CHEMISTRY COMMUNITY

daniela3D

It is meant to predict geometry of a molecule based on lone pairs and attached atoms. In order to solve the formula learn how to identify the bonding electron pairs and lone pairs.

daniela3D

Lewis Acid: takes a pair of electrons from another atom
*reasoning 1.) has an incomplete octet 2.) has a double/triple bond
Lewis Base: gives off a pair of electrons to another atom
*can donate to another lone pair

daniela3D

It's going to be cumulative with 8 questions but each question will have many parts to it like (a) (b) (c)

daniela3D

Yes. De Broglie focuses on calculating the wavelength of an object of mass.
When solving wavelengths use: wavelength= h/mv

When solving wavelength of a light or photon use: (E=hv; c=wavelength*frequency; E=hc/wavelength)

daniela3D

The photoelectric effect is a metal surface that emits electrons when light is shun upon it. In order to solve a problem like this you can use the equation: Ephoton- Work Function= Ekinetic . Work Function= property of the metal surface Ephoton: if not given use equations (E=hv; c=wavelength*frequen...

daniela3D

I actually had this problem too. For instance: if you have a problem in which you are dividing make sure to solve one portion(bottom or top) instead of doing it all at once. Also, if you are dealing with problems that have the power of 10^3 there's a symbol on your calculator that has (EE which repr...

daniela3D

When you see a number that has +- next to it you have to multiply by 2. Hence, 2(5) is the reasoning you acquire 10.

daniela3D

It is a bond with other metallic elements that share electrons causing them to be positively charged.

daniela3D

Dr.Lavelle said that Chemistry Community is meant to be a resource for students if they had questions. So if it is a question about the lessons or anything related to his class it is a valid question. All you have to do is post 3 times a week to get some easy points. So the post you made is complete...

daniela3D

If you are trying to calculate the wavelength of a wave of light (i.e. photon) use the 3 Light Equations: E=hv ; c=h[lambda] ; E=hc/[lambda].
But when dealing with moving objects such as cars or balls you use lambda=h/mv.

daniela3D

I don't think that's how it works. You need to find the weight of each reactant separately and compare which one weighs less. The one that weighs less is your limiting reactant.

daniela3D

Correct! Each time you see +/-, multiply the number given by 2.

daniela3D

He'll most likely provide have that info in the first page of our quizzes/tests. But it's always good to go over it.

daniela3D

The person I have my Peer Learning Sessions with said that most of the time the problems will tell you when to use it. However to identify it, it will ask you for the wavelength of something or the energy emitted as a result to the speed of wavelength (basically anything being questioned wavelengths).

daniela3D

In the lecture about "Wave Properties of Light" frequency and velocity are technically the same. However, their symbols differ from each other: frequency (s^-1)= velocity (m.s^-1)

daniela3D

In the lecture about "Wave Properties of Light" frequency and velocity are technically the same. However, their symbols differ from each other: frequency (s^-1)= velocity (m.s^-1)

daniela3D

Keep in mind that a photon is always positive.

daniela3D

I currently enrolled myself to my Peer Learning Session (PLS) for Chem 14A through AAP and it is very helpful! It is a small group of people with an instructor who has already taken the course who goes over what Lavelle has taught in class and provides work problems to work with.

daniela3D

The video modules he has posted on his websites are very helpful. For this question he explains why there has to be a whole number for the empirical formula and if you multiply one number you have to do the same to the rest. Highly recommend if you have not checked it out.

CHEMISTRY COMMUNITY

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