Search found 31 matches
- Sat Dec 08, 2018 9:50 pm
- Forum: Naming
- Topic: Do we need to know the ligand (en)?
- Replies: 2
- Views: 386
Re: Do we need to know the ligand (en)?
I think knowing the name (ethylenediamine) is necessary, but not the formula.
- Sat Dec 08, 2018 9:40 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond angles
- Replies: 3
- Views: 401
Re: Bond angles
I believe writing 90 degrees would be sufficient.
- Sat Dec 08, 2018 8:29 pm
- Forum: Naming
- Topic: Shorthands
- Replies: 2
- Views: 349
Shorthands
When writing out the full name for coordinate compounds which include a ligand such as ethylenediamine (en), can we still use the shorthand or do we have to remember the actual names?
- Wed Dec 05, 2018 12:12 am
- Forum: Bronsted Acids & Bases
- Topic: Memorizing Acid and Bases
- Replies: 2
- Views: 341
Re: Memorizing Acid and Bases
The most common ones are good to know, I think doing the homework will make it clear which ones come up the most.
- Wed Dec 05, 2018 12:11 am
- Forum: Naming
- Topic: 6th Edition 29c
- Replies: 3
- Views: 360
Re: 6th Edition 29c
Okay thank you!
- Mon Dec 03, 2018 7:30 pm
- Forum: Naming
- Topic: 6th Edition 29c
- Replies: 3
- Views: 360
6th Edition 29c
Hi, could someone explain why [Co(CN)5(OH2)]^2- has aqua in front of the rest of its name in the answer key?
- Tue Nov 27, 2018 10:59 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 3.39
- Replies: 2
- Views: 376
Re: 3.39
I believe when typically drawing lewis structures for ionic compounds, you include the ions in brackets to distinguish them from covalent compounds.
- Tue Nov 27, 2018 10:57 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: 4.17
- Replies: 3
- Views: 432
Re: 4.17
The formal charge is closer to 0 for the central oxygen atom when it has a lone pair and one double bond and one single bond.
- Tue Nov 27, 2018 10:54 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: 4.46
- Replies: 4
- Views: 577
Re: 4.46
I believe it's for the entire molecule.
- Mon Nov 19, 2018 11:15 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Help w/ 4.19 (6th edition)
- Replies: 2
- Views: 311
Help w/ 4.19 (6th edition)
For part b, I've been having difficulty with part b, which is the molecule (CH3)2Be. I understand the basic molecular shape and geometry, but I'm not sure I understand the Lewis structure. From what I've looked up, Be has single bonds with Carbon but no lone pairs. How is this possible if Be doesn't...
- Sun Nov 18, 2018 10:13 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Multiple different bond angles
- Replies: 6
- Views: 904
Re: Multiple different bond angles
whitneyh_4_4G wrote:If you click on this link you can download a software that shows molecules in 3D and you can move them around so you have a better idea of the shapes and angles! If that doesn't help you with remembering molecule bond angles for different shapes then I would just memorize them.
Wow! Thank you!
- Sun Nov 18, 2018 9:02 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Multiple different bond angles
- Replies: 6
- Views: 904
Re: Multiple different bond angles
TeCl4 has different bond angles because of its molecular geometry. It has seesaw geometry, since it has 4 single bonds and one lone pair. All seesaw geometries will have 90, 120, and 180 degree angles in their 3-D shape. If you look at a picture of "seesaw geometry" you can see each of th...
- Sun Nov 18, 2018 8:45 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Multiple different bond angles
- Replies: 6
- Views: 904
Multiple different bond angles
Why do some structures have bond angles of different degrees? For example, in my discussion section we used the example of TeCl4 as having angles of both 120 degrees and 90 degrees. Also, how do we determine when this is the case?
- Sun Nov 11, 2018 8:16 pm
- Forum: Electronegativity
- Topic: Help with 2.35 (6th edition)
- Replies: 1
- Views: 380
Help with 2.35 (6th edition)
Could someone explain how to approach 2.35?
Here is the text: 2.35 (a) Write an expression for the total coulombic potential energy for a lithium atom. (b) What does each individual term represent?
Here is the text: 2.35 (a) Write an expression for the total coulombic potential energy for a lithium atom. (b) What does each individual term represent?
- Fri Nov 09, 2018 2:05 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Naming the molecular shape
- Replies: 4
- Views: 583
Re: Naming the molecular shape
I think lone pairs matter when drawing the Lewis structure (since shape is based off of Lewis structure) but nomenclature is based off of number of bonds and angle. So you still have to be aware of the lone pairs, it's just not a necessity for the naming specifically.
- Sun Nov 04, 2018 7:56 pm
- Forum: Lewis Structures
- Topic: Double bonds vs. lone pairs
- Replies: 5
- Views: 3124
Double bonds vs. lone pairs
When drawing a Lewis dot structure, how do we know when to draw a molecule with double bonds or when to draw in lone pairs?
For example, CH2Cl2 has 20 valence electrons, but how do we know whether to draw Carbon and Chlorine with double bonds or to draw in lone pairs for chlorine?
For example, CH2Cl2 has 20 valence electrons, but how do we know whether to draw Carbon and Chlorine with double bonds or to draw in lone pairs for chlorine?
- Wed Oct 31, 2018 6:44 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Degeneration
- Replies: 3
- Views: 469
Re: Degeneration
Degenerate atomic orbitals are orbitals that have the same energy level.
- Wed Oct 31, 2018 6:41 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Test #2 Question #2
- Replies: 3
- Views: 789
Re: Midterm Question #2
So you would use the Heisenberg indeterminancy equation, which is (uncertainty in momentum) * (uncertainty in position) is greater than h/4pi. Momentum is mass times velocity so you would need to multiply its velocity (which is given) by it's weight (also given). Since the given velocity is in mph y...
- Wed Oct 31, 2018 6:36 pm
- Forum: *Shrodinger Equation
- Topic: Midterm
- Replies: 6
- Views: 1025
Re: Midterm
I think if there's a review session including it, it's fair game for the midterm. But it won't be a calculation question, it would probably be a conceptual question.
- Wed Oct 31, 2018 6:35 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Can someone explain Te2-?
- Replies: 2
- Views: 3318
Re: Can someone explain Te2-?
Thank you! My TA in discussion yesterday also confirmed this, so we know for sure it's true now.
- Tue Oct 30, 2018 9:30 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Can someone explain Te2-?
- Replies: 2
- Views: 3318
Can someone explain Te2-?
This is from homework problem 3.21 c from the 6th edition. The shorthand used for Te 2- is [Xe], which comes after tellurium in the periodic table. When does an ion use the noble gas that comes before in its electron configuration and when does it use the noble gas which comes afterwards? Sorry, I d...
- Mon Oct 22, 2018 8:49 pm
- Forum: DeBroglie Equation
- Topic: Can't quite get the answer right
- Replies: 2
- Views: 443
Re: Can't quite get the answer right
Ahh, yes, that's it. Thank you!
- Mon Oct 22, 2018 7:41 pm
- Forum: DeBroglie Equation
- Topic: Can't quite get the answer right
- Replies: 2
- Views: 443
Can't quite get the answer right
For question 1.39 in the 6th edition I've been having serious issues getting the correct answer while using De Broglie's Equation. The conversions I've been using is the given 1 ounce = 28.3 grams, 1609 meters = 1 mile and 60 sec = 1 hour. The answer supplied at the back of the textbook lists it as ...
- Mon Oct 22, 2018 6:47 pm
- Forum: Photoelectric Effect
- Topic: Help with 33 (6th edition) [ENDORSED]
- Replies: 3
- Views: 410
Re: Help with 33 (6th edition) [ENDORSED]
Thank you!
For part B (determining how much energy needed to remove electron from metal surface), would I use the equation Ek = .5 (Me)(Ve)^2?
For part B (determining how much energy needed to remove electron from metal surface), would I use the equation Ek = .5 (Me)(Ve)^2?
- Sun Oct 21, 2018 12:20 pm
- Forum: Photoelectric Effect
- Topic: Help with 33 (6th edition) [ENDORSED]
- Replies: 3
- Views: 410
Help with 33 (6th edition) [ENDORSED]
Could someone explain how to solve HW problem 33? In particular part A is causing me trouble.
Chemistry Community won't let me copy and paste the text of a question but it essentially asks to find the wavelength of an emitted electron with a velocity of 3600 kilometers per second.
Chemistry Community won't let me copy and paste the text of a question but it essentially asks to find the wavelength of an emitted electron with a velocity of 3600 kilometers per second.
- Fri Oct 12, 2018 6:05 pm
- Forum: Photoelectric Effect
- Topic: Photoelectric Effect
- Replies: 2
- Views: 300
Re: Photoelectric Effect
I think the maximum would be 1 million electrons, because there is a 1:1 ratio of photons to electrons in terms of energy. Each photon has enough energy to eject one electron and no more.
- Fri Oct 12, 2018 5:56 pm
- Forum: Properties of Light
- Topic: Electromagnetic Spectrum: Colors
- Replies: 3
- Views: 290
Re: Electromagnetic Spectrum: Colors
I'm not completely sure how scientists would officially classify it, but I believe that each human sees light slightly differently depending on their biology. The exact wavelength range for each color is an approximate because some people (and languages!) define the threshold between color in differ...
- Thu Oct 11, 2018 9:57 pm
- Forum: Properties of Light
- Topic: Explaining answer for 1.3
- Replies: 4
- Views: 394
Explaining answer for 1.3
Hi, I'm curious about the reasoning for the answer to question 1.3 (6th edition). The question is "Which of the following happens when the frequency of electromagnetic radiation decreases? Explain your reasoning." I understand why most of the scenarios don't happen, except c) "The ext...
- Thu Oct 04, 2018 11:47 pm
- Forum: SI Units, Unit Conversions
- Topic: 6th Edition E27, First Part
- Replies: 5
- Views: 480
Re: 6th Edition E27, First Part
You divide 1 H2O molecule by Avogadro's constant (6.02 * 10^23) to convert to moles, then multiple by molar mass to convert to grams.
- Thu Oct 04, 2018 11:44 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: (Typo??) HW L.35 - 7th edition
- Replies: 3
- Views: 432
Re: (Typo??) HW L.35 - 7th edition
I have the 6th edition and it's Fe3Br8 for me. It's probably a typo.
- Mon Oct 01, 2018 4:48 pm
- Forum: Balancing Chemical Reactions
- Topic: Need help w/ determining the moles of gas produced
- Replies: 2
- Views: 202
Need help w/ determining the moles of gas produced
Could someone explain how to find the net number of moles of gas produced for number 19 on the second review module? It involves the combustion of 4 moles of butane (C4H10) gas. I understand how to balance the equation but I'm unsure how to determine the net number of moles of gas produced. The poss...