Search found 30 matches
- Wed Mar 13, 2019 9:02 pm
- Forum: Second Order Reactions
- Topic: 6th edition 15.39
- Replies: 2
- Views: 579
Re: 6th edition 15.39
For part a, the coefficient does not affect the rate law equation.
- Wed Mar 13, 2019 6:53 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: 6th edition, 15.63
- Replies: 2
- Views: 323
6th edition, 15.63
In the solutions manual for this problem, the answer subtracts 0.59 from the equation for ln k2 - ln k1. Why do they do this?
- Wed Mar 13, 2019 6:51 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Frequency Factor, A
- Replies: 1
- Views: 244
Frequency Factor, A
Is there a way to calculate A?
- Wed Mar 06, 2019 7:23 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: fast and slow elementary reactions
- Replies: 3
- Views: 482
Re: fast and slow elementary reactions
The rate law of multi-step reactions can't be predicted from the net reaction, so the slow step determines the rate law.
- Wed Mar 06, 2019 7:20 pm
- Forum: Zero Order Reactions
- Topic: General Meaning of "Zero Order" Reactions
- Replies: 7
- Views: 743
Re: General Meaning of "Zero Order" Reactions
Zero-order reactions can also occur when there is a catalyst, so the reaction would depend on the catalyst instead of the concentration of reactant.
- Wed Mar 06, 2019 7:11 pm
- Forum: First Order Reactions
- Topic: Half-Life
- Replies: 2
- Views: 374
Half-Life
Why is the half-life for first order reaction the only one that is independent of initial [A]?
- Wed Feb 27, 2019 11:29 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Kinetics vs. Thermodynamics
- Replies: 3
- Views: 414
Kinetics vs. Thermodynamics
In class, Lavelle said when the activation energy is high, the reaction happens very slowly because kinetics, not thermodynamics, controls the reaction. What did he mean by kinetics rather than thermodynamics controlling the reaction?
- Wed Feb 27, 2019 11:25 pm
- Forum: Balancing Redox Reactions
- Topic: oxidizing agent and reducing agent
- Replies: 15
- Views: 1375
Re: oxidizing agent and reducing agent
The chemical that is reduced takes electrons from the other chemical, which is then oxidized, so is the oxidizing agent. Vice versa for the other chemical.
- Wed Feb 27, 2019 11:20 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: E cell
- Replies: 4
- Views: 669
Re: E cell
n is the transfer of electrons for the chemicals being reduced and oxidized. In this case, n is equal to 6 because Fe loses 6 electrons when oxidized and Cr gains 6 electrons when reduced after the reaction occurs.
- Thu Feb 21, 2019 12:03 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Maximum potential
- Replies: 1
- Views: 212
Maximum potential
I don't understand how maximum potential is calculated when there is very little current flow. How does that work?
- Wed Feb 20, 2019 11:58 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Salt Bridge/Porous Disk
- Replies: 5
- Views: 597
Re: Salt Bridge/Porous Disk
The salt bridge or porous disk between the anode and the cathode allow cation/anion diffusion. This keeps both solutions neutral so that the reaction is able to continue.
- Wed Feb 20, 2019 11:55 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Galvanic/Voltaic Cells
- Replies: 4
- Views: 573
Galvanic/Voltaic Cells
Is there a difference between the terms "galvanic" and "voltaic"? Or are they interchangeable?
- Tue Feb 19, 2019 1:22 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Equilibrium
- Replies: 3
- Views: 372
Equilibrium
Why is a reaction at equilibrium have G = 0?
- Tue Feb 19, 2019 1:20 pm
- Forum: Van't Hoff Equation
- Topic: Van't Hoff Equation
- Replies: 4
- Views: 467
Re: Van't Hoff Equation
R is referring to the gas constant.
- Tue Feb 19, 2019 1:17 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterms
- Replies: 4
- Views: 563
Midterms
Hi I was just wondering when our midterms will be passed back to us. Thank you.
- Thu Feb 07, 2019 1:16 am
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Degeneracy
- Replies: 2
- Views: 334
Degeneracy
Can some explain how the number of energy states/arrangements relates to the calculation for degeneracy?
- Thu Feb 07, 2019 1:12 am
- Forum: Phase Changes & Related Calculations
- Topic: Solids and Liquids
- Replies: 5
- Views: 533
Solids and Liquids
In reactions with solids and liquids, why is PV insignificant?
- Thu Feb 07, 2019 12:50 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Enthalpy
- Replies: 1
- Views: 191
Enthalpy
What is the difference between the H values used for Hess's Law and the H values used in standard enthalpy in formation?
- Thu Jan 31, 2019 9:45 pm
- Forum: Calculating Work of Expansion
- Topic: Equations for w
- Replies: 5
- Views: 491
Equations for w
I'm a little confused. What was the point of showing the integral for the work equation to arrive at the same work of expansion equation (w = -PV)?
- Thu Jan 31, 2019 9:41 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Work
- Replies: 3
- Views: 542
Re: Work
When work is done on a system, w is positive. When work is done by a system, w is negative.
- Thu Jan 31, 2019 9:39 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Piston and value of W
- Replies: 3
- Views: 389
Re: Piston and value of W
Work done by the system is energy lost, so w is negative. Work done on the system is energy gained, so w is positive.
- Thu Jan 24, 2019 10:00 pm
- Forum: Phase Changes & Related Calculations
- Topic: Heat and path taken
- Replies: 1
- Views: 207
Heat and path taken
How does heat depend on the "path taken"?
- Thu Jan 24, 2019 9:38 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: H and Q
- Replies: 4
- Views: 499
Re: H and Q
H, enthalpy, is the measure of potential energy change of a chemical reaction in kJ/mol, while q measures heat in joules. H and q are related, in that -H = +q.
Please correct me if I am wrong.
Please correct me if I am wrong.
- Thu Jan 24, 2019 9:28 pm
- Forum: Phase Changes & Related Calculations
- Topic: Thermochemistry Video Modules
- Replies: 1
- Views: 192
Thermochemistry Video Modules
Are there going to be video modules for the thermochemistry unit?
- Wed Jan 16, 2019 6:03 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Using a Eq. table for questions
- Replies: 1
- Views: 156
Re: Using a Eq. table for questions
When two reactions are combined, their K values are multiplied to find the K value of the new reaction.
- Wed Jan 16, 2019 6:00 pm
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Approximation of x
- Replies: 3
- Views: 498
Approximation of x
Can we only assume x is negligible (after ICE table) if the reaction is with a weak acid?
- Wed Jan 16, 2019 5:53 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Catalysts
- Replies: 7
- Views: 728
Re: Catalysts
Catalysts simply speed up the rates of both the forward and reverse reactions, and equilibrium will be reached more quickly. The concentrations of reactants and products at equilibrium will be unchanged.
- Sat Jan 12, 2019 3:48 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Values of K
- Replies: 2
- Views: 263
Re: Values of K
When K>10 3 products are favored, meaning there is largely more product than reactant at equilibrium. The opposite is true for when K<10 -3 . For the intermediate values, neither reactants nor products are "strongly favored", meaning there is a relatively equal amount of reactant and produ...
- Sat Jan 12, 2019 3:31 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Example in Class
- Replies: 7
- Views: 456
Re: Example in Class
Decreasing the amount of NH3 increases the yield of NH3 because the system would react in order to get back to chemical equilibrium. Taking away product in the system allows more reactants to react to form more product.
- Sat Jan 12, 2019 3:25 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Liquids and Solids
- Replies: 3
- Views: 167
Re: Liquids and Solids
I think Professor Lavelle said it's because solids and liquids aren't changed in concentration during the reaction.