CHEMISTRY COMMUNITY

Josceline 3J

The AXE is the formula for VSEPR, no?? OMG was I reading this all wrong all along???

Josceline 3J

This is the first time I hear about this. I wish I had known about it sooner. Anyways thanks, everyone.

Josceline 3J

I had another question when it comes to hybridization and counting how many bonds we have do lone pairs affect it? In the homework for that section, I remember there was one example where only 3 bonds were created but the answer was sp3 instead of sp2. That's why I'm guessing that something in the l...

Josceline 3J

One thing that we could also use to differentiate between them is that type of metals we are dealing with. For tetrahedral, it consists of all four complexes being non-transitional metals. Square planar in the other hand deals with 2nd and 3rd-row transitional metals.

Josceline 3J

We only get 3 points each week and we can get a total of 30 points for the whole quarter. I think that we had until week 10.

Josceline 3J

I honestly thought this was related to the electronegativity of the element. Thanks for all the help.

Josceline 3J

This are interactions between ions that are charged and a molecule/s that has a dipole.

Josceline 3J

I had the same question, but I didn't think this would be on the final since it was the things we cover. :(

Josceline 3J

Regarding the hybrid orbitals, I was wondering what determines if it is written as sp3 or sp2. What are we supposed to look at when deciding what number to use, I'm a bit confused.

Josceline 3J

I'm also not sure but I was looking at my notes and perhaps it is only the atoms that have both s and p shells full. We need to also consider that the number of hybrids orbitals are simply the regions od electron density.

Josceline 3J

I think we have to look at this problem in terms of what type of bonds and how it overlaps. sigma is not overlapping as much as pi bonds so it is stronger in that sense. sorry if this is confusing. Try searching an image online, if you see it might make more sense.

Josceline 3J

We went over it in discussion, it should be < 120, <90

Josceline 3J

I heard that we need to also feel very confident with the Lewis structures for the sections on molecular structure because an error in the structure can make you get everything else wrong.

Josceline 3J

I think it is the other way around. Pi bonds are weaker than the sigma bonds. Pi bonds are easier to break. I think it has to do with the sigma bonds been closer to the nucleus or something like that.

Josceline 3J

Is this like when you need to complete an octet and you form a bond with another nearby atom? If so, in such case would the one seeking to complete the octet be the one that accepts (Lewis acid) and the one that attaches to it (through a bond) the Lewis base??? OR does this have nothing to do with c...

Josceline 3J

wait I'm confused, are the s characters like the lone electrons in the central atom which make the bend/push on the attached atoms???

Josceline 3J

You could think of it as the second bond that is made. The sigma is the first bond (electrons are taken from the center, C--O ). The pi is formed by taking electrons from around the atom to create bonds. I'm not sure if it makes sense unless you see it, at least that's how they showed me.

Josceline 3J

for test 3 should we go about to study (the book) chapter 4 on molecular structures and shapes or should we focus on studying what the lectures are about? Since the test is supposed to be similar to the homework problems.

Josceline 3J

I'm sorry this is bit out of topic but what part of the book is this? will test 3 cover this too??

Josceline 3J

What is the difference between the molecular shape and the geometry shapes? I know more or so about the molecular but are these different from the geometry ones?? please help

Josceline 3J

The Sigma bond is when two electron clouds meet and create a bond (think of it as the FIRST bond that's made). And the Pi bond is the second bond made. This bond is made from electrons that are around/surrounding the bonded atoms. I don't know if it makes sense because you kind of need to see it but...

Josceline 3J

What exactly makes hydrogen bonds and covalent bonds strong?

Josceline 3J

I also started doing the blog post a bit late because I changed classed and I like you said there's no information on the syllabus. But really all you need to do is respond to others comments and ask questions. They told me that you need to have three post each week and that it has to be done no lat...

Josceline 3J

So the last test is in week 9, I hope its on the Lewis Structures.

Josceline 3J

Also, you should take into account that it is 4d^8 and that is always full so it will do anything to get full, hence reach stability. And yeah also because the 4d orbital needs to get filled before the 5s

Josceline 3J

Thank you so much this is really helpful!!

Josceline 3J

For the 4s orbital n+ l = 4 + 0 = 4. For the 3d n+l = 3 + 2 = 5. So 4s is lower in energy so fills first.After calcium the 3d orbital falls below the 4s in terms of energy. This means the 4s electrons are lost first in chemical reactions and define the atomic radius of the atom. In summary, repulsi...

Josceline 3J

Normally in class, they always start filling the boxes with an up spin and if all the boxes get up spins and you still have extras then the second round is when you would use the down spin. I think you should just stick to this because even the book does it this way.

Josceline 3J

For the 4s orbital n+ l = 4 + 0 = 4. For the 3d n+l = 3 + 2 = 5. So 4s is lower in energy so fills first.After calcium the 3d orbital falls below the 4s in terms of energy. This means the 4s electrons are lost first in chemical reactions and define the atomic radius of the atom. In summary, repulsi...

Josceline 3J

I know that valence electrons are the ones in the outermost shell but can someone please clarify the number of electrons that go in each shell?

Josceline 3J

It is like a reciprocal process that since the electron's path will be deflected, if you know the p, then you won't know where it will be. if you know its position, then you won't know its p Thank you so much, your answer really helped. It is much easier to remember and think of this as a reciproca...

Josceline 3J

Hello everyone, I'm struggling a bit with this concept. In the hw, it told us to find the ground state of elements (ex: Bi which has 83 electrons) and then the answer was [Xe]4f^(14)5d^(10)6s^(2)6p^(3). When it comes to elements with a high number of electrons is there another way to go about this o...

Josceline 3J

He said that test 2 is on Quantum world, so is it all of chapter 2?

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