CHEMISTRY COMMUNITY

Nicklas_Wright_1A

A straight line for ln(A) means the reaction is first order. For 1/A it means the reaction is second order. For A it means the reaction is zero order.

Nicklas_Wright_1A

If you use the equation you should get the right answer. I recommend rechecking your math as you probably put a decimal point in the wrong place.

Nicklas_Wright_1A

I don't think we will need to do that on the final exam.

Nicklas_Wright_1A

You can analyze the graph of the reaction or add the exponents of the rate law.

Nicklas_Wright_1A

The calculations are very different for different order reactions.

Nicklas_Wright_1A

I think the drop in sessions are the best because you can come and go as you please.

Nicklas_Wright_1A

You have to write the redox half reactions to determine the number of moles of electrons transferred.

Nicklas_Wright_1A

A negative voltage is possible, but it means the reaction will not be spontaneous.

Nicklas_Wright_1A

Charging a battery requires supplying it with energy.

Nicklas_Wright_1A

Mn does not always have an oxidation state of 7+. That was only true for that particular example.

Nicklas_Wright_1A

I believe they are tested against hydrogen, as it is impossible to test only one element at a time. Hydrogen is considered to have a potential of 0.

Nicklas_Wright_1A

It allows ions to flow from one vessel to the other. It only allows certain ions to pass through and not others.

Nicklas_Wright_1A

You need to know the Lewis structure. Otherwise, you won't know how many bonds of each type there are.

Nicklas_Wright_1A

It would affect the calculations though.

Nicklas_Wright_1A

It can also be a good idea to practice doing math problems slowly and methodically. If you make one mistake on the wrong question, it can cost you severely.

Nicklas_Wright_1A

Solids and liquids have a constant volume. Also, pressure is really only used to describe gasses.

Nicklas_Wright_1A

Gibbs free energy is not going to be on the midterm.

Nicklas_Wright_1A

The pressure of a normal calorimeter is always constant since it is open to the air.

Nicklas_Wright_1A

You can do that if you want. Just make sure to add the right reactions. Sometimes a question will give you delta H for the reverse reaction instead and you will need to account for that.

Nicklas_Wright_1A

Standard enthalpy of formation is the enthalpy used to create a compound from its elemental components. Since the elemental components are already in the elemental form, it does not take any enthalpy to create them from the elemental form.

Nicklas_Wright_1A

Yes, enthalpy is the heat energy plus the work used to expand. The energy needed for the reaction to occur is the activation energy.

Nicklas_Wright_1A

You could also increase the pressure.

Nicklas_Wright_1A

You also have to calculate K using the equilibrium pressures.

Nicklas_Wright_1A

That is a diprotic acid, meaning it can give off 2 protons per formula unit. The first ionization is when the first proton comes off and the second ionization is when the second one comes off. The acid is strong at first, but when it releases the first proton it becomes HSo4 which is a weak acid. Th...

Nicklas_Wright_1A

It does not matter.

Nicklas_Wright_1A

You can think of the solid ad liquid concentrations as being factored out and included in K.

Nicklas_Wright_1A

The reaction quotient is calculated the same way as the equilibrium constant. If the reaction is at equilibrium, it is called K and if the reaction is not at equilibrium yet, it is called Q.

Nicklas_Wright_1A

In addition, the reaction rate will increase.

Nicklas_Wright_1A

It looks to me like the total pressure is about 30, but the question is not asking for the total pressure anyway.

Nicklas_Wright_1A

Use equilibrium concentrations to calculate K. Use initial concentrations to calculate Q.

Nicklas_Wright_1A

I think it is probably possible for a carboxylic acid to be polyprotic. I don't see any reason why not.

Nicklas_Wright_1A

The first proton is released most easily. Successive protons are less likely to dissociate.

Nicklas_Wright_1A

(HSO₄)^-1

Nicklas_Wright_1A

Pi bonds do not involve hybridization.

Nicklas_Wright_1A

I'm not sure what that denotation is saying. Maybe try double checking what it says in the textbook in case you were reading it wrong.

Nicklas_Wright_1A

It needs to maintain a unhybridized orbital so that it can form a double bond.

Nicklas_Wright_1A

A test would usually tell you to either draw all resonance structures or just one of the resonance structures.

Nicklas_Wright_1A

I think that it would have some effect, but it probably isn't something that will make a difference in this class.

Nicklas_Wright_1A

The bonds are all the same. They are just being shown in 3D. The dashed bond is going into the page and the conical shaped bond is coming out of the page.

Nicklas_Wright_1A

Yes, they both work and I think your formula is much easier to remember and use.

Nicklas_Wright_1A

There are also many metals which are exceptions such as lead.

Nicklas_Wright_1A

Sigma bonds are used for single bonds and pi bonds are used for everything else. However, double and triple bonds still have one sigma bond and the rest are pi bonds.

Nicklas_Wright_1A

Bonds with a higher bond order are shorter than bonds with a lower bond order. Bond strength has to do with bond enthalpy, which we haven't learned yet. It is not necessarily related directly to bond order.

Nicklas_Wright_1A

I think it depends on the family. For alkali metals, what you are saying is true, but for halogens, which form anions, it is not true.

Nicklas_Wright_1A

I don't believe this was covered in lecture. Usually, if you try to make a lewis structure and are struggling, there might be a dative or coordinate bond.

Nicklas_Wright_1A

Glycine is a single molecule, but ammonium sulfate is an ionic compound comprised of two polyatomic ions.

Nicklas_Wright_1A

Nitrogen, Boron, and Beryllium are exceptions. They can have less than 8 valence electrons.

Nicklas_Wright_1A

The four H atoms are on the outside of N and since N has five valence electrons, there will be a bond connecting the two NH4 structures with the SO4 This is absolutely false. The nitrogen atom will make four bonds, one with each hydrogen. The fifth valence electron is lost because of the positive c...

Nicklas_Wright_1A

Probably not, but there will always be some basic things that you have to know, like what a mole is and stuff like that.

Nicklas_Wright_1A

I would definitely read the F section. I would not be surprised to see Lavelle test us on something we haven't gone over.

Nicklas_Wright_1A

I think the solutions manual may be wrong. That doesn't sound right to me at all.

Nicklas_Wright_1A

Everything said in the previous reply is true except the magnetic quantum number actually has different ranges for each value of the principle quantum number.
n=0 - ml=0
n=1 - ml=-1,0,1
n=2 - ml=-2,-1,0,1,2
n=3 - ml=-3,-2,-1,0,1,2,3

Nicklas_Wright_1A

The principal quantum levels of a Hydrogen atom correspond to different values of the principal quantum number n. Electrons with higher energy are found on higher energy levels.

Nicklas_Wright_1A

How many of which quantum number? If you are talking about the magnetic quantum number, then only 0-4 are possible.

Nicklas_Wright_1A

I think you just need to know the order of the types of radiation and maybe the numbers for only the main ones like visible light, infrared, and ultraviolet.

Nicklas_Wright_1A

They are the exact same thing.

Nicklas_Wright_1A

Try to think of light as being either a wave or a particle instead of both at the same time. In some instances it acts like one and other times it acts like the other. For each circumstance, find out which one it is acting like and treat it that way for the rest of the problem.

Nicklas_Wright_1A

A mole is just like a dozen, but instead of signifying 12 of something, it signifies 6.022x10^23. The reason that this number is used is because 6.022x10^23 amu is equal to 1 gram. This helps make calculations simpler.

Nicklas_Wright_1A

You must keep track of significant figures throughout your calculations, however you should not round until the end. If you need to, you can write down how many significant figures each number has as you go through each step, just remember to keep the numbers unrounded. Pay particular attention to l...

Nicklas_Wright_1A

If 5 grams of reactant A react with 7 grams of reactant B, 12 grams of product must be produced because mass is conserved.

Search found 60 matches