Search found 43 matches
- Sat Dec 08, 2018 5:41 pm
- Forum: Lewis Acids & Bases
- Topic: 6th edition 12.17
- Replies: 5
- Views: 472
Re: 6th edition 12.17
A metal hydroxide is generally basic, which is why BaO is basic. SO3 is acidic because a nonmetal oxide is generally acidic.
- Sat Dec 08, 2018 9:10 am
- Forum: Properties & Structures of Inorganic & Organic Acids
- Topic: J5 Sixth Edition
- Replies: 1
- Views: 446
Re: J5 Sixth Edition
H3O+ and H+ are the same thing, H+ is just a shorthand for H3O+!
- Thu Dec 06, 2018 11:00 am
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: (6th Edition) #12.49
- Replies: 1
- Views: 222
Re: (6th Edition) #12.49
I had the same question. I know that a weaker acid has a stronger conjugate base (and vice versa) but I was not able to figure out the structure of Morphine. I read in the Textbook that molecules with higher oxidation numbers are stronger acids, so if that applies I imagine BrO is a stronger base. H...
- Tue Dec 04, 2018 11:57 am
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Orbitals
- Replies: 3
- Views: 607
Re: Orbitals
What values are you referring to?
- Tue Dec 04, 2018 11:56 am
- Forum: Bronsted Acids & Bases
- Topic: Bronsted v. Lewis
- Replies: 1
- Views: 253
Bronsted v. Lewis
What is an example of a Lewis acid that is not a Bronsted? (or a base)
- Tue Dec 04, 2018 11:55 am
- Forum: Lewis Acids & Bases
- Topic: Naming of acids
- Replies: 2
- Views: 309
Re: Naming of acids
I think you should be familiar with the more common names from my understanding.
- Sun Dec 02, 2018 5:40 pm
- Forum: Bronsted Acids & Bases
- Topic: Bronsted v. Lewis v. Arrhenius
- Replies: 4
- Views: 650
Re: Bronsted v. Lewis v. Arrhenius
A Lewis acid accepts an electron pair, while a Bronsted acid donates a proton. A Lewis base donates an electron pair, and a Bronsted base accepts a proton.
Every Bronsted base is a Lewis base, but not every Lewis base is a Bronsted base.
Good luck!
Every Bronsted base is a Lewis base, but not every Lewis base is a Bronsted base.
Good luck!
- Thu Nov 29, 2018 11:17 am
- Forum: Bronsted Acids & Bases
- Topic: J15
- Replies: 2
- Views: 334
J15
Homework question J15 asks for the chemical equation of a proton transfer of a cation or anion with water
For example, a) NaC6H5O
How do you write this equation? The answer in the back of the book doesn't include Na in any part of the equation either.
For example, a) NaC6H5O
How do you write this equation? The answer in the back of the book doesn't include Na in any part of the equation either.
- Thu Nov 29, 2018 10:01 am
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Chelating Ligands
- Replies: 1
- Views: 247
Chelating Ligands
How do you tell if a ligand will form a chelate? What does it mean to be a chelate?
- Tue Nov 27, 2018 2:09 pm
- Forum: Hybridization
- Topic: Homework hybrid orbitals
- Replies: 1
- Views: 249
Re: Homework hybrid orbitals
The s character is the proportion of the hybridized orbital that is s. A hybridized orbital is like an average of the types of orbitals that make it up, so an sp2 hybridized orbital has less s character than an sp orbital. As the s-character increases, the angle also increases. Hope this helps!
- Tue Nov 27, 2018 2:07 pm
- Forum: Hybridization
- Topic: pi bonds
- Replies: 3
- Views: 332
Re: pi bonds
If you have an sp2 hybridized orbital, there is one p orbital left that is not hybridized. When you are filling electrons into the orbitals, the energy difference between sp2 and p is very small (because you can think of sp2 as an average of s and 2 p orbitals), so it is more energy favorable for th...
- Tue Nov 27, 2018 10:03 am
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: ligands and dentates
- Replies: 3
- Views: 397
Re: ligands and dentates
A ligand is any electron rich species that forms 1 or more bonds with a cation. A mono dentate bonds with a cation at 1 site, so it donates 1 electron pair. A Bidentate bonds at 2 sites, and donates 2 electron pairs. A tridentate bonds at 3 sites, and a hexadendate bonds at 6 sites.
- Fri Nov 23, 2018 5:40 pm
- Forum: Dipole Moments
- Topic: 6th Edition 4.29
- Replies: 2
- Views: 349
Re: 6th Edition 4.29
The first 2 structures are both polar because the Chlorine are very electronegative and would pull the dipole moments heavily towards the side they are on. In the third structure, the Chlorines are placed opposite each other and cancelling each other's dipole moment.
- Fri Nov 23, 2018 5:38 pm
- Forum: Lewis Structures
- Topic: Lewis Structure to 3D
- Replies: 3
- Views: 461
Re: Lewis Structure to 3D
I think that 2 of the Hydrogen would be connected with a wedged line, and 2 with a dotted line. I imagine that the Nitrogens would be connected on the same plane.
- Fri Nov 23, 2018 5:35 pm
- Forum: Sigma & Pi Bonds
- Topic: Drawing bonds
- Replies: 3
- Views: 356
Re: Drawing bonds
I don't think you will have to draw a sigma or pi bond, but you should know how they look on the internuclear axis. Sigma bonds are bonded directly on the axis, and pi bonds are bonded above/below the axis. Therefore, sigma bonds are moveable and can rotate, but pi bonds cannot rotate.
- Fri Nov 23, 2018 5:32 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Can the electronegativities of central/non-central atoms affect the bond angle?
- Replies: 2
- Views: 302
Re: Can the electronegativities of central/non-central atoms affect the bond angle?
I think that if there are no lone pairs, the bond angle would be equal. It might slightly change with lone pairs, but not dramatically. However, this does help clarify polarity/dipole moments!
- Tue Nov 13, 2018 3:09 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Electron Density
- Replies: 2
- Views: 208
Re: Electron Density
You must also consider lone pairs that change the angles between atoms surrounding the central atom.
- Tue Nov 13, 2018 3:08 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Rule 3 of the VSPER model
- Replies: 1
- Views: 199
Re: Rule 3 of the VSPER model
The lone pairs on the central atom determine the angles between the surrounding atoms. So technically, you do need to consider the position of the lone pairs, even though the shape is determined by the atoms.
- Tue Nov 13, 2018 3:02 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Rule 2 of VSEPR Model
- Replies: 2
- Views: 238
Re: Rule 2 of VSEPR Model
This rule means that when determine molecular structure, a single-, double-, and triple- bond all are treated as the same number of electronic region (1 region each). A double-bond is not considered 2 regions of density when determining shape.
- Sun Nov 11, 2018 6:28 pm
- Forum: Dipole Moments
- Topic: Bonding
- Replies: 3
- Views: 303
Re: Bonding
I believe that these attractions have minor differences, but we will consider them equal in this class.
- Fri Nov 09, 2018 1:01 pm
- Forum: Octet Exceptions
- Topic: Octet vs formal charge
- Replies: 16
- Views: 3052
Re: Octet vs formal charge
Is formal charge also more important than having resonance structure? How much does resonance affect stability?
- Fri Nov 09, 2018 12:57 pm
- Forum: Coordinate Covalent Bonds
- Topic: Coordinate Covalent Bond Definition
- Replies: 3
- Views: 2018
Re: Coordinate Covalent Bond Definition
How can you tell if a molecule has a coordinate covalent bond? Can you differentiate by the Lewis structure?
- Sun Nov 04, 2018 3:57 pm
- Forum: Lewis Structures
- Topic: Expanded Octet
- Replies: 4
- Views: 464
Expanded Octet
Are the atoms in the middle of a molecule generally the atoms with an expanded octet (rather than atoms on the periphery)? For example, in ICl4^-, even though it would make more sense for one of the Chlorine atoms to hold the negative charge because it is more electronegative than Iodine, the Iodine...
- Sat Nov 03, 2018 1:05 pm
- Forum: Lewis Structures
- Topic: Expanded Octet of Terminal Atoms
- Replies: 1
- Views: 592
Re: Expanded Octet of Terminal Atoms
From my understanding, they should be able to have an expanded octet as long as they are in at least the third period.
- Sat Nov 03, 2018 1:04 pm
- Forum: Lewis Structures
- Topic: Calculation of bond length
- Replies: 3
- Views: 349
Re: Calculation of bond length
The resonance bond length is around the average of the bonds that compromise it. I don't think at our level we can know exactly the bond length.
- Sat Nov 03, 2018 1:02 pm
- Forum: Lewis Structures
- Topic: Midterm Question about Central Atom in Lewis Structure
- Replies: 1
- Views: 174
Re: Midterm Question about Central Atom in Lewis Structure
I believe that is the general rule, so yes!
- Sat Oct 27, 2018 3:34 pm
- Forum: Sigma & Pi Bonds
- Topic: determining which bonds are in a molecule
- Replies: 4
- Views: 492
Re: determining which bonds are in a molecule
Yes, you also have to write out lewis structures to determine if bonds are single, double, or triple- and then showing sigma versus pi bonds!
- Sat Oct 27, 2018 3:32 pm
- Forum: Sigma & Pi Bonds
- Topic: Sigma v. Pi
- Replies: 6
- Views: 873
Re: Sigma v. Pi
Additionally, a sigma bond is a direct overlap over the nuclear axis, whereas a pi bond is an overlap above/below that axis.
- Sat Oct 27, 2018 3:32 pm
- Forum: Ionic & Covalent Bonds
- Topic: Homework 2B.21
- Replies: 3
- Views: 340
Re: Homework 2B.21
Additionally, if you write out both structures and calculate the formal charge (whichever has a 0 formal charge). The molecule with zero formal charge is the most stable structure, which is why it would be more likely to exist.
- Sat Oct 27, 2018 3:25 pm
- Forum: Trends in The Periodic Table
- Topic: electron affinity 1F.11
- Replies: 3
- Views: 758
Re: electron affinity 1F.11
Although I do not know if this is definitively why... I imagine that Be and Mg have equal ionization energies because both of their s shells are filled fully with 2 electrons. However this would not apply to Ga and In, but maybe because they only have 1 electron each in their valence shell (p), so i...
- Sat Oct 20, 2018 1:11 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: energy emission
- Replies: 1
- Views: 244
energy emission
In the atomic spectroscopy module, there is a true or false question:
The energy of an atom is increased when electromagnetic radiation is emitted from it?
The correct answer is false, does this mean the magnitude of the energy becomes lower, or the energy becomes more negative?
The energy of an atom is increased when electromagnetic radiation is emitted from it?
The correct answer is false, does this mean the magnitude of the energy becomes lower, or the energy becomes more negative?
- Sat Oct 20, 2018 11:11 am
- Forum: Photoelectric Effect
- Topic: Oil Drop Experiment
- Replies: 2
- Views: 280
Re: Oil Drop Experiment
This is also confusing me. I think naturally oil is not charged so the experimenters must have altered it manually?
- Sat Oct 20, 2018 11:09 am
- Forum: Einstein Equation
- Topic: Spectroscopy experimenting
- Replies: 4
- Views: 310
Re: Spectroscopy experimenting
I believe that if the energy of the photon = the threshold frequency, there is enough energy to remove an electron but not enough to give it a velocity. however, if the energy of the photon is greater than the frequency, the electron would have kinetic energy.
- Sat Oct 20, 2018 11:07 am
- Forum: Properties of Light
- Topic: 6th Edition: Problem 1.9
- Replies: 3
- Views: 327
Re: 6th Edition: Problem 1.9
You can determine the event by the frequency, wavelength, and energy based on a chart earlier in the chapter. I don't think that you will have to know these numbers, but you should know the range of visible light (400 nm to 700 nm).
- Sat Oct 13, 2018 6:51 pm
- Forum: Properties of Electrons
- Topic: Rydberg constant
- Replies: 7
- Views: 804
Re: Rydberg constant
You use the Rydberg constant when you are solving for the energy change when an electron changes energy levels.
- Sat Oct 13, 2018 6:50 pm
- Forum: Properties of Light
- Topic: Photoelectric Effect Module #28
- Replies: 1
- Views: 153
Re: Photoelectric Effect Module #28
a. Kinetic energy= 1/2(mv^2), and the mass of an electron is 9.109x10^-31 kg. b. I believe the energy here required to to remove 1 sodium electron would be equal to the work function. c. the Energy of the photon = work function + kinetic energy. If you find the energy, you also know that E=hv, (v=fr...
- Sat Oct 13, 2018 6:44 pm
- Forum: Photoelectric Effect
- Topic: Work Function
- Replies: 4
- Views: 226
Re: Work Function
I believe you would need to know either the threshold frequency or the velocity to answer this type of problem.
- Wed Oct 10, 2018 5:00 pm
- Forum: Properties of Light
- Topic: Homework Question 1A15
- Replies: 3
- Views: 226
Re: Homework Question 1A15
Since you know that it is part of the Lymann series (because it is a Hydrogen in the UV spectrum), you can fill in that the final n value is n=1. Then, you can plug that into the equation (frequency= Rydberg's constant((1/final n^2)-(1/initial n^2) and solve!
- Sun Oct 07, 2018 5:11 pm
- Forum: Limiting Reactant Calculations
- Topic: Chem Mod Limiting Reactants
- Replies: 2
- Views: 264
Re: Chem Mod Limiting Reactants
For Q30, A would be the limiting reactant because for every 1 mole of B being used, 2 moles of A are required.
For Q32, B would be in excess because all of A cannot use up all of B (because it is limiting).
I am also lost on question 33, sorry!
For Q32, B would be in excess because all of A cannot use up all of B (because it is limiting).
I am also lost on question 33, sorry!
- Sun Oct 07, 2018 5:08 pm
- Forum: Limiting Reactant Calculations
- Topic: Module 3 Question
- Replies: 3
- Views: 203
Re: Module 3 Question
No, because the law of conservation of mass. Additionally, that is why the percent yield will never be over 100%!
- Fri Oct 05, 2018 10:18 am
- Forum: Balancing Chemical Reactions
- Topic: Balancing reactions tips
- Replies: 29
- Views: 2039
Re: Balancing reactions tips
What helps me the most is to first balance the elements that occur the least, and then I move on to elements other than Oxygen and Hydrogen. I save elements that are not combined with anything other than itself for last!
- Mon Oct 01, 2018 12:13 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Question G25 in 6th edition [ENDORSED]
- Replies: 2
- Views: 163
Question G25 in 6th edition [ENDORSED]
Question G25 in the sixth edition asks how many molecules of substance X are left after diluting a solution 90 times. What kind of equation can you set up to solve this?
- Mon Oct 01, 2018 12:08 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Question G13 page F59 7th edition [ENDORSED]
- Replies: 1
- Views: 153
Re: Question G13 page F59 7th edition [ENDORSED]
Once you have the moles in the new solution (.05 mol), you need to multiply by the mole ratio of (2 moles N)/(1 mole NH4NO3)to find the moles of Nitrogen. Hope this helps!