CHEMISTRY COMMUNITY

Pritish Patil 1K

Rusting is spontaneous because it happens naturally over a long period of time.

Pritish Patil 1K

One would choose the largest reducing agent and the largest oxidizing agent.

Pritish Patil 1K

One can cancel out the waters or simply add the proper amount in the beginning.

Pritish Patil 1K

Yes, it must be for a balanced redox reaction.

Pritish Patil 1K

They both mean the same thing.

Pritish Patil 1K

The amount of energy would be the same as it is an isolated system.

Pritish Patil 1K

Adiabatic= no heat transfer (q=0)
Isothermal= no change in temperature (deltaT=0)

Pritish Patil 1K

Yes, different types of systems affect temperature and volume.

Pritish Patil 1K

You can tell when work is being done and the volume of the system is changing.

Pritish Patil 1K

There is no work done as there is no change in volume.

Pritish Patil 1K

There are charts on the internet that simplify which equation to use for a certain situation (ex: isobaric, isothermal, etc). Hope this helped!

Pritish Patil 1K

There will be a slight difference but nothing significant enough to warrant taking points off if work is done correctly.

Pritish Patil 1K

Because if delta S is small enough (negative enough = large negative number), then even if the reaction was slightly exothermic (delta H < 0), then delta G could be greater than 0, making it nonspontaneous.

Pritish Patil 1K

I'm not completely sure. But I assumed that because it is precipitation, the water is going from liquid to solid state. Because the freezing point of liquid water was 0 degrees C, I assumed that the precipitation would be spontaneous as the surrounding temperature was -10 degrees C, which is less th...

Pritish Patil 1K

Work greater than 0 means work is done on the system; work less than 0 means that work is done on the surroundings. deltaH greater than 0 means heat is flowing in the system and deltaH less than 0 means that heat is flowing out of the system (assuming constant pressure).

Pritish Patil 1K

Rotational energy is around an axis while vibrational is simply moving back and forth on one axis.

Pritish Patil 1K

When volume is constant, work = 0 J. This means that deltaU = q.

Pritish Patil 1K

4.18J is the specific heat capacity of water while 0.38J is the specific heat capacity of copper.

Pritish Patil 1K

It is given on the constants and equations sheet on all of our exams and tests.

Pritish Patil 1K

Yes, it is significant as many thermochemistry questions are based on this graph (ex: amt of energy needed from temp1 phase 1 to temp 2 phase 2). It is important to know this.

Pritish Patil 1K

Steam has more heat energy (q), causing a worse burn. This is because it takes a certain amount of energy to execute the phase change from boiling water to steam, in which the temperature of the substance does not change, only heat energy q.

Pritish Patil 1K

Only liquids and solids are not included in the equilibrium expression. Aqueous and gas phase molecules are included.

Pritish Patil 1K

E stands for the equilibrium concentration of the reactants and products.

Pritish Patil 1K

I read the textbook to understand the content in relation to the homework problems. However, if I don't understand something I go and watch a youtube video or something similar to help me understand.

Pritish Patil 1K

If a reaction is endothermic, then increasing the temperature will shift the reaction to the right and decreasing the temperature will shift the reaction to the left. If a reaction is exothermic, then decreasing the temperature will shift the reaction to the right and increasing the temperature will...

Pritish Patil 1K

If the change based on the approximation is less than 5% then an approximation can be made. Normally, this works for k values that are less than 10^-3.

Pritish Patil 1K

Most of the questions we will receive assume that the gas is an ideal gas. It will explicitly tell us.

Pritish Patil 1K

K does not have units, which is why points were probably taken off for writing bar after k. The units should cancel each other out as well.

Pritish Patil 1K

When the k value is less than 10^-3

Pritish Patil 1K

Q is the concentrations of the products over the reactants when the equation is not at equilibrium; K is the concentration of the products over the reactants when the equation is at equilibrium.

Pritish Patil 1K

Use water as another product and fill in the reactants.

Pritish Patil 1K

I would memorize for the final exam.

Pritish Patil 1K

Add up the charges of the ligands and the transition metal.

Pritish Patil 1K

Whichever atom has a higher atomic radius means that there will be a longer bond, therefore a stronger acid because more H+ can disassociate easier.

Pritish Patil 1K

The seven main ones you should memorize for the exam are:
HS04
HNO3
HClO4
HClO3
HBr
HI
HCl

Pritish Patil 1K

A neutral ligand has no effect on charge because it is neutral.

Pritish Patil 1K

Yes, they will be the same!

Pritish Patil 1K

I don't think we are required to draw the VSEPR model.

Pritish Patil 1K

It says on the website to know the End of Bonding 6th(3.12), 7th(2D) and all of Molecular Shape and Structure.

Pritish Patil 1K

I believe it would be the average of the two lengths.

Pritish Patil 1K

The test will be given in Week 9 discussions.

Pritish Patil 1K

Hydrogen bonding is stronger than most other IMF so it takes more energy to break.

Pritish Patil 1K

The trend follows that triple are are the shortest while single are the longest.

Pritish Patil 1K

We don't have to calculate them.

Pritish Patil 1K

I'm pretty sure dipole moments are only relevant in VSPER and not Lewis structures.

Pritish Patil 1K

The central atom would have the lowest ionization energy, which in this case is Oxygen.

Pritish Patil 1K

Compare the difference of electronegativity between the two atoms to determine what type and how strong the bond is.

Pritish Patil 1K

Draw the all the resonance structures with a double-headed arrow in between.

Pritish Patil 1K

They are rare and we do not need to worry about it for this course.

Pritish Patil 1K

Elements usually abide by the octet rule or want a half octet.

Pritish Patil 1K

There is a release of energy when atoms bind together, resulting in less energy than single atoms.

Pritish Patil 1K

The correct answer is the photoelectric effect because it best supports the idea that electromagnetic radiation is like particles. This is because in the photoelectric effect the radiation consists of packets of energy (photons) with a fixed energy based on a multiple of h(planck's constant).

Pritish Patil 1K

Use the equation for the energy level of an H-atom. (1/lambda=R((1/n^2 (initial)-(1/n^2(final))). Since we have the frequency, the lambda can be calculated. As well plug in n=4 for the final energy level and solve for the initial energy level.

Pritish Patil 1K

Because the electrons that are in the orbitals closer to the nucleus block the outer electrons, there is less "pull" toward the nucleus for the outer electrons and slight repulsion from inner electrons.

Pritish Patil 1K

I have not seen Dr. Lavelle introduce "f" yet so I would just stick with "v" (nu).

Pritish Patil 1K

The question is essentially asking if the wavelength of the ejected electron is too small to be detected. I'm pretty sure this means is it smaller than 10^-18 power.

Pritish Patil 1K

The trick is to first convert 2.5nm to 2.5x10^-9 meters (SI unit). Then plug into the rearranged equation of v=c/lambda to solve for the frequency.

Pritish Patil 1K

Instead of calculating both theoretical yields, one can use the mole ratios in the balanced chemical equation to determine which substance is the limiting reactant. Of course this may only be completed after the amount in moles for the substances are converted from grams or otherwise determined.

Pritish Patil 1K

In this case, the two zeros in the number would be considered significant because they are between two other significant figures. This results in the entire number in having a total of four significant figures.

Pritish Patil 1K

In the beginning you should convert the 1kg of CaCO3(s) to grams (1kg=1000g). Secondly, divide by the molar mass for CaCO3 in order to get the number of moles. Because the chemical equation is already balanced, simply look at the mole ratio between CaCO3 and see how many moles of the product will be...

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