Search found 36 matches
- Sat Mar 16, 2019 1:27 pm
- Forum: Balancing Redox Reactions
- Topic: How to tell if its in acidic or basic
- Replies: 6
- Views: 660
Re: How to tell if its in acidic or basic
I think they would have to tell us, because in most of the hw problems and in the midterm and tests, they told us whether it was in an acidic or basic solution. :)
- Sat Mar 16, 2019 1:24 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Final [ENDORSED]
- Replies: 9
- Views: 1095
Re: Final [ENDORSED]
I would assume so, or else we would need to "look them up" as most of the UAs and even Lavelle said during lecture I believe, because memorizing all of the Ecell values would be quite hard haha :) They might even state it in the problem too.:)
- Sat Mar 16, 2019 1:20 pm
- Forum: General Rate Laws
- Topic: Unique Rate quick question
- Replies: 2
- Views: 539
Re: Unique Rate quick question
605168557 wrote:In general for all reactions: aA --> bB + cC
The unique rate is -1/a * d[A]/dt = 1/b * d[B]/dt = 1/c * d[C]/dt
The unique rate is the same for all R & P in that 'unique' reaction
Ohhhh ok so unique rates normally do not have more than one reactants then? Is that what you mean?
- Sat Mar 16, 2019 1:18 pm
- Forum: Student Social/Study Group
- Topic: Solutions for Tests 1 and 2
- Replies: 7
- Views: 1129
Re: Solutions for Tests 1 and 2
Ashley P 4I wrote:I believe that test one is posted but not test two.
Where is test 1 posted at?
- Sat Mar 16, 2019 1:17 pm
- Forum: Student Social/Study Group
- Topic: Final Jitters
- Replies: 457
- Views: 334105
Final Jitters
Does anyone know how to calm down your anxieties before you take this final? Since having test anxiety can be very distracting while you're trying to study or even while you're taking the test itself. Open to any tips:)
- Sat Mar 16, 2019 1:10 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Cp vs Cv
- Replies: 1
- Views: 463
Re: Cp vs Cv
When I went to one of the review sessions, one of the UAs had stated that we use whichever one we are focusing on in the current problem and whichever one you use in your change in entropy equation, since you take into consideration each entropy calculation separately, since there are 2 delta S that...
- Sat Mar 16, 2019 12:57 pm
- Forum: Student Social/Study Group
- Topic: Solutions for Tests 1 and 2
- Replies: 7
- Views: 1129
Re: Solutions for Tests 1 and 2
Yeah I have the same question too^. I'm going to try looking for them, and I'll let you know if I find them, but hopefully someone else will respond with an answer before then:)
- Sat Mar 16, 2019 12:41 pm
- Forum: General Rate Laws
- Topic: Unique Rate quick question
- Replies: 2
- Views: 539
Unique Rate quick question
How are we able to figure out the unique rate of the reaction if there are more than one reactants given in the equation? Since I know if there was one reactant you would divide the rate of the reaction by the coefficient of that one reactant, but what if there are more than one? Do we multiply the ...
- Sat Mar 16, 2019 12:38 pm
- Forum: General Rate Laws
- Topic: Average Rate of Reaction
- Replies: 2
- Views: 434
Re: Average Rate of Reaction
yeah you got it girl!:)
- Thu Mar 14, 2019 5:42 am
- Forum: First Order Reactions
- Topic: Writing First Order Reactions
- Replies: 4
- Views: 698
Writing First Order Reactions
Does Lavelle want us to write the exponent of 1 for first order reactions? I just wanted to clarify.
An example could be:
rate=k[A]^1[B]^2
or does he want no exponent of 1? such as rate=k[a][B]^2
An example could be:
rate=k[A]^1[B]^2
or does he want no exponent of 1? such as rate=k[a][B]^2
- Thu Mar 14, 2019 5:39 am
- Forum: First Order Reactions
- Topic: pseudo first order [ENDORSED]
- Replies: 5
- Views: 910
Re: pseudo first order [ENDORSED]
What is a pseudo first order rate law again? My TA tried to explain it, but I still didn't really understand it. Sorry if this is a dumb question.
- Thu Mar 14, 2019 5:36 am
- Forum: Second Order Reactions
- Topic: Question 15.19 on 6th edition hw
- Replies: 1
- Views: 254
Question 15.19 on 6th edition hw
In Q: 15.19 on the 6th Edition Hw, how come the reaction of B is in second order? The concentration 2 of B was 3.02 and the concentration 1 of B was 1.25. The rate 2 is 50.8 and the rate 1 is 17.4. I end up getting 2.416^n=2.919, so n is about around the 1.2 area. Why did the solutions manual round ...
- Thu Mar 14, 2019 5:23 am
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: mmol vs mol
- Replies: 6
- Views: 1035
Re: mmol vs mol
Yeah it matters which one you use depending on the question you are trying to solve, since if the question asks for mmol, then use mmol, and vice versa. They should hopefully let you know in the question towards which units to use, since either they'll be provided, or it'll be specifically asked. :)
- Thu Mar 14, 2019 5:16 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Direction reaction goes
- Replies: 2
- Views: 508
Direction reaction goes
CH4(g) + 2H2S(g)-------> CS2(g) + 4H2(g) a.) 2.00 mol of CH4, 2.00 mol of CS2, 4.00 mol of H2S, and 4.00 mol of H2 are mixed in a 500 ml vessel at 960 K. Kc=0.046 for this reaction. Show using calculations if this reaction is at equilibrium. If not, which direction will the reaction process? b.) Ful...
- Thu Mar 14, 2019 4:25 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: pH question
- Replies: 1
- Views: 1264
pH question
Sodium Benzoate (NaC7H5O2) is used as a food preservative. What is the pH of a 0.10 M solution of sodium benzoate? The pka of benzoic acid (C2H6O2) is 4.404. Can someone help break this up for me? :) Thank you.
- Thu Mar 14, 2019 4:19 am
- Forum: Balancing Redox Reactions
- Topic: Balancing basic redox reactions
- Replies: 7
- Views: 840
Re: Balancing basic redox reactions
How do you balance basic redox reactions if OH and H2O both have O in them? (as opposed to acidic where you can just use H+ and automatically balance the equations)? Basically, what you do is you add the H2O first in the redox half reaction to balance out the Os on the two sides. For example, in th...
- Thu Mar 14, 2019 3:43 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Initial Concentration Question
- Replies: 1
- Views: 224
Initial Concentration Question
Question: "Suppose that 3 moles of H2(g) and 6 moles of F2(g) are mixed in a 3L flask. The equilibrium constant (Kc) of the above reaction is 115 at a specific temperature. Calculate the initial concentrations for each chemical species." Just to clarify, can anyone break it down step by st...
- Thu Mar 14, 2019 3:36 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Midterm Q3
- Replies: 4
- Views: 795
Midterm Q3
In Q3 of the Midterm, part D, it states Phosphoric acid is used to acidify foods and beverages such as various colas and jams and provides a tangy or sour taste. Write the reaction that represents Ka2 for phosphoric acid (H3PO4). What would've been the correct answer?
- Thu Mar 14, 2019 3:30 am
- Forum: General Rate Laws
- Topic: k1 vs k2?
- Replies: 4
- Views: 1865
Re: k1 vs k2?
In response to your question, I am going to ask a question to understand your thoughts and approach. How did you get "k2k" in your rate law for "rate=k2K[NOCl]^2/[NO]"? Since I believe that K would be a constant perhaps representing that value of "K2K", however I believ...
- Thu Mar 14, 2019 3:24 am
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: k1 prime or k-1
- Replies: 1
- Views: 259
Re: k1 prime or k-1
They both mean the same thing I believe. "K-1" is "K1prime", so I would assume that they can be used interchangeably.
Also, K-1 does not mean K subtract 1, in case that was a thought. :)
Also, K-1 does not mean K subtract 1, in case that was a thought. :)
- Thu Mar 14, 2019 3:18 am
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: K1 vs K2
- Replies: 2
- Views: 404
Re: K1 vs K2
I am unsure if this is what you meant by your question, but my TA had explained that we use K2 to represent the K(1)/K(-1), because K2 is like the variable representing the value of what K(1)/K(-1) day is. You can keep the K(1)/K(-1) there if you would like, but K2 is there to simplify your rate int...
- Thu Mar 14, 2019 3:03 am
- Forum: Student Social/Study Group
- Topic: Curve?
- Replies: 50
- Views: 6024
Re: Curve?
As of now with what he stated in the syllabus, if you were to receive about 250/500 points, you will pass the class with a C-, so if you have a 75%, then that means it might average up to a B or B+, depending as the student above said, on the class average. This what is some people in the class were...
- Mon Feb 25, 2019 1:56 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Tips for Discussion Test
- Replies: 6
- Views: 547
Re: Tips for Discussion Test
Are there any useful video links you guys recommend or any online resources that break down the questions step by step?
- Mon Feb 25, 2019 1:53 am
- Forum: Balancing Redox Reactions
- Topic: Question 14.3 6th Edition Hw
- Replies: 1
- Views: 244
Re: Question 14.3 6th Edition Hw
Also, what would we consider S2O3 (2-) (aq) to be? Is it a reduced? Or oxidized? Or none?
- Mon Feb 25, 2019 1:52 am
- Forum: Balancing Redox Reactions
- Topic: Question 14.3 6th Edition Hw
- Replies: 1
- Views: 244
Question 14.3 6th Edition Hw
In question 14.3 part a, in the following redox reaction below, it states that H2SO4- is the oxidizing agent and that Cl is the reducing agent. Why is that? Isn't Cl gaining electrons and its oxidation number is lowered from 0 to -2?
Cl2 (g) + S2O3 (2-) (aq) becomes Cl- (aq) + SO4 (2-) (aq)
Cl2 (g) + S2O3 (2-) (aq) becomes Cl- (aq) + SO4 (2-) (aq)
- Mon Feb 25, 2019 1:44 am
- Forum: Balancing Redox Reactions
- Topic: Adding OH- and H20 into reactions
- Replies: 3
- Views: 1198
Re: Adding OH- and H20 into reactions
In basic solution, you first balance O by using H2O, then balance H by adding H2O to the side of each half-reaction that needs H , and then add OH - to the other side of the equation Thank you! So we use H20 first to try to balance the O and then next we use it to balance the H, and then what's lef...
- Mon Feb 25, 2019 1:39 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Tips for Discussion Test
- Replies: 6
- Views: 547
Tips for Discussion Test
Does anyone have any tips or advice on how to prepare for the discussion test this week, or of what I should definitely know and go over? :)
- Mon Feb 25, 2019 1:36 am
- Forum: Balancing Redox Reactions
- Topic: 14.5 6th Edition Question Hw
- Replies: 1
- Views: 158
Re: 14.5 6th Edition Question Hw
Is it because of the difference in the oxygen's state? Or just because we need to include H2O and OH- into it? Thank you for your help!:)
- Mon Feb 25, 2019 1:35 am
- Forum: Balancing Redox Reactions
- Topic: 14.5 6th Edition Question Hw
- Replies: 1
- Views: 158
14.5 6th Edition Question Hw
How come we cannot do:
2 O(3) (aq) becomes 3 O(2) (g)
in the redox reaction:
O(3) (aq) + Br-(aq) becomes O(2) (g) + BrO(3)- (aq)
The solutions manual had stated the half reaction differently but why wouldn't this be correct?
2 O(3) (aq) becomes 3 O(2) (g)
in the redox reaction:
O(3) (aq) + Br-(aq) becomes O(2) (g) + BrO(3)- (aq)
The solutions manual had stated the half reaction differently but why wouldn't this be correct?
- Mon Feb 25, 2019 1:25 am
- Forum: Balancing Redox Reactions
- Topic: Adding OH- and H20 into reactions
- Replies: 3
- Views: 1198
Adding OH- and H20 into reactions
How do we know when we need to add OH- and H20 into the equations that take place in basic solutions? I know we need to add them to balance out the O's and H's in the reactants, but how do we know when to use OH- instead of H20, since my problem is that I use H2O instead of OH-. Thank you.
- Mon Feb 25, 2019 1:21 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Stability of reactants and products Midterm question
- Replies: 3
- Views: 650
Stability of reactants and products Midterm question
For Question 1 Part C given on the midterm, it says "using the data given in part A, comment on the relative stability of the reactants and the products." In the data in part A that it is referring to, it says that K > Q, so the reaction would not be in equilibrium. What would have been th...
- Fri Jan 18, 2019 8:57 am
- Forum: Administrative Questions and Class Announcements
- Topic: Studying for First Discussion Test
- Replies: 10
- Views: 781
Studying for First Discussion Test
I am a bit nervous for our first test in our discussion sections, and I was wondering what everyone else was doing to prepare themselves for this test, especially with the limited amount time, since I know some problems can take a while to complete. Thank you. :)
- Fri Jan 18, 2019 8:51 am
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: when is x negligible
- Replies: 7
- Views: 6667
Re: when is x negligible
Here something that another student said in this forum that helped me understand. :) "The reason that you can do an approximation where you "ignore" the x in the denominator [of the equation to find x when you complete the Ice tables], is because if the K value is smaller than 10^-3, ...
- Thu Jan 10, 2019 1:27 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Why Would Equilibrium cause death in humans?
- Replies: 3
- Views: 3122
Re: Why Would Equilibrium cause death in humans?
Hello, Here is a link that might help you understand this concept. :) http://www.biocab.org/Irreversibility.html "When individual living organisms lose their capacity to transfer their equilibrium toward the universe, they will be in equilibrium. This is our understanding of death as it fully o...
- Thu Jan 10, 2019 1:18 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: H2O
- Replies: 5
- Views: 346
Re: H2O
Hello,
Yes water will still be included, since only pure solids and pure liquids are excluded from the equation. Therefore, because the physical state of H2O is in a gaseous state, it should not be ignored and should be included. :)
Yes water will still be included, since only pure solids and pure liquids are excluded from the equation. Therefore, because the physical state of H2O is in a gaseous state, it should not be ignored and should be included. :)
- Thu Jan 10, 2019 1:11 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Keq vs. Kc vs. Kp
- Replies: 3
- Views: 21409
Re: Keq vs. Kc vs. Kp
Hello, Here is a pdf that helped me understand. I hope you can open it. If this doesn't help you or you can't open it, let me know and I can explain more. :) For using Keq for Kp, it depends, since Kp asks you to include the partial pressures of the gases with it, and its asking you to solve it usin...