CHEMISTRY COMMUNITY

Sreyes_1C

You should end up with the same result, i guess we just always try to pick out the easiest choice

Sreyes_1C

I also believe it'd always require some work/calculation

Sreyes_1C

from my understanding, the equation helps us account for the factors that impact the rate of a reaction that we don't see in the rate laws

Sreyes_1C

if its the same as cell potential I would assume we don't need to know much more about it

Sreyes_1C

yes, and not moles in the way we used to think of it, which is something that really confused me at first

Sreyes_1C

https://www.electrochem.org/biology-medicine

I found this, hopefully it helps

Sreyes_1C

Also, how do you know if a metal/other compound is a strong reducing/oxidizing agent? I imagine theres a few ways but I do remember reading somewhere that good reducing agents tend to have large atomic radiuses and atoms with low EN so I figure thats one way you might be able to tell if its strong,...

Sreyes_1C

It depends on what you're given but probably you can use the Nernst equation, but it depends on if you're given enough to use that

Sreyes_1C

Since we only change coefficients I don't believe the physical states are altered

Sreyes_1C

I find myself very lost at times and started going to the step up sessions, which I have found pretty helpful. Before then I would just go to my PLF but the step up sessions have given me a nice boost in my understanding

Sreyes_1C

Redox reactions just have to involve a change in oxidation number for one or more reactant elements, so it is not limited to that

Sreyes_1C

I'm not sure what sources switch it up, but I would say in the context of this class the anode will stay on the left and cathode on the right

Sreyes_1C

oxidizing agents = the ones carrying out the oxidation. and then same with reduction agents

Sreyes_1C

I like to think of it as, the oxidizing agents carry out the oxidation, and same with reduction

Sreyes_1C

I would assume we do not need to know it for the final

Sreyes_1C

I believe the units for entropy after the calculations should end up being J/K

Sreyes_1C

its zero for an isothermal reversible reaction!

Sreyes_1C

http://www.esru.strath.ac.uk/EandE/Web_ ... s/text.htm

This link slightly touches on this subject

Sreyes_1C

since what we learned involves expansion of volume, we need the change in volume to see how much work is done

Sreyes_1C

Mariana Fuentes 1L wrote:A way of identifying redox reactions is : The LEO goes GER.

LEO: Lose Electrons Oxidation

GER: Gain Electrons Reduction

there's also OIL RIG, which is:
Oxidation Is Loss= OIL
Reduction Is Gain= RIG

which is referring to loss/gain of electrons

Sreyes_1C

https://www.youtube.com/watch?v=v5sDNmYCaqo

this video on balancing redox reactions was helpful to me

Sreyes_1C

rusting is an oxidation reaction. iron reacts with water and oxygen to form hydrated iron(III) oxide. both water and oxygen and needed for rusting to occur. so our learning of these types of reactions applies

Sreyes_1C

the terms are used like interchangeable synonyms so I believe they are the same

Sreyes_1C

Robert Tran 1B wrote:The posts are usually counted at the end of the quarter. You should do 5/week to stay on track, but as long as you have 50 by the end of the quarter and you didn't do a bunch of them at the same time, you'll be good.

is this true? I assumed they were checked every week by the end of sunday

Sreyes_1C

https://www.youtube.com/watch?v=fdbrhQAM9Gw

this video helped me understand half reactions a little better.

Sreyes_1C

in that case, it seems like it is most likely wrong

Sreyes_1C

read closely as to what they give you. Sometimes they give you information to throw you off but look for any constant pressure, temperature, or volume. Also read closely to know exactly what values change. Also read for any words that describe the reaction or changes in the systems. If you know the ...

Sreyes_1C

https://www.youtube.com/watch?v=8xGf2vX0Hsw

not sure if it'll help but I tried this one

Sreyes_1C

Dang, studying for the midterm but this question has me curious now. I honestly have no idea but if we are trying to put it in context of that law, I guess matter isn't being created but rather expanded and recycled. But then again I don't know much about space and the universe. it'd be really crazy...

Sreyes_1C

AAP is honestly the best form of help with a class in my experience. PLFs help a lot and in my experience you form a nice small community with people in your classes you wouldn't have met otherwise

Sreyes_1C

AAP is honestly the best form of help with a class in my experience. PLFs help a lot and in my experience you form a nice small community with people in your classes you wouldn't have met otherwise

Sreyes_1C

https://www.toppr.com/guides/chemistry/ ... odynamics/

Sreyes_1C

I think we should usually convert to kelvin, but it might depend on what the question says

Sreyes_1C

not sure about the concepts, but I feel like if you know the conceptual side or the actual formula part well, you'll be able to figure out the part you don't know

Sreyes_1C

I assume we shouldn't focus on it much, but it might help knowing more about it but I am not sure if its worth risking studying it more instead of earlier topics

Sreyes_1C

How do I gain access to the emails of PLF instructors to join? I could use some help with chemistry and math /: if you're in AAP, you can just ask around and ask any PLF instructors if they know of any people who lead the PLF sessions you're looking for. I'm in AAP but one time my enrollment in PLF...

Sreyes_1C

the example i think of is a hydroflask. a water bottle like that isn't perfect, but ideally you can think that the temperatures don't transfer and that the temperature of the beverage in the bottle remains the same and not phased from the temperature outside the bottle.

Sreyes_1C

it is negative if the system is expelling energy by doing work onto the surroundings. It is positive if the surroundings are doing work on the system

Sreyes_1C

it means the volume or pressure will not change during the reaction. In the problems, it usually either specifies that it is constant, or you have to infer that based off what information they give you and the values they list

Sreyes_1C

I would assume they count, and I think you have to base it off how many sig figs the problem gives you. I believe its the lowest amount of sig figs the problem gives you and you match yours with those given

Sreyes_1C

Personally, what helped me memorize it was that i just learned to memorize the association of mass and volume to the word extensive, so when I thought of extensive I would remember mass and volume. so when I think of mass and volume I remember they depend on the amount of material

Sreyes_1C

I don't think he said it's going to be on the test

Sreyes_1C

Ritu Gaikwad 2E wrote:For the acids and bases, do we have to memorize the list of strong acids and bases for future tests and exams?

i'm not sure if we are required to memorize them, but it is usually good to know.

Sreyes_1C

I'm not sure if this answers your question but if the temperature is the same the concentration does not change the equilibrium constant (k). However, if you change the temperature it does change the equilibrium constant. So temperature is the only thing that can affect the the equilibrium constant...

Sreyes_1C

because its concentrations over concentrations, the M cancels out and its also just a ratio of the concentrations

Sreyes_1C

Elizabeth Harty 1A wrote:Are the calculations the same regardless of whether its concentration of partial pressure?

i believe the calculations are the same so i think its okay as long as you account for any differences in units or something

Sreyes_1C

bases also react with acids on human skin, which influences how they feel

Sreyes_1C

https://www.khanacademy.org/science/org ... sted-lowry

I found this video to be helpful with distinguishing the two

Sreyes_1C

yes so you would count the number of bonds to figure out the coordination number of the central atom

Sreyes_1C

I am not sure but if it is on the final I doubt it'd be very important. As long as you remember that basic definition

Sreyes_1C

the safe way would be to include it always, especially on an exam

Sreyes_1C

its classification as tetrahedral is based off of it having 4 regions of density, as it will have a lone pair on the O as just the three hydrogrens would not satisfy oxygen

Sreyes_1C

if they have the same pull opposite of each other, like 4 of the same atoms surrounding a central atom, they will cancel out.

Sreyes_1C

The three major types of intermolecular interactions are London dispersion forces, dipole–dipole interactions and hydrogen bonds

Sreyes_1C

linear will have no lone pairs so the bond angle will not be altered

Sreyes_1C

the lone pairs will not attract the other bonds and actually repel them so bond angle decreases

Sreyes_1C

I think there would only be one, but maybe there are exceptions to where there could technically be more than one

Sreyes_1C

so far, I do nt believe we should but perhaps later on that will be the case.

Sreyes_1C

A lone pair of electrons at a central atom always tries to repel bonded pair of electrons. So, the bonds are displaced slightly, which leads to a decrease of bond angle.

Sreyes_1C

Paramagnetic compounds are attracted to magnetic fields, they have unpaired electrons. diamagnetic compounds are repelled from magnetic fields. their electrons all have paired spins.

Sreyes_1C

Mg and Br have a smaller difference in electronegativity

Sreyes_1C

it is everything from the midterm onwards

Sreyes_1C

there is linear, trigonal planar, bent, tetrahedral, trigonal pyramidal, trigonal bypyramidal, seesaw, t shaped, octahedral, square pyramidal, square planar

Sreyes_1C

I don't believe it matters, as long as the number of regions of electron density is accurate

Sreyes_1C

it is definitely safe to draw the most stable lewis structure to help with that.

Sreyes_1C

bond angle is effected by lone pairs on the central atom. the presence of a lone pair decreases bond angle.

Sreyes_1C

to moves to the next higher energy orbital because it is excited

Sreyes_1C

valence electrons are removed from the highest energy level first

Sreyes_1C

I'm not sure if you mean bond strength, but if you do, single bonds are the weakest. Double bonds are stronger and triple are the strongest

Sreyes_1C

I believe we don't have to memorize those random ions. Unless we see them a lot, I doubt we'd have to memorize them

Sreyes_1C

longer bonds are weaker and shorter bonds are stronger.

Sreyes_1C

not sure if it varies, but generally, the stronger the bond, the shorter the length. So a triple would be shorter than a double and a double would be shorter than a single

Sreyes_1C

they can be placed as long as they satisfy the octet rule but you should try drawing a structure with zero formal charge because it will be most stable. the double/triple bonds will help getting the formal charge to zero

Sreyes_1C

you would use a double or triple bond to satisfy the number of valence e- each element needs. also they are used to get the formal charge to zero

Sreyes_1C

lone pairs are going to be two single dots next to each other that are not bonded to anything, thus making them lone pairs.

Sreyes_1C

Jorge Ramirez_4H wrote:Is electronegativity important when doing electron configurations?

for only electron configurations, it is not really useful. knowing what it is and its trend is more useful for bonds and lewis structures

Sreyes_1C

personally, reading a textbook does not help me, so I always recommend youtube videos. It is good to know what formulas you do not need to memorize, so you can watch these videos over and over again while focusing on learning to apply the formulas and conversions.

Sreyes_1C

the relationship would be that they are both necessary in understanding how filling up the orbitals works. You can start by using Hund's rule to make sure each orbital has an electron before doubling up. Then, you can use Pauli's principle to arrange it so each orbital has one up and one down.

Sreyes_1C

since the configurations continue to get longer and longer, you can start the longer configurations with an abbreviation of the noble gas that comes before it. The noble gases are the column all the way to the right and they have full outer shells, which makes it possible for us to use them when doi...

Sreyes_1C

Since this is only 14a I dont think we should know much more about the details of it than he explains in lecture. I think main thing to remember is the -1/2 and +1/2 numbers and that it is always one down and one up in an orbital

Sreyes_1C

ATingin_3I wrote:Why is it that each orbital can only hold 2 electrons max?

I suppose its just a given that is defined by the Pauli exclusion rule, along with how the two electrons must have different spins

Sreyes_1C

in vacuums, we don't see the same interferences as we would in realistic settings

Sreyes_1C

I believe it is always the same and it was a constant listed in the test sheet last week.

Sreyes_1C

I like to remember that two in phase waves leads to constructive and two out of phase lead to destructive. What helps me is drawing out what in phase/out of phase waves would look like to visualize how it would lead to destructive or constructive.

Sreyes_1C

yes and it might be one of the constants listed on the test sheets

Sreyes_1C

Jasmine Kim 3H wrote:If we need to use the answer of one question for the next question and our answer for the first question is wrong, will we not get full credit for the second, even if our calculations on the second were correct?

not entirely sure, but i believe you should still get some points for accurate process

Sreyes_1C

705327693 wrote:Do we have to know this stuff for the first test?

I would like to assume it wouldn't be directly tested on the first test but more than likely it would be necessary later on in the course

Sreyes_1C

Its always good to remember mass is neither created or destroyed. However it can be confusing since he mentioned something about atoms being destroyed in nuclear reactions, but pretty sure we won't see that in this class

Sreyes_1C

A bluebook is not mentioned in the syllabus for the first test

Sreyes_1C

It was so great to hear your story. Often times it feels like we should know exactly what we want to do with our careers but it is nice to see an example of success while not knowing exactly each step going forward.

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