Search found 36 matches
- Fri Nov 30, 2018 1:09 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: hydrogen atom in acid
- Replies: 2
- Views: 400
Re: hydrogen atom in acid
They loose H atoms more easily so that they can bind to other reactants when in a solution.
- Fri Nov 30, 2018 1:05 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: strong acids
- Replies: 4
- Views: 741
Re: strong acids
How do weak acids react in an aqueous solution?
- Fri Nov 30, 2018 12:59 pm
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: H+ Acidic and OH- Basic
- Replies: 4
- Views: 584
Re: H+ Acidic and OH- Basic
I believe that the idea of acids/bases is somewhat related to polar/nonpolar. Its just ideas and studies that have been conducted in order to better understand bow certain molecules interact in aqueous solutions. This will also help in labs!
Ah-hah!
Ah-hah!
- Sun Nov 25, 2018 4:59 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Test 3
- Replies: 38
- Views: 2498
Re: Test 3
Will we also need to know the degrees of the shapes?
- Sun Nov 25, 2018 4:58 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Shapes Not covered in Lecture
- Replies: 10
- Views: 1081
Re: Shapes Not covered in Lecture
can someone explain NO2 to me? I can think of multiple VSEPR shapes
- Sun Nov 25, 2018 4:57 pm
- Forum: Hybridization
- Topic: Hybridization
- Replies: 5
- Views: 525
Re: Hybridization
How many levels of hybridization will we need to know? sp3d2? more?
- Fri Nov 16, 2018 1:11 pm
- Forum: Lewis Structures
- Topic: Maximum amount of bonds
- Replies: 5
- Views: 606
Re: Maximum amount of bonds
Is it possible for an element in the 3s have more than an octet? this being sodium and magnesium. I am asking due to the fact that they do not have a 3d shell.
- Fri Nov 16, 2018 1:10 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Shortcut
- Replies: 4
- Views: 955
Re: Shortcut
for S/2, instead of counting how many electrons each bond has and dividing by two, you can just count how many lines (bonds) there are and not divide by anything. Just a quick tip to make your life easier. Ah-hah!
- Fri Nov 16, 2018 1:08 pm
- Forum: Student Social/Study Group
- Topic: Chemistry News
- Replies: 135
- Views: 163787
Re: Chemistry News
The kilogram is being redefined! https://youtu.be/c_e1wITe_ig
- Fri Nov 16, 2018 1:07 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Heisenberg and Wavelength
- Replies: 11
- Views: 1688
Re: Heisenberg and Wavelength
Hey guys, new interesting fact... the kilogram is being redefined! https://youtu.be/c_e1wITe_ig
- Fri Nov 09, 2018 1:08 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond Angles
- Replies: 13
- Views: 2289
Re: Bond Angles
What is the lowest degree that bonds can have in between each other? I know that electron repulsion leads to the largest possible degree of separation, but what could the lowest degree be?
- Fri Nov 09, 2018 1:05 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Trigonal Planar
- Replies: 8
- Views: 915
Re: Trigonal Planar
Does the Trigonal Planar structure means all the atoms are in the same plane? I'm kinda confused because Professor Lavelle added a 3-D structure of BF3. What is its actual structure? 2-D or 3-D? All molecules are 3D. He mentions lewis structure as 2D so that we get the idea on how to draw lewis str...
- Fri Nov 09, 2018 1:04 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Trigonal Planar
- Replies: 8
- Views: 915
Re: Trigonal Planar
What is the meaning of the solid line or the dotted line on Lewis Structures that are 3D?
- Sun Nov 04, 2018 4:37 pm
- Forum: Limiting Reactant Calculations
- Topic: Midterm Review Q2
- Replies: 8
- Views: 4315
Re: Midterm Review Q2
So to solve this problem you first have to write out the equation given in the problem then balance it, getting 4NH3+5O2=>4NO+6H2O. Then you take the grams of NH3 and O2 given and find the moles, multiply it by the mole ratio in the equation to get mols NO, then convert to grams. You find that O2 y...
- Sun Nov 04, 2018 4:24 pm
- Forum: Limiting Reactant Calculations
- Topic: Midterm Review Q2
- Replies: 8
- Views: 4315
Re: Midterm Review Q2
So to solve this problem you first have to write out the equation given in the problem then balance it, getting 4NH3+5O2=>4NO+6H2O. Then you take the grams of NH3 and O2 given and find the moles, multiply it by the mole ratio in the equation to get mols NO, then convert to grams. You find that O2 y...
- Sun Nov 04, 2018 1:11 pm
- Forum: Administrative Questions and Class Announcements
- Topic: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
- Replies: 121
- Views: 17213
Re: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
For #6, how are you supposed to convert the molar mass of GarBreadium to kg in order to use the de broglie equation? First you must find the weight of a single atom of GarBreadium -> (3.257g/1mol) x (1mol/6.02x20^23atoms) = 5.24x10^-24 g/atoms. Then you multiply by 1000 (1000g in 1 kg). Lastly you ...
- Sat Nov 03, 2018 4:27 pm
- Forum: Administrative Questions and Class Announcements
- Topic: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
- Replies: 121
- Views: 17213
Re: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
can anyone please help me with number 2? I got to dividing the molar mass of 667 by 30.024 and got 22? but i think its wrong because its such a large number. Thus my molecular formula so far is C22H44O22 ?? pls help Same... :( Actually, I just solved it. ill walk you through it: first you want ti d...
- Sat Nov 03, 2018 4:19 pm
- Forum: Administrative Questions and Class Announcements
- Topic: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
- Replies: 121
- Views: 17213
Re: MIDTERM PRACTICE - Garlic Bread Review Session [ENDORSED]
Karla_Ocampo 4E wrote:can anyone please help me with number 2? I got to dividing the molar mass of 667 by 30.024 and got 22? but i think its wrong because its such a large number. Thus my molecular formula so far is C22H44O22 ?? pls help
Same... :(
- Wed Oct 24, 2018 9:18 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Uncertainty in speed
- Replies: 5
- Views: 2392
Re: Uncertainty in speed
Why is it asking for speed? What does speed have to do with uncertainty of position?
- Tue Oct 23, 2018 7:04 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Problem 2.47
- Replies: 3
- Views: 955
Re: Problem 2.47
Be sure that when removing electrons, the electrons from the ns state are removed first before removing those from the (n-1)d state. (e.g. 4s state electrons before 3d electrons) what this means is, for example in B, 3d^5 comes before 4s^2 when written out, so since 4s^2 is in front that is the orb...
- Tue Oct 23, 2018 1:34 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Exercise 2.29
- Replies: 10
- Views: 3555
Re: Exercise 2.29
I will cover this in class in detail. This question is about 20 pages ahead of what we have covered. I am confused with this question which asks "How many electrons can have the the following quantum numbers in an atom, a) n=2, l-1 b)n=4, l=2, m1=-2 c) n=2 d) n=3, l=2, m1=+1 ?" and with 2...
- Fri Oct 19, 2018 1:17 pm
- Forum: Properties of Electrons
- Topic: Speed of an Electron (hw 1.43)
- Replies: 8
- Views: 4521
Re: Speed of an Electron (hw 1.43)
you could draw a square with the perimeter of the square representing the shell or orbit of an atom and putting an electron there, which would symbolize a potential place where the electron can be.
- Fri Oct 19, 2018 1:14 pm
- Forum: Properties of Light
- Topic: Friday 10/5 Lecture
- Replies: 7
- Views: 633
Re: Friday 10/5 Lecture
Also, when measuring a photon's energy, you are dealing with nu (Hz)
- Fri Oct 19, 2018 1:00 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Clarification on Heisenberg Equation
- Replies: 2
- Views: 310
Re: Clarification on Heisenberg Equation
I believe that what they are referring to is the fact that electrons move at the speed of light, which is why we use C (3 x 10^8 m.s^-1) in many formulas. So while we can calculate momentum, the electron has already moved a huge distance in barely any time.
- Tue Oct 16, 2018 6:07 pm
- Forum: Properties of Light
- Topic: Photons of light
- Replies: 5
- Views: 7727
Re: Photons of light
I get how you got E from the wavelength, but why do you need to divide 64 by the answer? (I also understand where the 64 came from) Is it to get the photons isolated from the J??
- Tue Oct 16, 2018 5:19 pm
- Forum: DeBroglie Equation
- Topic: H.W. Problem 1.55
- Replies: 3
- Views: 1245
Re: H.W. Problem 1.55
Why do we have to multiply 3600 by 100. I get that 100 cm is a meter, but wouldn't we then divide 3600 to get 3.6 meters?
- Fri Oct 12, 2018 1:19 pm
- Forum: Empirical & Molecular Formulas
- Topic: Empirical & Molecular Formulas
- Replies: 11
- Views: 1495
Re: Empirical & Molecular Formulas
Jasmine Chow 1F wrote:Can the empirical and molecular formula be the same?
They can be the same as long as the molar mass of the molecule is equal to the molar mass that would be given by the empirical.
- Fri Oct 12, 2018 1:17 pm
- Forum: Photoelectric Effect
- Topic: Variable for frequency
- Replies: 6
- Views: 533
Re: Variable for frequency
I guess you could replace nu (the greek letter that stands for frequency and looks like a V) with Hz so that it could be easier to differentiate in your own work, but I would make sure to be careful because the question will most likely give you the frequency with a V instead of Hertz.
- Fri Oct 12, 2018 1:14 pm
- Forum: DeBroglie Equation
- Topic: Angstrom?
- Replies: 8
- Views: 1517
Re: Angstrom?
It's important to remember that angstrom is only a measure of distance (meters), so be careful not to call 1 x 10^-10 an angstrom, because it could be 1 x 10^-10 liters or moles or anything, and angstrom wouldn't fit in anything other than meters.
- Mon Oct 08, 2018 3:04 pm
- Forum: Empirical & Molecular Formulas
- Topic: L35
- Replies: 5
- Views: 3468
Re: L35
First, you must convert the 2.50 t of NaBr to grams using the conversion factor 1.0 x 10^6 grams = 1 ton. Then you find the molar mass of NaBr (102.89g) and divide the grams of NaBr by NaBr's molar mass. Next, find the mole ratio between Fe and NaBr which is 3 mol Fe: 8 mol NaBr (don't forget to ma...
- Thu Oct 04, 2018 2:15 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Molarity and Dilution
- Replies: 11
- Views: 4406
Re: Molarity and Dilution
So the 75 mL of the original solution is not required to solve the final molarity?
- Wed Oct 03, 2018 7:36 pm
- Forum: Limiting Reactant Calculations
- Topic: Limiting Reactant Question
- Replies: 7
- Views: 1402
Re: Limiting Reactant Question
Do you have to find moles before finding limiting reactant?
- Tue Oct 02, 2018 12:20 pm
- Forum: Balancing Chemical Reactions
- Topic: Calculating Net Moles
- Replies: 3
- Views: 1635
Re: Calculating Net Moles
I wanted to follow up on this question; I too am hung up on one of the pre/post-assessment questions. It does not seem to be explained in the video module. Here is the question: 8. During a summer camping weekend 4 moles of butane (C4H10) gas were used for cooking. Chose the right balanced equation...
- Tue Oct 02, 2018 12:05 pm
- Forum: Balancing Chemical Reactions
- Topic: Net Number of Moles
- Replies: 3
- Views: 239
Net Number of Moles
What's the best way to find the net number of moles produced in a chemical reaction?
Ex. 4 moles of butane (C4H10) gas were combusted. Find the net number of moles of gas produced.
Ex. was taken from pre-module.
Ex. 4 moles of butane (C4H10) gas were combusted. Find the net number of moles of gas produced.
Ex. was taken from pre-module.
- Mon Oct 01, 2018 11:27 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3008603
Re: Post All Chemistry Jokes Here
Kevin Nguyen 4G wrote:Did you know that you can cool yourself to -273.15˚C and still be 0k?
That joke made ABSOLUTE ZERO sense.
- Mon Oct 01, 2018 2:16 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3008603
Re: Post All Chemistry Jokes Here
Explaining how one side of an equation must equal the other.