Search found 24 matches
- Tue Dec 04, 2018 7:21 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: pH scale
- Replies: 2
- Views: 262
pH scale
This part is a little confusing for me. If, basic solutions have less H3O+ than acids, and the pH log measures the amount of H3O+, then why do the larger numbers (8-14) correspond to bases?
- Tue Dec 04, 2018 7:18 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Ligand Binding Places
- Replies: 2
- Views: 382
Re: Ligand Binding Places
The textbook has a chart on page 724 in the 7th edition telling you the possible number of common ligands.
- Tue Dec 04, 2018 7:13 pm
- Forum: Naming
- Topic: 7th edition 9C.3: Potassium Hexacyanidochromate (III)
- Replies: 2
- Views: 339
Re: 7th edition 9C.3: Potassium Hexacyanidochromate (III)
Yes, since K has a charge of 1+ it would cancel out the 3- if there was three K
- Thu Nov 29, 2018 12:41 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Wednesday Lecture Notes
- Replies: 3
- Views: 415
Re: Wednesday Lecture Notes
i wasn't able to copy everything down, and Professor Lavelle didn't have any important announcements. naming coordination compounds (greek prefix) ligand names alphabetical order then tm (transition metal) cation name (roman numeral) if there are anions, then anion name (greek prefix) hydrate [Co(NH...
- Thu Nov 29, 2018 12:25 pm
- Forum: Dipole Moments
- Topic: 7th Edition 3F.1
- Replies: 1
- Views: 345
Re: 7th Edition 3F.1
a) Hydrogen since there's H & N atoms, dipole-dipole since there's dipole moments all around, and london forces since all molecules have london forces b) london, no dipole since the Br atoms cancel the dipole moments because of the symmetry c) london, hydrogen since theres H & O atoms, dipol...
- Thu Nov 29, 2018 12:14 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: VSEPR Formula: Central Atom
- Replies: 4
- Views: 446
VSEPR Formula: Central Atom
Can you have more than one central atom for the VSEPR formula? Such as A2? If so, why is I3- not A3 or AX2 but X3 instead?
- Sun Nov 25, 2018 11:27 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Naming Shapes
- Replies: 5
- Views: 521
Naming Shapes
Hello! For the exam and tests, is it better to straight up memorize the shape names or is there easy way to derive the names from the number of lone pairs and bonds?
- Sun Nov 25, 2018 11:20 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: pi-bonds
- Replies: 7
- Views: 679
Re: pi-bonds
When there is more than a single bond.
- Sun Nov 25, 2018 11:18 pm
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: Polarizability
- Replies: 3
- Views: 569
Re: Polarizability
I think that when ions have the same number of electrons, you go with the atom that has the largest atomic radius as the atom with the lowest polarizability.
- Wed Nov 07, 2018 11:17 pm
- Forum: Dipole Moments
- Topic: Dipole-Dipole vs Induced Dipole
- Replies: 5
- Views: 1080
Dipole-Dipole vs Induced Dipole
Hello, I was wondering what the difference between a "dipole-dipole" versus "dipole induced dipole" interaction was. Thank you!
- Wed Nov 07, 2018 11:13 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Wednesday 11/07/2018 lecture notes
- Replies: 1
- Views: 216
Re: Wednesday 11/07/2018 lecture notes
these are some of the notes i took down! from last chapter strengths & lengths of bonds weak (longer) bonds easily broken & more likely involved in reaction strong (shorter) bonds, harder to break & less reactive strength of a bond is measured by its DISSOCIATION ENERGY (ENERGY REQUIRED ...
- Wed Nov 07, 2018 11:06 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Electron density fluctuation
- Replies: 1
- Views: 292
Re: Electron density fluctuation
I'm assuming that because the fluctuation is so quick, the electrons are virtually everywhere at the same time and polarizing every atom. In other words, it does not matter if electron density only momentarily makes one side of the atom negative because those electrons will be back on that side in a...
- Sat Oct 27, 2018 1:54 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Ml Meaning
- Replies: 3
- Views: 2659
Ml Meaning
I understand that n corresponds to the shell and l is the type of orbital but what does ml correspond to? Is this something we will need to know? Thank you!
- Sat Oct 27, 2018 1:48 pm
- Forum: Trends in The Periodic Table
- Topic: Atomic Radius
- Replies: 7
- Views: 724
Re: Atomic Radius
There is less electrons to share the nucleus's positive charge once one of the electrons is removed, so the remaining ones have to take on more attraction to the nucleus .
- Sat Oct 27, 2018 1:44 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Effective Nuclear Charge vs. the Energy of a Shell
- Replies: 1
- Views: 192
Re: Effective Nuclear Charge vs. the Energy of a Shell
I think they have somewhat of a proportionate relationship. The higher n is, the lower the effective energy. Of course it also depends on how filled the last shell is and how many shells in total the atom has.
- Sun Oct 21, 2018 5:10 pm
- Forum: *Black Body Radiation
- Topic: Intensity of radiation
- Replies: 3
- Views: 727
Re: Intensity of radiation
It's related to the quantity of electrons, not the wavelength or frequency.
- Sun Oct 21, 2018 5:08 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Labeling Electron Orbitals
- Replies: 5
- Views: 813
Labeling Electron Orbitals
On Friday we went over the different labels to specify an electron (shell, subshell, max electrons, orientation, etc.) but I still cannot understand how you derive all of them, especially the orientation/spin. How can you tell what shell an electron is in or what spin it has? Thank you!
- Sun Oct 21, 2018 5:01 pm
- Forum: Trends in The Periodic Table
- Topic: Oxygen
- Replies: 1
- Views: 246
Re: Oxygen
The right side of the Periodic table doesn't have fixed signs on the charges of the elements, it's a case by case basis.
- Thu Oct 11, 2018 3:22 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Rydberg's Equation (hydrogen)
- Replies: 2
- Views: 220
Re: Rydberg's Equation (hydrogen)
En = - hR/n^2 is a simplified version that measures the lost energy of an electron. If you're trying to calculate the energy loss of a level, you need to know the frequency and level to solve it.
- Thu Oct 11, 2018 3:17 pm
- Forum: Photoelectric Effect
- Topic: φ
- Replies: 1
- Views: 239
Re: φ
I don't think we need to go over the symbol phi for this class. It has to do with organic chemistry and I believe it represents a group of atoms.
- Thu Oct 11, 2018 3:13 pm
- Forum: Properties of Electrons
- Topic: Explaining Millikan's Experiment
- Replies: 2
- Views: 343
Re: Explaining Millikan's Experiment
I believe he just choose that number because it was convenient. E is just a unit like moles that helps measure electric charge.
- Thu Oct 04, 2018 12:05 pm
- Forum: SI Units, Unit Conversions
- Topic: Homework Question Edition 6 E1
- Replies: 4
- Views: 459
Re: Homework Question Edition 6 E1
I assume it was just to underscore the large number, but I don't think there would be any problem if you answered in meters in a question like this for a quiz or test. I think meters is always the safest bet.
- Thu Oct 04, 2018 11:55 am
- Forum: Limiting Reactant Calculations
- Topic: Fundamentals 7th Edition M1
- Replies: 2
- Views: 517
Fundamentals 7th Edition M1
The problem asks Hydrazine, N 2 H 4, is an oily liquid used as a rocket fuel. It can be prepared in water by oxidizing ammonia with hypochlorite ions: 2 NH3(g) + ClO (aq) = N2H4(aq) + Cl (aq) + H2O(l). When 35.0 g of ammonia reacted with an excess of hypochlorite ion, 25.2 g of hydrazine was produce...
- Thu Oct 04, 2018 11:43 am
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Problem F.7
- Replies: 4
- Views: 1542
Re: HW Problem F.7
For a, you would first need to find the molar mass of two oxygen atoms. It is given that the metal M is 88.8% of the compound, so O2 must be the rest. I think next you can divide percentage of O2 (as a decimal, e.g. 20% would be .20) by its own molar mass, and finally multiply the number by 100 to f...