Replies: 5
- Views: 601
Re: adding entropy
Yes. You first assume constant temperature and calculate the change in entropy due to change in volume. Next, assume constant volume and calculate the change in entropy due the change in temperature. Just add these together to find the total change in entropy. (You could also do this the other way a...
- Wed Feb 13, 2019 9:04 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Enthalpy and qp
- Replies: 3
- Views: 456
Re: Enthalpy and qp
Enthalpy is defined as the heat transferred or gained under constant pressure. Therefore, it must be equal to qp.
- Tue Feb 12, 2019 3:07 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Reversible Reactions
- Replies: 8
- Views: 1264
Reversible Reactions
Are reversible reactions always isothermal? Can we assume that delta U = 0 for any reversible or isothermal reaction?
- Thu Feb 07, 2019 12:20 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 4C.3
- Replies: 1
- Views: 219
4C.3
This question states "Calculate the final temperature and the change in enthalpy when 1.15 kJ of energy is transferred as heat to 0.820 mol Kr(g) at 298 K and 1.00 atm (a) at constant pressure; (b) at constant volume. Treat the gas as ideal." I understand how to calculate the final tempera...
- Wed Feb 06, 2019 4:03 pm
- Forum: Phase Changes & Related Calculations
- Topic: What exactly is 3/2RT and when do we use it?
- Replies: 4
- Views: 3950
Re: What exactly is 3/2RT and when do we use it?
Internal energy is energy stored as kinetic energy and potential energy that can move in different ways, including translational energy, rotational energy, and vibrational energy. The translational energy is equivalent to 3/2RT and the rotational energy of a nonlinear molecule is also 3/2RT. Both of...
- Wed Feb 06, 2019 3:50 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: 6th edition 9.3
- Replies: 2
- Views: 613
Re: 6th edition 9.3
Convert celsius to kelvin and use the equation deltaS=q/T.
Part a: 65J/298K = .22 J/K
Part b: 65J/373K = .17 J/K
Part b is smaller because the temperature is greater, resulting in a smaller change in entropy (as you can observe from the equation).
Part a: 65J/298K = .22 J/K
Part b: 65J/373K = .17 J/K
Part b is smaller because the temperature is greater, resulting in a smaller change in entropy (as you can observe from the equation).
- Wed Feb 06, 2019 3:34 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: 3R/2 vs 5R/2
- Replies: 1
- Views: 456
Re: 3R/2 vs 5R/2
When the volume is constant, you should use 3R/2. When the pressure is constant, you should use 5R/2.
- Wed Jan 30, 2019 10:28 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: HW problem 4A.7
- Replies: 1
- Views: 378
Re: HW problem 4A.7
Yes exactly. The total heat will be the heat required to raise the copper temperature to 100 degrees Celsius (q(copper)) + the heat required to raise the water to 100 degrees Celsius (q(water)), using the formula you listed for both. For the second part you will just do q(water)/total heat *100% to ...
- Wed Jan 30, 2019 10:23 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Studying gases
- Replies: 2
- Views: 350
Re: Studying gases
Gases will probably be in a lot of the examples where work is being done because the work done by liquid and solids in a system is generally insignificant. However, they could definitely ask questions about solids and liquids in a closed system where the energy of the system is changed by heating/co...
- Wed Jan 30, 2019 10:19 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Forms of U Equations
- Replies: 3
- Views: 406
Re: Forms of U Equations
It depends on the what's happening in the problem. U=w+q is always true and can always be used. It just means that the change in the energy of the system is going to depend on the work done by or on the system and the heat released/absorbed. However, in some problems there is no work being done. If ...
- Thu Jan 24, 2019 9:27 am
- Forum: Ideal Gases
- Topic: Ice Table with quadratic equation on bottom
- Replies: 3
- Views: 306
Re: Ice Table with quadratic equation on bottom
I believe that's possible. Could you list the problem you are working on?
- Thu Jan 24, 2019 9:26 am
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: help on last module!
- Replies: 2
- Views: 336
Re: help on last module!
This has to be a mistake with the question. Adding water would not change the equilibrium concentration.
- Thu Jan 24, 2019 9:23 am
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Test 1
- Replies: 9
- Views: 717
Re: Test 1
Pretty much all of the formulas and conversions are given. You should know the following relationships:
pOH + pH = pKw
[OH][H30] = Kw
(Ka)(Kb) = Kw
pKa + pKb = pKw
PV = nRT
If you know these then you should be good.
pOH + pH = pKw
[OH][H30] = Kw
(Ka)(Kb) = Kw
pKa + pKb = pKw
PV = nRT
If you know these then you should be good.
- Thu Jan 17, 2019 2:41 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Effect of Pressure [ENDORSED]
- Replies: 2
- Views: 189
Re: Effect of Pressure [ENDORSED]
It's important to keep in mind that when counting the number of moles on each side, you are only counting the moles of gas. For example, if the reactant side has 2 moles of gas and 1 mole of a solid while the product side has 3 moles of gas, then the reaction will shift left because the reactants ha...
- Thu Jan 17, 2019 2:32 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Sixth Edition Question 11.87
- Replies: 2
- Views: 246
Re: Sixth Edition Question 11.87
If you think about it, gases such as oxygen and nitrogen typically exist as 02 and N2 because that is there lowest energy state. Therefore, in order to break this low energy state, energy has to be put into this system, therefore making it endothermic.
- Thu Jan 17, 2019 2:29 pm
- Forum: Ideal Gases
- Topic: #47 on Chemical Equilibrium 1B Video Module Assessment
- Replies: 3
- Views: 253
Re: #47 on Chemical Equilibrium 1B Video Module Assessment
Convert each concentration to a partial pressure using PV=nRT. You are given n/V, R and T so you just need to solve for P.
- Sat Jan 12, 2019 5:43 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Inert Gases
- Replies: 2
- Views: 144
Re: Inert Gases
Going off of what what previously said, the inert gas will change the pressure of the system. However, since this pressure isn't as a result of compression (which would decrease the volume and change the concentrations), it won't affect the calculations. Because of this, adding an inert gas will not...
- Sat Jan 12, 2019 5:38 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Effect of Partial Pressure on Concentration
- Replies: 2
- Views: 183
Re: Effect of Partial Pressure on Concentration
The partial pressure is different than the overall pressure. Basically, treat partial pressure kind of like concentration. For gases, often you are given the partial pressure instead of the concentration but as far as our calculations go you can treat them almost the same. The overall pressure is wh...
- Sat Jan 12, 2019 5:31 pm
- Forum: Ideal Gases
- Topic: Homework 6th edition Question 11.7
- Replies: 1
- Views: 132
Re: Homework 6th edition Question 11.7
I believe that the question is asking which flask shows when the reaction reached equilibrium. So even though the third flask and the fourth flask are both at equilibrium, the third flask better shows when the reaction first reached equilibrium. You can tell that it's at equilibrium at this point be...
- Mon Dec 03, 2018 8:57 pm
- Forum: Amphoteric Compounds
- Topic: Definition
- Replies: 6
- Views: 592
Re: Definition
Amphoteric means that a compound can behave as both an acid and a base. In general any of the metalloid oxides can be amphoteric. However, the most important example that you need to know is water... Water as a base: HCl(aq) + H2O(l) --> Cl-(aq) + H3O (aq) Water behaves as a base in this case becaus...
- Mon Dec 03, 2018 8:48 pm
- Forum: Air Pollution & Acid Rain
- Topic: Acid Rain Equations
- Replies: 1
- Views: 434
Acid Rain Equations
What were the other equations for the cause of acid rain besides the one with carbon dioxide (CO2 + H2O --> H2CO3)? What are some possible options to reduce acid rain?
- Mon Dec 03, 2018 7:41 pm
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Help With 6C.17
- Replies: 1
- Views: 224
Help With 6C.17
I'm having trouble with this question:
"Which is the stronger base, the hypobromite ion, BrO-, or morphine, C17H19O3N? Justify your answer."
From the solutions manual I saw that they used the pKb values of the base, but how are you supposed to know the pKb value?
"Which is the stronger base, the hypobromite ion, BrO-, or morphine, C17H19O3N? Justify your answer."
From the solutions manual I saw that they used the pKb values of the base, but how are you supposed to know the pKb value?
- Wed Nov 28, 2018 9:15 am
- Forum: Hybridization
- Topic: Ethene Hybrid Orbitals
- Replies: 4
- Views: 622
Re: Ethene Hybrid Orbitals
There is a total of 3 p-orbitals. In an sp hybridized orbital, one of those p orbitals is combined with the s orbital while the other two remain true p-orbitals. In an sp^2 hybridization, two p orbitals are hybridized with the s orbital, leaving one p-orbital unhybridized. In sp^3, all p orbitals ar...
- Wed Nov 28, 2018 9:07 am
- Forum: Hybridization
- Topic: 2F.1
- Replies: 2
- Views: 183
Re: 2F.1
Hybrid orbitals will point in the directions of the different VSEPR models we have learned so just figure out which VSEPR model each hybrid orbital corresponds to.
- Mon Nov 26, 2018 6:11 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Test 3
- Replies: 2
- Views: 358
Test 3
Are the intermolecular forces part of 2D? Should we expect to see this on the test?
- Fri Nov 23, 2018 12:40 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sixth Edition. Question 4.109
- Replies: 4
- Views: 1061
Re: Sixth Edition. Question 4.109
That is correct, since there are only two single bonds with oxygen you can assume that there are two lone pairs that are not shown to finish the octet around oxygen. Therefore, the shape must be bent with an angle of 109 degrees.
- Fri Nov 23, 2018 12:37 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 7th Edition Question 2E. 29
- Replies: 2
- Views: 110
Re: 7th Edition Question 2E. 29
In the second example, the dipole moments are pointed away from each other so some of that pull will be cancelled if the vectors are added together. However, if the two dipole vectors are added in the first example, they are pointed in almost the same direction so the magnitude will be larger.
- Fri Nov 23, 2018 12:35 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: I3- ion shape
- Replies: 2
- Views: 165
Re: I3- ion shape
It's easier to understand why it's linear if you imagine a bipyramidal structure. Since there are three lone pairs in the I3- ion, imagine that the three central atoms of the bipyramidal structure are removed, leaving only the top, middle, and bottom atoms in a linear formation.
- Sun Nov 18, 2018 3:24 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: bond angle
- Replies: 4
- Views: 430
Re: bond angle
We haven't been given a way to actually calculate the bond angles. However, it's easier to remember the angles if you remember the bond angles associated with each number of electron densities. For example, when there are two areas of electron density the angle will always be 180 degrees, when there...
- Sun Nov 18, 2018 3:19 pm
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: polarizing power of a cation
- Replies: 3
- Views: 355
Re: polarizing power of a cation
Polarizing power is the power of a cation to distort the shape of an anion by pulling its electrons over. In general, the smaller the ion, the more polarizing power it will have. This means that ions that are towards the top left side of the periodic table and with a greater charge will have a great...
- Sun Nov 18, 2018 3:12 pm
- Forum: Bond Lengths & Energies
- Topic: Dissociation Energy
- Replies: 4
- Views: 698
Dissociation Energy
On the outline it says we should know the following: • Explain how covalent bond dissociation energy is related to covalent bond multiplicity, atomic radius, and the presence of unpaired electrons. I understand that covalent bond dissociation is the energy required to break the bond. From my underst...
- Tue Nov 13, 2018 5:41 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Determining VSEPR bond angles
- Replies: 5
- Views: 1821
Re: Determining VSEPR bond angles
Each different geometric shape has implied bond angles. For instance, trigonal planar will always be 120 degrees, linear will be 180 degrees, tetrahedral will 109.5 degrees and so on. You won't need to calculate any bond angles, you will just have to figure out the shape and then use the bond angles...
- Tue Nov 13, 2018 5:36 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: The A in the VSEPR Formula [ENDORSED]
- Replies: 4
- Views: 252
Re: The A in the VSEPR Formula [ENDORSED]
The purpose of A is just to represent the central atom in the particular molecule that you are looking at.
- Tue Nov 13, 2018 5:35 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond Angles [ENDORSED]
- Replies: 2
- Views: 579
Re: Bond Angles [ENDORSED]
If you look at the diagram for an octahedral shape you can see that there are three atoms in the vertical direction that are in a straight line (or 180 degree angle). There's also 4 atoms located in the middle around this vertical line. These 4 atoms will repel each other and each form 90 degree ang...
- Tue Nov 06, 2018 12:07 pm
- Forum: Electronegativity
- Topic: Electronegativity calculation
- Replies: 4
- Views: 1543
Re: Electronegativity calculation
All we need to know is the trend of electronegativity. You should generally be able to tell which element is more electronegative when comparing between elements. However, you won't need to actually calculate the exact values. If there's a situation where the exact values are important a chart will ...
- Tue Nov 06, 2018 11:57 am
- Forum: Bond Lengths & Energies
- Topic: Resonance Structures
- Replies: 4
- Views: 375
Re: Resonance Structures
To expand on that, if there is only one resonance structure, the bond lengths will be exactly the length of a single bond or a double bond, depending on what kind of bond it is. However, if there are multiple resonance structures, the bond length will be somewhere in between the length of a single b...
- Tue Nov 06, 2018 11:54 am
- Forum: Octet Exceptions
- Topic: Octet Exceptions
- Replies: 4
- Views: 372
Re: Octet Exceptions
The only elements that the octet always applies to is B, C, N, O, F. The max number of electrons they can have is 8 because there is no 2d orbital, meaning once they fill up the 2s and 2p orbitals there's no room left for any additional bonds. Once you reach period 3, the 3d orbital can be utilized ...
- Sat Nov 03, 2018 9:02 pm
- Forum: Administrative Questions and Class Announcements
- Topic: What the Midterm Will Cover
- Replies: 5
- Views: 448
What the Midterm Will Cover
On the Midterm information sheet posted on the website it says that the midterm will cover up to 2C in the 7th edition and 3.11 in the 6th edition. However, in class on Friday and in some of the review sessions we went into the properties of bonds (which is 2D in the 7th edition). Is it possible tha...
- Tue Oct 30, 2018 10:43 pm
- Forum: Lewis Structures
- Topic: Exception to Octet Rule [ENDORSED]
- Replies: 3
- Views: 335
Exception to Octet Rule [ENDORSED]
How do you know when an element can have more than eight electrons? Do we just need to memorize the exceptions or is there some way of figuring it out?
- Tue Oct 30, 2018 10:40 pm
- Forum: Lewis Structures
- Topic: Drawing Lewis Structures
- Replies: 14
- Views: 1980
Re: Drawing Lewis Structures
No resonance won't affect the shape in the Lewis structures at all. To show resonance, you will need to draw multiple diagrams to show the different possibilities.
- Tue Oct 30, 2018 10:36 pm
- Forum: Trends in The Periodic Table
- Topic: Electron Affinity
- Replies: 2
- Views: 375
Re: Electron Affinity
I think he said that with electron affinity there's less of a clear trend as with ionization energy and atomic radius. In general the elements in the upper right side will have the highest electron affinity, but that doesn't guarantee that elements right next to each other or above/below each other ...
- Wed Oct 24, 2018 9:10 am
- Forum: Properties of Electrons
- Topic: colombic potential
- Replies: 2
- Views: 515
Re: colombic potential
This will not be on the test. He wanted us to understand the factors that affect electrons in multi-electron atoms, but you won't be asked to solve any equations like this.
- Wed Oct 24, 2018 9:08 am
- Forum: Properties of Light
- Topic: Visible Light Spectrum... ?
- Replies: 6
- Views: 500
Re: Visible Light Spectrum... ?
Yes it would be a good idea to memorize the visible light and UV wavelengths, but don't worry too much about memorizing the wavelengths of radio waves, gamma rays, etc because it most likely won't be on the test
- Wed Oct 24, 2018 9:04 am
- Forum: Properties of Light
- Topic: conceptual questions on the test 2?
- Replies: 3
- Views: 378
Re: conceptual questions on the test 2?
There most likely will be conceptual questions. You should be able to explain the photoelectric affect, and the atomic spectra, and other things he has put emphasis on
- Thu Oct 18, 2018 8:41 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: 1D 15
- Replies: 2
- Views: 163
Re: 1D 15
Yes, n stands for the principal quantum number, l stands for the orbital angular momentum, and m1 is the magnetic quantum number. n indicates the energy level, l indicates the rate at which the electron circulates around the nucleus, and m1 distinguishes the individual orbitals within a subshell.
- Thu Oct 18, 2018 8:37 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: 2s Orbital
- Replies: 2
- Views: 294
Re: 2s Orbital
I believe that the average distance of electrons from the nucleus in the 2s orbital is greater than the average distance of electrons in the 1s orbital. Both orbitals are drawn in a sphere shape showing the potential locations of the electrons, so the 2s sphere will be larger than the 1s sphere.
- Thu Oct 18, 2018 8:34 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Problem ID.11
- Replies: 3
- Views: 297
Problem ID.11
How do you figure out how many orbitals are subshells with l equal to a specific value?
- Mon Oct 08, 2018 3:52 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: How to understand the questions correctly
- Replies: 3
- Views: 418
Re: How to understand the questions correctly
In general I think those statements are true. Most of the questions should clearly state what form they want the answer with, and I'm sure it will be very clear on the test.
- Mon Oct 08, 2018 3:47 pm
- Forum: Balancing Chemical Reactions
- Topic: States of Matter
- Replies: 11
- Views: 975
Re: States of Matter
With what we are doing currently, the states of matter won't affect any calculations. My TA said that we should include the states whenever possible, and later on they will become more relevant to us.
- Mon Oct 08, 2018 3:44 pm
- Forum: Limiting Reactant Calculations
- Topic: Reactants and Reagents
- Replies: 4
- Views: 464
Re: Reactants and Reagents
Reagent refers to an actual physical chemical, while reactant refers to the word or symbol in the equation. If you were doing a physical experiment with real materials, you could refer to those materials as reagents. However, if you are talking about the reaction, you should refer to them as reactan...
- Wed Oct 03, 2018 4:38 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Calculating the amount of atoms in a sample
- Replies: 2
- Views: 199
Re: Calculating the amount of atoms in a sample
You will start by converting the mass into the number of moles by dividing by the molecular mass of the compound. To convert to formula units from moles, just multiply by Avogadro's constant.
- Wed Oct 03, 2018 4:27 pm
- Forum: SI Units, Unit Conversions
- Topic: Week 1 Homework Assignment [ENDORSED]
- Replies: 16
- Views: 1196
Re: Week 1 Homework Assignment [ENDORSED]
Does anyone know how the 7 questions will be graded? Should I be showing every single step and make sure my work is super clear, or is it more based on completion?
- Wed Oct 03, 2018 4:19 pm
- Forum: Limiting Reactant Calculations
- Topic: Finding theoretical yield
- Replies: 6
- Views: 631
Re: Finding theoretical yield
The molar ratio between the two reactants is essential for determining the limiting reactant. However, once you find the limiting reactant you do not need to use the molar ratio between the reactants to determine the theoretical yield. You will be using the molar ratio between the limiting reactant ...