CHEMISTRY COMMUNITY

Javier_Ochoa_DIS_3J

Bronsted acids just proton donators. It does not matter the atoms as long as it fulfills this definition.

Javier_Ochoa_DIS_3J

The longer the bond the more stable the acid is. The resulting conjugate base does not want to attract the H after disassociating.

Javier_Ochoa_DIS_3J

There are two definition you can use for acid and bases.
The Bronsted definition deals with the transfer of protons and the Lewis definition deals with the transfer of electrons.

Javier_Ochoa_DIS_3J

Ground state electron configuration starts from the beginning 1s2.

Javier_Ochoa_DIS_3J

I felt all the workshops I have been too were super helpful. You can't go wrong with Karen Leung though.

Javier_Ochoa_DIS_3J

I don't know about the globe but I found some in formation about Acid Rain in the US https://water.usgs.gov/edu/acidrain.html It states that acid rain is usually a pH of 5.0-5.5 It also states that in the Northeast there can be rain with the pH of 4.0 I assume that in many places around the globe th...

Javier_Ochoa_DIS_3J

single, double, and triple bonds are all the same when using the VSEPR model.

Javier_Ochoa_DIS_3J

I believe if it's fully symmetric than it would have to be non-polar considering an equal force on all sides. I am sure there are exceptions but I doubt we have to know them now.

Javier_Ochoa_DIS_3J

Electron Geometry is what the shape is considering all the regions of e- density including lone pairs and connected atoms to the center element. Molecular geometry is the shape considering only the connected atoms but while still using the electron repulsion of the lone pairs. In case my wording is ...

Javier_Ochoa_DIS_3J

Another easy way to memorize VSPER shapes is to memorize which ones correspond to which VSPER formula.

Javier_Ochoa_DIS_3J

Here is an example to help.

The formula is all about what is connected to the center atom. The number after X means the number elements attached to the center element. E represents the number of electron lone pairs attached to the center element.

I hope that helped a little.

Javier_Ochoa_DIS_3J

Single, double, and triple bonds are all the same when it comes to the molecular shape.

Javier_Ochoa_DIS_3J

It is slightly less at 106 because the lone pair attached to the center atom has a stronger repulsion force than if it was another element.

So usually we would expect 109.5 degrees but since we know a lone pair pushes the atoms slightly harder we know the angle is going to be a little smaller.

Javier_Ochoa_DIS_3J

I assume that if we are expected to memorize the angles it would be the most commons ones.

Javier_Ochoa_DIS_3J

A lewis Acids accepts electrons.

Javier_Ochoa_DIS_3J

Lewis bases give electrons and Lewis acids receive electrons.

Javier_Ochoa_DIS_3J

Will someone explain 8b? I know that we need to use all of the information given in the question but I am not sure how wavelength corresponds to work functions. Thank you! So the main equation you need is Eph = (work function of metal) - Ek (energy of electron ejected) This is not correct. See post...

Javier_Ochoa_DIS_3J

Any element below N=3 can have an expanded octet.

Javier_Ochoa_DIS_3J

This is the equation to find the formal charge.

Valance electrons - (lone pair electrons + number of bonds) = Formal charge.

Javier_Ochoa_DIS_3J

Any element in the 13th column does not need to have a full octet. This would include B, Al, Ga, In, Ti, and Nh.

However they are allowed to have 8 if the compound needs it.

Javier_Ochoa_DIS_3J

A quick and easy way to find out how many valance electrons an element has is to count left to right across periods for the S orbital and the P orbital. For example H would have 1 valance electron, Be would have 2, B would have 3, and C would have 4. This would make the noble gases have 8 valence el...

Javier_Ochoa_DIS_3J

Anything below 10^-18 m is too small to measure.

However professor said that he will give either numbers that are super small or super big compared to 10^-18.

Javier_Ochoa_DIS_3J

1 joule = 1.60218e-19 Ev

It is given on the equation sheet in front of every test near the bottom.

Javier_Ochoa_DIS_3J

Make sure the use parentheses around your numbers.

For example instead of doing 9 x 10^3 times 3 x 10^2

You should input the numbers like this (9 x 10^3) times (3 x 10^2)

It is important when dividing and doing things other than just multiplying.

Javier_Ochoa_DIS_3J

I don't believe there is a set date on the syllabus but I'd recommend getting it done by Sunday of that week?.

Javier_Ochoa_DIS_3J

The equations can be found here.

https://lavelle.chem.ucla.edu/wp-conten ... ations.pdf

Javier_Ochoa_DIS_3J

The above poster is correct.

The equation you are looking for is E = hc/λ

λ = wave length
E = energy
h = Planck constant
c = speed of light

H and C will be provided in the information sheet in the test.

Javier_Ochoa_DIS_3J

Hello, The way I understood it is that the reason this is true is because of how your TA stated when they said "by the time we calculate momentum, the object's position has already changed". What I took away from why this is, is because the more you investigate the position, the less you c...

Javier_Ochoa_DIS_3J

I'd also recommend putting the units as if it comes to partial credit for a question it might help who ever is grading it see what and where you went wrong. It could possibly improve your chances of getting more credit for a problem that would not have gotten it otherwise.

Javier_Ochoa_DIS_3J

I see that your question has been pretty much answered but I'd recommend using the limiting rule of on no more than .1 to check your work. If it takes you more than a few calculation to get to a whole number of moles it is clear something went wrong. I tend to make a lot of little mistakes so it hel...

Javier_Ochoa_DIS_3J

This is perfect! I've been looking for more practice problems. Looking forward to the workshop.

Javier_Ochoa_DIS_3J

Formula units is the atoms I believe. First you have to get the moles of the element(s), To get this you have to use the given grams and divide it by the total molar mass found on the periodic table. You would multiply the moles with 6.0221409e+23 (Avogadro constant) to find out how many atoms or fo...

Javier_Ochoa_DIS_3J

I believe the text book is covering the rounding that is used in banking and possibly in chem labs, it makes the numbers more easier to work with.

You should keep rounding the way you have been taught.

CHEMISTRY COMMUNITY

Search found 33 matches

Re: Bronsted Acids

Re: acidity

Re: Identifying the difference

Re: Bromine Electron Configuration

Re: Final Review

Re: Acid Rain

Re: double and triple bonds

Re: polarity

Re: vsepr model

Re: Memorizing the VSPER Models

Re: Vespr Formula

Re: Double Bonds in VSEPR

Re: Sulfite Ion?

Re: Bond Angles

Re: Determine Lewis Acid

Re: Acid vs base [ENDORSED]

Re: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]

Re: Expanded octets

Re: Lewis Structures- formal charge

Re: Lewis Structures

Re: Valence Electrons

Re: measuring wavelength

Re: The Uncertainty Principle

Re: Power calculations

Re: Chem Community Due Date

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Re: energy equation

Re: Clarification on Heisenberg Equation

Re: Units

Re: Rounding for limiting reactants

Re: DOWNLOAD SESSION WORKSHEETS HERE - Sundays 4-6pm (Karen) [ENDORSED]

Re: Formula Units?

Re: Rounding numbers ending in 5