Search found 39 matches
- Sun Mar 17, 2019 10:16 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Final Exam Practice Problem
- Replies: 3
- Views: 618
Re: Final Exam Practice Problem
Thank you for these!
- Sun Mar 17, 2019 10:16 pm
- Forum: Administrative Questions and Class Announcements
- Topic: LYNDON'S PORK RAMEN REVIEW
- Replies: 37
- Views: 7572
Re: LYNDON'S PORK RAMEN REVIEW
Thank you for all your help this quarter, Lyndon!
- Sun Mar 17, 2019 10:15 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Week 9 Worksheet (2E,I,K)
- Replies: 13
- Views: 5307
Re: Week 9 Worksheet (2E,I,K)
Thank you for all your help this quarter, Joyce!
- Sat Mar 16, 2019 10:25 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Lyndon's HOTDOG MIDTERM REVIEW SESSION!! FINALLY!
- Replies: 49
- Views: 11702
Re: Lyndon's HOTDOG MIDTERM REVIEW SESSION!! FINALLY!
Can anyone explain 1D?
Thanks!
Thanks!
- Sat Mar 16, 2019 10:16 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Pure Solids and Liquids
- Replies: 4
- Views: 714
Re: Pure Solids and Liquids
It is similar to how we do pseudo rate constants. We make one reactant so large that it basically doesn't affect the reaction rate, enabling us to just study the other reactant as if it is the only thing that affects the rate. Same thing with liquids and solids. They are in such high excess that the...
- Sat Mar 16, 2019 10:13 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Stability of reactants and products
- Replies: 2
- Views: 954
Re: Stability of reactants and products
The equilibrium constant will tell you this. If K is greater than 10^3 then it favors the products, meaning that the products are much mnore stable than the reactants. If K is smaller than 10^-3 then it favors the reverse reaction and the reactants are much more stable than the products. If K is bet...
- Sat Mar 16, 2019 10:11 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Catalyst in molecularity
- Replies: 1
- Views: 726
Catalyst in molecularity
When you report the moleculairty of a step, and that step includes a catalyst, do you include the catalyst in the molecularity or not? Thanks!
- Sat Mar 16, 2019 10:07 pm
- Forum: *Enzyme Kinetics
- Topic: Collision theory
- Replies: 3
- Views: 744
Re: Collision theory
The reaction that is least likely to occur has higher molecularity (i.e. third order reactions are less likely to occur than second order which are less likely to occur than first order). This is because two things need to happen for a reaction to occur: the molecules need to collide in the proper o...
- Sat Mar 16, 2019 10:02 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Test 2 Question 5
- Replies: 5
- Views: 910
Re: Test 2 Question 5
The second method is correct. I am not sure how you solved the first method, but you use the equation ln(k2/K1)= RT(1/T2 -1/T1) to solve for K2. Then you use K2 to find the concentration of H+. The equilibrium concentration of H+ at 10 degrees C for a neutral solution (we know it is neutral because ...
- Sat Mar 16, 2019 9:54 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Positive or Negative Ecell Values
- Replies: 4
- Views: 970
Re: Positive or Negative Ecell Values
Do you mean Ecell or E (standard) cell? Because E (with the circle on the top symbolizing standard conditions) is different from Ecell.
The Nernst equation shows the relationship between these: Ecell = E(standard) - (R*T)/(n*F) * lnQ
I hope that helps!
The Nernst equation shows the relationship between these: Ecell = E(standard) - (R*T)/(n*F) * lnQ
I hope that helps!
- Sat Mar 16, 2019 9:52 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: net rate of reaction
- Replies: 1
- Views: 604
Re: net rate of reaction
I am not totally sure what you mean by net rate of reaction, but for each elementary step the rate should look the same. For example: Step 1: A + B ----> C Step 2: C -----> D Both should have rate = k[reactants] so for step 1 use rate constant k1: rate = k1[A][B] and for step 2 use rate constant k2:...
- Sat Mar 16, 2019 9:50 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Catalysts
- Replies: 4
- Views: 671
Re: Catalysts
I think that it is better to just know the rule that a catalyst is something that appears in the beginning and end of the reaction (is not consumed, and is not an intermediate).
- Tue Mar 05, 2019 2:05 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Changing concentration to change rate
- Replies: 2
- Views: 337
Changing concentration to change rate
How does changing the concentration of different species affect the rate of the reaction? If a reactant has a coefficient of 1 and you double its concentration and the rate of reaction doubles then this is a first order reaction. If a reactant has a coefficient of 1 and you double its concentration ...
- Tue Mar 05, 2019 2:03 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Zero, First, and Second Order reactions
- Replies: 2
- Views: 384
Zero, First, and Second Order reactions
I still a bit confused on what exactly order of reaction means and how this interacts with different species. For example, in the reaction: H2 + I2 ----> 2HI. Why is this a second order reaction? Is it because each reactant has a coefficient of 1 and 1+1 equals 2, or because the product has a coeffi...
- Tue Mar 05, 2019 1:59 pm
- Forum: General Rate Laws
- Topic: Unique Rate
- Replies: 4
- Views: 416
Re: Unique Rate
You can calculate the unique rate by dividing the rate of reaction of a specific species by its coefficient. This is the unique rate of reaction, and will be the same rate if you use any of the species in the reaction.
- Tue Mar 05, 2019 1:57 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: 15.7 or finding rates of decomposition
- Replies: 2
- Views: 298
Re: 15.7 or finding rates of decomposition
If this is 15.7 in the 6th edition, I noticed that on the syllabus Dr. Lavelle did not include this in the practice problems to do.
- Tue Feb 26, 2019 6:20 pm
- Forum: Balancing Redox Reactions
- Topic: Basic redox reactions
- Replies: 3
- Views: 433
Basic redox reactions
How do you balance the H+ in a cell when it is basic?
I don't understand how to convert H+ into OH- and balance from there (what order of steps should I take?)
Thank you!
I don't understand how to convert H+ into OH- and balance from there (what order of steps should I take?)
Thank you!
- Tue Feb 26, 2019 3:53 pm
- Forum: Balancing Redox Reactions
- Topic: redox homework question
- Replies: 3
- Views: 318
redox homework question
Hi, in homework question 14.1 in the 6th edition, I am supposed to name the elements that undergo either oxidation or reduction. The answer solution does not include oxygen in it, even though it is oxidized. Can someone explain? H+ (aq) +cr2o7^2- (aq) +c2H5OH (aq) --> Cr^3+ (aq) + C2H4OH (aq) + H2O ...
- Mon Feb 25, 2019 8:53 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Reducing agent/oxidizing agent
- Replies: 5
- Views: 554
Reducing agent/oxidizing agent
When something is a "reducing agent", does this mean it gets oxidized or reduced? Furthermore, does this mean it is the cathode or the anode?
- Sun Feb 17, 2019 8:42 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: delta S of reaction
- Replies: 1
- Views: 343
delta S of reaction
Why is delta S of reaction different than delta S molar/delta S of formation of a substance? For example, in problem 9.55 (6th edition), we use an appendix to look up the delta S of formation (listed as delta S molar) of a substance, i.e. NH3, and subtract from it the delta S molar of its reactants ...
- Mon Feb 11, 2019 4:27 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Buffers
- Replies: 4
- Views: 808
Buffers
How do buffers work in acid base reactions? Can someone explain, thank you!
- Mon Feb 11, 2019 4:25 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Percent ionization vs percent deprotonation
- Replies: 3
- Views: 675
- Sun Feb 10, 2019 6:22 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Percent ionization vs percent deprotonation
- Replies: 3
- Views: 675
Percent ionization vs percent deprotonation
Is there a difference between calculating percent ionization and percent deprotonation? Are they the same thing?
Thanks!
Thanks!
- Wed Feb 06, 2019 1:10 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Thermochemistry // Thermodynamics
- Replies: 2
- Views: 397
Re: Thermochemistry // Thermodynamics
Thermodynamics is work, heat, and energy (this includes enthalpy and entropy), whereas thermochemistry is about the bonds and the molecular structure. I think of thermochemistry as the microscopic level, whereas thermodynamics is bigger picture.
- Tue Feb 05, 2019 6:32 pm
- Forum: Ideal Gases
- Topic: Ideal gas constant R
- Replies: 10
- Views: 1623
Re: Ideal gas constant R
Thank you for the responses!
- Mon Feb 04, 2019 5:02 pm
- Forum: Ideal Gases
- Topic: Ideal gas constant R
- Replies: 10
- Views: 1623
Ideal gas constant R
When do I plug in the ideal gas constant, R, as 0.0825, and when do I plug it in as 8.314?
Not sure when to use which!
Not sure when to use which!
- Mon Feb 04, 2019 4:42 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Homework Problem 8.21 in 6th edition: Q=mcat
- Replies: 1
- Views: 364
Homework Problem 8.21 in 6th edition: Q=mcat
Homework problem 8.23 in the 6th edition textbook states: "A calorimeter was calibrated with an electric heater, which supplied 22.5 kJ of energy as heat to the calorimeter and increased the temperature of the calorimeter and its water bath from 22.45 C to 23.97 C. What is the heat capacity o...
- Fri Feb 01, 2019 12:22 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Enthalpies
- Replies: 5
- Views: 513
Re: Enthalpies
Enthalpy refers to the change in the internal heat of the system at constant pressure (qp).
- Fri Feb 01, 2019 12:21 pm
- Forum: Calculating Work of Expansion
- Topic: Reversible Expansion
- Replies: 3
- Views: 349
Re: Reversible Expansion
Something else to note is that this equation is only used when temperature is constant, because all the other q equations involve a delta T, whereas this one is just T by itself.
- Fri Feb 01, 2019 12:19 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: CP/V
- Replies: 2
- Views: 316
Re: CP/V
Cp and Cv are constants. Cp=20.8 and Cv=12.5.
They are used in the q (or delta H) equations, where qp (q at constant pressure) = nCp(delta T), and qv (q at constant volume) = nCv(delta T).
Hope that helps!
They are used in the q (or delta H) equations, where qp (q at constant pressure) = nCp(delta T), and qv (q at constant volume) = nCv(delta T).
Hope that helps!
- Tue Jan 22, 2019 11:10 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Changes in Pressure, Volume, and Concentration
- Replies: 2
- Views: 258
Re: Changes in Pressure, Volume, and Concentration
Also something to be aware of is that if there is an increase in pressure but the same number of moles of gas on each side of the equation, then nothing happens to the system. If the question states that the PARTIAL pressure of one of the chemicals in the reaction increases, and not the total pressu...
- Tue Jan 22, 2019 11:07 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Second deprotonation
- Replies: 3
- Views: 404
Second deprotonation
Do we need to know second deprotonation for tomorrow's test?
Some of the homework problems for chapter 12 mention it (i.e. 6th edition 12.81)
Thanks!
Some of the homework problems for chapter 12 mention it (i.e. 6th edition 12.81)
Thanks!
- Thu Jan 17, 2019 3:48 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: How temperature affects K
- Replies: 4
- Views: 449
Re: How temperature affects K
Thank you Kim for your response! Super helpful.
Do you know why heat and temperature are not treated in the same way in terms of how they affect equilibrium? It seems like both heat and temperature would affect the rate that the molecules hit each other.
Do you know why heat and temperature are not treated in the same way in terms of how they affect equilibrium? It seems like both heat and temperature would affect the rate that the molecules hit each other.
- Thu Jan 17, 2019 3:32 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: How Ka and Kb relate to each other
- Replies: 1
- Views: 174
How Ka and Kb relate to each other
If Kc of the forward reaction is the inverse of the Kc of the reverse reaction, then does this mean that in an acid-base chemical equilibrium reaction, the conjugate acid would dissociate at the inverse rate that the conjugate base would accept a proton (in the opposite direction)? If my logic is fl...
- Thu Jan 17, 2019 3:27 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: How temperature affects K
- Replies: 4
- Views: 449
How temperature affects K
Why does changing temperature change the equilibrium constant K, but changing pressure, heat, and concentration does not?
- Thu Jan 17, 2019 3:20 pm
- Forum: Student Social/Study Group
- Topic: ICE Table
- Replies: 5
- Views: 555
Re: ICE Table
The reason that you can do an approximation where you "ignore" the x in the denominator, is because if the K value is smaller than 10^-3, then the x when multiplied out by this k value will be very negligible. So, instead of going through the whole process and doing the quadratic formula i...
- Thu Jan 10, 2019 1:29 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: How to use ICE tables
- Replies: 5
- Views: 725
How to use ICE tables
How do I know what to plug into ice tables? For example, I know that I can plug in molarity to find initial, change, and equilibrium. Will this work for pressure too?
Thanks!
Thanks!
- Thu Jan 10, 2019 1:24 pm
- Forum: Ideal Gases
- Topic: Identifying gases in equilibrium via pictures
- Replies: 2
- Views: 188
Re: Identifying gases in equilibrium via pictures
Thank you so much for your response! It makes much more sense now. I guess another way to think about it is that the reactants are the diatomic (stuck together) gas molecules and the products are the single, free floating molecules.
- Thu Jan 10, 2019 12:16 pm
- Forum: Ideal Gases
- Topic: Identifying gases in equilibrium via pictures
- Replies: 2
- Views: 188
Identifying gases in equilibrium via pictures
For this week's homework, one of the problems (11.7 in the 6th edition) shows a picture of four flasks with gas molecules in them. The gas is an unknown diatomic molecule, X2. Part a of the questions asks: "Which flask represents the point in time at which the reaction has reached equilibrium?&...