CHEMISTRY COMMUNITY

AvaGordon_4F

I don't think we are responsible for that distinction, at least for this class! 14B tho...

AvaGordon_4F

Its because of the way the chlorines are oriented! They are able to bind to two relatively close guanines on DNA and bind at TWO sites, which blocks dna replication mechanisms. Transplatin isn't able to complex twice and so the one bond it makes is not enough to block replication

AvaGordon_4F

Thank you so much for everything!! These worksheets were a life saver

AvaGordon_4F

Yeah I'm also confused about this...

AvaGordon_4F

I think we'll be covering that next class! My TA said in OH that its a detailed calculation but we'll do it step by step and it's more or less straight forward.

AvaGordon_4F

Im not positive but I think we would have to either have a picture or be told.

AvaGordon_4F

Yeah, like people are saying, one bond with DNA is not enough to block the DNA replication machinery. If its a trans molecule, there would only be one bond available to be made. In a cis molecule, two bonds are available to be made, and so those two bonds are what is necessary to disrupt DNA replica...

AvaGordon_4F

So covalent character is between atoms closer together on the table (that are most willing to SHARE their electron), whereas ionic character is between elements further apart (that are more willing to entirely donate their electrons). Between O and S, which are in the same group, but different perio...

AvaGordon_4F

Yeah, so pi bonds don't allow any rotation at all. An easy way to visualize this is to think of how sigma bonds are arranged tip to tip, so theres only one area of overlap between them (so they can rotate) but pi bonds are arranged side to side, so there are two areas of overlap between them. If a p...

AvaGordon_4F

Yes, to the best of my understanding, this unhybridized p orbital does contain electrons, they're just not involved in the hybridization bonding. They're the ones that are involved in double and triple bonding!

AvaGordon_4F

So interesting! Thanks

AvaGordon_4F

Well I think one of the main things is that one involves only 3 atoms, whereas the other involves 4. So the overall molecular shape will be different because of the 3 bonding pairs vs 4 bonding pairs

AvaGordon_4F

Yeah for sure! My email is avagordon93@gmail.com

AvaGordon_4F

Distortion in a tetrahedral molecule can also be due to the size of the atoms involved in the bonding interactions. If all of the surrounding atoms are the same element, then the bond angles will all be the same because the bonded atoms will all have the same atomic radius. If they're different, the...

AvaGordon_4F

I'd be very interested!

AvaGordon_4F

I think it's related to their shape

AvaGordon_4F

De Broglie basically was saying that all objects in our world have a wavelength, but that the more massive the object, the smaller the wavelength. Essentially we can only observe the wavelengths of an object when it's tiny enough (ie an electron or atom). So when we're talking about a baseball and w...

AvaGordon_4F

I went to dr. lavelle's OH to ask him about that a week or so ago and he mentioned that it was more a conceptual thing we need to know, in terms of shielding etc, but tbh for the midterm I'm not sure. Don't want to give u a wrong answer.

AvaGordon_4F

I had a differently worded question but I also think what they're asking for in your case was for you to say that energy levels are quantized in the atom. Meaning that the energy (and therefore frequency) of light that is emitted corresponds to the specific amounts of energy necessary to move an ato...

AvaGordon_4F

I am also confused about this. When the single electron in an H atom is excited up to, say, 5p, does it just bypass all the intermediate shells and subshells? Does it drop immediately down? Can it exist in that excited state for long? I'm just not sure I'm conceptualizing this properly...

AvaGordon_4F

Basically, Bohr frequency says that the frequency of the light emitted from any substance (visualized as a line on an emission spectroscopy) is directly related to the change in energy that it was responsible for enacting (ie a jump from n=2 --> n=1). So: frequency of emitted light = (deltaE)/planck...

AvaGordon_4F

Wasn't the whole thing about Heisenberg Indeterminacy the fact that at such a small level (the atomic level) our tools of measurement for position and momentum are not effective enough to not influence the measurements they take? Because I remember the professor (or maybe my TA) mentioning that its ...

AvaGordon_4F

I'm a little confused on #7 in the Quantum World Part 1 worksheet. I just can't seem to come up with (1/ni)=0.0278 and I'm not sure why. Could someone explain it to me possibly? I follow her formulas and rationale, I'm just not getting the right numbers...

AvaGordon_4F

I think I remember this... Do you mean the delta V answer we got from the problem we did in class? Because if so, that was a sample problem he did to show us that electrons could not be confined to the diameter of the nucleus. They have to exist outside of it. Because if we set our delta X value to ...

AvaGordon_4F

The photoelectric effect is the experiment that shows that light has particle qualities. They noticed that whether or not an electron was ejected from a metal had to do with the frequency of the light that was shone on it, not the intensity of that light. This showed that light was made of photons b...

AvaGordon_4F

From what I understand that's just the attraction between positive and negatively charged things.

AvaGordon_4F

Honestly not sure... Maybe email your TA? They're probably not going to provide calculators, so if they say you can't use yours that would be awful. Definitely borrow one to be safe.

AvaGordon_4F

You'll need to buy a scientific calculator for the midterm and final, I believe. On the syllabus it says that "only non-programmable, non-graphing calculators are allowed".

AvaGordon_4F

I also was wondering this. My TA said that we would not be expected to translate from written word --> formula but several UAs have said otherwise.

AvaGordon_4F

Hi! So I had the same question and my TA (Anton) said that whenever doing calculations using molar masses, it's best to uses the entire number, including all of the decimals listed. He said it's because depending on what calculations you're doing, it may impact your final answer, and you'll never be...

AvaGordon_4F

Does anyone know when (if?) the audio-visual focus topics are due? I switched into this class a few days ago and I'm a little confused. Thank you!!

AvaGordon_4F

If you'd like, Dr. Lavelle also put up a great resource that explains how to use Sig Figs. It's super comprehensive and it walks you through all the rules (even the weird ones, like the ones about zeros) kind of painlessly! I'll link it below! There is also another one that is more of a formula shee...

AvaGordon_4F

Not sure if anyone else has mentioned this but I've found that studying in groups is really a great way to get a better grasp on the material. Not only will you feel less alone while you're grappling with the new material, but its also an objective fact that teaching a concept to someone is the best...

AvaGordon_4F

I believe so, yes! You need to calculate mass percentage composition and get a percentage for every element involved, because that is the crucial information you need to do the rest of the problem. Once you have that, you can proceed with solving the rest (by assuming you have 100 g of the compound,...

CHEMISTRY COMMUNITY

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Re: tetrahedral or square planar?

Re: Cisplatin

Re: DOWNLOAD SESSION WORKSHEETS HERE - Sundays 4-6pm (Karen) [ENDORSED]

Re: Polydentate

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Re: Sick the last 2 weeks and need lecture notes

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Re: Chem Test 2, #5 b

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Re: DOWNLOAD SESSION WORKSHEETS HERE - Sundays 4-6pm (Karen) [ENDORSED]

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Re: Zeros in sig figs

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